For two programs at a university, the type
of student for two majors is as follows.

Find the probability a student is a science major,
given they are a graduate student.

The determinant of the given matrix is -6.

The determinant of the given matrix can be found by using the formula det(A) = a(det(M11)) - b(det(M12)) + c(det(M13)), where Mij is the matrix obtained by deleting the i-th row and j-th column of A. Applying this formula, we get:

det(A) = a(det(M11)) - b(det(M12)) + c(det(M13))
= a(((-2e)(c+i))-((-2f)(b+h))) - b(((-2d)(c+i))-((-2f)(a+g))) + c(((-2d)(b+h))-((-2e)(a+g)))
= -2(aei + bfg + cdh + cei + bdi + afh)
= -2(det(a b c d e f g h i))
= -2(3)
= -6.

Therefore, the determinant of the given matrix is -6. This means that the matrix is invertible, since its determinant is non-zero. Intuitively, this makes sense, since the matrix is a 3x3 matrix with three linearly independent rows.

The negative sign indicates that swapping two rows or columns of the matrix would change its sign, but would not affect its invertibility.

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The solution to the differential equation dx/dt = x*sin(t), with the initial condition x(0) = 1, is x(t) = e^(-cos(t)).

To solve the differential equation:

dx/dt = x*sin(t)

We can separate the variables and integrate both sides:

1/x dx = sin(t) dt

Integrating both sides gives:

ln|x| = -cos(t) + C

Where C is a constant of integration. Solving for x, we have:

|x| = e^(-cos(t)+C) = e^C * e^(-cos(t))

Since x(0) = 1, we can substitute t=0 and x=1 into the solution to find C:

|1| = e^C * e^(-cos(0))

So e^C = 1, and C=0. Substituting this value of C back into the solution, we have:

|x| = e^(-cos(t))

Since the initial condition x(0) = 1, we take the positive value of the absolute value:

x(t) = e^(-cos(t))

Therefore, the solution to the differential equation dx/dt = x*sin(t), with the initial condition x(0) = 1, is x(t) = e^(-cos(t)).

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C  is  the true mean is contained in it.

Since we have a 98% confidence interval, we expect 98% of the intervals generated from the 1200 samples to contain the true mean. Therefore, we expect 0.98 x 1200 = 1176 intervals to contain the true mean.

Since we have a 98% confidence interval, we expect 2% of the intervals generated from the 300 samples to not contain the true mean. Therefore, we expect 0.02 x 300 = 6 intervals to not contain the true mean.

We cannot determine with certainty whether the true mean is contained in the given interval, but we can say that there is a 98% probability that the true mean falls within the interval

Therefore, the answer is C.

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Answer:

8

Step-by-step explanation:

The first step is to simplify the fraction inside the parentheses,

using a^b / a^c = a^(b-c)

6^7  3^3             6^(7-6)   3^(3-4)   = 6^1  3^-1   =  6/3  =2

-----------------  =                                                    

6^6    3^4          

Now we take care of the outside parentheses

3^2 = 2*2*2 = 8                                                            

The lim(x→∞) x*sin(6π/x) does not exist.

The limit you want to find is lim(x→∞) x*sin(6π/x). To solve this limit, we will use l'Hospital's Rule, which is applicable when the limit takes the indeterminate form 0*∞.

Step 1: Rewrite the limit as a fraction:
lim(x→∞) (sin(6π/x)) / (1/x)

Step 2: Apply l'Hospital's Rule by differentiating both the numerator and the denominator:
Numerator: d(sin(6π/x))/dx = (6π*cos(6π/x)) * (-1/x²)
Denominator: d(1/x)/dx = -1/x²

Step 3: Simplify the limit:
lim(x→∞) [(6π*cos(6π/x)) * (-1/x²)] / [-1/x²] = lim(x→∞) 6π*cos(6π/x)

Step 4: Evaluate the limit:
Since cos(6π/x) oscillates between -1 and 1 as x approaches infinity, the limit does not exist.

