it is 20 4×5 trust me i did this for like 30 min
Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. View Available Hint(s) 2000 kg 1000 kg 500 kg 4000 kg 500 kg 1000 kg 5 m/s 10 m/s 20 m/s 5 m/s 10 m/s 20 m/s largest smallest The correct ranking cannot be determinar Submit
Since impulse is defined as a change in momentum, we may conclude that since all autos are based on magnitude, their initial momentum and ultimate momentum are the same. Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5
What is magnitude?Magnitude is a term used in physics to describe an object's maximal size and direction. Magnitude is a factor that is shared by both scalar and vector quantities. We are aware that by definition, scalar quantities are those with only magnitude. It displays an object's size, direction, or motion in absolute or relative terms. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.
How much is a magnitude?One is roughly 10 times greater than the other if two integers are separated by one order of magnitude. They differ by a factor of around 100 if they are separated by two orders of magnitude. The greater value is less than 10 times the smaller value when two numbers are of the same order of magnitude.
Briefing:Automobile-1 Mass= 2000kg = 5m/s
Automobile-2 Mass= 1000kg = 10m/s
Automobile-3 Mass= 500kg = 20m/s
Automobile-4 Mass= 4000kg = 5m/s
Automobile-5 Mass= 500kg = 10m/s
Automobile-6 Mass= 1000kg = 20m/s
Since we now understand that each car's momentum is the result of its mass and velocity, we will have
Automobile-1
P₁ = m × v
P₁ = (2000)(5)
P₁ = 2 × 10⁴kgm/s
Automobile-2
P₂ = m × v
P₂ = (1000)(10)
P₂ = 10⁴kgm/s
Automobile-3
P₃ = m × v
P₃ = (500)(20)
P₃ = 10⁴kgm/s
Automobile-4
P₄ = m × v
P₄ = (4000)(5)
P₄ = 2 × 10⁵kgm/s
Automobile-5
P₅ = m × v
P₅ = (500)(10)
P₅ = 10³kgm/s
Automobile-6
P₆ = m × v
P₆ = (1000)(20)
P₆ = 2 × 10⁵kgm/s
Then the momentum is:
Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5
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In a physics lab, Ray Zuvlite arranges two mirrors with a right angle orientation as shown. Ray then directs a laser line at one of the mirrors. The light reflects off both mirrors as shown. If angle A is 38°, determine the what is the angle measure of angles B, C, and D?
The angle measure of angle B = 25° and angle C = 65° and angle D = 25°.
What is meant by measure?Through the use of a protractor, angles are measured in degrees (°). In order to calculate or draw angles in terms of degrees, a protractor is a measuring tool that is utilized. Using a protractor, for instance, we can observe that the black arrow in the image below crosses the 90° line at 100°. Thus, the angle has a 100° measurement. A degree is a unit of measurement for a plane angle in which one complete rotation equals 360 degrees, generally indicated by the symbol °. It is included in the SI brochure as an acceptable unit even though it is not a SI unit—the radian is the SI unit of angular measure.
The given parameters are;
The orientation of the two mirrors = At right angle to each other
The laser light is directed at one of the mirror
The measure of angle, A = 25°
The measures of angle B, C, and D are found as follows;
We have;
∠A = ∠B = 25°, by angle of incidence equals angle of reflection
∠B = 25°
∠B + ∠C = 90° by sum of the acute angles of a right triangle
25° + ∠C = 90°
∴ ∠C = 90° - 25° = 65°
∠C = 65°
∠E = ∠C = 65° by angle of incidence equals angle of reflection
∴ ∠E = 65°
Line 'L' is perpendicular to the second mirror, therefore, the angle between line 'L' and the second mirror = 90° = ∠E + ∠D
∠E + ∠D = 90°, by angle sum property
Therefore;
65° + ∠D = 90°
∴ ∠D = 90° - 65° = 25°
∠D = 25°
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A 3.0 cm diameter water line splits into two 1.0 cm diameter pipes. All pipes are circular and at the same elevation.In the larger diameter section, the water speed is 2.0 and the gauge pressure is 50. What is the gauge pressure at a point in one of the narrower branches?
If all pipelines are round and of the same elevation as the question suggests, then point B's gauge pressure is 11.5 KPa.
The definition of elevationDistance above water level is known as elevation. Elevations are often expressed in feet or meters. On charts, they can be represented by contour lines that link points of the same elevation, by colours, or by numbers that indicate the precise elevations of specific places on the Planet's surface.
Briefing:From continuity equation:
Velocity of water at B = (2*pi*3²)/[2*pi*1²] =9 m/s
then from Bernoulli equation;
v² /2 + φ + p/ρ =constant
ρ=1000 kg/m³
3²/2 +φ +50000/1000 = 9²/2 +φ +P/1000
Therefore,
Pressure at B = 11.5 KPa
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The complete question is-
The 3.0 cm-diameter water line in the figure splits into two 1.0 cm-diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 2.0 m/s and the gauge pressure is 50 kPa.
