(PLZ I NEED HELP QUICLY) Angela lives in a remote area serviced by only two cell phone towers. Tower 1 is located 5 miles west and 2 miles south of her home and transmits a signal for 12 miles. Tower 2 is located 8 miles east and 7 miles north of her home and transmits a signal for 10 miles. Consider the location of Angela’s house to be (0, 0) on a coordinate grid. The system of inequalities represents this scenario.
Angela travels to a friend’s house, which is 4 miles east and 8 miles north of her house. Will Angela have cell phone service at her friend’s house?

A. Angela will not have any cell phone service.
B. Angela will have cell phone service from tower 1 only.
C. Angela will have cell phone service from tower 2 only.
D. will have cell phone service from both towers.

Answer:

The probability is 7/11

Step-by-step explanation:

This is because there are 7 blue coins that you can grab out of 11 coins in total.

Answer:

Negative

Step-by-step explanation:

From the scatter plot displayed, we could clearly observe the direction of the trend line as it produces a negative slope. For high values of y, the values of x are low and similarly, high values of x have low y values. Therefore, this kind of relationship between the two variables is considered negative.

Answer:

5, -4

Step-by-step explanation:

midpoint = x1 + x2/2 ,y1 + y2/2

= 0 + 10 /2 , -2 + -6/2

= 10/2 , -8/2

midpoint = 5, -4

28.571429% that is 2

hope this helped

Answer:

50% Is the answer

Answer:

3 bagel recipe and 2 doughnut recipes are needed

Step-by-step explanation:

Given the expression

3d + 5b = 21 .. 1

d + b = 5 .... 2

We can use the expression to look for the amount of doughnut recipe and bagel recipe needed by solving the equations simultaneously

Multiply equation 1 by 1 and 2 by 3 to have;

3d + 5b = 21 .. 3

3d + 3b = 15 .... 4

Subtract 3 from 4

5b - 3b = 21 - 15

2b = 6

b = 6/2

b = 3

Substitute b = 3 into equation 2;

From 2,

d = b = 5

d + 3 = 5

d = 5 - 3

d = 2

Hence 3 bagel recipe and 2 doughnut recipes are needed

Answer:

12/5

Step-by-step explanation:

Pythagorean theorem=> adjacent side=5

tanx=oppx/adjx

tanx=12/5

Answer:

I give bases example the triangle pyramid

Yes, based on the information, it should be noted that social recommendations can increase ad effectiveness.

The study you mentioned found that viewers who arrived at an advertising video through social media recommendations were more likely to correctly recall the brand being advertised than viewers who arrived by browsing. This is because social recommendations come from people we trust, and we are more likely to be influenced by their opinions.

First, social recommendations are more personalized. They are based on the interests of the person who is making the recommendation, so they are more likely to be relevant to the person who is receiving the recommendation. Second, social recommendations are more credible. We trust the opinions of our friends and family, so we are more likely to believe their recommendations. Third, social recommendations are more timely. They are shared in real time, so they are more likely to be relevant to the current moment.

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The formula for the sequence is an = [tex]2^n[/tex], where n is a positive integer. This formula is proven correct using mathematical induction.

To find a formula for the sequence defined by a1 = 1 and ak = 2ak-1, we can use mathematical induction to establish a pattern and then derive the formula. Here's how we can solve it step by step:

Step 1: Base case:

For k = 1, we have a1 = 1.

Step 2: Assume the formula holds for some positive integer n, where n ≥ 1.

Assume that an = [tex]2^{n-1[/tex] for some positive integer n.

Step 3: Use the assumption to prove the formula for the next term.

Now, let's prove that an+1 = [tex]2^n[/tex] holds.

Using the recursive formula ak = 2ak-1, we have:

an+1 = 2an

Substituting the assumed formula an = [tex]2^{n-1[/tex], we get:

an+1 = 2([tex]2^{n-1[/tex])

To simplify, we have:

an+1 = [tex]2^n[/tex]

Step 4: Conclusion:

Based on the assumption and the proof for the next term, we can conclude that the formula an = [tex]2^n[/tex] holds for all positive integers n ≥ 1.

Therefore, the formula for the sequence defined by a1 = 1 and ak = 2ak-1 is an = [tex]2^n[/tex].

