To known the coefficient of friction and static force to solve this question.
What is kinetic friction force?
The term "kinetic friction" describes a force that exists between moving surfaces. A force is felt that is opposing the direction of a moving body on the surface. The amount of force that is applied will depend on the kinetic friction coefficients of the two materials.
What is coefficient of static force?
The highest ratio of applied force to normal force when there is no motion is known as the coefficient of static friction. We are all aware that frictional force opposes motion.
F=t²
fs max = 4/10*10= 4N
Therefore, at t= 2 blocks start moving
(t²-3) =ma
⇒ dv/dt= (t²-3)
⇒ ∫_o^v〖dv=∫_l^3(〗( (t²-3) dt
=v= 1/3 (27-8)-3(1)
=3.33m/s
Therefore, the frictional force acting on the box is 3.33m/s.
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if buoyant force push things upwards, why don't hot air balloons and planes get pushed into outer space
Answer:
I think that's because the force of gravity is greater than the buoyant force, and for the hot air balloons, they can increase/decrease the temperature of the air in the balloon in order for it to rise/fall for more control. For planes, they use aerodynamics as well as the help of a couple of engines to thrust the plane forward. I hope this helps.
Bumps, Blemishes and Beyond
Imagine that you are working in either a cosmetic surgery clinic or a medical spa, and you
are meeting a client for the first time. They have come to you for a simple procedure, but
when you're doing the consultation with the person, you notice some suspicious-looking
lesions on their skin. You explain to the client that you are concerned about them, and you'd
like them to see their healthcare provider before you can proceed with treatment. They ask
you to write your findings down so that they can share them with their primary care provider.
You are going to search for images of two different types of lesions online and imagine them
to be what your client is presenting with. Using the terminology that you learned about
lesions, describe them in enough detail that someone could picture the areas in their mind
without the images. You will be expected to submit the images to the dropbox to support
your written work. You will need to include the type, shape, distribution, color, size, and
presence of drainage in your descriptions for it to be considered complete.
Benzoyle peroxide
This chemical helps to eliminate excess oil from the skin, kills acne-causing bacteria, and removes dead skin cells that can block pores. Products containing benzoyl peroxide are sold over the counter in strengths ranging from 2.5% to 10%.
Can blemishes be removed with Vaseline?He continues by saying that the petroleum jelly itself is ineffective at treating the zit. By creating a seal over the skin, it actually aids in protecting the skin barrier as the zit heals.
Do skin imperfections disappear?Scars from acne do not completely disappear on their own. With age, depressed acne scars frequently grow more obvious due to collagen loss in the skin. But there are numerous procedures that might lessen the prominence of acne scars. hyperpigmentation following inflammation or Within a few months, redness could naturally.
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If another object (a can of beans) was dropped from 12 meters in free fall, how long will it take for that object to fall to the ground?
The time it takes the object to fall to the ground from a height of 12 m is 1.56 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the object to fall to the ground, we use the formula below.
Formula:
H = ut+gt²/2.............. Equation 1Where:
H = Heightg = Acceleration due to gravityt = Timeu = Intial velecityFrom the question,
Given:
u = 0 m/s (drop from height)g = 9.8 m/s²H = 12 mSubstitute these values into equation 1 and solve for t.
12 = (0×t)+(9.8t²)/29.8t² = 12×2t² = 12×2/9.8t² = 2.45t = √2.45t = 1.56 seconds.Hence, the time it takes the object to fall to the ground is 1.56 seconds.
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What is the distance between two objects if one (a 185,000 kg object) experiences a gravitational force of 0.00200 N due to a 225,000 kg object
Using the gravitational force, the mass of item 1 and object 2, and the Newton's law of gravity calculator, one may calculate the distance between two objects.
How is gravitational distance determined?g = GM/r2, where M is the Earth's mass, r is its radius (or the distance from the Earth's center to where you are standing), and G is the gravitational constant. The gravitational constant is G (without the subscripts), while the speed of light is c.