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To start off, we can use the fact that the total area under the probability density function (PDF) must equal 1. This is because the PDF represents the probability of X taking on any particular value, and the total probability of all possible values of X must add up to 1.

So, we can set up an integral to solve for the constant c:

integral from 0 to 1 of c(1-x) dx = 1

Integrating c(1-x) with respect to x gives:

cx - (c/2)x^2 evaluated from 0 to 1

Plugging in the limits of integration and setting the integral equal to 1, we get:

c - (c/2) = 1

Solving for c, we get:

c = 2

Now that we have the value of c, we can use the PDF to find probabilities of X taking on certain values or falling within certain intervals. For example:

- The probability that X is exactly 0.5 is:

PDF(0.5) = 2(1-0.5) = 1

- The probability that X is less than 0.3 is:

integral from 0 to 0.3 of 2(1-x) dx = 2(0.3-0.3^2) = 0.36

- The probability that X is between 0.2 and 0.6 is: integral from 0.2 to 0.6 of 2(1-x) dx = 2[(0.6-0.6^2)-(0.2-0.2^2)] = 0.56

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The Option C is correct that Negative 3 less-than x less-than-or-equal-to 2 by solving inequality using an algebraic expression.

The equation-like form of the formula 5x 4 > 2x + 3 has an arrowhead in place of the equals sign. It is an illustration of inequity. The left half, 5x 4, is larger than the right half, 2x + 3, as evidenced by this.

To solve the inequality, we need to isolate the variable, x, in the middle of the inequality.

Starting with:

-4 < 3x + 5 ≤ 11

Taking out 5 from each component of the inequality:

-4 - 5 < 3x + 5 - 5 ≤ 11 - 5

Simplifying:

-9 < 3x ≤ 6

Dividing by 3 (and remembering to reverse the direction of the inequality if we divide by a negative number):

-3 < x ≤ 2

Therefore, the solution to the inequality is:

-3 < x ≤ 2

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The Option C is correct that Negative 3 less-than x less-than-or-equal-to 2 by solving inequality using an algebraic expression.

The equation-like form of the formula 5x 4 > 2x + 3 has an arrowhead in place of the equals sign. It is an illustration of inequity. The left half, 5x 4, is larger than the right half, 2x + 3, as evidenced by this.

To solve the inequality, we need to isolate the variable, x, in the middle of the inequality.

Starting with:

-4 < 3x + 5 ≤ 11

Taking out 5 from each component of the inequality:

-4 - 5 < 3x + 5 - 5 ≤ 11 - 5

Simplifying:

-9 < 3x ≤ 6

Dividing by 3 (and remembering to reverse the direction of the inequality if we divide by a negative number):

-3 < x ≤ 2

Therefore, the solution to the inequality is:

-3 < x ≤ 2

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Answer:

C. 5/16 yd^2

Step-by-step explanation:

We know that surface area is simply the sum of the area of every shape on a three-dimensional object.

Thus, we can find the surface area of the square pyramid by finding the sum of the area of the square and the area of the four triangles.

The formula for area (A) of a square is,

[tex]A=s^2[/tex], where s is the side of the square.

In the square, the side is 1/4 yd, so we can find its area:

[tex]A=(1/4)^2\\A=1/16[/tex]

The formula for area of a triangle is,

[tex]A=1/2bh[/tex], where b is the base and h is the height.

We're given that the base of every triangle is 1/4 yd and the height of each triangle is 1/2 height.

Thus, we can find the area of all four triangles by finding the area of one triangle and multiply it by 4:

[tex]4A=4(1/2*1/4*1/2)\\4A=4(1/16)\\4A=1/4[/tex]

Now, the sum of the area of the square and four triangles will give us the surface area of the square pyramid:

[tex]SA=1/16+1/4\\SA=5/16[/tex]

The simplified form of the given expression is:

(2x + 3) / [(x - 3) (x + 1)]

To do simplification of the expression, we first need to find the common denominator of the two fractions. The common denominator of the first fraction is (x - 3) (x + 1), and the common denominator of the second fraction is (x - 3).

