The probabilities are:
P(0 < z < 1.96) = 0.4750
P(-1.23 < z < 0) = 0.3907
P(z > 0.82) = 0.2061
P(z < -1.77) = 0.0384
P(-0.20 < z < 1.56) = 0.5199
P(1.12 < z < 1.43) =0.0550
P(z > -1.43) = 0.9236
To locate the chances of the usage of the same old ordinary distribution, we will use a well-known normal desk or a calculator. Here are the calculations for the given possibilities:
P(0 < z < 1.96):
Using the standard everyday desk, the place to the left of one.Ninety-six is 0.9750, and the vicinity to the left of zero is 0.5000. Therefore, the chance between zero and 1.96 is:
P(0 < z < 1.96) = 0.9750 - 0.5000 = 0.4750
P(-1.23 < z < 0):
Using the usual ordinary table, the vicinity to the left of -1.23 is 0.1093, and the area to the left of zero is zero.5000. Therefore, the possibility between -1.23 and 0 is:
P(-1.23 < z < 0) = 0.5000 - 0.1093 = 0.3907
P(z > 0.82):
Using the standard everyday table, the region to the left of zero.82 is zero.7939. Therefore, the possibility of z being extra than 0.82 is:
P(z > 0.82) = 1 - 0.7939 = 0.2061
P(z < -1.77):
Using the same old regular desk, the vicinity to the left of -1.Seventy-seven is zero.0384. Therefore, the chance of z being much less than -1.77 is:
P(z < -1.77) = 0.0384
P(-zero.20 < z < 1.56):
Using the standard ordinary desk, the area to the left of -0.20 is 0.4207, and the area to the left of 1.56 is 0.9406. Therefore, the opportunity between -0.20 and 1. Fifty-six is:
P(-0.20 < z < 1.56) = 0.9406 - 0.4207 = 0.5199
P(1.12 < z < 1.43):
Using the standard regular desk, the place to the left of 1.12 is 0.8686, and the location to the left of one. Forty-three is zero.9236. Therefore, the opportunity between 1.12 and 1. Forty-three is:
P(1.12 < z < 1.43) = 0.9236 - 0.8686 = 0.0550
P(z > -1.43):
Using the same old normal desk, the location to the left of -1.43 is zero.0764. Therefore, the possibility of z being greater than -1. Forty-three is:
P(z > -1.43) = 1 - 0.0764 = 0.9236
Please word that the chances are rounded to 4 decimal locations for clarity.
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The correct question is:
"Find the probability using the standard normal distribution. P(0 < z <1.96), P(-1.23 < z < 0), P(z > 0.82), P(z < -1.77), P(-0.20 < z < 1.56), P(1.12 < z < 1.43), P(z > -1.43)"
Find the deflection u (x, y, t) satisfying the wave equation utt = 4 (uxx + Uyy) for a rect- = angular plate with fixed ends and dimensions: horizontal a = 2pi and vertical b initial velocity is g(x, y) = 0 The initial displacement is f(x, y) = - 3sin(5x) * sin(6y) + 11sin(6x) * sin(9y)
TheThe general solution to the wave equation utt = 4 (uxx + Uyy) is given by the D’Alembert’s formula. Therefore, the solution to the given problem is obtained by finding the specific form of the initial conditions u (x, y, 0) = f (x, y) and ut (x, y, 0) = g (x, y) and then use these values to find u (x, y, t) using the D’Alembert’s formula.
Let us find the form of the wave u(x,y,t) that satisfies the wave equation utt = 4 (uxx + Uyy) given the initial displacement f(x,y) = -3sin(5x)sin(6y) + 11sin(6x)sin(9y) and g(x,y) = 0.
Solution:
The D’Alembert’s formula for the wave equation is given by:
`u(x,y,t) = (1/2) [f(x+ct,y) + f(x-ct,y)] + (1/(2c)) ∫_((x-ct))^(x+ct)∫_((y-c(t-s)))^(y+c(t-s)) g(s,r) dr ds`
where c is the speed of the wave. Comparing with the wave equation `utt = c^2(uxx + uyy)` we have `c = 2`
Therefore, the solution to the wave equation is given by:
`u(x,y,t) = (1/2) [-3sin(5(x+2t))sin(6y) -3sin(5(x-2t))sin(6y) +11sin(6(x+2t))sin(9y) +11sin(6(x-2t))sin(9y)]`
Hence, the solution is:
`u(x,y,t) = (1/2) [-3sin(5(x+2t))sin(6y) -3sin(5(x-2t))sin(6y) +11sin(6(x+2t))sin(9y) +11sin(6(x-2t))sin(9y)]`
So, this is the required solution.
