Suppose that a certain fortunate person has a net worth of $77.0 billion ($ 7.70×1010 ). If her stock has a good year and gains $3.20 billion ( 3.20×109 ) in value, what is her new net worth?
Express your answer to three digits.

Answers

Answer 1

her new network is $80.20 billion


Related Questions

Meat-eating animals are:

decomposers
second-order consumers
producers
first-order consumers
HELP

Answers

Answer:

decomposers

Explanation:

How many moles of solute are in 53.1 mL of 12.5M HCI?

Answers

Molarity = moles of solute/volume of solution in liters.

From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

We have 53.1 mL, or 0.0531 L, of a 12.5 M, or 12.5 mol/L, solution. Multiplying 12.5 mol/L by 0.0531 L, we obtain 0.664 moles. So, in this volume of solution, there are 0.664 moles of solute (HCl).

If a sample of oxygen gas has a pressure of 810 torr at 298 K, what will be its pressure if its temperature is raised to 330K?

Answers

Answer:

The pressure is = 897 torr

Explanation:

We use Gay Lussac's Law.

A percent composition analysis yields
22.6% phosphorus (P) and 77.4%
chlorine (CI). What is the empirical
formula for the compound?
А
B
P2C17
PCI:

Answers

Answer:

PCl₃

Explanation:

To determine the empirical formula of a compound, we need to follow a series of steps.

Step 1: Divide each percent composition by the atomic mass of the element

P: 22.6/30.97 = 0.729

Cl: 77.4/35.45 = 2.18

Step 2: Divide all the numbers by the smallest one, i.e. 0.729

P: 0.729/0.729 = 1

Cl: 2.18/0.729 ≈ 3

The empirical formula of the compound is PCl₃.

How is gravity an attractive force?

Answers

Gravitational force -an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.
an attractive force that exists between all objects with mass Because mass is always positive. There are different notions of mass, but they're equivalent. ... The masses in Newton's law of gravitation, F=Gm1m2r2, are gravitational masses.

USA test prep wave 1 performance task

Answers

Answer:

Performance Tasks 188; Instructional Videos 75

Explanation:

Explain why a city that receives 10 hours more light each day has colder average temperatures. Explain

Answers

Explanation:

This would be similar to how the poles work in the North and South. Due to their placement, they recieve much more sun light than the rest of the Earth since we rotate horizontally. However, their placement also makes them farther from the sun than the rest of Earth, therefore not receiving as much heat.

plz, help me I'm so confused!

(this is also science)

Answers

Answer:

Well, there is no photo...

Explanation:

James made a poster showing the two body systems that regulate a person's pulse. Which two systems did james represent on his poster? F nervous and circulatory G resiratoty and endocrine systems H circular and digestive system I digestive and nervous system

Answers

Answer:

F

Explanation:

Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce
a precipitate of copper (II) phosphate and aqueous potassium sulfate.

Answers

Answer:

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

Explanation:

The question is missing but I think it must be about writing and balancing the equation.

Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce  a precipitate of copper (II) fluoride (I fixed a mistake here) and aqueous potassium sulfate. This is a double displacement reaction.

CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄

Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

In the hydrogenation of ethylene using a nickel catalyst, the initial concentration of ethylene is 1.65 mol⋅L−1 and its rate constant (k) is 0.0014 mol⋅L−1⋅s−1 . Determine the rate of reaction if it follows a zero-order reaction mechanism.

Answers

Answer:

.0014 M/s ( (mol*L^-1 / s) )

Explanation:

Since the rate law of a zero order reaction is Rate = k[A]^0, the rate is .0014 * (1.65)^0 = .0014

PLEASE HELP
How many chlorine atoms are needed to satisfy the octet rule when forming an ionic compound with a cation of charge 3+?

Answers

Answer:

not the right answer but I need this for the answer the question thing

3 chlorine atoms are needed to satisfy the octet rule when forming an ionic compound with a cation of 3+ charge.