How is the gravitational force between two objects calculated?By applying Newton's equation, we can accomplish this quite easily: forcegravity is defined as G M m2 separation. Suppose that you weigh 60 kilograms and your colleague weighs 70 kilograms. The center-to-centre distance, r, is 1 m, and the gravitational constant, G, is 6.67 10 -11 newtons square meter kilogram-2.
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What type of interference occurs when the crests of one wave overlaps with the crests of another wave?.
Constructive interference occurs when crests of one wave overlap the crests of the other wave.
What are the properties of constructive interference?
The two waves must travel through the same medium along with the properties of the waves must be the same. They should have same amplitude and wavelength. The amplitude of the wave is the height of the crest or trough. Upward displacement occurs when the waves undergo constructive interference; hence, the upward displacement of the medium is greater than the displacement of the two interfering pulses.
It occurs when the phase difference between the two waves is an even multiple of π (180°).
Example: When we see two speakers right next to each other, we can experience constructive interference when the distance from each speaker to the observer is the same. The path difference should be equal to zero.
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5. the 1200-turn coil in a dc motor has an area per turn of 1.1x10-2 m2. the design for the motor specifies that the magnitude of the maximum torque is 5.8 nm. when the coil is placed in a 0.20-t magnetic field. what is the current in the coil?
The rotating equivalent of force is torque. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect.
A coil's torque is determined by:
equals niABsin
where I is the coil's current
Area of the coil equals A.
Magentic field = B
n is the coil's total number of turns.
and = angle between the field B and area vector A
The maximum torque would occur at 900, where sinθ = 1.
Maximum torque therefore equals niAB.
alternatively 5.8N-m = (1200) i(1.1x10-2m2) (0.20-T)
or the coil's current, I is 2.196A
The formula for torque is rF=rFsin(r). To put it another way, the cross product of the distance vector and the force vector, where 'a' is the angle between r and F, is what is known as torque (the distance between the pivot point and the place where force is applied).
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Complete the following statement: when a net torque is applied to a rigid object, it always produces a.
When a net torque is given to a rigid object, it always causes an angular velocity change.
What exactly is meant by torque?Torque is defined as a force that causes an object to revolve around an axis. In linear kinematics, force causes an item to accelerate; in rotational kinematics, torque causes an object to accelerate. Torque is a vector quantity.
Based on the vector values involved, we must predict what will happen when a net torque is applied to a rigid object.
As a result, when a net torque is applied to the rigid item, the rate of rotation changes.
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a cart starting from rest rolls down a hill and at the bottom has a speed of 4 m/s. if the cart were given an initial push. so its initial speed at the too of the hill was 3 m/s. what would x be its speed at the bottom?
The correct answer of speed at 5 m/s at the bottom.
What is the connection between speed and kinetic energy?
A moving object's kinetic energy is inversely related to its mass and to the square of its velocity. Accordingly, an item with identical mass and speed will have twice the kinetic energy as one with double the mass and speed will have four times the kinetic energy.
When starting from rest, the cart’s PE is changed into KE:
Change in PE = Change in KE = 1/2m(4)²
When starting from 3 m/s, the
final KE is: KEf= KEi+ Change in KE= 1/2 m(3) ²+ 1/2m(4) ²= 1/2 m(25)
= 1/2 m(5) ²
Speed is not the same as kinetic energy
Hence the answer of speed is 5 m/s.
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a constant torque of 31.4 space n times m is exerted on a pivoted wheel. if the angular acceleration is 4 pi space rad divided by s squared, then the moment of inertia will be
The moment of inertia will be 2.5kgm².
Inertia method an item will keep its present-day movement till a few force causes its speed or course to change. The term is nicely understood as shorthand for "the principle of inertia" as described with the aid of Newton in his first regulation of motion.
Inertia is a property of count number that causes it to withstand changes in pace (pace and/or path). consistent with Newton's first regulation of movement, an object with a given speed maintains that velocity except acted on by an external pressure.
Inertia is the pressure that holds the universe together. literally. without it, count number would lack the electric forces vital to shaping its present-day arrangement. Inertia is counteracted by way of the warmth and kinetic strength produced with the aid of transferring debris.
