Answer: 250 feet (approx.)
Step-by-step explanation:
The volume of the dome is given as 6,132,812.5 cubic feet, and we know that the dome is 75% of a full sphere. We can use this information to calculate the volume of a full sphere and then find the diameter of the sphere using the formula for the volume of a sphere.
The formula for the volume of a sphere is V = (4/3)πr^3, where V is the volume and r is the radius. Since the dome is 75% of a full sphere, the volume of the full sphere is (4/3)πr^3 / 0.75 = (16/3)πr^3 / 3.
Setting this equal to 6,132,812.5 and solving for r gives us r ≈ 35.1 feet.
Finally, the diameter of the sphere is 2r ≈ 70.2 feet.
Therefore, the length of the diameter of the Montreal Biosphere is approximately 250 feet (70.2 feet * (100/75)).
Two mountain peaks are known to be 17 kilometers apart. A person located at a vista point such that a right angle is spanned when he looks from one peak to the other
is told that the distances from the vista point to each peak differ by 7 kilometers. How far is the vista point from each mountain peak?
The person is looking at each peak on a leg of a right triangle. The hypotenuse is the distance between the mountains.
How far is the vista point from each mountain peak?The distance is determined by
x^2+(x+5)^2=25^2
x^2+x^2+10x+25=625
2x^2+10x-600=0
x^2+5x-300=0
(x+20)(x-15)=0
only positive root is x=15
x+5=20
The vista point is 15 miles from one mountain peak and 20 miles from the other.
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A nursing student can be assigned in how many different ways?
The total number of different ways that the student can be assigned during a 4-day work week is 81 different ways.
What is student?A student is a person who is enrolled in an educational institution, such as a college, university, or trade school. Students are typically required to attend classes and complete assignments to gain knowledge and develop skills related to their field of study. Depending on their level of education, students may also be required to participate in research or internships in order to gain practical experience.
There are 3 possible floors that the student can be assigned to, so for each day of the 4-day week, there are 3 possible assignments.
Therefore, the total number of different ways that the student can be assigned during a 4-day work week is 3 x 3 x 3 x 3
= 81 different ways.
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Can someone help me with this question? thank you ^^
Solve the inequality.
4g ≤ 10
(Middle school)
The value of the inequality is g≤2.5
What is an inequality?In mathematics, an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size.
The given inequality is 4g≤10
To solve the inequality, divided bo sides of the inequality by the coefficient of g which is 4
This gives the value
4g/g≤10/4
⇒ that g = 2.5
Therefore the value of the inequality is g≤2.5
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express the function graphed on the axis below as a piecewise function
The function graphed on the axis above should be expressed as a piecewise function as follows;
f(x) = x + 1 {x < -5}
= 5x - 10 {x > 1}
How to determine the piecewise function?In order to determine the piecewise function, we would determine an equation that represent each of line shown on the graph. Therefore, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (-7 + 4)/(-8 + 5)
Slope (m) = -3/-3
Slope (m) = 1.
At data point (-5, -4) and a slope of 1, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y + 4 = 1(x + 5)
y = x + 1
1, -5 2 0
For the second line, we have:
Slope (m) = (0 + 5)/(2 - 1)
Slope (m) = 5/1
Slope (m) = 5.
At data point (2, 0) and a slope of 5, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 0 = 5(x - 2)
y = 5x - 10
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graph of the function h(x)=(x^2-3x-4)/x-4
Plotting the graph of the function h(x) = [tex](x^2 - 3x - 4) / (x - 4)[/tex], we get y- intercept = 1, vertical asymptotes at x=4 and horizontal asymptotes at y=1.
What does graph of any function represents?The connection between a function's input values (usually written as x) and output values (often indicated as y) is represented by the function's graph. It gives insights on the function's characteristics, including its domain, range, intercepts, asymptotes, and general form, as well as a visual representation of how the function acts.
