Maya started driving at 2pm at 80km/h. What time did Maya get to L.A?

The margin of error for the 99% confidence interval used to estimate the population proportion is approximately 0.00992 or 0.992%.

To find the margin of error for a 99% confidence interval for a population proportion, we need to follow these steps:

Step 1: Determine the sample proportion (p-hat)
In this case, 1860 out of 9300 subjects showed improvement. So, the sample proportion is:
p-hat = 1860/9300 ≈ 0.2

Step 2: Find the critical value (z-score) for the 99% confidence interval
For a 99% confidence interval, the critical value (z-score) is approximately 2.576. This can be found using a z-table or statistical calculator.

Step 3: Calculate the standard error
The standard error can be found using the formula:
SE = sqrt((p-hat * (1 - p-hat))/n)
Where n is the number of subjects. In this case:
SE = sqrt((0.2 * (1 - 0.2))/9300) ≈ 0.00385

Step 4: Calculate the margin of error
Finally, the margin of error can be found by multiplying the critical value and the standard error:
Margin of Error = z-score * SE
Margin of Error = 2.576 * 0.00385 ≈ 0.00992

So, the margin of error for the 99% confidence interval used to estimate the population proportion is approximately 0.00992 or 0.992%.

In summary, the margin of error for this clinical test is 0.992%, which represents the uncertainty around the estimated population proportion of subjects who show improvement after treatment. This means that we can be 99% confident that the true population proportion lies within 0.2 ± 0.00992.

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The statement "consider a wave form s(t)=5 sin 10 π t 2 sin 12 π t. the signal s(t) is sampled at 10 hz. do you expect to see aliasing" is true because aliasing is expected.

When sampling a signal s(t) = 5 sin(10πt) * 2 sin(12πt) at 10 Hz, you can expect to see aliasing. The Nyquist sampling theorem states that a signal should be sampled at least twice the highest frequency present in the signal to avoid aliasing.

The two sinusoids in s(t) have frequencies of 5 Hz (10πt) and 6 Hz (12πt). The highest frequency is 6 Hz, so according to the Nyquist theorem, the signal should be sampled at least at 12 Hz (2 times the highest frequency) to avoid aliasing. Since the signal is sampled at 10 Hz, which is lower than the required 12 Hz, aliasing will occur.

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The return value of the given linear regression model with weights containing an input vector < 3, 1, 5 > is 85

To find the output of the given linear regression model with weights w0=6, w1=9, w2=2, and w3=10 for the input vector <3, 1, 5>,

follow these steps:

1. Multiply each input value by its corresponding weight: (3 * w1) + (1 * w2) + (5 * w3)

2. Add the result from step 1 to the bias term, w0.

Let's calculate:

Step 1: (3 * 9) + (1 * 2) + (5 * 10) = 27 + 2 + 50 = 79

Step 2: 79 + 6 = 85

So, the linear regression model will return a value of 85 for the given input vector <3, 1, 5>.

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Answer:

Step-by-step explanation:

To find the average value of the function f(x) = x^2(x^3 + 30) on the interval [-3, 3], we use the formula:

fave = (1/(b-a)) * ∫[a,b] f(x) dx

where a = -3 and b = 3.

So, we have:

fave = (1/(3-(-3))) * ∫[-3,3] x^2(x^3 + 30) dx

fave = (1/6) * [∫[-3,3] x^5 dx + 30∫[-3,3] x^2 dx]

fave = (1/6) * [0 + 30(2*3^3)]

fave = 2430

Therefore, the average value of the function f on the given interval is 2430.

To find the average value of the function h(u) = In(u) on the interval [1, 5], we use the formula:

have = (1/(b-a)) * ∫[a,b] h(u) du

where a = 1 and b = 5.

So, we have:

have = (1/(5-1)) * ∫[1,5] ln(u) du

have = (1/4) * [u ln(u) - u] from 1 to 5

have = (1/4) * [(5 ln(5) - 5) - (ln(1) - 1)]

have = (1/4) * (5 ln(5) - 4)

have = 0.962

Therefore, the average value of the function h on the given interval is approximately 0.962.

