Calculate the molarity of a solution prepared by diluting 125 mL of 0.400 M K2Cr2O7 with 875 mL of water?

0.057 M is the molarity of a solution prepared by diluting 125 mL of 0.400 M [tex]K_2Cr_2O_7[/tex] with 875 mL of water.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given:

[tex]V_1[/tex] =125 mL

[tex]V_2[/tex] =875 mL

[tex]M_1[/tex] =0.400 M

[tex]M_2[/tex] =?

[tex]M_1 V_1[/tex]=[tex]M_2V_2[/tex]

0.400 M x 125 mL = [tex]M_2[/tex] x 875 mL

0.05714285714 =[tex]M_2[/tex] = 0.057 M

Hence, 0.057 M is the molarity of a solution prepared by diluting 125 mL of 0.400 M [tex]K_2Cr_2O_7[/tex] with 875 mL of water.

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