What is the gauge pressure at point B?
I need help on this
A planet has a different meaning than the astronomical understanding of what a planet is. Before the advent of telescopes, the night sky was thought to consist of two very similar components. Fixed stars, which are stationary relative to each other, and moving objects ("wandering stars").
What are planets?
Planets are large, round objects that are neither stars nor remnants. The best theory of planet formation available is the nebular hypothesis, which postulates that interstellar clouds collapse from the nebula, creating young protostars orbiting the protoplanetary disk. Planets grow within this disk by the gradual accumulation of matter by gravity, a process called accretion. The solar system has at least eight planets: the terrestrial planets Mercury, Venus, Earth, and Mars, and the giant planets Jupiter, Saturn, Uranus, and Neptune. Each of these planets rotates around an axis that is tilted with respect to the poles of its orbit. All of them have atmospheres, but Mercury's is faint, and some share features such as ice caps, seasons, volcanism, hurricanes, tectonics, and even hydrology. Except, the planets in our solar system generate magnetic fields, and all planets except Venus and Mercury have natural satellites. Giant planets have planetary rings, most notably Saturn's rings.
Some cultures equate celestial bodies with gods, and these connections to mythology and folklore exist in naming schemes for newly discovered celestial bodies in the solar system. When the heliocentric theory superseded the heliocentric theory in the 16th century and his 17th century, the earth itself was recognized as a planet.
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The map below shows the path of a river. The arrow
shows the direction the river is flowing. LettersA
and B identify the banks of the river.The water depth is greater near bank A than bank B
because the water velocity near bank A isA) faster, causing deposition to occur
B) faster, causing erosion to occur
C) slower, causing deposition to occur
D) slower, causing erosion to occurAnswer: B
Different landforms are created during the process of water erosion, which flows water downhill. Rills, gullies, streams, rivers, tributaries, waterfalls, floodplains, meanders, lakes, and other natural features
What are the names of a river's beginning and end?
The source and mouth of a river are its beginning and closing, respectively. Before they get to the river's mouth, numerous rivers and streams will converge. The smaller streams and rivers are referred to as tributaries.
A river's beginning is at its mouth, correct?
The mouth of a river is where it flows into an ocean, a lake, or another river. River mouths are extremely dynamic places. The flow of a river collects material from the river, debris through bank erosion, and
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A straight, nonconducting plastic wire 9.50cm {\rm cm} long carries a charge density of 125nC/m {\rm nC/m} distributed uniformly along its length. It is lying on a horizontal tabletop.
A) Find the magnitude and direction of the electric field this wire produces at a point 5.50 {\rm cm} directly above its midpoint.
B) If the wire is now bent into a circle lying flat on the table, find the magnitude and direction of the electric field it produces at a point 5.50cm {\rm cm} directly above its center.
Part A. The midway magnitude of the electric field is 17.2 * 10³ N/C.
Part B. The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.
The intensity of an Electric Field
Given this, the wire length is 9.50 cm and the charge density is 125 nC/m.
Part A
The electric field at the wires halfway is
E = q/4πε * 1/ (z(z²/a²+1)¹/²)
Where E is the intensity of the electric field, 8.85*10⁻¹² is the permittivity, z is 5.5 cm, a is the midpoint, 9.5/2 cm, and q is the charge density.
Substituting the value in the above equation
E = 17.2 * 10³N/C
The midway magnitude of the electric field is 17.2 * 10³ N/C
Part B
When the wire is a circle then, the charge density at the wire is
Q = q*l
Q= 1.235 * 10⁻⁸ * 0.095
Q = 1.235*10⁻⁸ C
And to calculate the radius
r = l/2π
r = 9.50/ 2*3.14
r = 1.512cm
r = 0.015m
The electric field density at the midpoint of the circle is,
E = Q/4π * z(z²+r²)¹/² * E
Substituting the values in the above equation, we get
E = 47.17 * 10³ N/C
The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.
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Based on current evidence, decide whether each of the following statements apply to the concept of dark matter, dark energy, both, or neither. Drag each statement into the appropriate bin.
Dark Matter Only:
as mass.
most common form of mass in the halo of the Milky Way Galaxy.
detected through its gravitational attraction.
likely to consist of tiny, weakly interacting particles.
Dark Energy Only:
inferred to exist from the measured acceleration of the universe's expansion.
the proposed source of a universal repulsive force.
Both Dark Matter and Dark Energy:
the universe contains more of this than it contains matter made from atoms.
we do not know what it is made of.
Neither Dark Matter nor Dark Energy
blocks light from stars behind it.
"dark" because it emits only infrared light.
The concept that the information applies to is illustrated below:
Dark matter:
Detected through its gravitational attraction
Has mass
Most common forms of mass in the halo of the Milky way galaxy, likely to consist of subatomic particles.
Dark energy:
Inferred to exist from the measured acceleration of the universe's expansion.
The proposed source of a universal repulsive force.