Help will give brainliest

Classify the following alcohol as primary,
secondary or tertiary.
OH
A. primary
B. secondary
C. tertiary

Answers

Answer:

The correct answer is C, tertiary.

The following alcohol is a tertiary alcohol. Hence, option C is correct.

What is primary alcohol?

A primary alcohol is a compound in which a hydroxy group, ‒OH, is attached to a saturated carbon atom which has either three hydrogen atoms attached to it or only one other carbon atom and two hydrogen atoms attached to it.

Here, the carbon atom holding the OH group is attached directly to three alkyl groups.

Hence, the following alcohol is a tertiary alcohol.

Learn more about alcohol here:

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What chemical test to differentiate propane and propene

Answers

Answer:

If you add bromine water, an aqueous solution of bromine, to the test tubes, you can tell which is propene, the alkene. The bromine reacts with and saturates the double bonds in alkenes, and so decolourises.

please give brainly

Using bromine water..the bromine will react with double bond in propene so it will decolourise the bromine water

Calculate the number of copper atoms in a 63.55 g
sample of copper.​

Answers

Answer:

there are N_A, "Avogadro's number" of copper atoms in a 63.55*g mass of copper wire. And N_A, "Avogadro's number" = 6.022xx10^23 individual copper atoms. I look on the Periodic Table, and at Z=29, i.e. copper, the quoted atomic mass is 63.55*g.

Explanation:

One mole of every substance contains 6.022×10²³ atoms. The atomic mass of copper is 63.55 g. Thus it is one mole of copper which contains copper 6.022×10²³ atoms.

What is copper?

Copper is 29th element in periodic table. It is a transition metal classified into d-block. Transition metals are named so because they in between the metals and non-metals in periodic table.

Transition metals have varying oxidation state. Copper exists in +1, +2 and +3 oxidation states.

Any substance containing 6.022×10²³ atoms is called one mole of that substance. This number is called Avogadro number. Hence one mole of each element contains avogadro number of its atoms.

Similarly one mole of each compound contains 6.022×10²³ number of molecules. Here, the atomic mass of copper is 63.55 g. That is one mole of copper weighs 63.55 g. Hence, number of atoms in 63.55 g of copper is 6.022×10²³ atoms.

To find more about Avogadro number, refer the link below:

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A diver takes a balloon with a volume of 2.5Lfrom the surface, where the pressure is 1.0 atm, to a depth of 20m, where the pressure is 3.0 atm. What happen to the volume of the balloon? What if the end of the subnerged balloon is on a long pipe that goes to the surface and is attached to another balloon?

Answers

Answer:

The explanation is given below:

Explanation:

As we know that the volume is inversely proportional to the volume. If the pressure is rising from 1 atm to 3 atm so the volume of the ballon would decrease

P_1V_1 = P_2V_2

1.0 × 2.5L = 3 × V_2

V_2 = 0.833L

Since the air is moving from high pressure to low pressure and the two ballons are interconnected via a long pipe so the movement of the air is from bottom to top

A solution has a
pH of 2.5.
Answer the following questions.
pOH =
[H]=
[OH]=

Answers

Answer:

pOH = 11.5

[H⁺] = 0.003 M

[OH⁻] = 3 × 10⁻¹² M

Explanation:

The computation is shown below:

Given that

pH = 2.5

Based on the above information

We know that

pH + pOH = 14  ⇒  pOH = 14 - pH

pOH = 14 - 2.5

pOH = 11.5

[H⁺] = 10^(-pH) = 10^(-2.5)

[H⁺] = 0.003 M

[OH⁻] = 10^(-pOH)

= 10^(-11.5)

= 3 × 10⁻¹² M

[OH⁻] = 3 × 10⁻¹² M

Hence, the above represents the answer

Atoms are the smallest unit of an element that holds the physical identity of that element. T or F

Answers

Answer:

True

Explanation:

True
Explanation
True

How many moles would be present in a gas contained in a 100.0 mL vessel at 25.0oC at a pressure of 2.50 atm?