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Part a:Here, In be the number of n-digit quinary (0, 1, 2, 3, 4) sequences with(i) at least one 3 and (ii) the first 3 occurs before the first 0 (possibly no 0's).Since there is at least one 3 in the n-digit sequence, we start the sequence by selecting one of the 5 digits. There are five ways to do this.The next digits are chosen according to one of the three cases shown below:1) A string of (n-1) digits where no 0's are included in the string.2) A string of (n-1) digits where at least one 0 appears in the string before the first 3.3) A string of (n-1) digits where 3 appears before the first 0 in the string.The first string in case 1 can be formed in 4 different ways because no 0's can appear in the string and there are 4 digits to choose from (0, 1, 2, 4). There are 5 choices for the first digit and thus 5*4 quinary sequences of length n with at least one 3 and no 0's that start with the selected digit.The first string in case 2 can be formed in 5 different ways because the first 3 can appear in any position before the first 0. The remaining digits are chosen in n-2 positions because the first digit is already chosen (which is 3) and n-1 digits are left. There are 4 choices for each of the remaining n-2 positions because no 0's can appear in the string and there are 4 digits to choose from (0, 1, 2, 4). Thus, there are 5*5*4^(n-2) quinary sequences of length n with at least one 3 and at least one 0 that start with the selected digit.The first string in case 3 can be formed in n-1 different ways because the first 3 can appear in any position before the first 0. The remaining digits are chosen in n-2 positions because the first digit is already chosen (which is 3) and n-1 digits are left. There are 4 choices for each of the remaining n-2 positions because no 0's can appear in the string and there are 4 digits to choose from (0, 1, 2, 4). Thus, there are 5*(n-1)*4^(n-2) quinary sequences of length n with at least one 3 and at least one 0 that start with the selected digit.Therefore, the number of n-digit quinary sequences with (i) at least one 3 and (ii) the first 3 occurs before the first 0 (possibly no 0's) is the sum of the number of sequences in each of the three cases above, i.e.In = 5*4^(n-1) + 5*5*4^(n-2) + 5*(n-1)*4^(n-2)Part b:Recurrence: qn = 3q(n-1) + 4^(n-1) + 2.   q1 = 1. Let's see if qn = 39(n-1) + 5(n-1) satisfies this recurrence.q1 = 1 = 3(1-1) + 4^(1-1) + 2 = 0 + 1 + 2 = 3(0) + 5(1-1) + 1 = 0 + 0 + 1Thus, q1 = 1 satisfies the recurrence.qn+1 = 3qn + 4^n + 2 = 3(39n-1 + 5n-1) + 4^n + 2= 117(n-1) + 15(n-1) + 4^n + 2= 132(n-1) + 4^n + 3Using this formula, we can see that q2 = 91.Part c:Here, we need to finish the induction proof of this fact 2 that In = (n > 1).Induction Hypothesis: Assume true for n = k, i.e., Pk = Ik = 5*4^(k-1) + 5*5*4^(k-2) + 5*(k-1)*4^(k-2)Induction Step: To show that it is true for n = k+1, we need to show that the formula given above holds. The first digit can be any of the 5 digits (0, 1, 2, 3, 4) and the remaining digits can be selected in one of the three ways discussed in part (a).Case 1: n-1 digits with no 0'sThere are 4 choices for each of the n-1 digits, since 0 cannot be used. Therefore, there are 4^(n-1) such sequences with no 0's.Case 2: n-1 digits with at least one 0 before the first 3The first 3 can be in any of the n-1 positions, and the digits before it must be chosen from the set {0,1,2,4}. The remaining digits can be chosen in any of the 4 choices. Therefore, there are 5*(n-1)*4^(n-2) such sequences.Case 3: n-1 digits with 3 before 0We start by selecting one of the n-1 positions for the 3, then the remaining digits are chosen from the set {0,1,2,4}. There are (n-2) positions left for the remaining digits. There are 4 choices for each position, since 0 cannot be used. Therefore, there are 5*(n-1)*4^(n-2) such sequences.Thus, the total number of n-digit quinary sequences with at least one 3 and with the first 3 before the first 0 isIn = 5*4^(n-1) + 5*5*4^(n-2) + 5*(n-1)*4^(n-2) = qn+1 - qn = 132(n-1) + 4^n + 3 - (39(n-1) + 5(n-1)) = 93(n-1) + 4^n + 3which completes the induction proof.Part d:Since qn = 39n-1 + 5n-1, we haveqn+1 - qn = 132n - 39n - 5n = 88nTherefore, qn+1 = qn + 88nSubstituting qn = 39n-1 + 5n-1, we getqn+1 = qn + 88n = 39n-1 + 5n-1 + 88n = 39n + 5n + 88(n-1)Simplifying, we getqn+1 = 132(n-1) + 4^n + 3Therefore, en = In - In-1 = 93(n-1) + 4^n + 3 - 93(n-2) - 4^(n-1) - 3= 93n - 93(n-1) - 4^(n-1)= 93 - 4^(n-1)Thus, the closed form for en is en = 93 - 4^(n-1).