Calculation:-
τ=Iα
31.4=I×4π
31.4=I×4(3.14)
⟹I=2.5kgm²
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the speed of the incoming water is 15 cm/s and the cross-sectional area of the hose carrying the water is 4.0 cm2. 1) determine the time required for a 30-l container to be filled with water. (express your answer to two significant figures.)
The time required to fill a 25 liter container with water is 8.3 minutes.
What is time?Time can be described in mathematics as an ongoing and continuous series of events that take place one after another, from the past through the present, and into the future. The duration of events or the gaps between them can be measured, compared, or even ordered using time.It is possible to define time as the dimension on which any system evolves.Its length can be expressed in terms of milliseconds, seconds, minutes, hours, days, weeks, months, and years.It is a quantity that is a part of several measurements that are used to compare the length of events or the gaps between them, to compare how long they last, to order events, and to measure how quickly things change in the real world or in our conscious experience.To learn more about time from the given link :
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If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentum at this instant? express your answer in kilogram-meters squared per second squared.
The net torque applied to the item equals the rate of change of angular momentum.
The net torque is equal to the weight "mg" times the angle between the weight's line of action and the origin (x dL/dt = mgx = mgrCos) (36.8)
Alternatively, it is composed of the weight perpendicular to the position vector times its magnitude, r dL/dt = mgCos(36.8).
clearly the same equation.
Just enter the values because everything is already provided. Finding L's rate of change does not require knowledge of particle velocity.
what is angular momentum?
The characteristic of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.
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The net torque is equal to the weight "mg" times the angle between the weight's line of action in angular momentum and the origin (x dL/dt = mgx = mgrCos) (36.8)
What is angular momentum?
The characteristic of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.
The net torque applied to the item equals the rate of change of angular momentum. Alternatively, it is composed of the weight perpendicular to the position vector times its magnitude, r dL/dt = mgCos(36.8).
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the work required to carry a particle with a charge of 6.0 c from a 5.0-v equipotential surface to a 6.0-v equipotential surface and back again to the 5.0-v surface is:
The work required to carry a particle with a charge of 6.0 c from a 5.0-v equipotential surface to a 6.0-v equipotential surface and back again to the 5.0-v surface is zero.
What are the properties of equipotential surface?
The electric field present around the surface is perpendicular to an equipotential surface.
Two equipotential surface can never met or intersect.
The direction is always from high potential to low potential.
If there is an isolated point charge, then the equipotential surface is a sphere.
Equipotential points are those points in an electric field that has same electric potential. If these points are connected by any line or curve, it is said to be equipotential line and the surface on which it lies is the equipotential surface.
The work done between two points in an equipotential surface is always zero. It is calculated in the following manner:
If any charge moves from point Va to Vb in an equipotential surface, then work done in moving charge
W= q0 (Va- Vb)
As (Va- Vb) = 0 so the total work is equal to zero.
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How do you think you can calculate the total distance traveled if you were running at a constant speed?.
Distance = Speed x Time is a formula for calculating the total distance one covered while running at a constant speed.
To determine the total distance travelled if one is running at a constant speed we use formula:
d = s x t
d = distance covered
s = speed of the object
t = time taken.
The distance travelled is directly proportional to the amount of time required when the speed is constant.
d ∝ t
(at constant speed)
Distance = Speed x Time, is a formula for calculating the total distance one covered while running at a constant speed.
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if the tmt and e-elt get built as planned, what is one exciting potential discovery that astronomers hope to be able to make with them?
One exciting potential discovery that astronomers hope to be able to make with the E-ELT and TMT is life on other planets.
TMT and E-ELT are (currently) proposed telescopes. TMT (short for Thirty Meter Telescope) is a very large telescope composed of many small mirrors each about 1,4m in size. E-ELT (short for European Extremely Large Telescope) is going to be around 39m in diameter.
These proposed telescopes have very high resolution and sharper detection. They will be able to detect any exoplanet's atmosphere while it's transiting its star. In that detection, these telescopes may search for any biomarker molecules to detect the presence of life and habitability of the exoplanet.
