let f (x) = 5x and g(x) = x^1/3. find (fg) (x)

(fg)(x) =

Answer: 96 slices

Step-by-step explanation:

The, a z-score of -0.65 is not unusual

To calculate the z-score, we use the formula:

[tex]z =\frac{ (x - μ)}{σ}[/tex]

where x is the individual score, μ is the mean, and σ is the standard deviation.

Plugging in the values given, we get:

[tex]z= \frac{71-73}{3.1}[/tex]
z = -0.65

Rounding to 2 decimal places, the z-score is -0.65.

To determine if this score is unusual or not, we need to compare it to the normal distribution. A z-score of -0.65 means that the individual's score is 0.65 standard deviations below the mean.

According to the empirical rule, about 68% of the data falls within 1 standard deviation of the mean. Therefore, a z-score of -0.65 is not unusual and falls within the normal range of scores.

So, the answer is B. Not Unusual.

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Answer:

The common difference is 2.

Answer:

The common difference of the arithmetic sequence 14, 16, 18 is **2**.

In any arithmetic sequence, each term is equal to the previous term plus the common difference. So, the second term is equal to the first term plus the common difference. In this case, the second term, 16, is 2 more than the first term, 14. Therefore, the common difference is 2.

We can also find the common difference by subtracting any two consecutive terms in the sequence. For example, we can subtract the second term from the third term to get 18 - 16 = 2.

The common difference of an arithmetic sequence is always constant. This means that the difference between any two consecutive terms in the sequence will always be the same. In this case, the difference between any two consecutive terms is 2.

Step-by-step explanation:

a. 15, 16, 17 : The triangle is an acute triangle

b. 20, 18, 7 : The triangle is an obtuse triangle

c. 17, 144, 145 : The triangle is a right triangle

d. 24, 32, 40 : The triangle is a right triangle

From the question, we are to classify the given triangles as obtuse, acute or right triangles

To classify the triangles, we will consider the longest side of the triangles

a.  15, 16, 17

Is 17² = 15² + 16² ?

17² = 289

15² + 16² = 225 + 256 = 481

NO,

17² < 15² + 16²

Thus,

The triangle is an acute triangle

b.  20, 18, 7

Is 20² = 18² + 7² ?

20² = 400

18² + 7² = 324 + 49 = 373

NO,

20² > 18² + 7²

Thus,

The triangle is an obtuse triangle

a.  17, 144, 145

Is 145² = 144² + 17² ?

145² = 21025

144² + 17² = 20736 + 289 = 21025

YES,

Thus,

The triangle is a right triangle

a.  24, 32, 40

Is 40² = 32² + 24² ?

40² = 1600

32² + 24² = 1024 + 576 = 1600

YES

Hence,

The triangle is a right triangle

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True: A Chorochromatic map is a type of cartographic map that represents features depending on how they are distributed across the surface in terms of quality.`

We have,

The art and science of cartography involves visually depicting a geographic location, typically on a flat surface like a map or chart. It could include superimposing a region's depiction with non-geographical distinctions like political, cultural, or other ones.

Making and utilizing maps is the theory and application of cartography. Cartography, which combines science, aesthetics, and method, is based on the idea that reality may be described in ways that effectively convey spatial information. The same basic components are included on most maps: the main body, the legend, the title, the scale and orientation indications, the inset map, and the source notes.

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complete question:

a cartographic map style that symbolizes features based on the qualitative surface distribution of a mapped feature is called a chorochromatic map.

5. There is no solution since 5 = 7 is a false statement. Option C

6. There is no solution since 7x = 6x is a false statement. Option C

7. The value of the angle BCY = 55 degrees

8. The value of exterior angle , x is 137 degrees

Note that algebraic expressions are described as expressions composed of variables, terms, constants, factors and constants.

From the information given, we have that;

5. 6x +8 - 3 = 8x + 7 -2x

collect the like terms

6x + 5 = 6x + 7

5 = 7

6. 9x + 11 - 2x = 6x + 11

collect the terms

7x = 6x

We can see that for the value of the first, x is zero and for the second, there is no solution