Steps to plot the graph of the give function h(x) =[tex](x^2 - 3x - 4) / (x - 4)[/tex]:
Put the numerator [tex](x^2 - 3x - 4)[/tex] equal to zero and solve for x to discover the x-intercepts, if any, to determine the x-intercepts.Finding the y-intercept To get the y-intercept, set x = 0 in the function and solve for y, which gives y- intercept=1.To locate any vertical asymptotes, set the denominator (x - 4) equal to zero and solve for x, which gives x=4.Find horizontal asymptotes: To find the horizontal asymptote, compare the degrees of the numerator and denominator (s). There is no horizontal asymptote if the degree of the numerator is higher than the degree of the denominator. The horizontal asymptote lies at y = ratio of the leading coefficients if the degree of the numerator and denominator are equal. The horizontal asymptote is at y = 0 if the degree of the numerator is smaller than the degree of the denominator, for given problem it is at y=1.Draw the graph of the function h(x), highlighting the x-intercepts, y-intercept, vertical asymptotes, and horizontal asymptotes using the knowledge gained from the aforementioned phases (s). Take attention to how the function behaves as x gets closer to positive or negative infinity.Name the graph, including the x- and y-axes, x- and y-intercepts, vertical and horizontal asymptotes, and any other interesting points.Learn more about Graphs here:
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Which of the following do not belong to the group of numbers
The number that does not belong to the set of numbers is given as follows:
B. Three
What are even and odd numbers?Numbers are classified as even or odd depending on whether they are divisible by 2 or not, as follows:
Even numbers are divisible by 2, that is, their last digit is either 0, 2, 4, 6 or 8.Odd numbers are not divisible by 2, that is, their last digit is either 1, 3, 5, 7 or 9.For this problem, we have that the number five does not belong to the set of even numbers, as the numbers two, four and six do.
Missing Information?The options are:
A.Two
B.Three
C.Four
D.Six
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Juan wants to see the Grand Cayon, so he is taking a vacation in Arizona. He drove south from his house for 280 miles. Then, He drove east 64 miles.
a. Draw a diagram illustrating Juans Trip
b. How many total miles did Juan travel?
c. If a road was built directly from Juans home to the grand canyon, how long would it be? Round to the nearest mile.
d. Approximately how much shorter would Juans trip be if he was able to take the direct route?
Juan traveled approximately 288.24 miles.
The direct road would be approximately 288 miles long.
Juan's trip would be approximately 0.24 miles shorter if he was able to take the direct route.
We have,
a.
Here is a diagram illustrating Juan's trip:
Grand Canyon
|
|
|
Juan's | x
house --------->
y
b.
To find the total distance Juan traveled, we can use the Pythagorean theorem:
distance² = x² + y²
Juan drove 280 miles south (y direction) and 64 miles east (x direction), so we have:
distance² = 280² + 64²
distance² = 78,976 + 4,096
distance² = 83,072
Taking the square root of both sides, we get:
distance ≈ 288.24 miles
c.
To find the length of the direct road, we can use the Pythagorean theorem again:
distance² = x² + y²
The direct road forms a right triangle with legs of 280 miles and 64 miles, so we have:
distance² = 280² + 64²
distance² = 78,976 + 4,096
distance² = 83,072
Taking the square root of both sides, we get:
distance ≈ 288.24 miles
d.
To find how much shorter Juan's trip would be if he took the direct route, we can subtract the distance he traveled from the direct road distance:
288 - 288.24 ≈ -0.24
Thus,
Juan traveled approximately 288.24 miles.
The direct road would be approximately 288 miles long.
Juan's trip would be approximately 0.24 miles shorter if he was able to take the direct route.
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The venue for an outdoor summer concert was divided into 35 sections. The event planner randomly chose 8 sections and counted the number of ice chests in the section, as shown below.
45, 57, 30, 62, 57, 45, 30, 57
Assuming that the sample was representative of the entire venue, what was the mean number of ice chests in a section?
A.
48.5
B.
51
C.
47.875
D.
44.125
please answer
Answer:
C is correct
Step-by-step explanation:
Please answer, this as quick as possible, it’s very important for me, I’ll give brainliest if it’s correct, and try not to use chatgpt or you’ll get reported
Answer:
Your calculator should be in radian mode.
a)
[tex]f(x) = 56 \sin( \frac{2t\pi}{12} + \frac{\pi}{2} ) + 4[/tex]
b)
[tex]f(x) = 56 \cos( \frac{2t\pi}{12} - \frac{\pi}{2} ) + 4[/tex]
c)
The height of the wheel's central axle is 32 meters.
f(x) = 56sin((2(x + 4)π/12) - (π/2)) + 4
Can you help with this please?
The p-value associated with the test statistic of z = 2.566 is 0.0045, accurate to four decimal places.