I suckkk at math.. Help?
Answer:
B. x=6
Step-by-step explanation:
substitute -7 into 2y to get -14. your new equation should be 4x-14=10. add 14 to both sides to get 4x=24, divide both sides by 4 to get x=6.
Answer:
B. 6
Step-by-step explanation:
y = -7
4x + 2(-7) = 10
4x + (-14) = 10
4x = 10 - (-14)
4x = 24
x = 6
I Need Answers Quick
Answer:
42.78cm2
Step-by-step explanation:
Area =100°/360 * 22/7 * 7^2
=42.78cm2
Which of the following describes the fraction 2/5?
5 is the part, 2 is the whole, and the fraction is equivalent to 25%.
2 is the part, 5 is the whole, and the fraction is equivalent to 25%.
5 is the part, 2 is the whole, and the fraction is equivalent to 40%.
2 is the part, 5 is the whole, and the fraction is equivalent to 40%.
The correct description of the fraction 2/5 is,
⇒ 2 is the part, 5 is the whole, and the fraction is equivalent to 40%.
What is mean by Percentage?A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.
To Calculate the percent of a number , divide the number by whole number and multiply by 100.
Given that;
The fraction is,
⇒ 2/5
Now, We can change into percent as;
⇒ 2/5 × 100%
⇒ 2 × 20%
⇒ 40%
Thus, The correct description of the fraction 2/5 is,
⇒ 2 is the part, 5 is the whole, and the fraction is equivalent to 40%.
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20 points helppppppppppppppppppppppppppppp
PLZZ anyone solve this ASAP
Answer:
[tex] cos^{-1}(cos\frac{ 7π}{6})=cos^{-1}(cos\frac{7*180}{6})[/tex]
[tex] cos^{-1}(cos{210})[/tex]
[tex] cos^{-}(cos(180+30))[/tex]
[since in third quadrant cos 30=-[tex] \frac{\sqrt{3}}{2}][/tex]
[tex] cos^{-}(- \frac{\sqrt{3}}{2})[/tex]
:150°or [tex] \frac{5π}{6}[/tex]
150°or [tex] \frac{5π}{6}[/tex]is a required answer.
Factor 64u–40.
Write your answer as a product with a whole number greater than 1.
Answer: 8(8u-5)
Step-by-step explanation:
Find a number that goes into both 64 and 40 the GCF of both is 8 so 8 goes on the outside of the new factor 8u-5 because if we distribute back we should arrive at the original equation
8(8u-5)
Calculate the volume
Two number cubes are rolled.
What is the probability that the first lands on an odd number and the second lands
on an even number?
Simplify your fraction.
O / 을
0 O
3
Answer:
cubes have 6 numbers
3 odd, 3 even
Step-by-step explanation:
probablity=desiredoutcome/totalpossibleoutcomes
there are 6 total desired outcomes (3 on each cube)
total possible, there are 6*6 or 36 total possible outcomes
so 6/36 or 1/6 chance
The temperature at sunrise is 40°F. Each hour, the temperature rises 4°F. Write an equation that models the temperature y, in degrees Fahrenheit, after x hours. What is the graph of the equation?
Write an equation that models the temperature y, in degrees Fahrenheit, after x hours.
Answer:
y = 4x + 40
Step-by-step explanation:
At sunrise, 0 hours have passed, meaning x = 0.
When x = 0, the temperature is 40, meaning that 40 is the y-intercept.
And every x hours the temperature rises by 4 degrees F
what is the approximate area of the hexagon? 224 cm2 336 cm2 448 cm2 672 cm2
The value of area of hexagon is,
A = 672 cm²
Given that;
In a hexagon;
Apothem of the hexagon = 14 cm
And, perimeter of the hexagon: 96 cm
Since, We know that,
Area of the hexagon = [(3√3) / 2] a²
where, a is the measure of the side
Since, hexagon has 6 sides.
Perimeter = 6a
96 cm = 6a
96 cm / 6 = a
16 = a
We can also use the area of a triangle to approximate the area of the hexagon. There are 6 triangles in the hexagon .
Area of a triangle = (height x base) / 2
A = (14 cm x 16 cm) / 2
A = 224 / 2
A = 112 cm²
So, Area of hexagon is,
A = 112 cm² x 6 triangles
A = 672 cm²
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Complete question is,
A regular hexagon has an apothem measuring 14 cm and an approximate perimeter of 96 cm.
What is the approximate area of the hexagon?
224 cm2
336 cm2
448 cm2
672 cm2
STRESSING OUT ABOUT THIS ONE
I had this one before. I'm pretty sure it is 1.61
Answer:
1.61
Step-by-step explanation:
It just makes since.