Answers

Answer:

n = 0.0102 mol.

Explanation:

Hello there!

In this case, according to the ideal gas law, which allows us to set up a relationship among volume, pressure, temperature and moles, we can define it as:

[tex]PV=nRT[/tex]

Thus, given the volume in liters (0.1000 L), temperature in kelvins (298.15 K) and pressure in atmospheres (2.50 atm), we can solve for moles as shown below:

[tex]n=\frac{PV}{RT}[/tex]

Thereafter, we plug in the aforementioned values to obtain:

[tex]n=\frac{2.50atm*0.1000L}{0.08206\frac{atm*L}{mol*K}*298.15K}\\\\n=0.0102mol[/tex]

Best regards!

1.1
Which of these is NOT an intermolecular force?
A
Covalent bonding
B
Hydrogen bonding
с
London / dispersion forces
Dipole - dipole forces
1.2
London forces are found between ...
A two polar molecules.
B two non-polar molecules.
C a polar molecule and a non-polar molecule.
Da polar molecule and an ionic substance.
(2
1.3 Which of the following compounds have a shape that can be described as
trigonal bipyramidal?
A
CH4
B
PCL5
с
SF6
D
BF3
(2)
1.4
Which of the following have the same molecular geometry?
CO2, H20, BeCl2 and N20
A
CO2, BeCl2 and N2O
B
H20 and N20 only
C
H20, BeCl2 and CO2
CO2 and N20 only
(2)​

Answers

Answer:

1.1) Covalent bonding

Explanation:

All of the above are intermolecular forces except covalent, which is intramolecular.

Sally rides her bike to the store to get some Skittles. The store is 5 km
away. If it takes her 10 minutes to get to the store what is her average
speed?

0.5 km/hr
0.5 mph
0.5 km/min
5 km/min

Answers

Answer:

Sally's average speed is 0.5 km/min

Explanation:

speed=distance/time

so, 5km/10min=0.5 km/min

I have to make question longer this question
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Do you breathe air?

Answers

Answer:

Of course I breathe air.

Explanation:

I'm not a fish.

Answer:

[tex]ummmmmmm \: yes \: [/tex]

The following substances dissolve when added to water. Classify the substances according to the strongest solute-solvent interaction that will occur between the given substances and water during dissolution. Drag the appropriate items to their respective bins. Not all bins may contain an item and some bins may contain multiple items.NH3 AlBr3 CH3OH AlCl

Answers

Answer:

NH3 ------dipole - dipole forces

CH3OH ------ dipole - dipole forces

AlBr3 ------- ion - dipole forces

AlCl3 ------- ion - dipole forces

Explanation:

Let us recall that water is a polar molecule. This means that water has a positive as well as a negative end. NH3 also has a dipole. The interaction between solute and solvent dipoles leads to the dissolution of NH3 in water. Hence the strongest intermolecular force here is dipole - dipole forces.

Similarly, CH3OH  possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.

As for AlBr3 and AlCl3, the two substances dissociate into ions in solution and these ions interact with the dipole in water via ion - dipole interaction as its strongest intermolecular interaction.

Answer:

Dipole -dipole forces :

Ammonia [tex]NH_3[/tex]

Aluminium Chloride [tex]AlCl[/tex]

Methanol [tex]CH_3OH[/tex]

Ion dipole forces :

Aluminium bromide [tex]AlBr_3[/tex]

Explanation:

Because water is not in ionic form it can only forms dipole forces which are strongest. Methanol, Ammonia and AlCl are also dipoles not ions . Thus dipole dipole forces exist.

On the other hand, aluminium bromide are ionic and it can forms ion dipole bonds with water.

For more information on this visit

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A dilute solution of hydrofluoric acid has a volume of 3.0 L and a molarity of 3.0
M. If the original solution had a volume of 2.0L, what was the initial molarity?

Answers

Answer:

4.5M

Explanation:

The solution was diluted from 2.0L to 3.0L, the dilution factor was:

3.0L / 2.0L = 1.5.