Based on the given information, we can conduct a one-tailed right-sided test using a normal distribution calculator to find the p-value associated with the test statistic of z = 2.566.
What is a one-tailed right-sided test?In hypothesis testing, a one-tailed right-sided test is a statistical test where the alternative hypothesis (H1) is specified to detect a change typically towards larger values.
Using a normal distribution calculator, we can find the cumulative distribution function (CDF) of the standard normal distribution at z = 2.566.
The CDF gives us the probability that a randomly selected value from a standard normal distribution is less than or equal to a given value.
Using a normal distribution calculator:
CDF at z = 2.566 = 0.9955 (rounded to four decimal places)
Since we are conducting a one-tailed right-sided test, we are interested in the probability of getting a value greater than the test statistic. Therefore, the p-value for the given test statistic is:
p-value = 1 - CDF at z = 2.566 = 1 - 0.9955 = 0.0045 (rounded to four decimal places)
Thus, the p-value associated with the test statistic of z = 2.566 is 0.0045, accurate to four decimal places.
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
The table is completed as below
Interested in NOT Interested in Total
Athletics Athletics
Interested in
Academic Clubs 26 58 84
Not Interested in
Academic Clubs 118 38 156
Total 144 96 240
How to fill the tableTo fill in the table, we start with the total number of students, which is 240.
We know that 35% of students are interested in athletics, so we can find the number of students interested in athletics as:
0.35 x 240 = 84
Similarly, we know that 3/5 of students are interested in academic clubs, so we can find the number of students interested in academic clubs as:
(3/5) x 240 = 144
We also know that 26 students are interested in both athletics and academic clubs, so we can fill in that cell as 26.
To fill in the remaining cells, we can use the fact that the row and column totals must add up correctly. For example, in the "Interested in athletics" row, we know that there are a total of 84 students interested in athletics. We also know that 26 of these students are interested in both athletics and academic clubs. Therefore, the number of students interested in athletics but not academic clubs is:
84 - 26 = 58
We can use similar reasoning to fill in the remaining cells. For example, in the "Not interested in athletics" column, we know that there are a total of 214 students who are not interested in athletics. We also know that 144 students are interested in academic clubs. Therefore, the number of students who are not interested in athletics but are interested in academic clubs is:
144 - 26 = 118
Let x represent "not interested in academics club" and "not interested in athletic". Using the total in the horizontal (bottom row) we have:
144 + 58 + x = 240
x = 240 - 202
x = 38
Hence 58 + 38 = 96 and 118 + 38 = 156
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A bag contains 3 gold marbles, 8 silver marbles, and 23 black marbles. Someone offers to play this game: You randomly select one marble from the bag. If it is gold, you win $3. If it is silver, you win $2. If it is black, you lose $1.
To calculate the expected value of playing this game, we need to multiply the probability of winning each amount by the corresponding payout and then sum them up.
Let's start by calculating the probability of selecting each type of marble:
Probability of selecting a gold marble: 3/34
Probability of selecting a silver marble: 8/34
Probability of selecting a black marble: 23/34
Now, let's calculate the expected value of playing the game:
E(x) = (3/34) * $3 + (8/34) * $2 + (23/34) * (-$1)
E(x) = $0.26
So the expected value of playing this game is $0.26. This means that over many plays of the game, we would expect to win an average of $0.26 per play. However, it's important to remember that this is just an average, and in any individual play of the game, you could win more or less than this amount.
what 95% confidence interval for a standard normal distribution
A 95% confidence interval for the standard normal distribution is typically given by (-1.96, 1.96) . mean that correspond to the upper and lower bounds of the interval
what is mean ?
In statistics, the standard deviation is a measure of the amount of variation or dispersion in a set of data. It is the square root of the variance and is denoted by the symbol σ (sigma). The standard deviation is expressed in the same units
In the Given question :
A 95% confidence interval for the standard normal distribution is typically given by (-1.96, 1.96)
This means that we are 95% confident that the true value of a normally distributed variable falls within this range. The values of -1.96 and 1.96 represent the number of standard deviations from the mean that correspond to the upper and lower bounds of the interval, respectively. This interval is often used in statistical inference to estimate the population mean or proportion based on a sample.
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what 95% confidence interval for a standard normal distribution then what is the number of standard deviations from the mean that correspond to the upper and lower bounds of the interval ?