To find all numbers b such that the average value of f(x) = 6 + 10x - 9x^2 on the interval [0, b] is equal to 7, we use the formula:

fave = (1/(b-a)) * ∫[a,b] f(x) dx

where a = 0 and b = b.

So, we have:

7 = (1/b) * ∫[0,b] (6 + 10x - 9x^2) dx

7b = [6x + 5x^2 - 3x^3/3] from 0 to b

7b = 2b^2 - 3b^3/3 + 6

21b = 6b^2 - b^3 + 18

b^3 - 6b^2 + 21b - 18 = 0

Using synthetic division, we find that b = 2 is a root of this polynomial equation. Dividing by (b-2), we get:

(b-2)(b^2 - 4b + 9) = 0

The quadratic factor has no real roots, so the only solution is b = 2.

Therefore, the only number b such that the average value of f(x) on the interval [0, b] is equal to 7 is 2.

To estimate the average world population to the nearest million during the time period of 1950 to 1980, we need to find:

ave = (1/(1980-1950)) * ∫[1950,1980] P(t) dt

ave = (1/30) * ∫[1950,1980] 2560e^(0.017185t) dt

Using the formula for integrating exponential functions, we get:

ave = (1/30) * [2560

The overall order of the reaction is 2nd order.

Option B is the correct answer.

We have,

The overall order of a chemical reaction is the sum of the orders of the reactants in the rate law.

In this case,

The rate law is given as:

Rate = k[X][Y]

The order with respect to X is 1, and the order with respect to Y is 1.

Therefore, the overall order of the reaction is:

1 + 1 = 2

Thus,

The overall order of the reaction is 2nd order.

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The axis of symmetry is 2, x-intercept are (3,0) and (1,0) , y-intercept is (0,3) vertex is 2

Here we have to point the values on the given graph.

Then we get the graph like the following.

Now, we have to identify the value of axis of symmetry, x-intercept(s), y-intercept, & vertex through the following definition.

The axis of symmetry is a vertical line that divides the graph of a function into two mirror images. It passes through the vertex, which is the highest or lowest point on the graph. To find the axis of symmetry, we need to look for the vertical line that divides the graph into two equal parts is x = 2.

The x-intercept(s) are the points where the graph of a function crosses the x-axis. To find the x-intercepts, we need to look for the points where the graph intersects the x-axis, which is the horizontal line with a y-coordinate of (3,0) and (1,0)

The y-intercept is the point where the graph of a function crosses the y-axis. To find the y-intercept, we need to look for the point where the graph intersects the y-axis, which is the vertical line with an x-coordinate of 0 that is (0,3)

The vertex is the highest or lowest point on the graph of a function, depending on whether the function opens upward or downward. To find the vertex, we need to locate the point where the function reaches its maximum or minimum value is 2.

The completed graph is illustrated below.

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Answer:

= 8

Step-by-step explanation:

4/5 * 10 = 8/

1

= 8

The surface given by the function f(x, y) = y² is a cylinder with rulings parallel to the x-axis. The generating curve is described by z = y². The domain of the function is the entire xy-plane, and the range is z ≥ 0.

The function f(x, y) = y² describes a surface in three-dimensional space. Since the variable x is missing, the surface will not depend on x, and the rulings (lines) of the surface will be parallel to the x-axis. This makes the surface a cylinder with rulings parallel to the x-axis.

The generating curve of the surface is given by z = y², which means that the z-coordinate of any point on the surface is equal to the square of the y-coordinate. This generates a parabolic shape along the y-axis, extending infinitely in the positive and negative y-directions.

The domain of the function is the entire xy-plane, which means that the function is defined for all values of x and y. There are no restrictions on the values of x and y in the domain.

The range of the function is z ≥ 0, which means that the z-coordinate of any point on the surface will always be greater than or equal to zero. This is because the function f(x, y) = y² always produces non-negative values for z, since any real number squared is always non-negative.

Therefore, the surface described by the function f(x, y) = y² is a cylinder with rulings parallel to the x-axis, the generating curve is given by z = y², the domain is the entire xy-plane, and the range is z ≥ 0.