Next, we can combine the two fractions using the common denominator:

[(2x - 1) (x - 3) + 1 (x + 1)] / [(x - 3) (x + 1) (x - 3)]

Simplifying the numerator gives:

(2x² - 7x + 4) / [(x - 3) (x + 1) (x - 3)]

Now we can factor the numerator:

[(2x - 1) (x - 4)] / [(x - 3) (x + 1) (x - 3)]

And finally, we can cancel out the common factor of (x - 3) in the numerator and denominator, giving us the simplified form:

(2x + 3) / [(x - 3) (x + 1)]

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For 90° bending of sheet metal, the preferred operation depends on the specific requirements of the application and the properties of the sheet metal being used.

V-die bending is a common method that involves the use of a V-shaped die and a punch to bend the metal into a 90° angle.

This method is suitable for bending metal with sharp corners and straight flanges, and can produce accurate and repeatable bends with a high degree of consistency.

Wiping-die bending, on the other hand, involves the use of a wiping die and a punch to gradually form the metal into a 90° angle. This method is suitable for bending metal with irregular shapes or contours, and can produce smooth and uniform bends without causing any damage to the metal.

In general, if the sheet metal has sharp corners and straight flanges, V-die bending is preferred as it can produce accurate and repeatable bends with a high degree of consistency.

However, if the sheet metal has irregular shapes or contours, wiping-die bending may be preferred as it can produce smooth and uniform bends without causing any damage to the metal. Ultimately, the choice of bending operation will depend on the specific requirements of the application and the properties of the sheet metal being used.

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Bit strings of length 10 contain

(a) 210 bit strings of exactly four 1s,

(b) 386 bit strings of at most four 1s,

(c) 848 bit strings of at least four 1s.

(a) To count the number of bit strings of length 10 that contain exactly four 1s, we can use the binomial coefficient formula:

C(10, 4) = 10! / (4! * (10-4)!) = 210

Here, C(10, 4) represents the number of ways to choose 4 positions out of 10 for the 1s, and the remaining positions must be filled with 0s.

(b) To count the number of bit strings of length 10 that contain at most four 1s, we need to count the number of bit strings with 0, 1, 2, 3, or 4 1s and add them up. We can use the binomial coefficient formula for each case:

C(10, 0) + C(10, 1) + C(10, 2) + C(10, 3) + C(10, 4) = 1 + 10 + 45 + 120 + 210 = 386

(c) To count the number of bit strings of length 10 that contain at least four 1s, we can count the total number of bit strings and subtract the number of bit strings with fewer than four 1s.

The total number of bit strings is [tex]2^{10}[/tex]= 1024.

The number of bit strings with fewer than four 1s is the same as the number of bit strings with at most three 1s, which we found in part (b):

[tex]2^{10}[/tex]- C(10, 0) - C(10, 1) - C(10, 2) - C(10, 3) = 1024 - 1 - 10 - 45 - 120 = 848

Therefore, there are 210 bit strings of length 10 that contain exactly four 1s, 386 bit strings of length 10 that contain at most four 1s, and 848 bit strings of length 10 that contain at least four 1s.

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The missing value is 17. So the complete equation is: 2² + 3² + 17 = 4²

We can start by simplifying the left-hand side of the equation:

2² + 3² = 4 + 9 = 13

Now we can rewrite the equation as:

13 + ? = ?²

To solve for the missing value, we can try different values of ? until we find one that satisfies the equation. We notice that ? = 4 works, since:

13 + 4 = 17

4² = 16

Therefore, the missing value is 17. So the complete equation is:

2² + 3² + 17 = 4²

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The linearization of the function z=xy√ at the point (-2, 9) is: L(x,y) = -6 + 3√(x+2) - 2√(y-9)

The linearization of a function f(x,y) at a point (a,b) is given by:

L(x,y) = f(a,b) + fx(a,b)(x-a) + fy(a,b)(y-b)

where fx and fy are the partial derivatives of f with respect to x and y, evaluated at (a,b).