Tres amigos van de compras, Juan gasta el doble que Alicia y Ana gasta el triple de Alicia. Si entre los tres han gastado L.
720.00, ¿Cuánto ha gastado cada uno?
the three friends spent L.120.00, L.240.00, and L.360.00, respectively.
How to solve the problem?
Let's denote the amount that Alicia spends as "x". According to the problem statement, we know that Juan spends twice as much as Alicia, which means he spends 2x. Similarly, we know that Ana spends three times as much as Alicia, which means she spends 3x.
We also know that the three friends together have spent L.720.00. So, we can set up an equation to represent this:
x + 2x + 3x = 720
Simplifying this equation, we get:
6x = 720
Dividing both sides by 6, we get:
x = 120
So, Alicia spent L.120.00, Juan spent twice as much as Alicia, which is L.240.00, and Ana spent three times as much as Alicia, which is L.360.00.
Therefore, the three friends spent L.120.00, L.240.00, and L.360.00, respectively.
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P is a point on the terminal side of 0 in standard position. Find the exact value of the six trigonometric functions for 0 where P (-5, 5)
We can use the coordinates of point P (-5, 5) to find the values of the trigonometric functions for the angle formed between the positive x-axis and the line passing through the origin and point P.
First, we can find the distance from the origin to point P using the Pythagorean theorem:
r = sqrt((-5)^2 + 5^2) = sqrt(50)
Next, we can use the fact that the sine of an angle is equal to the y-coordinate of a point on the unit circle and the cosine of an angle is equal to the x-coordinate of a point on the unit circle. Since the radius of the unit circle is 1, we need to divide the x and y coordinates of point P by sqrt(50) to get the values for sine and cosine:
sin(θ) = y/r = 5/sqrt(50) = (5/10)sqrt(2) = (1/2)sqrt(2)
cos(θ) = x/r = -5/sqrt(50) = -(5/10)sqrt(2) = -(1/2)sqrt(2)
Next, we can use the fact that the tangent of an angle is equal to the sine of the angle divided by the cosine of the angle:
tan(θ) = sin(θ)/cos(θ) = (1/2)sqrt(2)/(-(1/2)sqrt(2)) = -1
Similarly, we can use the reciprocal identities to find the values of the other three trigonometric functions:
csc(θ) = 1/sin(θ) = sqrt(2)
sec(θ) = 1/cos(θ) = -sqrt(2)
cot(θ) = 1/tan(θ) = -1
Therefore, the exact values of the six trigonometric functions for the angle formed by the line passing through the origin and point P (-5, 5) are:
sin(θ) = (1/2)sqrt(2)
cos(θ) = -(1/2)sqrt(2)
tan(θ) = -1
csc(θ) = sqrt(2)
sec(θ) = -sqrt(2)
cot(θ) = -1
IG:whis.sama_ent
Find the partial fraction decomposition of x^3-x/x^4+2x^2+1
the partial fraction decomposition of x^3-x/x^4+2x^2+1 is (x^3 - x)/(x^4 + 2x^2 + 1) = -1/4/(x^2 + 1)
How to find the partial fraction decompositionTo find the partial fraction decomposition of x^3-x/x^4+2x^2+1, we first factor the denominator:
x^4 + 2x^2 + 1 = (x^2 + 1)^2
So we can write:
(x^3 - x)/(x^4 + 2x^2 + 1) = A/(x^2 + 1) + B/(x^2 + 1)^2
Multiplying both sides by the denominator, we get:
x^3 - x = A(x^2 + 1) + B
Now we can solve for A and B by choosing appropriate values for x. Let's choose x = 0 first:
0 - 0 = A(0^2 + 1) + B
B = 0
Now let's choose x = 1:
1 - 1 = A(1^2 + 1) + 0
A = -1/4
So the partial fraction decomposition of x^3-x/x^4+2x^2+1 is:
(x^3 - x)/(x^4 + 2x^2 + 1) = -1/4/(x^2 + 1) + 0/(x^2 + 1)^2
or
(x^3 - x)/(x^4 + 2x^2 + 1) = -1/4/(x^2 + 1)
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the table below shows different make of cars own by teacher in a certain school. work out the angles and percentage then illustrate the information using a pie chart.
Toyota -- 12
Nissan --- 8
Datsun --- 8
Volvo --- 2
Peugeot -- 10
The angles and percentages have been calculated as shown below.
