Can someone help me with this. Will Mark brainliest.

Answer:

(5,6)

Step-by-step explanation:

I'm guessing you mean the coordinates for the point where the lines intersect

Answer:

I believe it is b: (5,6)

Explanation:

The point (5,6) is the only point on the graph that both lines go through.

Answer:

x= -1 and 5

hope that helps

The solutions to the quadratic equation [tex]4(x+2)^2=36[/tex] are x = -5 and x = 1.

Given the following data:

In this exercise, you're required to determine the value of x by solving for the factors (roots) of the given quadratic equation.

In Mathematics, the standard form of a quadratic equation is given by;

[tex]ax^2 + bx + c =0[/tex]

Where:

Dividing both sides by 4, we have:

[tex]4(x+2)^2=36\\\\(x+2)^2=9[/tex]

Taking the square root of both sides, we have:

[tex]x+2=\pm3\\\\x=\pm 3-2[/tex]

x = -5 or 1.

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Answer:

i cat see it

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

60 divided by 28.3 which gives u 2.120141342756184

so round it which gives u 2

Answer:

its c  because its not a b or d  and its alround 13 feet

Step-by-step explanation:

Answer:

The exact same

Step-by-step explanation:

^ just means put it up like 3^2=3²

Answer:

-18

Step-by-step explanation:

5a2-7-b3

[tex]5*a*2-7-b*3[/tex]

[tex]5\cdot \left(-2\right)\cdot \left(2\right)-7-\left(-3\right)\cdot 3[/tex]

Therefore, -18 is your answer.

Hope this helped! :)

Answer:

[tex]M(7 ; 4)[/tex]

Step-by-step explanation:

midpoint -M

[tex]M(\frac{x_{1}+x_{2}}{2} ; \frac{y_{1}+y_{2}}{2} )[/tex]

[tex]M(\frac{9+5}{2} ; \frac{6+2}{2} )[/tex]

[tex]M(7 ; 4)[/tex]

Answer:

(7, 4 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

Here (x₁, y₁ ) = (9, 6) and (x₂, y₂ ) = (5, 2) , then

midpoint = ( [tex]\frac{9+5}{2}[/tex] , [tex]\frac{6+2}{2}[/tex] ) = ([tex]\frac{14}{2}[/tex] , [tex]\frac{8}{2}[/tex] ) = (7, 4 )

If an equation indicates addition in its presentation, in order to solve for the unknown, you must perform the inverse operation, which is subtraction.

Equations typically involve an equality between two expressions, with one or more unknown variables.

To isolate the unknown variable and determine its value, you need to perform operations on both sides of the equation to simplify and solve for the variable.

When an equation shows addition, you can undo that operation by subtracting the same value from both sides of the equation. This ensures that the equation remains balanced and maintains equality.

For example, consider the equation:

x + 5 = 10

To solve for x, you need to eliminate the 5 added to x. To do so, you subtract 5 from both sides of the equation:

x + 5 - 5 = 10 - 5

x = 5

By subtracting 5 from both sides, you isolate the variable x and find that its value is 5.

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Answer:

A. a + b = 180 is the correct option.

Answer:

2x+10=-8

x=9

3x=9

x=3

2x=8

x=4

4x=20

x=5

Step-by-step explanation:

Answer:

the slope is 3

the y intercept is (0,-7)

Step-by-step explanation:

3x-y=7 solve for y

add y to both sides

3x=7+y

subtract 7 from both sides

y=3x-7

y=mx+b

m=slope

b=y-intercept

3=slope

-7=y-intercept

Hope that helps :)

To approximate the value of f(1.5) using the tangent line to the graph of f at x = 1, we first find the derivative of f(x) to determine the slope of the tangent line at x = 1. The derivative is f'(x) = -2 sin x. Evaluating f'(x) at x = 1, we find the slope to be approximately -1.6829.

Next, we use the point-slope form of a line to find the equation of the tangent line. We have the point (1, f(1)) ≈ (1, 1.5839) and the slope -1.6829. Plugging these values into the point-slope form, we obtain the equation of the tangent line as y ≈ -1.6829x + 3.2668.

Finally, we substitute x = 1.5 into the equation of the tangent line to approximate f(1.5). After calculation, we find that f(1.5) is approximately 0.0009.

Therefore, the approximation for f(1.5) using the tangent line to the graph at x = 1 is approximately 0.0009.

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Answer:

It would decrease, but not necessarily by 8%

If the teacher had used a 90% confidence interval rather than a 98% confidence interval, the width of the interval would decrease, but not necessarily by 8%.

Option D is the correct answer.

A confidence interval is a range of values that is likely to contain the true value of an unknown parameter, such as a population means or proportion, based on a sample of data from that population.

It is a statistical measure of the degree of uncertainty or precision associated with a statistical estimate.

We have,

The width of a confidence interval is determined by the level of confidence and the sample size.