In this case, we have f(x,y) = xy√ and (a,b) = (-2,9). We need to find fx and fy at this point:

fx(x,y) = y√

fy(x,y) = x√

Evaluating these at (-2,9), we get:

fx(-2,9) = 3√

fy(-2,9) = -2√

So the linearization of f at (-2,9) is:

L(x,y) = f(-2,9) + fx(-2,9)(x+2) + fy(-2,9)(y-9)

= -6 + 3√(x+2) - 2√(y-9)

Therefore, the linearization of the function z=xy√ at the point (-2, 9) is:

L(x,y) = -6 + 3√(x+2) - 2√(y-9).

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The given sequence 1, 4/3, 5/3, 2, ... is neither an arithmetic nor a geometric sequence.

An arithmetic sequence is a sequence of numbers in which the difference between any two consecutive terms is always the same. This difference is called the "common difference" and is denoted by the letter "d". The first term of an arithmetic sequence is usually denoted by "a".

The general form of an arithmetic sequence can be written as:

a, a + d, a + 2d, a + 3d, ...

According to the given information:

The given sequence 1, 4/3, 5/3, 2, ... is neither an arithmetic nor a geometric sequence.

An arithmetic sequence is a sequence in which the difference between any two consecutive terms is constant. In other words, if you subtract any term from its adjacent term, you will always get the same value. Similarly, a geometric sequence is a sequence in which the ratio between any two consecutive terms is constant. In other words, if you divide any term by its adjacent term, you will always get the same value.

Let's check the given sequence to see if it satisfies the conditions for arithmetic or geometric sequences:

1 - 4/3 = -1/3

4/3 - 5/3 = -1/3

5/3 - 2 = -1/3

As we can see, the differences between consecutive terms are not constant, so the given sequence is not an arithmetic sequence.

1 / (4/3) = 3/4

(4/3) / (5/3) = 4/5

(5/3) / 2 = 5/6

As we can see, the ratios between consecutive terms are not constant, so the given sequence is not a geometric sequence.

Therefore, the given sequence 1, 4/3, 5/3, 2, ... is neither an arithmetic nor a geometric sequence.

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Answer:

Arithmetic

Step-by-step explanation:

4/3-1= 1/3

1+1/3=4/3

4/3+1/3=5/3

5/3+1/3=6/3

6/3=2

So that means this is an arithmetic sequence.

The values of V such that G'(V) = 0 are V = 5 and V = -5.

What is derivative?

In calculus, the derivative is a measure of how much a function changes with respect to its input. It is the slope of the tangent line at a point on a curve, or the rate of change of the function at that point. In other words, the derivative of a function tells us how quickly the function is changing at a particular point.

To find the derivative of the function G(V), we need to take the derivative of each term and add them up.

[tex]G(V) = V^3 - 75V + 6[/tex]

[tex]G'(V) = 3V^2 - 75[/tex]

To find the values of V such that G'(V) = 0, we set G'(V) equal to zero and solve for V:

[tex]3V^2 - 75 = 0[/tex]

[tex]3V^2 = 75[/tex]

[tex]V^2 = 25[/tex]

V = ±5

Therefore, the values of V such that G'(V) = 0 are V = 5 and V = -5.

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For the original function f(x) = x2 + 9:
Domain: Since x2 is defined for all real numbers, the domain is all real numbers, or (-, ).
Range: Since x2 is always non-negative and we add 9 to it, the range is [9, ].

To find the inverse function of f(x) = x^2 + 9, follow these steps:

1. Replace f(x) with y: y = x^2 + 9
2. Swap x and y: x = y^2 + 9
3. Solve for y to get the inverse function:

Subtract 9 from both sides:
x - 9 = y^2

Take the square root of both sides (considering only the positive square root as the original function has a non-negative output):
y = sqrt(x - 9)

The inverse function is f^(-1)(x) = sqrt(x - 9).