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Answer:

the 1 one

Step-by-step explanation:

Answer:

113.4=x(18)

x=6.3

Step-by-step explanation:

It says the product of a number, x, and 18 is 113.4. Since it says product there will be multiplication. The word "is" tells us that x and 18 equals 113.4. Is x= 6.3, 6.3 times 18 equals 113.4. This is a true equation.

Answer:

The highest temperature was 33C warmer  than the lowest temperature.

Step-by-step explanation:

In order to find how many degrees warmer was the highest temperature, you have to calculate the difference between both temperatures:

23-(-10)

According to the sign rule, you have to change the subtraction sign  to addition and then, change the sign on the umber after that and add the numbers, which is:

23+10=33

According to this, the answer is that the highest temperature was 33C warmer  than the lowest temperature.

relation R on set A = {23, 51, 36, 75, 35, 11, 102, 9, 10, 29}, aRb means a ≡ b (mod 3), which indicates that a and b have the same remainder when divided by 3.

In the given relation R on set A = {23, 51, 36, 75, 35, 11, 102, 9, 10, 29}, aRb means a ≡ b (mod 3), which indicates that a and b have the same remainder when divided by 3.

To represent this relation R in digraph notation, we can draw a directed graph where each element of set A is represented as a node, and there is a directed edge from node a to node b if aRb holds true.

Let's go through each element of set A and determine the directed edges based on the given relation R:

1. For 23, its remainder when divided by 3 is 2. Therefore, there will be an edge from 23 to itself.

2. For 51, its remainder when divided by 3 is 0. There will be an edge from 51 to itself.

3. For 36, its remainder when divided by 3 is 0. There will be an edge from 36 to itself.

4. For 75, its remainder when divided by 3 is 0. There will be an edge from 75 to itself.

5. For 35, its remainder when divided by 3 is 2. There will be an edge from 35 to itself.

6. For 11, its remainder when divided by 3 is 2. There will be an edge from 11 to itself.

7. For 102, its remainder when divided by 3 is 0. There will be an edge from 102 to itself.

8. For 9, its remainder when divided by 3 is 0. There will be an edge from 9 to itself.

9. For 10, its remainder when divided by 3 is 1. There will be an edge from 10 to itself.

10. For 29, its remainder when divided by 3 is 2. There will be an edge from 29 to itself.

In this digraph, each node represents an element from set A, and the directed edges indicate the relation R (a ≡ b mod 3).

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Answer:

Option 4: 4¹¹

Step-by-step explanation:

Looking at the problem, I need to work out 4⁴ squared first, which is the same as 4⁸. Then multiply that by 4³ to get 4¹¹. What I did was simply add 3 + (4 * 2), which is 11.

Answer:

Step-by-step explanation:

Answer:

Lol its in total of 34

Step-by-step explanation:

Answer:

6 apples

Step-by-step explanation:

3 apples cost $1.00

so for $2.00, 2x3÷1=6

hope it helps. plz mark me as brainliest.

Answer:

6 apples

Step-by-step explanation:

if three apples are 1 dollar then every time you add a dollar you would get three more apples

so it would look somthing like

1$ = 3 apples

2$= 6 apples

3$= 9 apples  

4$= 12 apples

so on

A hose will be needed vertical walls to run along the entire outer edge of the floor and up around the door of the greenhouse 88 feet .

To calculate the length of the hose needed to run along the entire outer edge of the floor and up around the door of the greenhouse, we need to consider the perimeter of the floor and the additional distance around the door.

The perimeter of the floor is the sum of the lengths of all four sides of the rectangle. Since the greenhouse is 20 ft long and 16 ft wide, the perimeter of the floor is:

Perimeter of floor = 2(length + width) = 2(20 ft + 16 ft) = 2(36 ft) = 72 ft

In addition to the floor perimeter, to account for the distance around the door. The door is 8 ft wide, so the additional distance around the door is:

Distance around door = 2(width of door) = 2(8 ft) = 16 ft

calculate the total length of the hose needed by adding the perimeter of the floor and the distance around the door:

Total length of hose = Perimeter of floor + Distance around door = 72 ft + 16 ft = 88 ft