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R is not reflexive. To show this, we need to find an integer a such that a is not related to itself under R. Let a = 1, then 3a - 5a = -2, which is not even. Therefore, 1R1 is not true, and R is not reflexive.

R is not symmetric. To show this, we need to find integers a and b such that aRb but bRa is not true. Let a = 1 and b = 2, then 3a - 5b = -13, which is odd. Therefore, 1R2 is false. However, 3b - 5a = 1, which is also odd, so 2Ra is false. Therefore, R is not symmetric.

R is anti-symmetric. To show this, we need to show that if aRb and bRa, then a = b. Suppose 3a - 5b and 3b - 5a are both even. Then we can write 3a - 5b = 2k and 3b - 5a = 2m for some integers k and m. Adding these equations gives 2a - 2b = 2(k + m), or a - b = k + m, which is even. Therefore, aRb and bRa implies that a = b, and R is anti-symmetric.

R is transitive. To show this, suppose aRb and bRc, then 3a - 5b and 3b - 5c are both even. We can write 3a - 5b = 2k and 3b - 5c = 2m for some integers k and m. Substituting the first equation into the second gives 3a - 5c = 3b - 5b - 5c = -2b - 5c + 10b = 8b - 5c = 2(4b - 5c/2) = 2n for some integer n. Therefore, aRc, and R is transitive.

R is not an equivalence relation because it is not reflexive and not symmetric. However, R is a partial order because it is anti-symmetric and transitive.

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The equation for the line tangent to y = [tex]-1 - 7x^2[/tex] at (-2, -29) is y = 28(x + 2) - 29.

To find the equation for the line tangent to y = [tex]-1 - 7x^2[/tex] at (-2, -29), we'll need to first find the derivative of the given function to determine the slope of the tangent line.

The given function is y = [tex]-1 - 7x^2.[/tex]

Differentiate y with respect to x:
dy/dx = -14x

Now, evaluate the derivative at the point (-2, -29) to find the slope of the tangent line:
dy/dx| (x=-2) = -14(-2) = 28

The slope of the tangent line is 28. To find the equation of the tangent line, use the point-slope form: y - y1 = m(x - x1), where m is the slope, and (x1, y1) is the given point (-2, -29).

y - (-29) = 28(x - (-2))
y + 29 = 28(x + 2)

Now, solve for y:
y = 28(x + 2) - 29

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(x - (a+48))² + (y - (b+19))² = 24.5² This is the equation for all possible positions (x,y) on the boundary of the cell tower's service coverage.

To write an equation for all possible positions (x,y) on the boundary of the cell tower's service coverage, we first need to determine the coordinates of the center of the coverage.

We know that the cell tower is located 48 miles east and 19 miles north of the center of the small town, so we can add these distances to the coordinates of the town's center. If we let (a,b) be the coordinates of the town's center, then the coordinates of the cell tower would be (a+48,b+19).

Next, we know that the cell tower services everything within a radius of 24.5 miles from it. This means that any point (x,y) on the boundary of the coverage circle would be exactly 24.5 miles away from the cell tower. We can use the distance formula to write an equation for this:

√[(x - (a+48))² + (y - (b+19))²] = 24.5

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It will take them 12 minutes to complete a lap at the same time.

A prime factor is any non-zero natural integer that can be divided only by itself and by 1. Actually, a few of the initial prime numbers are  and so forth. a sum which has been doubled to yield a new sum.

For example, if we divide 15 by Three and 5, you get 3 -5 = 15. major components: All prime but non-composite components are referred to as prime factors. a few 30 prime factors2, 3, or 5 are. It is essential to list 2 twice as (2 2 3 (or (22 3) in order to factors 12 since only 2 и 3 were primary elements of 12. 2 + 3 cannot be added to make 12.

Finding the lowest common multiple  of the time required for each person to do a lap will help us determine how long it will take Sean, Luis, and Heron to finish a lap simultaneously.

Brendan requires four minutes to complete a lap.

For Miguel, a lap takes 6 minutes to complete.

Heron need three minutes to finish a lap.