Now let's find the domain and range:

For the original function f(x) = x^2 + 9:
- Domain: Since x^2 is defined for all real numbers, the domain is all real numbers or (-∞, ∞).
- Range: Since x^2 is always non-negative and we add 9 to it, the range is [9, ∞).

For the inverse function f^(-1)(x) = sqrt(x - 9):
- Domain: The square root function is defined only for non-negative numbers. So, the domain is [9, ∞).
- Range: The square root function has a non-negative output. So, the range is [0, ∞).

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The acceleration of the particle with position vector r(t) = (g sin t)i + (g cos t)j + htk can be expressed in the form [tex]aT^T + aN^N[/tex] without finding T and N.  

The tangential component of the acceleration is given by aT = g cos t i - g sin t j, while the normal component is aN = -h k. This means that the particle is undergoing a uniform circular motion with radius g and angular velocity dθ/dt = g/h.

The tangential component of the acceleration is responsible for changing the speed of the particle, while the normal component is responsible for changing the direction of the velocity vector.

In other words, the tangential component is perpendicular to the normal component and together they form a right-angled triangle with hypotenuse equal to the acceleration vector.

Therefore, by expressing the acceleration vector in terms of its tangential and normal components, we can better understand the motion of the particle without explicitly calculating the unit tangent and normal vectors.

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The value of x from the Intersecting chords that extend outside circle is 13

From the question, we have the following parameters that can be used in our computation:

Intersecting chords that extend outside circle

Using the theorem of intersecting chords, we have

8 * (3x - 2 + 8) = 12 * (x + 5 + 12)

This gives

8 * (3x + 6) = 12 * (x + 17)

Using a graphing tool, we have

x = 13

Hence, the value of x is 13

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To find the volume, you need to multiply all the values together.

1/3 x 5/6 x 2/3 = 5/27

The period of simple harmonic motion of the mass-spring system can be found using the formula: T = 2π√(m/k) where T is the period, m is the mass, and k is the spring constant.

In this case, the mass of the object is 2 N, but we need to convert this to kilograms by dividing by the acceleration due to gravity: m = 2 N / 9.8 m/s^2 = 0.204 kg The spring constant is given as 4 N/m. Plugging in these values to the formula, we get: T = 2π√(0.204 kg / 4 N/m) = 2π√(0.051 m) ≈ 0.804 s .

Therefore, the period of simple harmonic motion for this mass-spring system is approximately 0.804 seconds. Now, we can find the period using the mass (0.204 kg) and the spring constant (4 N/m). T = 2π √(0.204 kg / 4 N/m) T ≈ 2π √(0.051) T ≈ 1.42 s The period of simple harmonic motion is approximately 1.42 seconds.

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Answer:

Step-by-step explanation:

So 20% of the science club students is 10.

I am trying to find 100% as this equals ALL the students on the science club trip.

20% = 10

100% / 20% = 5

This means I need to multiply both sides by 5 to get to 100%
20% = 10

(Multiply both sides by 5)

100% = 50

Therefore there are 50 students in the science club (C)

On a strange and unusual island, the natives of which are either Knights or Knaves. The natives are neither A nor B are knaves in first scenario.    The natives are either all of them of C, D, and E are knights or two of them are knaves in other scenario. The natives are F is a knave, G is a knave, and H's truth value cannot be determined in third scenario. There is no gold on the island.

If A is a knight, then what A said must be true, which means both A and B are knaves, which is a contradiction. Therefore, A must be a knave, which means what A said must be false. Thus, neither A nor B are knaves.

If C is a knight, then what C said must be true, which means all of them are knaves, which is a contradiction. Therefore, C must be a knave, which means what C said must be false.

Thus, at least one of them is not a knave. If D is a knight, then what D said must be true, which means D is a knight, and exactly one of them is a knight, which is a contradiction since C is a knave. Therefore, D must be a knave, which means what D said must be false. Thus, either all of them are knights or two of them are knaves.

We encounter three natives named F, G, and H. F says that all of them are knaves, which means that either F, G, or H must be a knight. G says that exactly one of them is a knave, which means that G cannot be a knight because if G were a knight, then both F and H would have to be knaves, which contradicts what F said.

So, G must be a knave. Now, we know that at least one of F or H is a knight, since either of them being a knight would satisfy G's statement. We can't determine which one is a knight, so we can't determine the truth value of H's statement.

Therefore, we cannot determine whether H is a knight or a knave. So, the answer is F is a knave, G is a knave, and H's truth value cannot be determined.

Suppose J is a knight. Then, what J said must be true, which means there is gold on the island. But this contradicts what J said since J is not a knave. Therefore, J must be a knave, which means what J said must be false. Thus, there is no gold on the island.

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The total number of people is given as follows:

5 + 16 + 27 + 19 + 18 + 3 = 88.

Out of these people, 3 are females with green eyes, hence the percentage is given as follows:

p = 3/88 x 100%

p = 3.4%.

Out of these 88 people, 16 + 27 = 43 are males without green eyes, hence the percentage is given as follows:

p = 43/88 x 100%

p = 48.9%.

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If a researcher conducted a 2-tailed, non-directional test with an alpha level of .04, then the corresponding critical value Z-score(s) for a 2-tailed, non-directional test with an alpha level of 0.04 would be -2.06 and 2.06, respectively.

Explanation:

To find the critical value z-scores for a 2-tailed, non-directional test with an alpha level of 0.04, you can follow these steps:

Step 1. Divide the alpha level by 2, since it's a 2-tailed test: 0.04 / 2 = 0.02.

Next, we can use a standard normal distribution table or a Z-score calculator to find the Z-score(s) that correspond to an area of 0.02 in the tail(s) of the standard normal distribution.

For a 2-tailed test, we need to find two critical values, one for each tail. Since the standard normal distribution is symmetric, the critical values will be the same in magnitude but opposite in sign. So, we need to find the Z-score that corresponds to an area of 0.02 in the lower tail and the Z-score that corresponds to an area of 0.02 in the upper tail.

Step 2. Use a z-score table or online calculator to find the z-score corresponding to an area of 0.98 (1 - 0.02) in the standard normal distribution.

Therefore, the corresponding critical value Z-score(s) for a 2-tailed, non-directional test with an alpha level of 0.04 would be -2.06 and 2.06, respectively.

The correct answer is:
a. +2.06 and -2.06

These z-scores represent the critical values, with 2% of the area in each tail of the distribution.

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The solution to the differential equation [tex]dp[/tex] = aP - b, where a and b are nonzero constants, is P(t) = (b/a) + Ce^(at), where C is a constant of integration.

To solve the differential equation, we can start by separating the variables and integrating both sides. This gives us:

∫ 1/P dP = ∫ a dt - ∫ b dt

Simplifying the integrals and taking antiderivatives, we get:

ln|P| = at - bt + C

where C is a constant of integration. Exponentiating both sides gives us:

|P| = e^(at-bt+C)

Since a and b are nonzero constants, we can write this as:

|P| = e^C * e^(at) * e^(-bt)

Using the absolute value notation is not necessary because the exponential function is always positive, but it is included here for completeness. We can rewrite this as:

P(t) = ± e^C * e^(at) * e^(-bt)

We can simplify this expression by setting the constant of integration to C = ln(b/a), which gives us:

P(t) = (b/a) * e^(at) + De^(-bt)

where D is a constant of integration. We can simplify this further by combining the constants of integration, giving us:

P(t) = (b/a) + Ce^(at)

where C = De^(-bt) is another constant of integration. This is the final solution to the differential equation [tex]dp[/tex] = aP - b.

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An unbiased estimator is a sample statistic that equals a population parameter on average.

