i’ll give brainliest (worth 15 pts)

The two necessary steps to put this equation into standard form is A) Add 3 to both sides and subtract 8x from both sides.

To put the equation x² - 3x + 27 = 8x - 3 into standard form, the two necessary steps are:

A. Add 3x to both sides: By adding 3 to both sides of the equation, we eliminate the constant term -3 on the right side and move it to the left side.

x² - 3x + 3x + 27 = 8x - 3 + 3x

x² + 27 = 11x

B. Subtract 11x from both sides:  By subtracting 8x from both sides of the equation, we eliminate the term 8x on the right side and move it to the left side.

x² + 27 - 11x = 11x - 11x

x² - 11x + 27 = 0

Therefore, the equation in standard form is x² - 11x + 27 = 0. Therefore, the correct answer is option A.

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Answer:

28 units

Step-by-step explanation:

Given data

Let the width be x

The length is =3x+5  

Perimeeter= 234

The expression for the perimeter is  

P=2L+2W

Substitute

234= 2*x+2(3x+5)

234= 2x+6x+10

Collect like terms

234= 8x+10

234-10= 8x

224=8x

x= 224/8

x=28

Hence the width is 28 units

Answer:

7,893,600 different combinations

Step-by-step explanation:

Answer:

We have a total.of 26 alphabets in the english language and numbers 0 to 9 will be 10.

Since there are no other limitations, we have to arrange 8 places with the 36 options we have.

It will simply be 36c8.

The answer will be 3,02,60,340.

Answer:

I belive the answer is 1/324

Answer:

[tex] cos^{-1}(cos\frac{ 7π}{6})=cos^{-1}(cos\frac{7*180}{6})[/tex]

[tex] cos^{-1}(cos{210})[/tex]

[tex] cos^{-}(cos(180+30))[/tex]

[since in third quadrant cos 30=-[tex] \frac{\sqrt{3}}{2}][/tex]

[tex] cos^{-}(- \frac{\sqrt{3}}{2})[/tex]

:150°or [tex] \frac{5π}{6}[/tex]

150°or [tex] \frac{5π}{6}[/tex]is a required answer.

Answer:

b = -3.

Step-by-step explanation:

If the 3 points are collinear then:

Slope of AB = Slope  of BC and so

(0-2)/(b + 6) = (-4-0)/( 3 - b)

-4(b + 6) = -2(3 - b)

-4b - 24 = -6 + 2b

-24 + 6 = 2b + 4b

6b = -18

b = -3.

[tex]c+20=55\\c=55-20\\c=35[/tex]

Answer:

Maybe try explaining that if you narrow it down and simplify the numbers by dividing them by 8 or somewhere around there.

The value of area of hexagon is,

A = 672 cm²

Given that;

In a hexagon;

Apothem of the hexagon = 14 cm

And, perimeter of the hexagon: 96 cm

Since, We know that,

Area of the hexagon = [(3√3) / 2] a²    

where, a is the measure of the side

Since, hexagon has 6 sides.

Perimeter = 6a

96 cm = 6a

96 cm / 6 = a

16 = a

We can also use the area of a triangle to approximate the area of the hexagon. There are 6 triangles in the hexagon .

Area of a triangle = (height x base) / 2

A = (14 cm x 16 cm) / 2

A = 224 / 2

A = 112 cm²

So, Area of hexagon is,

A = 112 cm²  x  6 triangles

A = 672 cm²

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Complete question is,

A regular hexagon has an apothem measuring 14 cm and an approximate perimeter of 96 cm.

What is the approximate area of the hexagon?

224 cm2

336 cm2

448 cm2

672 cm2

The correct description of the fraction 2/5 is,

⇒ 2 is the part, 5 is the whole, and the fraction is equivalent to 40%.

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

To Calculate the percent of a number , divide the number by whole number and multiply by 100.

Given that;

The fraction is,

⇒ 2/5

Now, We can change into percent as;

⇒ 2/5 × 100%

⇒ 2 × 20%

⇒ 40%

Thus, The correct description of the fraction 2/5 is,

⇒ 2 is the part, 5 is the whole, and the fraction is equivalent to 40%.

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Answer:

mean: 5

Step-by-step explanation:

(9 + 3 + 1 + 8 + 3 + 6) / 6 = 5

Answer:

22

Step-by-step explanation:

Answer:

6x

Step-by-step explanation:

because i said so 2+2+2=6 and x=5 but two x=10

Answer: 8(8u-5)

Step-by-step explanation:

Find a number that goes into both 64 and 40 the GCF of both is 8 so 8 goes on the outside of the new factor 8u-5 because if we distribute back we should arrive at the original equation

8(8u-5)

a. The name of the theory used to predict molecular geometries is the VSEPR (Valence Shell Electron Pair Repulsion) theory.

b. The name of the molecular shape for a molecule consisting of a central atom bonded to 2 outer atoms with two lone pairs on the central atom is "bent" or "angular." This molecular shape is also sometimes referred to as "V-shaped" due to its characteristic angular structure.

c. The name of the molecular shape for a molecule consisting of a central atom bonded to 4 outer atoms with no lone pairs on the central atom is "tetrahedral." This molecular shape is characterized by a central atom at the center with four symmetrically arranged outer atoms, forming a three-dimensional tetrahedron-like structure.