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Why did the ball move the same distance when it was on the flatbed truck that accelerated 0. 2 m/s?.
The ball moves the same distance when it was on the flatbed truck because of Relative velocity.
The relative velocity of the ball with respect to the truck is same as of truck with respect to ball at equal times.
Relative velocity - Relative velocity is velocity of an object in relation to another object
It is the measure of how fast two objects are moving with respect to each other.
The distance travelled by each object is determined by product of velocity and time of motion
d = vt
where, d= distance
v = velocity
t = time
so here we can say that if the ball is moved the same distance when it was on truck, then the relative velocity of the ball with respect to truck is same as of truck with the ball.
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some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. what force (in n) must a 64.0 kg grouper exert to stay submerged in salt water if its body density is 1003 kg/m3?
The force (in n) must a 64.0 kg grouper exert to stay submerged in salt water if its body density is 1003 kg/m3 will be 15.6 newtons.
The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. Therefore, we have the mass of the fish times g times the ratio of densities minus 1, which is 85.0 kilograms times 9.80 newtons per kilogram times 1.025 times 10 to the 3 kilograms per cubic meter (density of seawater) divided by 1015 kilograms per cubic meter (density of the fish) and equals 8.21 newtons.
F= d/a
=1003 /64
=15.6 N
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while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever.
Using the theories of fulcrum ,we got that it is true that while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever.
A fulcrum is the stationary point of a lever while a lever arms connect the fulcrum to the points on the lever arms that are actually vertically aligned with the centers of mass
Hence, while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever is true.
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(Complete question) is:
while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever, Select true : false.
8. A bullet is fired horizontally from a gun. At the same time and from the same height,
a bullet is dropped. If we neglect the effects of air resistance, how will the time the
two bullets spend in the air compare to each other?
a. the bullet that is fired will spend less time in the air, hitting the ground first.
b. there is not enough information to determine this.
c. both bullets will spend the same amount of time in the air, landing at the same time.
d. the bullet that is fired will spend longer in the air, landing later.
Answer:
C hit the ground at the same time
Explanation:
Both bullets have to fall the same VERTICAL distance and are affected by gravity the same way in this regard.
approximately how many times greater is the atmospheric pressure in jupiter's core than on earth's surface?
Approximately 100 million times greater is the atmospheric pressure in jupiter's core than on earth's surface.
The average atmospheric pressure at sea level at 15 degrees Celsius is the unit of measurement known as an atmosphere. 1,013 millibars is equal to 760 millimeters of mercury, or 29.92 inches, in one atmosphere. When the bulb is pressed, air from the tube and bulb escapes as bubbles. The liquid's surface does, however, experience atmospheric pressure. The water moves inside the tube when we release the bulb. The pressure that the air around us puts on us is known as air pressure, whereas the pressure that the atmosphere puts on the earth is known as atmospheric pressure. Mercury barometer is used to measure atmospheric pressure, while tore gauges are used to measure air pressure. Since our internal pressure is roughly equal to the external atmospheric pressure, we are not affected by the pressure of the atmosphere around us.
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A family in a car with the ma of 1400 kg. In an accident it hit a wall and goe from a peed of 27 m/ to a tandtill in 1. 5 econd. Calculate the force involved
The force involved is F₁.₅=-25.2KN when the car hit a wall and goes from a speed of 27m/s
What is meant by force?A force is an influence in physics that can modify the velocity of an object. A force can modify the velocity of a mass item. A force is a vector quantity since it has both magnitude and direction. It is measured in newtons, the SI unit of mass (N). The sign F represents force.
In its original form, Newton's second law states that the net force acting on an object equals the rate at which its momentum varies with time.