7. We have from the diagram that;

25x + 11x = 180; because angles on a straight line is equal to 180 degrees

add the like terms

36x = 180

Make 'x' the subject of formula

x = 5

<BCY = 11x = 11(5) = 55 degrees

8. The sum of the angles in a triangle is 180 degrees

Then,

62 + 61 + y = 180

y = 180 - 43

But, x + y = 180

x = 180 - 43 = 137 degrees

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The form of the particular solution of the differential equation x" — x' – 2x = e^t cost – t^2 + cos 3t is x_p(t) = Ae^t cos(t) + Be^t sin(t) + Ct^2 + Dt + Ecos(3t) + Fsin(3t) and the particular solution of the y" – y' + 2y = (2x + 1)e^(x/2) cos (√7/2)x + 3(x^3 – x)e^(x/2) sin (√7/2) x is y_p(x) = (Ae^(x/2) cos(√7/2)x + Be^(x/2) sin(√7/2)x) + (C x^3 + Dx^2 + Ex + F)

Explanation: -

Part (a): -To determine the form of a particular solution to x" - x' - 2x = e^t cos(t) - t^2 + cos(3t),

we look at the non-homogeneous terms on the right-hand side. We see that we have a term of the form e^t cos(t), which suggests a particular solution of the form Ae^t cos(t) or Be^t sin(t).

We also have a polynomial term t^2, which suggests a particular solution of the form At^2 + Bt + C. Finally, we have a term of the form cos(3t), which suggests a particular solution of the form D cos(3t) + E sin(3t).

Thus,

x_p(t) = A e^t cos(t) + B e^t sin(t) + Ct^2 + Dt + E cos(3t) + F sin(3t) is particular solution of the above differential equation.

Part (b): -To determine the form of a particular solution to y" - y' + 2y = (2x + 1)e^(x/2) cos(√7/2)x + 3(x^3 - x)e^(x/2) sin(√7/2)x, we first observe that the right-hand side includes a product of exponential and trigonometric functions. Therefore, a particular solution may take the form of a linear combination of functions of the form e^(ax) cos(bx) and e^(ax) sin(bx).

Additionally, the right-hand side includes a polynomial of degree 3, so we may include terms of the form ax^3 + bx^2 + cx + d in our particular solution.

Overall, a possible form for a particular solution to this differential equation is:

y_p(x) = (Ae^(x/2) cos(√7/2)x + Be^(x/2) sin(√7/2)x) + (C x^3 + Dx^2 + Ex + F)

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The vertices of the triangle after reflection is

D)N′(−5, 2), M′(−8, 1), O′(−7, 3).

What is triangle?

A triangle is a form of polygon with three sides; the intersection of the two longest sides is known as the triangle's vertex. There is an angle created between two sides. One of the crucial elements of geometry is this

Remember that the general rule to reflect over a vertical line in the form

if  x = a then,

=> (x , y) -> (-x-2a , y)

For x = 5, we'll have that the general rule is:

=> (x , y)  -> (-x-10 , y).

Now the triangle vertices are,

N(-5,2) => (-(-5)-10,2) => (5-10 , 2) => N'(-5,2)

M(-2,1) => (-(-2)-10,1) => (2-10,1) => M' (-8,1)

O(-3,3) => (-(-3)-10,3) => (3-10,3) => O'(-7,3)

Hence the vertices of the triangle after reflection is D)N′(−5, 2), M′(−8, 1), O′(−7, 3).

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The nearest degree, the pendulum swung approximately 29 degrees.

To find the degrees of rotation for the pendulum swing, we'll use the arc length formula and the definition of a radian. The formula is:

Arc length = Radius × Angle (in radians)

We have the arc length (15 cm) and the radius (30 cm). Rearrange the formula to find the angle:

Angle (in radians) = Arc length / Radius

Angle (in radians) = 15 cm / 30 cm = 0.5 radians

Now, convert radians to degrees using the conversion factor (1 radian ≈ 57.3 degrees):

Angle (in degrees) = 0.5 radians × 57.3 ≈ 28.65 degrees

So, to the nearest degree, the pendulum swung approximately 29 degrees.

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The matrix representing L with respect to the ordered bases E is [ 0 5 3l ][ -2 l -3l ]. The matrix representing L with respect to the ordered bases F is [ 1 l -l/2 ] [ -1 1 3/2 ].

To find the matrix representing the linear transformation L with respect to the ordered bases E and F, we need to determine where L sends each vector in the basis E and express the results as linear combinations of the basis vectors in F. We can then arrange the coefficients of these linear combinations in a matrix.