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Given:

The data point is (3,10.5).

The prediction equation is [tex]y=-6.1x+12.5[/tex].

To find:

The value of the residual for this data point.

Step-by-step explanation:

The data point is (3,10.5). So, the actual value is 10.5 at [tex]x=3[/tex].

Prediction equation is

[tex]y=-6.1x+12.5[/tex]

Putting [tex]x=3[/tex], we get

[tex]y=-6.1(3)+12.5[/tex]

[tex]y=-18.3+12.5[/tex]

[tex]y=-5.8[/tex]

The formula for residual is:

Residual = Actual value - Expected value

[tex]Residual=10.5-(-5.8)[/tex]

[tex]Residual=10.5+5.8[/tex]

[tex]Residual=16.3[/tex]

Therefore, the residual for the given data point is 16.3.

Answer:

divide 460/60

Step-by-step explanation:  

60 rep one hour and you will find your answer

Answer: I’m sorry I meant B

Step-by-step explanation: 9.6/3=3.2

3.2•8=25.6

TheThe general solution to the wave equation utt = 4 (uxx + Uyy) is given by the D’Alembert’s formula. Therefore, the solution to the given problem is obtained by finding the specific form of the initial conditions u (x, y, 0) = f (x, y) and ut (x, y, 0) = g (x, y) and then use these values to find u (x, y, t) using the D’Alembert’s formula.

Let us find the form of the wave u(x,y,t) that satisfies the wave equation utt = 4 (uxx + Uyy) given the initial displacement f(x,y) = -3sin(5x)sin(6y) + 11sin(6x)sin(9y) and g(x,y) = 0.

Solution:
The D’Alembert’s formula for the wave equation is given by:

`u(x,y,t) = (1/2) [f(x+ct,y) + f(x-ct,y)] + (1/(2c)) ∫_((x-ct))^(x+ct)∫_((y-c(t-s)))^(y+c(t-s)) g(s,r) dr ds`

where c is the speed of the wave. Comparing with the wave equation `utt = c^2(uxx + uyy)` we have `c = 2`

Therefore, the solution to the wave equation is given by:

`u(x,y,t) = (1/2) [-3sin(5(x+2t))sin(6y) -3sin(5(x-2t))sin(6y) +11sin(6(x+2t))sin(9y) +11sin(6(x-2t))sin(9y)]`

Hence, the solution is:

`u(x,y,t) = (1/2) [-3sin(5(x+2t))sin(6y) -3sin(5(x-2t))sin(6y) +11sin(6(x+2t))sin(9y) +11sin(6(x-2t))sin(9y)]`

So, this is the required solution.

The equation of the red graph, g(x) is g(x) =1/3x²

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

In the graph, we can see that

This means that

g(x) = 1/3f(x)

Recall that

f(x) = x²

This means that

g(x) =1/3x²

This means that the equation of the red graph is g(x) =1/3x²

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The matrix [T][tex]\left \{ {{B} \atop {B'}} \right.[/tex] represents the linear operator T with respect to the bases B′ and B.

The matrix representation [tex][T]\left \{ {{B} \atop {B'} \right.[/tex] of the linear operator T relative to the ordered bases B' and B, we need to determine how the basis vectors of B' are transformed under the linear operator T and express them as linear combinations of the basis vectors of B.

B′={1} and B={(0),[−1.0]} we can represent the basis vectors as column matrices

[1][tex]\left \{ {\atop {B'}} \right.[/tex] = [1]

[0][tex]\left \{ \atop {B'}} \right.[/tex] = [tex]\left[\begin{array}{ccc}0\\0\\\end{array}\right][/tex]

[-1.0][tex]\left \{ \atop B' \right.[/tex] = [tex]\left[\begin{array}{ccc}-1\\0\\\end{array}\right][/tex]

Now, we can apply the linear operator T to the basis vectors of B' and express the results in terms of the basis vectors of B.