A higher confidence level requires a wider interval, and a larger sample size typically results in a narrower interval.

Since the sample size is fixed in this case, changing the confidence level will result in a change in the width of the interval.

As the confidence level increases, the width of the interval also increases. This is because a higher confidence level requires a larger margin of error, which is added to the point estimate to create the interval.

Therefore,

If the teacher had used a 90% confidence interval rather than a 98% confidence interval, the width of the interval would decrease, but not necessarily by 8%.

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Answer:

The answer is C. 8 mm

Step-by-step explanation:

For me, i was able to divide the 80 by 12 and get 6.667 thus i was able to round up and conclude the answer in the answer choices

Answer:

c

Step-by-step explanation:

Answer:

139 cm

Step-by-step explanation:

Answer:

The answer is 440

Step-by-step explanation:

I just took the test and got that question right

Answer: 6

Step-by-step explanation:

The total amount needed by Kallen for the gift and the wrapping paper will be:

= $43.87 + $2.94

= $46.81

Since he earns $8.25 for each lawn he mows, the number of lawns they he will need to complete to buy the gift and wrapping will be:

= $46.81 / $8.25

= 5.67

= 6 lawns approximately

He'll need to mow 6 lawns

The p-value for testing the hypothesis that the average runtime of HP laptops is not equal to 120 minutes, based on a sample mean of 130 minutes from a sample of 50 laptops, is approximately 0.0006 (rounded to four decimal places).

To calculate the p-value, we use the t-test. Given the null hypothesis that the average runtime is 120 minutes, the alternative hypothesis is that it is not equal to 120 minutes. We compare the sample mean to the hypothesized population mean using the t-distribution.

Using the formula for the t-statistic:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

t = (130 - 120) / (25 / sqrt(50))

t = 10 / (25 / 7.0711)

t = 2.8284

The degrees of freedom for the t-distribution are (sample size - 1) = (50 - 1) = 49.

Using the t-distribution table or statistical software, we find that the two-tailed p-value for a t-value of 2.8284 with 49 degrees of freedom is approximately 0.0006.

Therefore, the p-value for this hypothesis test is approximately 0.0006.

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Answer:

2) 4/5

3) 3

Step-by-step explanation:

2) 4/8-3=4/5

3)5x-4=3x+2

2x=6

x=3

Answer:

2) 4/5

3)x=3

Step-by-step explanation:

1) 4/8-3= 4/5

2) 5x-4=3x+2

bring 3x to left side and bring -4 to right side (remember signs will be reversed that is 3x becomes -3x and -4 will be 4

5x-3x=4+2

2x=6

x=6/2

x=3

put 3 in place of x

5*3-4=3*3+2

15-4=9+2

11=11

Answer:

Each term of a geometric sequence increases or decreases by a constant factor called the common ratio. The sequence below is an example of a geometric sequence because each term increases by a constant factor of 6. Multiplying any term of the sequence by the common ratio 6 generates the subsequent term.

Step-by-step explanation:

Please give brainliest

please help me

Step-by-step explanation:

mark me brilliant

(1) To find the value of B that makes f_(XY)(x,y) a valid joint density function, we need to ensure that the total probability over the entire domain is equal to 1. In this case, the domain is |x|<1 and |y|<1.

The integral of f_(XY)(x,y) over the given domain should be equal to 1:

∫∫ f_(XY)(x,y) dx dy = 1

∫∫ B(1+xy) dx dy = 1

To solve this integral, we integrate with respect to x first and then with respect to y:

∫(∫ B(1+xy) dx) dy

∫[Bx + B(xy^2)/2] dy, integrating with respect to x

Bxy + B(xy^2)/2 + C, integrating with respect to y

Now, evaluate the integral over the given domain:

∫[-1,1] [Bxy + B(xy^2)/2 + C] dy

[Bxy^2/2 + B(xy^3)/6 + Cy] evaluated from -1 to 1

[B/2 + B/6 + C] - [-B/2 - B/6 - C]

(B/2 + B/6 + C) - (-B/2 - B/6 - C)

2B/3 = 1

Solving for B:

B = 3/2

Therefore, the value of B that makes f_(XY)(x,y) a valid joint density function is B = 3/2.

(2) To determine if X and Y are uncorrelated, we need to calculate the covariance between X and Y. If the covariance is zero, then X and Y are uncorrelated.

Cov(X, Y) = E[XY] - E[X]E[Y]

To calculate E[XY], we need to find the joint expectation:

E[XY] = ∫∫ xy f_(XY)(x,y) dx dy

E[XY] = ∫∫ xy (3/2)(1+xy) dx dy

Integrating over the domain |x|<1 and |y|<1, we can calculate E[XY].

Similarly, we need to calculate E[X] and E[Y] to determine Cov(X, Y).

If Cov(X, Y) is found to be zero, then X and Y are uncorrelated.