An unbiased estimator is a sample statistic that equals a population parameter on average. In statistics, the bias (or bias) of an estimator is the difference between the expected value of the estimator and the true value of the predicted parameter. An approximate rule or decision with zero bias is called neutral. In statistics, "bias" is the goal of the estimator. Bias is a different concept from consistency: the consistency estimate may equal the actual measurement, but be biased or unbiased; see Deviation and Consistency for more information. Unbiased estimates are preferred over unbiased estimates, but in practice, sampling estimates are often used (usually unbiased) because estimates without further consideration of the population are unfair.

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The measure of arc CD is 56°

Angles around a point describes the sum of angles that can be arranged together so that they form a full turn.

The sum of angle at a point is 360°. This means that the addition of angles Ina circle or angles on a circumference is 360°

Since BE is a diameter, it shows that it has divided the circle into two equal part.

Therefore;

BC + CD + DE = 180°

49+75 + CD = 180°

CD = 180-(49+75)

CD = 180 - 124

CD = 56°

therefore the measure of the arc CD is 56°

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The first graph has a domain of approximately (-2.4, 14.1) and a range of approximately (-10, 6.9), while the second graph has a domain of approximately (-8, 3) and a range of approximately (-5, 13). The domain and range may vary slightly depending on the specific graphs being analyzed.

Based on the information provided, I can help you estimate the domain and range of the function y = f(x) for both scenarios: 1. For the first graph: Domain of f(x): Approximately (-2.4, 14.1). Range of f(x): Approximately (-10, 6.9)2. For the second graph: Domain of f(x): Approximately (-8, 3). Range of f(x): Approximately (-5, 13)Please note that these are estimates and may vary slightly depending on the specific graphs you are analyzing.For question 2, the domain of the function y = f(x) graphed to the right is the interval from x = 1 to x = 2.4. This is because the graph does not extend beyond these values on the x-axis. Therefore, any input value for x that falls within this interval is within the domain of the function.

The range of the function y = f(x) graphed to the right is the interval from y = 1 to y = 10.69. This is because the graph does not extend beyond these values on the y-axis. Therefore, any output value for y that falls within this interval is within the range of the function.For question 3, the domain of the function y = f(x) graphed to the right is the interval from x = -8 to x = infinity.

This is because the graph extends indefinitely towards the left on the x-axis, but does not extend beyond any point towards the right. Therefore, any input value for x that falls within this interval is within the domain of the function.The range of the function y = f(x) graphed to the right is the interval from y = 13 to y = infinity.

This is because the graph extends indefinitely upwards on the y-axis, but does not extend beyond any point downwards. Therefore, any output value for y that falls within this interval is within the range of the function.

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The missing graph is attached below

Answer:

8. Image below!

9. 134 feet

10. Below.

11. The answers represent the timings at which the rocket was at height 164 feet.

12. 5.702s

Step-by-step explanation:

8. Image below

9. [tex]f(1)= -16(1)^2+100(1)+50 = 134[/tex]

I'm doing this in a rush but I can tell you what you can do for the rest.

10. Use the quadratic formula

[tex]164 = -16x^2+100x+50\\\\0 = -16x^2+100x-214\\\\[/tex]

And set a= -16, b=100, c=-214

You'll get two x-values.

11. The answers represent the timings at which the rocket was at height 164 feet.

12. Hitting the ground means the height is equal to 0. So...

[tex]0 = -16x^2+100x+50\\[/tex]

Using the quadratic formula you get

x=5.702s

and

x= 0.548s

This means the rocket hits the ground at 5.702s.

The probability of drawing at least one red card is (d) 60/90.

The probability of drawing at least one red card can be found by finding the probability of drawing two yellow cards and subtracting that from 1.

The probability of drawing a yellow card on the first draw is 6/10. The probability of drawing a yellow card on the second draw, without replacement, is 5/9 (since there are only 9 cards left). So the probability of drawing two yellow cards in a row is:

(6/10) * (5/9) = 30/90

To find the probability of drawing at least one red card, we can subtract this from 1:

1 - 30/90 = 60/90

So the answer is (d) 60/90.

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