We know that,
Force=ma
F=ma
F=m((v-u)/t)
Given, t=1.5 second
Velocity v=0m/s at stand still
And mass m=1400kg
Speed u=27m/s
F₁.₅=1400((0-27m/s)/1.5)
F₁.₅=-25.2KN
Therefore, the force involved is F₁.₅=-25.2KN
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A spring has an unstretched length of 11 cm . It exerts a restoring force F when stretched to a length of 12 cm. For what total stretched length of the spring is its restoring force 3F? At what compressed length is the restoring force 2F?
Using the spring constant relation, the required length and compressed length of the spring at the given force values are 14 cm and 9 cm respectively.
A.) Using the given formula,
F = ke
Where k = spring constant , e = extension and e = (Final length - Initial length)
Initial length, l = 11
Final length = L1 = 12
F = k(12 - 11)
F = k(1)
F = k
Length for a restoring force of 3F ;
3F = k (Final length - Initial length)
k = F
3F = F(L1 - 10)
3F = - 11F + F(L1)
F(L1) = 3F + 11F
F(L1) = 14F
L1 = 14 cm
Hence, required length is 14 cm
B.) Let compressed length = c
2F = F(initial length - compressed length)
2F = F(10 - c)
2F = 11F - F(c)
F(c) = 11F - 2F
F(c) = 9F
c = 9F / F
c = 9 cm
Therefore, the required compressed length is 9 cm
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a car is towing a boat on a trailer. the driver starts from rest and accelerates to a velocity of 11.0 m/s in a time of 27.2 is. the combined mass of the boat and trailer is 514 kg. the frictional force acting on the trailer can be ignored. what is the tension in the hitch that connects the trailer to the car?
The correct answer is 207 Newton Tension in the hitch that connects the trailer to the car.
What is Newton's second law of motion?
The relationship between the force applied to an object with mass and its net acceleration is described by Newton's second law of motion. This relationship is mathematically precisely proportional, which means that a greater force will produce a greater acceleration.
Given,
Initial Velocity = u = 0 m/s
Final Velocity = v = 11 m/s
Time = 27.2 Sec (Unit of time is not given, we consider Second as unit of time)
Mass = 514 Kg i.e., combined mass of boat and Trailer
Force = Mass x Acceleration (As Acceleration= Velocity / Time)
= 514 x (11 / 27.2) = 207 N
Hence Tension is 207 N in the hitch that connects the trailer to the car (Frictional force is neglected here).
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The weight of the atmosphere results in P_0 at the surface of the oil layer. Then the weight of the oil and the weight of the water combine to create the pressure at the bottom. Why does air pressure decrease with increasing altitude? (Select all that apply.) Less air above pushes down. Hot air rises. The weight of the air above is smaller. Colder air is less dense. There is more air below to push up more strongly. The weight of the air below is smaller. Use the worked example above to help you solve this problem. In a huge oil tanker, salt water has flooded an oil tank to a depth of h_2 = 4.75 m. On top of the water is a layer of oil h_1 = 8.40 m deep, as in the cross-sectional view of the tank as shown in the figure. The oil has a density of 0.700 g/cm^3. Find the pressure at the bottom of the tank. (Take 1,025 kg/m^3 as the density of salt water.) Calculate the pressure on the top lid of a chest buried under 3.80 meters of mud with density 1.75 x 10^3 kg/m^3 at the bottom of a 11.5-m-deep lake.
The pressure at the bottom of the oil layer is given by,
P₁ = P₀ + ρgh₁ = (1.01 x 105 Pa) + (7 x 102 kg/m³) (9.8 m/s2) (8.4 m)
P₁ = (1.01 x 105 Pa) + (576.2 x 102 Pa)
P₁ = 1.58 x 105 Pa
Now, the pressure at the bottom of the tank which will be given using a formula, we have
P[tex]__{bottom}[/tex] = P1 + \rho g h2 = (1.58 x 105 Pa) + (1.025 x 103 kg/m3) (9.8 m/s2) (4.75 m)
P[tex]__{bottom}[/tex] = (1.58 x 105 Pa) + (47.7 x 103 Pa)
P[tex]__{bottom}[/tex] = 2.05 x 105 Pa
The pressure under mud will be given as
P₁ = P₀ + ρgh₁ = (1.01 x 105 Pa) + (1.75 x 103 kg/m3) (9.8 m/s2) (3.8 m)
P₁ = (1.01 x 105 Pa) + (65.1 x 103 Pa)
P₁ = 1.66 x 105 Pa
Now, the pressure on the top lid of a chest buried will be given as:
P[tex]__{top}[/tex] = P1 + \rho g h2 = (1.66 x 105 Pa) + (1.025 x 103 kg/m3) (9.8 m/s2) (11.5 m)
P[tex]__{top}[/tex] = (1.66 x 105 Pa) + (115.5 x 103 Pa)
P[tex]__{top}[/tex] = 2.81 x 105 Pa
The question is clearer in the picture
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while underway in fog you hear a whistle signal consisting of one prolonged blast followed immediately by two short blasts. which vessels are required to sound this signal in fog?