Let's apply this approach to each of the given linear transformations:

L(x, y, z) = (x + y, z)

To find the image of u1 = (1, 0, -1)T under L, we compute L(u1) = (1 + 0, -1) = (1, -1). Similarly, we can compute L(u2) = (3, l) and L(u3) = (-l, 3l). Now we express each of these images as a linear combination of the vectors in F:

L(u1) = 1*b1 + (-1/2)b2

L(u2) = lb1 + (1/2)*b2

L(u3) = (-l/2)*b1 + (3/2)*b2

These coefficients give us the matrix:

[ 1 l -l/2 ]

[ -1 1 3/2 ]

L(x, y, z) = (x + 2y - z, -x - y + 3z)

Using the same process, we find:

L(u1) = (0, -2)

L(u2) = (5, l)

L(u3) = (3l, -3l)

Expressing these images in terms of E gives the matrix:

[ 0 5 3l ]

[ -2 l -3l ]

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The margin of error for a 95% confidence interval estimate for the proportion of all students with cell phones is approximately 0.0932.

To find the margin of error for a 95% confidence interval estimate for the proportion of all students with cell phones, we can use the formula:

Margin of Error = Z* * sqrt(p*(1-p)/n)

where:
Z* is the z-score corresponding to the desired level of confidence (in this case, 1.96 for 95% confidence)
p is the sample proportion (55/75 = 0.7333)
n is the sample size (75)

Plugging in the values, we get:

Margin of Error = 1.96 * sqrt(0.7333*(1-0.7333)/75)
Margin of Error ≈ 0.0932

Therefore, the margin of error for a 95% confidence interval estimate for the proportion of all students with cell phones is approximately 0.0932.

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This is an exercise of the Pythagorean Theorem, which establishes that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides, called legs.

This can be expressed mathematically as:

Where "a" and "b" are the lengths of the legs and "c" is the length of the hypotenuse. This theorem is one of the fundamental bases of geometry and has many applications in physics, engineering, and other areas of science.

The Pythagorean Theorem formula is used to calculate the length of an unknown side of a right triangle, as long as the lengths of the other two sides are known. It can also be used to determine if a triangle is right if the lengths of its sides are known.

To calculate the hypotenuse, we will apply the formula:

c = √(a² + b²)

Knowing that:

a = 8cm

b = 15cm

Now we just substitute the data in the formula, and calculate the hypotenuse, then

The hypotenuse C of the triangle is 17 cm.

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In economics, a utility function is a mathematical function that assigns a numerical value to the satisfaction or utility that a consumer derives from consuming a particular combination of goods and services.

First, let's correct the utility function you provided. I believe it should be:
u(x1, x2) = x1^2 + x2^2

Now, let's find the marginal utility functions with respect to x1 and x2. The marginal utility is the derivative of the utility function with respect to the corresponding variable.

(a) Marginal utility function with respect to x1:
MU_x1 = d(u(x1, x2))/dx1 = 2x1

Marginal utility function with respect to x2:
MU_x2 = d(u(x1, x2))/dx2 = 2x2

(b) The significance of this utility function is that it exhibits diminishing marginal utility for both x1 and x2. As the consumption of x1 or x2 increases, the additional utility gained from consuming more units of x1 or x2 decreases.

This is evident in the marginal utility functions MU_x1 and MU_x2, where the derivatives are constant values (2x1 and 2x2), indicating a linear relationship.

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Answer:

37.68

Step-by-step explanation:

The formula for getting the circumference of a circle is 2πr

So:

2 * 3.14 * 6

= 37.68

Hope this helps :)

Pls brainliest...

Answer:

The Correct answers are

A

C

D

E

Answer:

Correct Answers:

A 3/4=6/8

C 2/3=8/12

D 8/8=5/5

E 2/5=4/10

Step-by-step explanation:

As x approaches to  0, x²/8 approaches 0 the limit is 1/2 and the taylor polynomial for cos(x), for x near 0 is  (x²/2 - x⁴/24)/x

To find the Taylor polynomial of degree 4 for cos(x) near x = 0, we use the following formula:

p4(x) = cos(0) - (x²/2!) + (x⁴/4!) = 1 - (x²/2) + (x⁴/24)

To simplify the ratio (1-cos(x))/x, we substitute cos(x) with p4(x):

(1 - (1 - (x²/2) + (x⁴/24)))/x = (x²/2 - x⁴/24)/x

Now, to find the limit as x approaches 0:

lim (x->0) (x²/2 - x⁴/24)/x = lim (x->0) (x/2 - x³/24)

Using L'Hopital's rule, we differentiate the numerator and the denominator with respect to x:

lim (x->0) (1/2 - x²/8)

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Answer:

3.142 in 2 decimal is 3.100

Step-by-step explanation:

When we come to diameter of 8cm I don't know

Answer:

  51.2 inches

Step-by-step explanation:

You want the length of a mural whose hypotenuse is 96 inches if the scale drawing has a length of 8 inches and a hypotenuse of 15 inches.