(3) To prove or disprove independence between X and Y, we need to check if the joint probability density function (pdf) can be factorized into the product of the marginal pdfs of X and Y.

If f_(XY)(x,y) = f_X(x)f_Y(y), then X and Y are independent.

To determine if this factorization holds, we need to compare the joint pdf f_(XY)(x,y) with the product of the marginal pdfs f_X(x) and f_Y(y). If they are equal, then X and Y are independent. Otherwise, they are dependent.

(4) To prove or disprove the independence between X^2 and Y^2, we follow a similar approach as in (3). We compare the joint pdf of X^2 and Y^2 with the product of their marginal pdfs. If they are equal, X^2 and Y^2 are independent. Otherwise, they are dependent.

By examining the factorization of the joint pdfs and comparing them with the product of the marginal pdfs, we can determine the independence relationships between the variables X, Y, X^2, and Y^2.

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The given expression -13n^{2}+5n+23[/tex] is odd using modulo.

We are given to show that -13n2 + 5n + 23 is odd by using modulo.

Let's try to understand what modulo means:Modulo is a mathematical operation that finds the remainder when one number is divided by another. It is represented by the percentage symbol (%).

Now we can use the concept of modulo to show that -13n2 + 5n + 23 is odd.Note:An integer is odd if it is not even. In other words, odd numbers can't be divided evenly by 2. They leave a remainder of 1 when divided by 2.To show that -13n2 + 5n + 23 is odd, we need to take the given expression modulo 2.$$-13n^2 + 5n + 23 \; \mathrm{mod} \; 2$$We know that every odd integer can be written in the form of 2n + 1 where n is an integer. Now we just have to show that the expression -13n2 + 5n + 23 can be written in the form 2n + 1.$$-13n^2 + 5n + 23 \equiv 1 \; \mathrm{mod} \; 2$$Let's assume k is an integer such that $$-13n^2 + 5n + 23 = 2k + 1$$Rearranging the above expression, we get$$-13n^2 + 5n + 22 = 2k$$Now, we can use the concept of odd and even numbers. We know that an even number can be represented in the form 2n, where n is an integer. Now we just have to show that the expression -13n2 + 5n + 22 can be represented in the form 2n.$$-13n^2 + 5n + 22 = -13n^2 + 13n - 8n + 22$$$$= 13(n-1)(n-2) - 8$$We know that the product of two odd numbers is odd, and the subtraction of an even number from an odd number is odd. Here, (n-1) and (n-2) are consecutive integers, which means one of them is even and the other is odd. Therefore, the product (n-1)(n-2) is even. Hence, the above expression is odd.Since -13n2 + 5n + 23 is equivalent to 1 modulo 2, which means it can be represented in the form of 2n+1. Therefore, -13n2 + 5n + 23 is odd.

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The given recurrence relation is an = 400 - 5an-2 + 200-3, with initial values a0 = 1 and a1 = 2. We need to find an explicit formula for a(n).

To find an explicit formula for a(n), we will first solve the recurrence relation and then generalize the pattern. Let's expand the relation for a few terms to observe the pattern:

a2 = 400 - 5a0 + 200-3 = 400 - 5(1) + 200-3 = 397

a3 = 400 - 5a1 + 200-3 = 400 - 5(2) + 200-3 = 388

a4 = 400 - 5a2 + 200-3 = 400 - 5(397) + 200-3 = -9603

a5 = 400 - 5a3 + 200-3 = 400 - 5(388) + 200-3 = -1260

From the given examples, we can observe that the recurrence relation alternates between positive and negative values. This suggests that the relation might have a periodic pattern. Since the given recurrence is a second-order relation (in terms of n), it is reasonable to assume that the pattern repeats every two terms.

Based on this observation, we can establish the following explicit formula for a(n):

a(n) = (-1)^(n mod 2) * (200n - 5^(n/2) + 200-3)

In this formula, the term (-1)^(n mod 2) alternates between -1 and 1 depending on the parity of n, ensuring the alternating pattern. The other terms account for the linear and exponential components of the recurrence relation.

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Answer: should be 7819.20

explanation:

7200 * .043 * 2 = 619.20

7200 + 619.20 = 7819.20

Answer:

We meet again

Step-by-step explanation:

When a rectangle is dilated by a scale factor k, the length and width of the rectangle are both multiplied by k. In this case, the length of the rectangle is being dilated by a scale factor of 5. So the length of the rectangle after the dilation will be 20 * 5 = **100 meters**.

Answer:

21.952 [tex]yards^{3}[/tex]

Step-by-step explanation:

The volume of a cube is side length cubed.

So [tex]2.8^{3}[/tex] = 21.952

Answer: f

=  x = − 3 x + 1 = x = 1 4 g = x 2 + 2 x − 5f( x ) = f ( x )

Step-by-step explanation: