Please please help. It’s due at 11:59. I don’t understand

The tangent line to f(x) = e ˣ at the point x = 2 has slope equal to f ' (2):

f(x) = e ˣ   →   f '(x) = e ˣ   →   f ' (2) = e ²

At x = 2, the function takes on a value of f (2) = e ². Use the point-slope formula to get the equation of the tangent line:

y - e ² = e ² (x - 2)

Solve for y :

y = e ² x - e ²

Answer:

11, 13, 17, 19,

Step-by-step explanation:

dunno

Answer:

x = -85/3

Step-by-step explanation:

The solution is, the value of x is - 33.33 in 3(6x-5)-7(3x+10)=0.

Simplify simply means to make it simple. In mathematics, simply or simplification is reducing the expression/fraction/problem in a simpler form. It makes the problem easy with calculations and solving.

here, we have,

given expression is:

3(6x-5)-7(3x+10)=0

now, we have to simplify the expression to solve for x

we get,

3(6x-5)-7(3x+10)=0

or, 18x - 30 - 21x - 70 = 0

or, 18x - 21x -30 - 70 = 0

or, - 3x - 100 = 0

or, 3x = -100

or, x = -100/3

or, x = - 33.33

Hence, The solution is, the value of x is - 33.33 in 3(6x-5)-7(3x+10)=0.

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Answer:

82

Step-by-step explanation:

add 7 to 5 fifthteen times

If Clipner had 15 days to prepare her seventh grade class for their next math exam. On the first day. she gave the class 7 math problems to

complete. Each day following, Ms. Clipner gave the class 5 more math problems to solve in preparation. Then 82 problems did Ms. Clipner give

the class for review

Two or more expressions with an equal sign is called as Equation.

By given data, On the first day. she gave the class 7 math problems to complete. Each day following, Ms. Clipner gave the class 5 more math problems to solve in preparation.

We need to find how many problems did Ms. Clipner give

the class for review .

=7+15(5)

=7+75

After adding 75+7, we get

=82

Hence 82  problems did Ms. Clipner give the class for review.

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Answer:

The relative frequency of rolling a particular number can be calculated using the formula

relative frequency , where f is the actual frequency of an event and n is the number of times the experiment is performed. This experiment had the following results:

The relative frequency of rolling a 1 is 0.2.

The relative frequency of rolling a 2 is about 0.23.

The relative frequency of rolling a 3 is about 0.13.

The relative frequency of rolling a 4 is 0.15.

The relative frequency of rolling a 5 is 0.15.

The relative frequency of rolling a 6 is about 0.13.

The relative frequencies of rolling 1, 2, 3, 4, 5, and 6 are quite similar. So, the relative frequency is a good predictor of the theoretical probability.

Step-by-step explanation:

this is exact answer from edmentum so change it up a bit

Answer: false, 44 is not less than 24

Step-by-step explanation:

Substitute-3 for x and -7 for y.

4(-3)-8(-7)<24

-12+56<24

44<24

Answer:

420

Step-by-step explanation:

Answer:

38%

Step-by-step explanation:

Answer:

38% is correct

ED2021

Answer:

Some

Step-by-step explanation:

the mean absolute deviation would intersect and would there for be some but at far enough apart to not be a lot

Answer:

The correct answer is 5in

Step-by-step explanation:

6+4=10÷2=5in

Answer:I think 3 years

Step-by-step explanation:

sorry if im wrong

Answer:

Step-by-step explanation:

hello :  here is an solution

Answer:

y=-8x+8

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

y=-8x+8

Answer:

8.3

Step-by-step explanation:

Answer:

No, there is not sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting.

This means that the null hypothesis is:

[tex]H_{0}: \mu = 434[/tex]

It is believed that the machine is underfilling the bags.

This means that the alternate hypothesis is:

[tex]H_{a}: \mu < 434[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

434 is tested at the null hypothesis:

This means that [tex]\mu = 434[/tex]

A 9 bag sample had a mean of 431 grams with a variance of 144.

This means that [tex]X = 431, n = 9, \sigma = \sqrt{144} = 12[/tex]

Value of the test-statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{431 - 434}{\frac{12}{\sqrt{9}}}[/tex]

[tex]z = -0.75[/tex]

P-value of the test:

The pvalue of the test is the pvalue of z = -0.75, which is 0.2266

0.2266 > 0.01, which means that there is not sufficient evidence to support the claim that the bags are underfilled.