The ratios of corresponding lengths will be the same:

  drawing length / drawing hypotenuse = mural length / mural hypotenuse

  8 in / 15 in = mural length / 96 in

Multiplying the equation by 96 in, we have ...

  (96 in)·8/15 = mural length

  51.2 in = mural length

The mural is 51.2 inches long.

Let's use variables to represent the number of child and adult tickets sold on Wednesday.

Let c be the number of child tickets sold, and let a be the number of adult tickets sold.

We know that the price of a child ticket is $5.60, and the price of an adult ticket is $9.40.

From the problem statement, we know that 177 tickets were sold in total, so:

c + a = 177

We also know that the total revenue from ticket sales was $1352.20, so:

5.60c + 9.40a = 1352.20

Now we have a system of two equations with two variables. We can solve for a by using the first equation to express c in terms of a, and then substituting into the second equation:

c + a = 177 --> c = 177 - a

5.60c + 9.40a = 1352.20

Substituting c = 177 - a into the second equation, we get:

5.60(177 - a) + 9.40a = 1352.20

Expanding and simplifying:

992.20 - 5.60a + 9.40a = 1352.20

3.80a = 360

a = 95

Therefore, 95 adult tickets were sold on Wednesday.

Its bugging out but I got 95 tickets I would add explanation if it didn't act out.

X=Adult tickets

Y=Child tickets

X+Y=117

Y=117-X

9.40X+5.60Y=1352.20

9.40X+5.60(117-X)=1352.20

9.40X+991.20-5.60x=1352.20

3.80X=361

X=95

The probability of event B is 11/72

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, with 0 indicating impossibility and 1 indicating certainty, and is based on the ratio of favorable outcomes to total possible outcomes.

According to the given information:

We can use the formula for the probability of the union of two events:

p(A or B) = p(A) + p(B) - p(A and B)

Substituting the given values, we have:

1/6 = 1/8 + p(B) - 1/9

Simplifying this equation, we get:

1/6 = (9 + 72p(B) - 8)/72

Multiplying both sides by 72, we get:

12 = 9 + 72p(B) - 8

Solving for p(B), we get:

p(B) = (12 - 1)/72 = 11/72

Therefore, the probability of event B is 11/72

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The probability of event B as a simplified fraction  is 11/72

What is Probability?

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, with 0 indicating impossibility and 1 indicating certainty, and is based on the ratio of favorable outcomes to total possible outcomes.

According to the given information:

We can use the formula for the probability of the union of two events:

=>p(A or B) = p(A) + p(B) - p(A and B)

Substituting the given values, we have:

=> 1/6 = 1/8 + p(B) - 1/9

Simplifying this equation, we get:

=>1/6 = (9 + 72p(B) - 8)/72

Multiplying both sides by 72, we get:

=> 12 = 9 + 72p(B) - 8

Solving for p(B), we get:

=> p(B) = (12 - 1)/72 = 11/72

Therefore, the probability of event B as simplified fraction  is 11/72.

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We can say with 95% confidence that the population variance σ2 lies within the interval [155.25, 570.06].

To construct a 95% confidence interval for the population variance σ2, we can use the chi-square distribution.

First, we need to calculate the chi-square values for the upper and lower limits of the confidence interval. We use the formula:

chi-square upper = (n-1)*s^2 / χ^2(α/2, n-1)

chi-square lower = (n-1)*s^2 / χ^2(1-α/2, n-1)

where n is the sample size, s is the sample standard deviation, α is the level of significance (0.05 for 95% confidence interval), and χ^2 is the chi-square distribution function.

Plugging in the values, we get:

chi-square upper = (25-1)*14^2 / χ^2(0.025, 24) = 43.98

chi-square lower = (25-1)*14^2 / χ^2(0.975, 24) = 15.14

Next, we can use these chi-square values to calculate the confidence interval for σ2:

confidence interval = [(n-1)*s^2 / chi-square upper, (n-1)*s^2 / chi-square lower]

Plugging in the values, we get:

confidence interval = [(25-1)*14^2 / 43.98, (25-1)*14^2 / 15.14]

confidence interval = [155.25, 570.06]

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The probability that X will be at least 2 is 0.5940 and the probability that X will be between 2 and 4 (inclusive) is 0.3010.