In this case, blast at intervals of not more than two minutes is the signal which will be used by power-driven vessels when underway. One long blast plus two short blasts at intervals of not more than two minutes is the signal used by sailing vessels.
Why do vessels sound signals in fog?
Heavy fog leads to severe issues that lead to reduction in the signal-to-noise ratio to levels which may even affect the communication system. It leads to Restricted Visibility. Therefore various methods are used including Foghorns , fog signals that warn vehicles of hazards or rocky coastlines , and some other boats in foggy conditions.
Apart from this certain other methods including prolonged blast, fog signals, communication with the satellite can be used. The whole process is undertaken to reduce the amount of harmful impacts, issues that may be faced by the vessels
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Power-driven vessel underway making way are required to sound this signal in fog.
What is Power-driven vessel?The term "power driven vessel" means any vessel propelled by a machine. The term "sailing vessel" signal a vessel under sail, provided that no propulsion machinery is used.Power-driven vessel include sailing vessels operated by engine power. Here are the lights you need: Red and green sidelights are visible from at least two miles away on a dark, clear night.Mechanical vehicles in motion must give way to uncommand vehicles. For purposes of Rule 3(b), the term "engine craft" means any machine-powered craft. Power-driven vessel means a vessel propelled by an engine, fuel, rocket, or similar device.To learn more about Power-driven vessel from the given link:
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why or how do neutrons help to reduce the repulsion between protons and stabilize the atoms nucleus?
a car is traveling 21 m/s when the driver sees a child standing in the road. he takes 0.8s to react then steps on the breaks and slows at 7.5m/s^2. how far does the car go before it stops?
The distance traveled by the car before it stops when moving with a velocity of 21 m/s is 19.2 m.
What is distance?Distance is the total length between two points.
To calculate the distance the car move before stopping, we use the formula below.
Formula:
S = ut+at²/2......... Equation 1Where:
S = Distanceu = Initial velocityt = Timea = accelerationFrom the question,
Given:
u = 21 m/st = 0.8 sa = 7.5 m/sSubstitute these values into equation 1
S = (21×0.8)+(7.5×0.8²/2)S = 16.8+2.4S = 19.2 mHence, the distance traveled by the car before it stops is 19.2 m.
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in what direction will the seesaw rotate, and what will the sign of the angular acceleration be? in what direction will the seesaw rotate, and what will the sign of the angular acceleration be? the rotation is in the clockwise direction and the angular acceleration is positive. the rotation is in the clockwise direction and the angular acceleration is negative. the rotation is in the counterclockwise direction and the angular acceleration is positive. the rotation is in the counterclockwise direction and the angular acceleration is negative.
The rotation is in the counterclockwise direction and the angular acceleration is positive.
What is angular acceleration?
The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
A rigid body's points all share the rotating velocity and acceleration.
Therefore, The rotation is in the counterclockwise direction and the angular acceleration is positive.
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The angular acceleration is positive and the rotation is counterclockwise.
Angular acceleration:
In physics, angular acceleration is the temporal rate of change of angular velocity. Because there are two types of angular velocity, spin angular velocity as well as orbital angular velocity, there are two types of angular acceleration, spin angular acceleration as well as orbital angular acceleration. Spin angular acceleration is the angular acceleration of a rigid body as to its centre of rotation, whereas orbital angular acceleration is the angular acceleration of a point particle around a fixed origin. Therefore, = d d t.