With 4, 6, & 3 as the LCM is 12. As a result, it will take Rory, Miguel, and Heron 12 minutes to finish a lap simultaneously.

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To find the value of probability p that maximizes the variance of a Bernoulli random variable, we need to take the derivative of the variance formula with respect to p and set it equal to 0: d/dp [p(1-p)] = 1-2p = 0.

The value of probability p that maximizes the variance of a Bernoulli random variable is 1/2.The variance of a Bernoulli random variable is given by the formula Var(X) = p(1-p), where p is the probability of success. To find the value of p that maximizes the variance, you can take the derivative of the variance formula with respect to p and set it to zero.d(Var(X))/dp = d(p(1-p))/dp = 1 - 2pSetting the derivative equal to zero:1 - 2p = 0Solving for p:p = 1/2So, the value of probability p that maximizes the variance of a Bernoulli random variable is 0.5 or 1/2.

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The text is asking for a step-by-step sequence to solve quadratic problems using the quadratic formula.

A quadratic equation is a polynomial equation of the second degree, meaning it contains at least one squared term. The standard form of a quadratic equation is ax² + bx + c = 0, where a, b, and c are constants and x is the variable. The quadratic formula is used to find the solution(s) of a quadratic equation. The formula is x = (-b ± sqrt(b² - 4ac)) / 2a.

Answer:

Step-by-step explanation:

put your equation into

ax²+bx+c

determine a, b, and c

plug into formula

simplify numbers under the square root first (b²-4ac)

then simplify the root.  ex.  √12 can be simplified to 2√3

then reduce if the bottom can be reduced with both of the terms on top

the critical numbers of g(t) are approximately -0.690 and 0.690

To find the critical numbers of the function g(t) = t⁵ - t, we need to first find the derivative of the function.

g'(t) = 5t⁴ - 1

Then we set the derivative equal to zero and solve for t:

5t⁴  - 1 = 0
5t⁴ = 1
t⁴ = 1/5
t = [tex]±(1/5)^{(1/4)}[/tex]

However, we need to check if these values are in the domain of the function, which is t < 4.

[tex](1/5)^{(1/4)}[/tex]≈ 0.690, which is less than 4, so it is a valid critical number.
-[tex](1/5)^{(1/4)}[/tex] ≈ -0.690, which is also less than 4, so it is also a valid critical number.

Therefore, the critical numbers of g(t) are approximately -0.690 and 0.690, and we can write them as a comma-separated list:

-0.690, 0.690

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The inverse of g' (-1/5) is -15625 / 4^{5/4}.

To find g' (-1/5), we first need to find g(x) which is the inverse of f(x). To do this, we start by setting y = f(x) and solving for x.
y = f(x) = {x^7} / {x^4 + 4}

Multiplying both sides by x^4 + 4, we get:
y(x^4 + 4) = x^7

Expanding the left side, we get:
y(x^4) + 4y = x^7

Substituting u = x^4, we get:
yu + 4y = u^(7/4)

Rearranging and solving for y, we get:
y = (u^(7/4)) / (u + 4)

Substituting back u = x^4, we get:
y = (x^7) / (x^4 + 4)

Thus, g(x) = (x^7) / (x^4 + 4).

Now, to find g'(-1/5), we need to take the derivative of g(x) and evaluate it at x = -1/5.

Using the quotient rule, we get:
g'(x) = [7x^6(x^4+4) - x^7(4x^3)] / (x^4+4)^2

Substituting x = -1/5, we get:
g'(-1/5) = [7(-1/5)^6((-1/5)^4+4) - (-1/5)^7(4(-1/5)^3)] / ((-1/5)^4+4)^2

Simplifying and expressing in exact form, we get:
g'(-1/5) = [-(4/3125)^(3/4)] / (4/3125)^2 = -1 / (4/3125)^{5/4} = -15625 / 4^{5/4}

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Answer: 87

Step-by-step explanation: 3 x 29=87 because you are multiplying the amount of people in the survey by 3

Based on the analysis, there is no 3x3 matrix A such that A^2 = -I_3. To understand this analysis let's consider whether there exists a 3x3 matrix A such that A^2 = -I_3, where I_3 is the 3x3 identity matrix.