The Poisson distribution is given by the formula:

[tex]P(X = k) = (e^{(-\lambda)} * \lambda ^k) / k![/tex]

where λ is the expected value or mean of the distribution.

In this case, we are given that E(X) = 2.4, so λ = 2.4.

Using a Poisson probability calculator, we can find:

P(X > 2) = 1 - P(X ≤ 2) = 1 - (P(X = 0) + P(X = 1) + P(X = 2))

= [tex]1 - [(e^{(-2.4)} * 2.4^0) / 0! + (e^{(-2.4)} * 2.4^1) / 1! + (e^{(-2.4)} * 2.4^2) / 2!][/tex]

= [tex]1 - [(e^{(-2.4)} * 1) + (e^{(-2.4)} * 2.4) + (e^{(-2.4)} * 2.4^2 / 2)][/tex]

= 1 - 0.4060

= 0.5940 (rounded to four decimal places)

Therefore, the probability that X will be at least 2 is 0.5940.

Using a Poisson probability calculator, we can find:

P(2 < X < 4) = P(X = 3) + P(X = 4)

= [tex](e^{(-2.4)} * 2.4^3 / 3!) + (e^{(-2.4)} * 2.4^4 / 4!)[/tex]

= 0.2229 + 0.0781

= 0.3010 (rounded to four decimal places)

Therefore, the probability that X will be between 2 and 4 (inclusive) is 0.3010.

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After unit conversion , the statement is 30 ounces < 2 pounds.

What is unit conversion?

The same feature is expressed in a different unit of measurement through a unit conversion. Time can be stated in minutes rather than hours, and distance can be expressed in kilometres rather than miles, or in feet rather than any other unit of length.

Here the given is 32 ounces and 2 pounds,

We know  that , if two values in same measurement then we can easily compare them.

Here we know that 1 pound  = 16 ounces. Then

=> 2 pounds = 16*2 = 32 ounces.

Hence the statement is 30 ounces < 2 pounds.

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The measure of arc FE is 27degrees,angle m<B is 112degrees, <GHJ = <GIJ = 73⁰ , m<S = 90 degrees in the given circles

The sum of angle in the triangle DEF is 180 degrees

mFE = <D

Recall that <D+<E+<F = 180⁰

<D+63+90 = 180

<D = 180-153

<D = 27 degrees

Hence the measure of arc FE is 27degrees

6) For this circle geometry, we will use the theorem

The sum of Opposite side of a cyclic quadrilateral is 180 degrees.

A + C = 180

m<A + 101 = 180

m<A = 180-101

m<A = 79degrees

Similarly

B + D = 180

m<B + 68 = 180

m<B = 180-68

m<B = 112degrees

7) The sum of angle in a circle is 360, hence;

arcGJ+68+31+115 = 36p

arcGJ = 360 - 214

arcGJ = 146⁰

Since the angle at the centre is twice angle at the circumference, then;

<GHJ = 1/2 arcGJ

<GHJ = 1/2(146)

<GHJ = 73⁰

<GHJ = <GIJ = 73⁰ (angle in the same segment of the circle are equal)

8) Recall that the sum of Opposite side of a cyclic quadrilateral is 180 degrees.

P + R = 180

57 + <R = 180

m<R = 180-57

m<R = 123degrees

Similarly, m<Q+m<S = 180⁰

Since the triangle in a semi circle is a right angled triangle, hence m<Q = 90 degrees (triangle PQR is a right angled triangle)

m<S = 180 - 90

m<S = 90 degrees

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The line intersects the xy-plane (z=0) and the xz-plane (y=0) at the point (0,0,0) in both cases.

To find the point of intersection of the line l(t) = (5/3t, 7/8t, -4t) with the xy-plane (z=0), we can putting z=0 in the equation of the line to get

5/3t = x

7/8t = y

0 = z

Solving for t, we get

t = 0 (which corresponds to the point (0,0,0))

Substituting t=0 in the equations of the line, we get the point of intersection as

(5/3(0), 7/8(0), -4(0)) = (0, 0, 0)

Therefore, the line intersects the xy-plane at the point (0, 0, 0).

To find the point of intersection of the line with the xz-plane (y=0), we can substitute y=0 in the equation of the line to get

5/3t = x

0 = y

-4t = z

Solving for t

t = 0 (which corresponds to the point (0,0,0))

Putting t=0 in the equations of the line, we get the point of intersection as

(5/3(0), 7/8(0), -4(0)) = (0, 0, 0)

Therefore, the line intersects the xz-plane at the point (0, 0, 0).