TRIG HELP NEED TO FIND C IS IT NOT ALT ANGLES?????
[tex]c+20=55\\c=55-20\\c=35[/tex]
If the data point is at (3, 10.5) and the prediction equation is y = -6.1x + 12.5, what is the value of the residual for this data point?
Given:
The data point is (3,10.5).
The prediction equation is [tex]y=-6.1x+12.5[/tex].
To find:
The value of the residual for this data point.
Step-by-step explanation:
The data point is (3,10.5). So, the actual value is 10.5 at [tex]x=3[/tex].
Prediction equation is
[tex]y=-6.1x+12.5[/tex]
Putting [tex]x=3[/tex], we get
[tex]y=-6.1(3)+12.5[/tex]
[tex]y=-18.3+12.5[/tex]
[tex]y=-5.8[/tex]
The formula for residual is:
Residual = Actual value - Expected value
[tex]Residual=10.5-(-5.8)[/tex]
[tex]Residual=10.5+5.8[/tex]
[tex]Residual=16.3[/tex]
Therefore, the residual for the given data point is 16.3.
Given the data set, calculate the mean
{9, 3, 1, 8, 3, 6}
Please help!!!
Answer:
mean: 5
Step-by-step explanation:
(9 + 3 + 1 + 8 + 3 + 6) / 6 = 5
The scores earned in a flower-growing competition are represented in the stem-and-leaf plot.
2 0, 1, 3, 5, 7
3 2, 5, 7, 9
4
5 1
6 5
Key: 2|7 means 27
What is the appropriate measure of variability for the data shown, and what is its value?
The IQR is the best measure of variability, and it equals 16.
The range is the best measure of variability, and it equals 45.
The IQR is the best measure of variability, and it equals 45.
The range is the best measure of variability, and it equals 16.
The appropriate measure of variability for the given data is the IQR, and its value is 16.
Based on the given stem-and-leaf plot, which represents the scores earned in a flower-growing competition, we can determine the appropriate measure of variability for the data.
The stem-and-leaf plot shows the individual scores, and to measure the spread or variability of the data, we have two commonly used measures: the range and the interquartile range (IQR).
The range is calculated by subtracting the smallest value from the largest value in the dataset. In this case, the smallest value is 20, and the largest value is 65. Therefore, the range is 65 - 20 = 45.
The interquartile range (IQR) is a measure of the spread of the middle 50% of the data. It is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). Looking at the stem-and-leaf plot, we can identify the quartiles. The first quartile (Q1) is 25, and the third quartile (Q3) is 41. Therefore, the IQR is 41 - 25 = 16.
In this case, both the range and the IQR are measures of variability, but the IQR is generally preferred when there are potential outliers in the data. It focuses on the central portion of the dataset and is less affected by extreme values. Therefore, the appropriate measure of variability for the given data is the IQR, and its value is 16.
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HELP I NEED HELP ASAP
HELP I NEED HELP ASAP HELP I NEED HELP ASAP
HELP I NEED HELP ASAP HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
Answer:
i think the answer would be A
A vending machine dispenses coffee into a twenty-ounce cup. The amount of coffee dispensed into the cup is normally distributed with a standard deviation of 0.03 ounce. You can allow the cup to overfill 4% of the time. What amount should you set as the mean amount of coffee to be dispensed? Click to view page 1 of the table. Click to view page 2 of the table. 19.9 ounces
The mean amount of coffee to be dispensed should be set at μ + 0.0525 ounce, where μ represents the original mean amount of coffee. This ensures that the cup overfills only 4% of the time.
To determine the mean amount of coffee to be dispensed, we need to find the value that corresponds to the 96th percentile of the normal distribution. This value represents the amount of coffee that should not be exceeded 96% of the time.
Using a standard normal distribution table or a calculator, we find that the z-score corresponding to the 96th percentile is approximately 1.75.
Since the standard deviation is given as 0.03 ounce, we can set up the equation:
1.75 = (x - μ) / 0.03
Solving for x, the mean amount of coffee to be dispensed, we get:
x - μ = 1.75 * 0.03
x - μ = 0.0525
x = μ + 0.0525
Therefore, the mean amount of coffee to be dispensed should be set at μ + 0.0525 ounce to ensure that the cup overfills only 4% of the time.
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3. Savannah estimates that her dog weights 30
pounds. When she takes her dog to the vet for
his check-up, the dog is placed on the scale and
actually weights 32.5 pounds. What was
Savannah's percent of error of her estimate?
Round to the nearest percent.
Answer:
8%
Step-by-step explanation:
Please help me I know it's A but I don't know why.