Step:1. Start by assuming that there is a 3x3 matrix A such that A^2 = -I_3.
Step:2. Recall that the determinant of a matrix squared (det(A^2)) is equal to the determinant of the matrix (det(A)) squared: det(A^2) = det(A)^2.
Step:3. Compute the determinant of both sides of the equation A^2 = -I_3: det(A^2) = det(-I_3).
Step:4. For the 3x3 identity matrix I_3, its determinant is 1. Therefore, the determinant of -I_3 is (-1)^3 = -1.
Step:5. From step 2, we know that det(A^2) = det(A)^2. Since det(A^2) = det(-I_3) = -1, we have det(A)^2 = -1.
Step:6. However, no real number squared can equal -1, which means det(A)^2 cannot equal -1.
Based on the analysis, there is no 3x3 matrix A such that A^2 = -I_3.

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The length of the curve is approximately 4.7 units when rounded to one decimal place.

Explanation:

To find the length of the curve, follow these steps:

Step 1: To find the length of the curve, we need to use the formula:

length = ∫(a to b) √(dx/dt)^2 + (dy/dt)^2 dt

Step 2: In this case, we have x = cos(2t) and y = sin(3t) for 0 ≤ t ≤ 2, First, find the derivatives dx/dt and dy/dt so we can find dx/dt and dy/dt as:

dx/dt = -2sin(2t)
dy/dt = 3cos(3t)

Step 3: Substituting these into the formula, we get:

length = ∫ (0 to 2) √((-2sin(2t))^2 + (3cos(3t))^2) dt

length = ∫ (0 to 2) √(4sin^2(2t) + 9cos^2(3t)) dt
This integral must be evaluated numerically.

Step 4: Using a calculator or software to evaluate the integral numerically, we get:

length ≈ 4.7

Therefore, the length of the curve is approximately 4.7 units when rounded to one decimal place.

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The step 6 of his work canbe justified using any of the algebraic properties

Given that

Step 6: x equals 20

In general, algebraic properties that could be used to justify Step 6 might include the following:

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The two vectors parallel to the plane are AB(8, -5, 4) and AC(0, 7, 6).

The vector perpendicular to the plane is (-58, -48, 56).

Vector AB is parallel to the plane since it connects two points on the plane, A and B.

The coordinate point is calculated as;

AB = B - A

= (11, -5, 2) - (3, 0, -2)

= (8, -5, 4)

Vector AC is also parallel to the plane since it connects two points on the plane, A and C.

The coordinate point is calculated as;

AC = C - A

= (3, 7, 4) - (3, 0, -2)

= (0, 7, 6)

To find a vector perpendicular to the plane, we will take the cross product of two vectors in the plane, such as AB and AC.

AB x AC = (8, -5, 4) x (0, 7, 6)

=  (-58, -48, 56)

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Answer:

The statements that are true are:

6 + 3 = 9 and 4 · 4 = 16 (both are true statements)

5 · 3 = 15 or 7 + 5 = 20 (at least one of these statements is true, since the word "or" means that only one of the two statements needs to be true for the entire statement to be true)

The other two statements are false:

If 6 > 10, then 8 · 3 = 24 (this statement is false, because the premise "6 > 10" is false, and a false premise can never imply a true conclusion)

If 6 · 3 = 18, then 4 + 8 = 20 (this statement is false, because the conclusion "4 + 8 = 20" does not follow logically from the premise "6 · 3 = 18")

The final image is real since it is located to the right of the second lens. It is also upright since the magnification is positive.

(a) Using the thin lens formula, 1/f = 1/p + 1/q, where f is the focal length, p is the object distance, and q is the image distance, we have:

1/f = 1/p - 1/q1

Substituting the given values, we get:

1/11.6 = 1/16.2 - 1/q1

Solving for q1, we get:

q1 = 6.97 cm

Therefore, the image formed by the first lens is located 6.97 cm to the right of the lens.