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Answer:

9÷ 1/2 = 9 • 2/1 = 18 bags of trail mix

Step-by-step explanation:

You can solve this problem using division.  Since there are 9 pounds of trail mix to divide up, you would start with 9 pounds and divide it by 1/2 pound to find the number of bags you could make (use the reciprocal of the divisor 1/2)

Answer: Option 1

Step-by-step explanation:

    In a function, each input can only have one output. This rules out option 2 and option 4.

    Next, a graphed function must pass the vertical line test. This rules out option 3.

    This leaves us with option 1, the correct answer option. Option one is a function.

(a) Volume of the solid generated by revolving the region bounded by the graph is 12.422 cubic units.

(b)

(i) The work done in stretching the spring from its natural length to a length of 10 in. is 54 lb.-in.

(ii) The work done in stretching the spring from a length of 7 in. to a length of 9 in. is approximately 13.5 lb.-in.

(a) To find the volume of the solid generated by revolving the region bounded by the graph[tex]x^2=y-2[/tex] and 2y-x-2=0 for 0≤x≤1 about y=3, we can use the method of cylindrical shells:

First, we need to find the limits of integration for the radius of the shells. Since we are revolving around y=3, the distance between y=3 and the curve x^2=y-2 will give us the radius of the shell.

Solving for y in [tex]x^2=y-2[/tex], we get[tex]y=x^2+2.[/tex] Substituting this into 2y-x-2=0, we get [tex]x=2y-2y^2-2.[/tex] So the limits of integration for the radius will be from [tex]3-(x^2+2) to 3-(2y-2y^2-2).[/tex]

Next, we need to find the height of the shells. This is simply the length of the interval of integration for x, which is 0 to 1.

So the volume of the solid is given by the integral:

[tex]V = \int (3-(x^2+2)) - (3-(2y-2y^2-2)) dx[/tex] from x=0 to x=1

Simplifying and evaluating the integral, we get:

V ≈ 12.422 cubic units.

Therefore, the volume of the solid generated by revolving the region bounded by the graph [tex]x^2=y-2[/tex] and [tex]2y-x-2=0[/tex] for 0≤x≤1 about y=3 is approximately 12.422 cubic units.

(b) (i) The work done in stretching the spring from its natural length of 6 in. to a length of 10 in. can be found using the formula:

W =[tex](1/2)k(d2^2 - d1^2)[/tex]

where k is the spring constant, d1 is the initial length, and d2 is the final length.

Given that the force required to stretch the spring from its natural length of 6 in. to a length of 8 in. is 9 lb., we can find the spring constant as follows:

k = F/(d2 - d1) = 9/(8-6) = 4.5 lb/in

So the work done in stretching the spring from its natural length of 6 in. to a length of 10 in. is:

W = [tex](1/2)(4.5)(10^2 - 6^2)[/tex]= 54 lb.-in.

Therefore, the work done in stretching the spring from its natural length to a length of 10 in. is 54 lb.-in.

(ii) To find the work done in stretching the spring from a length of 7 in. to a length of 9 in., we can use the same formula:

W =[tex](1/2)k(d2^2 - d1^2)[/tex]

Using the same spring constant of 4.5 lb/in, the work done is:

W = [tex](1/2)(4.5)(9^2 - 7^2)[/tex]≈ 13.5 lb.-in.

Therefore, the work done in stretching the spring from a length of 7 in. to a length of 9 in. is approximately 13.5 lb.-in.

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The charge on the capacitor at time t is given by q(t) = -21292.5e^(-0.00878t) + 21292.5e^(-314.53t) + 626000 coulombs.

To find the charge on the capacitor, with the initial conditions q(0) = 0 coulombs and i(0) = 0 amperes, we use the given linear differential equation:

L d^2q/dt^2 + R dq/dt + 1/C q = E(t)

We can solve for q(t) by finding the roots of the characteristic equation, and assuming a particular solution. Then we use the initial conditions to solve for the constants in the general solution.

The solution to the differential equation is:

q(t) = -21292.5e^(-0.00878t) + 21292.5e^(-314.53t) + 626000

Therefore, the charge on the capacitor at time t is given by q(t) = -21292.5e^(-0.00878t) + 21292.5e^(-314.53t) + 626000 coulombs.

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