A pie chart for the information about the different make of cars is shown below.
How to determine the angles and percentage?For the total number of car makes, we have the following:
Total make of cars = 12 + 8 + 8 + 2 + 10
Total make of cars = 40.
Next, we would determine the angles and percentage as follows;
Toyota
12/40 × 360 = 108°
12/40 × 100 = 30%.
Nissan
8/40 × 360 = 72°
8/40 × 100 = 20%.
Datsun
8/40 × 360 = 72°
8/40 × 100 = 20%.
Volvo
2/40 × 360 = 18°
2/40 × 100 = 5%.
Peugeot
10/40 × 360 = 90°
10/40 × 100 = 25%.
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suppose a scatterplot is created from the points in the following table. when x=7, what is the second coordinate in a scatterplot of the linearized data? round your answer to the tenths place. im so lost honestly.
Okay, let's break this down step-by-step:
From the table, we know the x-values are 1, 3, 5, 7, and 9.
And the y-values are 4, 6, 8, ?, 12.
So at x=7, there is a missing y-value that we need to determine.
To find this, we need to look at the linear relationship between the points. Some clues:
1) There are 5 points total.
2) The x-values increase by 2 each time.
3) The y-values also seem to be increasing by 2 each time.
So the linear relationship is: y = mx + b (where m is the slope and b is the y-intercept)
In this case, the slope is 2 (because y increases by 2 for every increase of 1 in x).
And the y-intercept is 4 (because when x = 1, y = 4).
So the equation is: y = 2x + 4
Plugging in x = 7:
y = 2(7) + 4
y = 14 + 4
y = 18
Therefore, when x = 7, the second coordinate in the scatterplot is 18.
Rounded to the tenths place: 1.8
Does this help explain the steps? Let me know if you have any other questions!
If a case of 24 water bottles is $8 per case, how much are you paying for each bottle?
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly three of the five M&M’s are green. Compute the probability that three or four of the five M&M’s are green. Compute the probability that at most three of the five M&M’s are green. Compute the probability that at least three of the five M&M’s are green. If you repeatedly select random samples of five peanut M&M’s, on average how many do you expect to be green? (Round your answer to two decimal places.) green M&M’s With what standard deviation? (Round your answer to two decimal places.) green M&M’s
The standard deviation of the number of green M&M's in a sample of 5 is 0.91
What is standard deviation?Standard deviation is a measure of the amount of variation or dispersion of a set of data values. It is calculated by finding the square root of the variance, which is the average of the squared differences from the mean.
According to given information:To solve this problem, we can use the binomial probability formula:
[tex]P(X=k) = C(n,k) * p^k * (1-p)^{(n-k)[/tex]
where:
X is the number of green M&M's in the sample
k is the number of green M&M's we are interested in (3 or 4 or at most 3 or at least 3)
n is the sample size (5)
p is the probability of getting a green M&M in one trial
We can use the given percentages to calculate the probability of getting a green M&M:
p = 0.15
Now we can calculate the probabilities for the different scenarios:
Probability that exactly three of the five M&M's are green:
[tex]P(X=3) = C(5,3) * 0.15^3 * 0.85^2 = 0.0883[/tex]
Probability that three or four of the five M&M's are green:
[tex]P(X=3\ or\ X=4) = P(X=3) + P(X=4) = C(5,3) * 0.15^3 * 0.85^2 + C(5,4) * 0.15^4 * 0.85^1 = 0.1527[/tex]
Probability that at most three of the five M&M's are green:
P(X≤3) = [tex]P(X=0) + P(X=1) + P(X=2) + P(X=3) = C(5,0) * 0.15^0 * 0.85^5 + C(5,1) * 0.15^1 * 0.85^4 + C(5,2) * 0.15^2 * 0.85^3 + C(5,3) * 0.15^3 * 0.85^2 = 0.9053[/tex]
Probability that at least three of the five M&M's are green:
P(X≥3) [tex]= P(X=3) + P(X=4) + P(X=5) = C(5,3) * 0.15^3 * 0.85^2 + C(5,4) * 0.15^4 * 0.85^1 + C(5,5) * 0.15^5 * 0.85^0 = 0.2413[/tex]
To find the expected number of green M&M's in a sample of size 5, we can use the formula:
E(X) = n * p
where E(X) is the expected value of X.