(b) The image formed by the first lens acts as an object for the second lens. Using the thin lens formula again, we have:

1/f = 1/p2 + 1/q1

Substituting the given values, we get:

1/5 = 1/p2 + 1/6.97

Solving for p2, we get:

p2 = 3.32 cm

The distance from the second lens to the image of the first lens is then:

q2 = p2 + q1 = 3.32 + 6.97 = 10.29 cm

Therefore, the image of the first lens is located 10.29 cm to the right of the second lens.

(c) The object distance for the second lens is simply the image distance of the first lens:

p2 = q1 = 6.97 cm

(d) Using the thin lens formula again, we have:

1/f = 1/p2 + 1/q2

Substituting the given values, we get:

1/5 = 1/6.97 + 1/q2

Solving for q2, we get:

q2 = 13.95 cm

Therefore, the final image is located 13.95 cm to the right of the second lens.

(e) The magnification of the first lens is given by:

m1 = -q1/p = -6.97/16.2 ≈ -0.43

(f) The magnification of the second lens is given by:

m2 = -q2/p2 = -13.95/3.32 ≈ -4.20

(g) The total magnification of the system is given by the product of the magnifications of the two lenses:

m = m1 × m2 ≈ 1.81

(h) The final image is real since it is located to the right of the second lens. It is also upright since the magnification is positive.

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Answer:

24.15

Step-by-step explanation:

d = √ (x2 - x1)^2 + (y2 - y1)^2

AB = 8

BC = 4√5 = 8.94427190

AC = 2√13 = 7.21110255

Add 8 + 8.94 + 7.21 = 24.15

Answer:

24.15

Step-by-step explanation:

hope this helps

Using De Moivre's theorem, we have: z = r^(1/10) * (cos(θ/10) + i*sin(θ/10)). As we are looking for 10 roots, we need to find each root by varying k from 0 to 9: z_k = (√910)^(1/10) * (cos(2πk/10) + i*sin(2πk/10))Substitute k from 0 to 9 to obtain all the real and complex roots of the equation z^10 = 910.

To find all real and complex roots of the equation z^10 = 910, we can use the polar form of complex numbers. First, we can write 910 in polar form: 910 = 910(cos(0) + i sin(0)) Next, we can express z in polar form as well: z = r(cos(θ) + i sin(θ)) Substituting these expressions into the equation z^10 = 910 and using De Moivre's Theorem, we get: r^10(cos(10θ) + i sin(10θ)) = 910(cos(0) + i sin(0)) Equating the real and imaginary parts, we get: r^10 cos(10θ) = 910 cos(0) = 910 r^10 sin(10θ) = 910 sin(0) = 0

The second equation gives us two possible values of θ: θ = 0 and θ = π (since sin(π) = 0). For θ = 0, the first equation gives us: r^10 cos(0) = 910 r^10 = 910 r = (910)^(1/10) So one possible solution is z = (910)^(1/10). For θ = π, the first equation gives us: r^10 cos(10π) = 910 r^10 (-1) = 910 r^10 = -910 Since r must be real, this equation has no real solutions.

However, we can find 5 complex solutions by using the 5th roots of -910: (-910)^(1/5) = 2(cos(π/5) + i sin(π/5)) (-910)^(1/5) = 2(cos(3π/5) + i sin(3π/5)) (-910)^(1/5) = 2(cos(5π/5) + i sin(5π/5)) = -2 (-910)^(1/5) = 2(cos(7π/5) + i sin(7π/5)) (-910)^(1/5) = 2(cos(9π/5) + i sin(9π/5)) Using these values of r and θ, we can write the 6 solutions to z^10 = 910 as: z = (910)^(1/10) z = 2(cos(π/5) + i sin(π/5)) z = 2(cos(3π/5) + i sin(3π/5)) z = -2 z = 2(cos(7π/5) + i sin(7π/5)) z = 2(cos(9π/5) + i sin(9π/5))

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Using the limit comparison test, we determined that the series (A) diverges, (B) converges, (C) diverges, and (D) converges.

We can use the limit comparison test with the series 1/n to determine whether the series converges or diverges:

lim n→∞ (n7 + n2) / n = lim n→∞ (n7/n + n2/n) = ∞

Since this limit diverges to infinity, we cannot use the limit comparison test with the series 1/n. We can try another convergence test.