Answer:

the picture isnt loading. it says error.

Step-by-step explanation:

Answer:

Ummm Don't know

Step-by-step explanation:

Answer:

[tex]x - 2y = -10[/tex]  

Step-by-step explanation:

1) Use the point-slope formula [tex]y-y_1 = m(x-x_1)[/tex] to write the equation of the line in point-slope form with the given information. From there, we can convert it to standard form. Substitute values for [tex]m[/tex], [tex]x_1[/tex], and [tex]y_1[/tex] in the formula.

Since [tex]m[/tex], or the slope, is equal to [tex]\frac{1}{2}[/tex], substitute [tex]\frac{1}{2}[/tex] for [tex]m[/tex] in the formula. Since [tex]x_1[/tex] and [tex]y_1[/tex] represent the x and y values of a point the line intersects, substitute the x and y values of (6,8) into the formula as well. This gives the following equation:

[tex]y-8 = \frac{1}{2} (x-6)[/tex]

2) Now, convert the equation above into standard form, represented by the equation [tex]Ax + Bx = C[/tex]. Expand the right side, move the terms with the variables to the left side, then move the constants to the right side. Make sure that [tex]A[/tex] isn't negative and all the terms are integers and relatively prime.

[tex]y-8=\frac{1}{2}(x-6)\\y-8 = \frac{1}{2} x-3\\-\frac{1}{2} x+y -8=-3\\-\frac{1}{2} x+y=5\\x -2y = -10[/tex]

So, the answer is [tex]x - 2y = -10[/tex].

Answer:

The values of a, b, and c determine the shape and position of the parabola. The domain of a function is the set of all real values of x that will give real values for y. The range of a function is the set of all real values of y that you can get by plugging real numbers into x. The quadratic parent function is y = x2.

Step-by-step explanation:

just read carefully and look it up on symbolab

Answer:

The answer to your problem is 1 5/6

Answer:

11/6

Step-by-step explanation:

First you need to get a common denomintor in order to add fractions.  Here you can multiply 6/3 by two to get 12/6.  Then you can just do 12/6-1/6 since adding a negative number is the same as subtracting, leaving you with 11/6, which cannot be reduced so that is your final answer.

Answer: No

Step-by-step explanation: MAD(Mean Absolute Deviation is 5, and if the mean of data set c is 10, 10+5=15 at most and the mean of data set d is 30, 30-5=25 at most and there is no overlap

Answer:

Your answer is no

Step-by-step explanation:

Answer:

22ft

Step-by-step explanation:

Given the height of Bills modeled by the function h(t) = -16t^2 + 128t.

To get his height after 5.5secs, we will replace t with 5.5 a shown;

h(t) = -16t^2 + 128t.

h(5.5) = -16(5.5)^2 + 128(5.5)

h(5.5) = =-484+704

h(5.5) = 220ft

Hence his height after 5.5secs is 22ft

Answer:

$850

Step-by-step explanation:

Interest = Principal x Rate x Time

I = 2000(.0425)(10)

I = 850

Answer:

0.7385 = 73.85% probability that it is indeed a sample of copied work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Identified as a copy

Event B: Is a copy

Probability of being identified as a copy:

80% of 15%(copy)

100 - 95 = 5% of 100 - 15 = 85%(not a copy). So

[tex]P(A) = 0.8*0.15 + 0.05*0.85 = 0.1625[/tex]

Probability of being identified as a copy and being a copy.

80% of 15%. So

[tex]P(A \cap B) = 0.8*0.15 = 0.12[/tex]

What is the probability that it is indeed a sample of copied work?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.12}{0.1625} = 0.7385[/tex]

0.7385 = 73.85% probability that it is indeed a sample of copied work.

Answer:

4.7 · 10^7

Step-by-step explanation:

Answer:

Answer is 9

Step-by-step explanation:

I did the quiz also used a median calculator I don't think this will help but hopefully it dose or something

Answer:

Your answer will be D. 15,840:) you're welcome, have a great day:)!

Answer:

12

Step-by-step explanation:

hope it helps

see attached

Answer:

Yellow- y = -3 + 5

Red- y = 2x + 5

Purple- y = 2x - 6

Blue- x = 5

Green- y = 2

I hope this helps you ^^ Good luck :]