Answer:
Maybe try explaining that if you narrow it down and simplify the numbers by dividing them by 8 or somewhere around there.
determine whether the following equations are second-order linear differential equations.(a)y'' = −3x(y')2
To determine whether the equation y'' = −3x([tex]y')^2[/tex]is a second-order linear differential equation, we need to examine its form.
A second-order linear differential equation has the general form:
[tex]y'' + p(x)y' + q(x)y = r(x)[/tex]
where y is the dependent variable, x is the independent variable, and p(x), q(x), and r(x) are functions of x.
In the given equation, [tex]y'' = -3x(y')^2,[/tex]we can observe that the dependent variable y only appears in the squared term [tex](y')^2.[/tex]This indicates that the equation is not linear in y or its derivatives. It contains a non-linear term [tex](y')^2[/tex]multiplied by the function -3x.
Therefore, the equation [tex]y'' = -3x(y')^2 i[/tex] is not a second-order linear differential equation.
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An online store sold a gift basket at five different prices and recorded the number of gift baskets that were sold at each price. The results are shown in the scatterplot.
Complete question :
An online store sold a gift basket at five different prices and recorded the number of gift baskets that were sold at each price. The results are shown in the scatterplot.
Which statement is correct based on the scatterplot?
There is no relationship between price and gift baskets sold because the points do not form a straight line.
There is no relationship between price and gift baskets sold because there are multiple prices at which 80 gift baskets were sold.
There is a relationship between price and gift baskets sold, and the relationship is that as the price increases, the gift baskets sold increases.
There is a relationship between price and gift baskets sold, and the relationship is that as the price increases, the gift baskets sold decreases.
Answer:
There is a relationship between price and gift baskets sold, and the relationship is that as the price increases, the gift baskets sold decreases.
Step-by-step explanation:
From the scatterplot provided, it could be observed thatbthere is a linear trend in the plot created. This shows that there is a relationship between the price of gifts and the number if gift basket sold.
Furthermore, the slope of the linear trend line that could be drawn from the plotted data is negative, A negative slope Indicates a negative relationship, that is an increase in x leads to corresponding decrease in y. He ce, as price increases the number sold decreases
Answer:
d and/ or the other dude
Step-by-step explanation:
The following estimated regression equation is based on 10 observations was presented. ŷ 29.1270 +0.5906x1 + 0.4980x2 = Here SST = 6,589.125, SSR = 6,282.500, sb₁ = 0.0808, and $₂ = 0.0603. a. Compute MSR and MSE (to 3 decimals). MSR = MSE = b. Compute F and perform the appropriate F test (to 2 decimals). Use a = 0.05. Use the F table. F = The p-value is Select your answer At a = 0.05, the overall model is - Select your answer c. Perform a t test for the significance of B₁ (to 2 decimals). Use a = 0.05. Use the t table. tB₁ = The p-value is - Select your answer - At a = 0.05, there is - Select your answer ✓ relationship between y and 1. d. Perform a t test for the significance of B₂ (to 2 decimals). Use a = 0.05. Use the t table. tB₂ = d. Perform a t test for the significance of B₂ (to 2 decimals). Use a = 0.05. Use the t table. tB₂ = The p-value is - Select your answer At a = 0.05, there is - Select your answer - ✓relationship between y and X2.
There is a significant relationship between y and both x1 and x2.
MSR = 306.625, MSE = 30.844b. F = 9.939 and p-value = 0.007. At a = 0.05, the overall model is significant.
tB₁ = 7.301 and p-value = 0.0009. At a = 0.05, there is a significant relationship between y and x1. d. tB₂ = 4.771 and p-value = 0.0008. At a = 0.05, there is a significant relationship between y and x2.
In a regression model, the F-test is used to determine whether the regression coefficient as a whole is statistically significant or not.
The p-value of the F-test is compared to the significance level (α) to determine statistical significance.
If the p-value is less than α, the regression coefficient as a whole is considered statistically significant. If it is greater than α, then it is not statistically significant.
t-test is used to determine whether each individual regression coefficient is statistically significant or not.
The p-value of the t-test is compared to the significance level (α) to determine statistical significance.
If the p-value is less than α, the regression coefficient is considered statistically significant.
If it is greater than α, then it is not statistically significant.
In this question, the F-test is significant at a = 0.05, and the t-test for both x1 and x2 is significant at a = 0.05.
Therefore, there is a significant relationship between y and both x1 and x2.
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The temperature at the point (x, y, z) in a substance with conductivity
K = 7.5 is u(x, y, z) = 3y² + 3z².