A rigid body's points all share the rotating velocity and acceleration.
Therefore, The rotation is in the counterclockwise direction and the angular acceleration is positive.
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✓= √219.8113) ✓=5.8 m/s RE=1/6/240)100.07²: / 44,946.75
Suzie Lavtaski (m=56 kg) is skiing at Bluebird Mountain. She is moving at 16 m/s across the crest of a ski hill
located 34 m above ground level at the end of the run.
+719
775
a. Determine Suzie's kinetic energy.
b. Determine Suzie's potential energy relative to the height of the ground at the end of the run.
c. Determine Suzie's total mechanical energy at the crest of the hill.
d. If no energy is lost or gained between the top of the hill and her initial arrival at the end of the run, then
what will be Suzie's total mechanical energy at the end of the run?
e. Determine Suzie's speed as she arrives at the end of the run and prior to braking to a stop.
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a.) Kinetic energy = 1/2 × mv^2
=1/2 × 56 × 16^2
=7168 J
b.) Potential energy = m .g. h
=56 ×9.8 ×34
=18,678.24 J
c.) Total energy = kinetic energy + potential energy
=7168+18,678.24
=25,846.24 J
d ) Because no energy is lost or gained between the top of the hill and her initial arrival at the end of the run, then the total mechanical energy at the top of the hill or any place across the crest and the bottom of the crest .
Thus , Total mechanical energy = 25,846.24 J
e) As we know, total energy = potential energy + kinetic energy
but at the end of the run it's potential energy is zero.
So, Total energy = 1/2 ×m ×v^2
25,846.24= 1/2 ×56 ×v^2
V= 30.38 m/s
Hence, Suzie's speed as she arrives at the end of the run is 30.38 m/s
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light that is polarized along the vertical direction is incident on a sheet of polarizing material. only 87% of the intensity of the light passes through the sheet. what angle is the axis of the polarizer oriented, with respect to the vertical?
Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.
A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.
given
Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.
Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is
θ₂ = θ₁ + 90°
= 31.94° + 90°
= 1 21.94°
for the first sheet and
Icos²θ₁ = I
I/I₀ = 0.72
θ₁ = cos⁻¹√(0.72)
= 31.94°
for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.
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figure shows a silver ribbon whose cross section is 1.0 cm by 0.20 cm. the ribbon carries a current of 110 a from left to right, and it lies in a uniform magnetic field of magnitude 1.25 t. using a charge density value of n
72.828×[tex]10^{-7}[/tex]Volt is the Hall potential between the edges of the ribbon.
We know that Hall potential is given by =IB/qnd where
I is the current flowing
,B is the magnetic field ,
q is the charge of the electron,
n is the charge density of electron,
and d is the thickness
So, we are given that current(I)=110Ampere,magnetic field(B)=1.25Tesla,
charge of electron(q)=1.6×[tex]10^{-19}[/tex]C, charge density (n)= 5.9x1028,thickness
(t) as 2.cm
So, putting the values of the respected quantities on the above formula ,we get
Hall potential([tex]V_h[/tex])=(110×1.25)/(1.6×[tex]10^{-19}[/tex]×5.9×[tex]10^{28}[/tex]×0.2×[tex]10^{-2}[/tex])
=>([tex]V_h[/tex])=[137.5/1.888]×[tex]10^{-7}[/tex]
=>([tex]V_h[/tex])=72.828×[tex]10^{-7}[/tex]Volt.
Hence, the Hall potential is 72.828×[tex]10^{-7}[/tex]Volt.
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(Complete question) is:
Figure shows a silver ribbon whose cross section is 1.0 cm by 0.20 cm. The ribbon carries a current of 110 A from left to right, and it lies in a uniform magnetic field of magnitude 1.25 T. Using a charge density value of n = 5.9x1028 electrons per cubic meter for silver, find the Hall potential between the edges of the ribbon.