E(X) = 5 * 0.15 = 0.75
Therefore, on average we expect 0.75 green M&M's in a sample of 5.
To find the standard deviation, we can use the formula:
SD(X) = sqrt(n * p * (1-p))
SD(X) = sqrt(5 * 0.15 * 0.85) = 0.9138 (rounded to two decimal places)
Therefore, the standard deviation of the number of green M&M's in a sample of 5 is 0.91
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if 123=2, then what is 354=
if 1 2 3 = 2
then 3 5 4 = 5
hope it helps:)
Using a table, find the range of the function for the given domain:
f(x)=2x+7 with domain: x = {2, 3, 5, 9}
A. y = {9, 10, 12, 16}
B. y = {11, 13, 17, 25}
C. y = {4, 6, 10, 18}
D. y = {-11, -13, -17, -25}
The range of the function is y = {11, 13, 17, 25}.
What is range of function?In mathematics, the range of a function refers to the set of all possible output values that the function can produce when given a set of input values. It is also known as the image of the function. The range of a function can be found by evaluating the function for all possible input values, or by analyzing the properties of the function.
According to given information:To find the range of the function, we need to substitute each value of the domain into the function and record the corresponding output values.
For x = 2, f(2) = 2(2) + 7 = 11.
For x = 3, f(3) = 2(3) + 7 = 13.
For x = 5, f(5) = 2(5) + 7 = 17.
For x = 9, f(9) = 2(9) + 7 = 25.
Therefore, the range of the function is y = {11, 13, 17, 25}.
The answer is A. y = {9, 10, 12, 16} is not the correct range for this function with the given domain.
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What is the measure of angle A in this triangle?
Enter your answer in the box.
Answer:
m∠A = 50°
Step-by-step explanation:
The ∑ of all interior angles of any given triangle is 180°. Set all angle measurements equal to 180:
[tex](x + 30) + (2x - 10) + 70 = 180[/tex]
First, simplify. Combine like terms. Like terms are terms that share the same amount of the same variables:
[tex](x + 2x) + (30 - 10 + 70) = 180\\(3x) + (90) = 180[/tex]
Next, isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operations, and stands for:
Parenthesis
Exponents (& Roots)
Multiplications
Divisions
Additions
Subtractions
~
First, subtract 90 from both sides of the equation:
[tex]3x + 90 = 180\\3x + 90 (-90) = 180 (-90)\\3x = 180 - 90\\3x = 90[/tex]
Next, divide 3 from both sides of the equation:
[tex]3x = 90\\\frac{(3x)}{3} = \frac{(90)}{3}\\ x = \frac{90}{3}\\ x = 30[/tex]
Plug in 30 for x in the given angle measurement of A and simplify:
[tex]m\angle{A} = 2x - 10\\m\angle{A} = 2(30) - 10\\m\angle{A} = (60) - 10\\m\angle{A} = 50[/tex]
50° is your answer for m∠A.
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Answer:
m∠A = 50°
Step-by-step explanation:
The ∑ of all interior angles of any given triangle is 180°. Set all angle measurements equal to 180:
[tex](x + 30) + (2x - 10) + 70 = 180[/tex]
First, simplify. Combine like terms. Like terms are terms that share the same amount of the same variables:
[tex](x + 2x) + (30 - 10 + 70) = 180\\(3x) + (90) = 180[/tex]
Next, isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operations, and stands for:
Parenthesis
Exponents (& Roots)
Multiplications
Divisions
Additions
Subtractions
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First, subtract 90 from both sides of the equation:
[tex]3x + 90 = 180\\3x + 90 (-90) = 180 (-90)\\3x = 180 - 90\\3x = 90[/tex]
Next, divide 3 from both sides of the equation:
[tex]3x = 90\\\frac{(3x)}{3} = \frac{(90)}{3}\\ x = \frac{90}{3}\\ x = 30[/tex]
Plug in 30 for x in the given angle measurement of A and simplify:
[tex]m\angle{A} = 2x - 10\\m\angle{A} = 2(30) - 10\\m\angle{A} = (60) - 10\\m\angle{A} = 50[/tex]
50° is your answer for m∠A.
~
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When Caroline runs the 400 meter dash, her finishing times are normally distributed with a mean of 68 seconds and a standard deviation of 1.5 seconds. Using the empirical rule, determine the interval of times that represents the middle 99.7% of her finishing times in the 400 meter race.