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a) The determination of the equivalent units of production for materials and conversion costs is as follows:

                                                       Units       Materials       Conversion

Completed and transferred out  12,500        12,500            12,500

Ending work in process                2,850         2,850                1,710

Total equivalent units                  15,350       15,350              14,210

b) The calculation of the unit costs is as follows:

                                      Direct Materials     Conversion Costs

Production costs                $42,980                 $34,104

Total equivalent units           15,350                    14,210

Unit costs                              $2.80                      $2.40

c) The preparation of the cost reconciliation schedule is as follows:

                                         Direct Materials  Conversion Costs  Total Costs

Beginning work in process      $0                        $0                     $0

Cost to be accounted for       $42,980                 $34,104          $77,084

Total production costs           $42,980                 $34,104          $77,084

Costs accounted for units:

Completed / transferred out $35,000               $30,000         $65,000

Ending work in process          $7,980                   $4,104          $12,084

Total costs accounted for    $42,980                 $34,104         $77,084

Equivalent units are the multiplication of the number of physical (or actual) units on hand by the percentage of completion of the units.

1. Completed and transferred out 12,500 units.

2. Beginning work in process = $0

Ending work in process = 2,850 units 60% complete

Production Costs

Direct materials costs = $42,980 100% complete in terms of materials at July 31.

Direct labour = $15,700

Manufacturing overhead = $18,404

Total conversion costs = $34,104 ($15,700 + $18,404)

Equivalent units of production:

                                                       Units       Materials       Conversion

Completed and transferred out  12,500        12,500            12,500

Ending work in process                2,850         2,850 (100%)    1,710 (60%)

Total equivalent units                  15,350       15,350              14,210

Unit costs:

                                      Direct Materials     Conversion Costs

Production costs                $42,980                 $34,104

Total equivalent units           15,350                    14,210

Unit costs                              $2.80                      $2.40

                                 ($42,980 ÷ 15,350)    ($34,104 ÷ 14,210)

Cost Reconciliation Schedule:

                                         Direct Materials  Conversion Costs  Total Costs

Beginning work in process      $0                        $0                     $0

Cost to be accounted for       $42,980                 $34,104          $77,084

Total production costs           $42,980                 $34,104          $77,084

Costs accounted for units:

Completed / transferred out $35,000               $30,000         $65,000

                                 (12,500 x $2.80)              (12,500 x $2.40)

Ending work in process          $7,980                   $4,104          $12,084

                                   (2,850 x $2.80)              (1,710 x $2.40)    

Total costs accounted for    $42,980                 $34,104         $77,084

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Answer:

Kala's first step.

Step-by-step explanation:

Solving linear equations.

But Kala did not do that. Instead, she skipped the first stages and moved on ahead, making her equation invalid.

Answer:

C

Step-by-step explanation:

Add like terms to get

4.5a + 4b + 3.5c

Answer:

1.8 inches

Step-by-step explanation:

Create a proportion where x is the distance on the map

[tex]\frac{1}{55}[/tex] = [tex]\frac{x}{99\\}[/tex]

Cross multiply and solve for x

55x = 99

x = 1.8

So, the distance on the map is 1.8 inches

Answer:

1.8 inches

Step-by-step explanation:

Scales on a map always represent the direct proportion.

Compare the distances as fractions:

Inches on the map

________________  =  [tex]\frac{1}{55} = \frac{x}{99}[/tex]

Miles on the ground

[tex]x = \frac{1x99}{55}[/tex]

[tex]x = \frac{99}{55}[/tex]

[tex]x = \frac{9}{5} = 1\frac{4}{5}[/tex]

x = 1.8 inches

Answer:

6

Step-by-step explanation:

because  i had the same question and the departments where 6

Answer:

Hey! I can teach you this.

The range is the distance between the highest and lowest numbers.

In this case, the lowest number is 3, and the highest is 54, making the range 54 - 3, which is 51.

Because 3 is 51 away from 54. I hope this helps you!

Here's an Overleaf PDF I created with an explanation for your question:

Answer:

No

Step-by-step explanation:

Say n was equal to 2

7(2) + 6 =20

13(2) = 26

Answer:

90°

Step-by-step explanation:

Formula to find EACH interior angle:

[tex]\frac{(n-2) *180}{n}[/tex]

Given:

n (number of sides) = 4

Work:

[tex]\frac{(n-2) *180}{n} \\\\\frac{(4-2) *180}{4} \\\\\frac{(2) *180}{4} \\\\\frac{360}{4} \\\\90[/tex]