That means the solution was diluted 1.5 times.

As the final molarity of the diluted solution is 3.0M, the initial molarity of the solution was:

3.0M * 1.5 =

4.5M is the molarity of the original solution

There are 3 gases in a container, methane has a partial pressure of 1.23 atm, ethane's partial pressure is 1.48 atm and an unknown pressure of propane. The pressure in the container was measure to be 4.43 atm. What is the partial pressure of propane?

A) 1.72
B) 1.35
C) 1.69
D) 1.53

Answers

Answer:

A) 1.72 atm

Explanation:

Dalton's Law of Partial Pressures

[tex]P_{t} = P_{1} + P_{2} + P_{3} ....[/tex]

4.43 atm = 1.23 atm + 1.48 atm + x

x = 4.43 atm - (1.23 atm + 1.48 atm)

x = 1.72 atm

what do protons determine about an element

Answers

The number of protons in an atoms determines the atoms identity. Electrons determine the electrical charge.

Answer:

The number of protons in one atom of an element determines the atom's identity, and the number of electrons determines its electrical charge. The atomic number tells you the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element.

Explanation:

An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
final volume is 1.75 L. What was the initial temperature?

Answers

Answer:

[tex]T_1=-91.18\°C[/tex]

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

[tex]\frac{T_1}{V_1}= \frac{T_2}{V_2}[/tex]

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

[tex]T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C[/tex]

Best regards!

how many atoms of carbon are in a diamond with a mass of 0.568 g?

Answers

Answer:

There are 2.85 x 10^22 atoms of carbon in a diamond with a mass of 0.568 g.

Hope this helps! :)

Is carbonic acid (H2CO3) soluble in water?

Answers

Answer:

it is soluble in water

Explanation:

mark brainliest pliiz cutee:)

Yes it is soluble in water

Determine the enthalpy of neutralization in Joules/mmol for a solution resulting from 19 mL of 1 M NaOH solution and 19 mL of a HCl with the same molarity. If separately, each had a temperature of 28.6 degrees Celsius, and upon addition, the highest temperature reached by the solution was graphically determined to be 37.3 degrees Celsius. Round to the nearest whole number.

Answers

Answer:

[tex]\Delta _{neutralization}H=-73\frac{J}{mmol}[/tex]

Explanation:

Hello there!

In this case, by considering this calorimetry problem, it is possible to realize that the heat released by the reaction between HCl and NaOH is absorbed by the reaction mixture, which can be assumed to have the same density and specific heat of pure water; thus, we calculate this heat as a function of the specified temperature change:

[tex]Q_{rxn}=-Q_{solution}\\\\Q_{rxn}=-m_{solution}C_{solution}(T_2-T_1)[/tex]

Thus, we plug in the data, by also considering that the total volume of solution is 19mL+19mL=38mL:

[tex]Q_{rxn}=-(38mL*\frac{1g}{1mL} )(4.184\frac{J}{g\°C}) (37.3\°C-28.6\°C)\\\\Q_{rxn}=-1383.2J[/tex]

Next, since the reaction between NaOH and HCl is:

[tex]NaOH+HCl\rightarrow NaCl+H_2O[/tex]

Whereas there is 1:1 mole ratio of NaOH to HCl, we infer they both react with the same moles, defined by the volume and molarity:

[tex]n_{rxn}=0.019L*1mol/L\\\\n_{rxn}=0.019mol[/tex]

Finally, to compute the enthalpy of neutralization we divide the total heat due to the reaction by the reaction moles to obtain:

[tex]\Delta _{neutralization}H=\frac{Q_{rxn}}{n_{rxn}=}\\\\ \Delta _{neutralization}H=\frac{-1383.23J}{0.019mol}\\\\\Delta _{neutralization}H=-72801.6\frac{J}{mol}*\frac{1mol}{1000mmol}\\\\\Delta _{neutralization}H=-73\frac{J}{mmol}[/tex]

Best regards!

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