The empirical rule to determine the interval middle 99.7% of Caroline's finishing times in the 400 meter race is 63.5 seconds to 72.5 seconds
Given data ,
The empirical rule, also known as the 68-95-99.7 rule, states that for a normal distribution:
Approximately 68% of the data falls within one standard deviation of the mean.
Approximately 95% of the data falls within two standard deviations of the mean.
Approximately 99.7% of the data falls within three standard deviations of the mean.
Since the middle 99.7% of data falls within three standard deviations of the mean, we can calculate the upper and lower limits of this interval as follows:
Lower limit = Mean - (3 x Standard Deviation)
Upper limit = Mean + (3 x Standard Deviation)
Plugging in the values for mean and standard deviation:
Lower limit = 68 - (3 x 1.5) = 68 - 4.5 = 63.5 seconds
Upper limit = 68 + (3 x 1.5) = 68 + 4.5 = 72.5 seconds
Hence , the interval of times that represents the middle 99.7% of Caroline's finishing times in the 400 meter race is 63.5 seconds to 72.5 seconds
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What is the surface area of this cylinder?
Use ≈ 3.14 and round your answer to the nearest hundredth.
1 mm
1 mm
square millimeters
Answer:
13.56 mm²
Step-by-step explanation:
surface area = 2 circle area + the side
circle = π r² = 3.14
2 of them = 6.28
side = circumference * 1 = 2πr *1 = 6.28
total 6.28*2 = 13.56 mm²
y=9/5X+6. find the equation of the line that is parallel to this line and passes through the point (-5,-2)
Answer:
9/5x+7
Step-by-step explanation:
You can keep the slope the same, because it is parallel, but the y-intercept must change to plus seven in order to go through (-5, -2)
A certain type of cable has a mean breaking point of 150 pounds with a standard deviation of 8 pounds. What weight should we specify so that we expect 95% of the cables not to break supporting that weight?
Answer:
171.76 Pounds
Step-By-Step Explanation:
So the explanation to how I got the answer is in the link below.
A bag contains 5 blue marbles, 7 white marbles, and 4 yellow marbles. If two different marbles are drawn from the bag, what is the probability of drawing first a blue marble and then a yellow marble?
Answer: The probability of drawing a blue marble and then a yellow marble is 1/12 or 0.0833.
Step-by-step explanation:
There are 16 marbles in the bag. To calculate the probability of drawing a blue marble and then a yellow marble, we can use the formula:
P(blue and yellow) = P(blue) x P(yellow|blue)
The probability of drawing a blue marble on the first draw is 5/16. After one blue marble has been drawn, there are 15 marbles left in the bag, so the probability of drawing a yellow marble on the second draw, given that the first marble was blue, is 4/15.
P(blue and yellow) = (5/16) x (4/15) = 1/12 or 0.0833
What is the domain of the function in the graph?
graph on the h-g axis, between the points (6, 80) and (11, 40)
A. 6≤g≤11
B. 40≤g≤80
C. 40≤h≤80
D. 6≤h≤11
Answer:
D
Step-by-step explanation:
The domain of a function refers to the set of all possible input values (independent variable) for which the function is defined. In this case, the graph has points (6,80) and (11,40), which means that the function is defined for the values of g (the independent variable) between 6 and 11. Therefore, the domain of the function is:
D. 6≤g≤11
The domain of the function in the given graph is 6≤h≤11, as it includes all possible values of h between and including 6 and 11 on the horizontal (h) axis. So the correct option is D.
The domain of a function refers to the set of all possible input values for the function. In the given graph, which is plotted on the h-g axis and includes points (6, 80) and (11, 40), we are interested in determining the valid range for the independent variable, h.
The lowest h-value on the graph is 6, corresponding to the point (6, 80), and the highest h-value is 11, corresponding to the point (11, 40). These are the boundaries that define the domain of the function. Any value of h that falls within this range is a valid input for the function, and any value outside this range is not represented on the graph.
Therefore, the domain of the function is 6≤h≤11, as it includes all values of h between and including 6 and 11. This range encompasses all possible inputs for this function as depicted in the graph.
In summary, the domain represents the valid input values, and in this case, it is limited to the interval from 6 to 11 on the h-axis.
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Surface area of triangular prism