Find the rate of heat flow inward across the cylindrical surface
y² + z² = 6, 0 ≤ x ≤ 3
The integration is ∫∫(q · dS) = ∫[0 to √6] ∫[0 to √6] (-45y - 45z) dy dz.
The rate of heat flow inward across the cylindrical surface y² + z² = 6, 0 ≤ x ≤ 3 can be determined by calculating the flux of the heat vector field through the surface.
To find the rate of heat flow, we need to calculate the surface integral of the heat flux vector across the given cylindrical surface. The heat flux vector is given by q = -K∇u, where K is the conductivity and ∇u is the gradient of the temperature function u(x, y, z).
First, we find the gradient of u:
∇u = (∂u/∂x)i + (∂u/∂y)j + (∂u/∂z)k
= 0i + (6y)j + (6z)k
Then, we calculate the heat flux vector:
q = -K(∇u)
= -7.5(0i + (6y)j + (6z)k)
= -45yj - 45zk
Next, we calculate the surface area element vector, dS, of the cylindrical surface. Since the surface is defined by y² + z² = 6, we can parameterize it as r(y,z) = yi + zk. Taking the cross product of the partial derivatives, we obtain dS = (∂r/∂y) x (∂r/∂z) dy dz = (-j -k) dy dz.
Finally, we can calculate the surface integral by integrating the dot product of q and dS over the given cylindrical surface:
∫∫(q · dS) = ∫∫(-45yj - 45zk) · (-j -k) dy dz
To find the limits of integration, we note that the surface extends from y² + z² = 6 to the origin, which corresponds to 0 ≤ y² + z² ≤ 6. Since the surface is symmetric, we can integrate over a quarter of the surface, from y = 0 to y = √6 and z = 0 to z = √6.
Performing the integration, we get:
∫∫(q · dS) = ∫[0 to √6] ∫[0 to √6] (-45y - 45z) dy dz
Evaluating this double integral will give us the rate of heat flow inward across the cylindrical surface.
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Jessie needs to earn more than $160 every month.
B. Enter the minimum number of hours, to the nearest whole, Jessie would have to work to earn $160 in a month.
Answer:
divide 460/60
Step-by-step explanation:
60 rep one hour and you will find your answer
Help with these will give brainliest
Answer:
$ 45,600
Step-by-step explanation:
Solve 3(2x - 7)<4x - 8
Answer:
x < 6.5
Step-by-step explanation:
3(2x - 7) < 4x - 8
6x - 21 < 4x - 8
6x - 4x < -8 + 21
2x < 13
x < 6.5
In a diving meet, you score 8.4 and 7.88.
What is your total score?
Answer: 16.28?
Step-by-step explanation:
Can anyone help me pls ? ( it’s talking about the blue dot ) will give brainliest!!
Answer:
NO
Step-by-step explanation:
From the graph attached,
Equation of the line parallel to x-axis is y = 3.
Since, the line is dotted line, equation will be an inequality (having sign of < or >)
Now shaded region is below the line so equation of the inequality will be,
y < 3
Any point below the dotted line will be the solution of the given inequality.
Therefore, blue dot on the dotted line represented by y = 3 will not be the solution of the inequality.
Answer is NO.
Find b given that A (-6, 2), B (b, 0), and C (3,-4) are collinear.
Answer:
b = -3.
Step-by-step explanation:
If the 3 points are collinear then:
Slope of AB = Slope of BC and so
(0-2)/(b + 6) = (-4-0)/( 3 - b)
-4(b + 6) = -2(3 - b)
-4b - 24 = -6 + 2b
-24 + 6 = 2b + 4b
6b = -18
b = -3.
2. One of the goals of this lab is to become familiar with different shapes of simple molecules. a. What is the name of the theory used to predict molecular geometries? b. Suppose a molecule consists of a central atom bonded to 2 outer atoms. There are two lone pairs on the central atom. What is the name of the molecular shape of this molecule? c. Suppose a molecule consists of a central atom bonded to 4 outer atoms. There are no lone pairs on the central atom. What is the name of the molecular shape of this molecule?
a. The name of the theory used to predict molecular geometries is the VSEPR (Valence Shell Electron Pair Repulsion) theory.
b. The name of the molecular shape for a molecule consisting of a central atom bonded to 2 outer atoms with two lone pairs on the central atom is "bent" or "angular." This molecular shape is also sometimes referred to as "V-shaped" due to its characteristic angular structure.
c. The name of the molecular shape for a molecule consisting of a central atom bonded to 4 outer atoms with no lone pairs on the central atom is "tetrahedral." This molecular shape is characterized by a central atom at the center with four symmetrically arranged outer atoms, forming a three-dimensional tetrahedron-like structure.
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