We can use the limit comparison test with the series 1/n3 to determine whether the series converges or diverges:

lim n→∞ (3n3 − 2n) / (6n5 + 2n + 1) = lim n→∞ (n2 − 2/n2) / (2n5 + 1/n + 1/n5) = 1/2

Since this limit is a positive finite number, the series converges if and only if the series ∑ 1/n^3 converges. Since the p-series with p = 3 converges, the series ∑ (3n^3 - 2n) / (6n^5 + 2n + 1) also converges.

We can use the limit comparison test with the series 1/n to determine whether the series converges or diverges:

lim n→∞ 2n / (4n − n2) = lim n→∞ 2/n(4 − n) = 0

Since this limit is a finite number, the series converges if and only if the series ∑ 1/n converges. Since the harmonic series diverges, the series ∑ 2n / (4n - n^2) also diverges.

We can use the limit comparison test with the series 1/n^2 to determine whether the series converges or diverges:

lim n→∞ sin(1/n) / (1/n^2) = lim n→∞ sin(1/n) * n^2 = 1

Since this limit is a positive finite number, the series converges if and only if the series ∑ 1/n^2 converges. Since the p-series with p = 2 converges, the series ∑ sin(1/n) / n also converges.

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let's firstly get the EQUATion, of the graph before we get the inequality.

so we have a quadratic with two zeros, at -6 and 8, hmmm and we also know that it passes through (-2 , 10)

[tex]\begin{cases} x = -6 &\implies x +6=0\\ x = 8 &\implies x -8=0\\ \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{original~polynomial}{a ( x +6 )( x -8 ) = \stackrel{0}{y}}\hspace{5em}\textit{we also know that } \begin{cases} x=-2\\ y=10 \end{cases}[/tex]

[tex]a ( -2 +6 )( -2 -8 ) = 10\implies a(4)(-10)=10\implies -40a=10 \\\\\\ a=\cfrac{10}{-40}\implies a=-\cfrac{1}{4} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{1}{4}(x+6)(x-8)=y\implies -\cfrac{1}{4}(x^2-2x-48)=y \\\\\\ ~\hfill {\Large \begin{array}{llll} -\cfrac{x^2}{4}+\cfrac{x}{2}+12=y \end{array}}~\hfill[/tex]

now, hmmm let's notice something, the line of the graph is a solid line, that means the borderline is included in the inequality, so we'll have either ⩾ or ⩽.

so hmmm we could do a true/false region check by choosing a point and shade accordingly, or we can just settle with that, since the bottom is shaded, we're looking at "less than or equal" type, or namely ⩽, so that's our inequality

[tex]{\Large \begin{array}{llll} -\cfrac{x^2}{4}+\cfrac{x}{2}+12\geqslant y \end{array}}[/tex]

The arc length of the polar curve r = 2 from θ = 0 to θ = 2 is 4.

Explanation:

To find the arc length of the polar curve r = 2 from θ = 0 to θ = 2, Follow these steps:

Step 1: To find the arc length of the polar curve r = 2 from θ = 0 to θ = 2, we can use the arc length formula for polar coordinates:

Arc length (L) = ∫√(r^2 + (dr/dθ)^2) dθ, from θ = 0 to θ = 2

Given r = 2, dr/dθ = 0 (since r is a constant)

Step 2: Now substitute r and dr/dθ into the formula:

L = ∫√(2^2 + 0^2) dθ, from θ = 0 to θ = 2

L = ∫√(4) dθ, from θ = 0 to θ = 2

L = ∫2 dθ, from θ = 0 to θ = 2

Step 3: Integrate with respect to θ:

L = 2θ | from θ = 0 to θ = 2

Step 4: Evaluate the definite integral:

L = 2(2) - 2(0) = 4

So the arc length of the polar curve r = 2 from θ = 0 to θ = 2 is 4.

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Answer:

[tex] \frac{y}{28} = \frac{7}{25} [/tex]

[tex]25y = 196[/tex]

[tex]y = 7.84[/tex]

Answer:

Step-by-step explanation:

4. percent x whole