T([1][tex]\left \{ {\atop {B'}} \right.[/tex] = [1][tex]\left \{ {\atop {B'}} \right.[/tex] = [1] = 1.[0][tex]\left \{ \atop {B'}} \right.[/tex] + 0.[-1.0][tex]\left \{ \atop B' \right.[/tex]

Therefore, we have

[T][tex]\left \{ {{B} \atop {B'}} \right.[/tex] = [tex]\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right][/tex]

The matrix [T][tex]\left \{ {{B} \atop {B'}} \right.[/tex] represents the linear operator T with respect to the bases B′ and B.

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Answer:

that earns 3% interest compounded annually. He ... Is the equation A = 21000(1 – 0.12)'a model of ... (1+0.03)= 1.03 ... The value of a car purchased for $20,000 decreases ... Kathy plans to purchase a car that depreciates. ... B) P= 10,000(0.8) ... YEARS. Wolves d is less than 1! d is more than 11. 1 Growth f(x) = 80(0.1165).

Step-by-step explanation:

yah it's not probably it's not 2 mmmm

Answer:

x≥k   y for you y≥42 inches tall

Step-by-step explanation:

can i have brainliest if right

Answer:

x=18

Step-by-step explanation:

Answer:

x= 18

Step-by-step explanation:

To solve this equation you have to work backwards

Start by dealing with the numbers that we know:

450 + (28.75 × x) = 967.5

-450                          -450

28.75x = 967.5

(when a number and a letter in mathematics are next to each other they are multiplying)

Now divide to find the value of x:

967.5 ÷ 28.75 = 18

18 is the value of x

To determine whether the equation y'' = −3x([tex]y')^2[/tex]is a second-order linear differential equation, we need to examine its form.

A second-order linear differential equation has the general form:

[tex]y'' + p(x)y' + q(x)y = r(x)[/tex]

where y is the dependent variable, x is the independent variable, and p(x), q(x), and r(x) are functions of x.

In the given equation, [tex]y'' = -3x(y')^2,[/tex]we can observe that the dependent variable y only appears in the squared term [tex](y')^2.[/tex]This indicates that the equation is not linear in y or its derivatives. It contains a non-linear term [tex](y')^2[/tex]multiplied by the function -3x.

Therefore, the equation [tex]y'' = -3x(y')^2 i[/tex] is not a second-order linear differential equation.

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Answer:

Expression: Y = -10/3 X

Y = 10/3

Step-by-step explanation:

If Y varies directly as X, then;

Y∝X

Y = kX

k is the constant of variation

If Y = 10 and X = -3

10 = -3k

k = -10/3

Substitute k = -10/3 into the expression Y = kX

Y = -10/3 X

This gives the required expression

To get the value of Y when X = -1

Recall that Y = kX

Y = -10/3 (-1)

Y = 10/3

Hence the value of Y is 10/3

Answer:

Value of x = 70'

Step-by-step explanation:

Given:

Given quadrilateral is a cyclic quadrilateral, in a cyclic quadrilateral sum of opposite angle is 180' .

Find:

Value of x

Computation:

x' + 110' = 180'

x' = 180' - 110'

Value of x = 70'

The integration is ∫∫(q · dS) = ∫[0 to √6] ∫[0 to √6] (-45y - 45z) dy dz.

The rate of heat flow inward across the cylindrical surface y² + z² = 6, 0 ≤ x ≤ 3 can be determined by calculating the flux of the heat vector field through the surface.

To find the rate of heat flow, we need to calculate the surface integral of the heat flux vector across the given cylindrical surface. The heat flux vector is given by q = -K∇u, where K is the conductivity and ∇u is the gradient of the temperature function u(x, y, z).

First, we find the gradient of u:

∇u = (∂u/∂x)i + (∂u/∂y)j + (∂u/∂z)k

= 0i + (6y)j + (6z)k

Then, we calculate the heat flux vector:

q = -K(∇u)

= -7.5(0i + (6y)j + (6z)k)

= -45yj - 45zk

Next, we calculate the surface area element vector, dS, of the cylindrical surface. Since the surface is defined by y² + z² = 6, we can parameterize it as r(y,z) = yi + zk. Taking the cross product of the partial derivatives, we obtain dS = (∂r/∂y) x (∂r/∂z) dy dz = (-j -k) dy dz.

Finally, we can calculate the surface integral by integrating the dot product of q and dS over the given cylindrical surface:

∫∫(q · dS) = ∫∫(-45yj - 45zk) · (-j -k) dy dz

To find the limits of integration, we note that the surface extends from y² + z² = 6 to the origin, which corresponds to 0 ≤ y² + z² ≤ 6. Since the surface is symmetric, we can integrate over a quarter of the surface, from y = 0 to y = √6 and z = 0 to z = √6.

Performing the integration, we get:

∫∫(q · dS) = ∫[0 to √6] ∫[0 to √6] (-45y - 45z) dy dz

Evaluating this double integral will give us the rate of heat flow inward across the cylindrical surface.

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