Dark matter and dark energy:
The universe contains more of this than it contains matter made from atoms.
We do not know what it is made of.
Neither:
Blocks light from stars behind it, 'dark' because it emits only infrared light.
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a force of 300N is applied to a 1500kg car at rest. a)what is its acceleration. b)what will its velocity be 5secs later
The acceleration will be 0.2m/s^2 while the velocity will be 1m/s
Acceleration and VelocityGiven DataForce = 300N
Mass = 1500kg
Time = 5 seconds
We know that
Force = ma
a = F/m
a = 300/1500
a = 0.2 m/s^2
Also, the expression for Velocity is given as
Ft = mv
300*5 = 1500*v
Making velocity the subject of the formula we have
1500 = 1500*v
v = 1 m/s
The rate of change of an object's velocity with respect to time is defined as acceleration.
Acceleration implies that the speed is changing, but this is not always the case. When an object moves in a circular path at a constant speed, it is still accelerating because its velocity direction changes.
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Two physical science classes are playing tug of war. Mrs. Hankinson’s class pulls left with a force of 100 N, while Mrs. Wade’s class pulls with a force of 105 N in the opposite direction.
What is the net force, and which class won?
A. 205 N, Mrs. Wade's class
B. 5 N, Mrs. Wade's class
C. 205 N, it was a tie
D. 5 N, Mrs. Hankinson's class
The net force is 5 N and the class that won is Mrs. Wade's class (Option B)
How do I determine the net force?We can obtain the net force by using the following formula:
Net force = Opposite force - force of pull
Now, we shall determine the net force as illustrated below:
Force by Mrs. Hankinson’s class = 100 NForce by Mrs. Wade’s class = 105 NNet force =?Net force = Opposite force - force of pull
Net force = Mrs. Wade’s class - Mrs. Hankinson’s class
Net force = 105 - 100
Net force = 5 N
From the above calculation, we can say that the net force is 5 N and the class that won given the above data is Mrs. Wade’s class
Therefore, the correct answer to the question is:
5 N, Mrs. Wade's class (Option B)
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establish the relation among energy, density, strain and stress
Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation.
When water flows from section 1 at upstream to section 2 at downstream in an open channel, the water depth decreases by a factor of 2
The answer to the question is 5.66 feet for the channel's diameter after 2 if it is 12 feet wide at 1.
What makes upstream and downstream different?Simply expressed, upstream activities comprise the discovery and production of petroleum and natural gas, whereas downstream activities relate to the procedures used from the extraction phase until the product is given to the client in the desired shape.
Briefing:[tex]$$\begin{aligned}& F r_1=\frac{V_1}{\sqrt{g V_1}}=0.5 \text {, or } \sqrt{g Y_1}=2.0 V_1 \\& \text { and } \\& F_{r_2}=\frac{V_2}{\sqrt{g y_2}}=3.0 \text { where } y_2=0.5 y_1 \\& \text { Thus, } \frac{V_2}{\sqrt{0.5 g Y_1}}=3.0 \text {, or } \sqrt{g y_1}=V_2 /(3 \sqrt{0.5}) \\& \text { By equating Eq. (1) and }(2) ; 2.0 V_1=V_2 /(3 \sqrt{0.5}) \\& \text { or } \\& V_2=4.24 V_1\end{aligned}$$[/tex]
However,
[tex]$Q_1=Q_2$[/tex] or [tex]$b_1 y_1 V_1=b_2 y_2 V_2$[/tex]
where [tex]$b=$[/tex] channel width. Thus, with [tex]$b_1=12 \mathrm{ft}$[/tex]
(12ft)y₁(V₁) = b₂(0.5y₁)(4.24V₁) or b₂ = 12ft/0.5(4.24) = 5.66ft
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The complete question is-
In flowing from section 1 to section 2 along an open channel, the water depth decreases by a factor of 2 and the Froude number changes from a subcritical value of 0.5 to a supercritical value of 3.0. Determine the channel width at 2 if it is 12 ft. wide at 1.
If it requires 9 J of work to stretch a spring by 2 cm from its equilibrium length, how much more work will be required to stretch it an additional 4 cm
A spring will therefore need 72 J of work to stretch an additional 4 cm from its equilibrium length if it takes 9 J to stretch it that far.
What is equilibrium length?The length of a multi-mode optical fiber required to achieve a static mode distribution from a particular excitation condition is known as the equilibrium length, and it is sometimes used to characterize stationary mode distributions. There is a location where the weight and spring force are equal in magnitude but in the opposite direction. The equilibrium position is where you are at this moment. There is a net force known as the restoring force that is directed toward the equilibrium position if the mass is in any other position.
How do you find the equilibrium length of a spring?F = -kx. The proportional constant k is referred to as the "spring constant". It gauges the stiffness of the spring. When a spring is stretched or compressed to a length that differs by an amount equal to or greater than x, it produces a force F = -kx in the direction of its equilibrium position. From its equilibrium length.
Briefing:Knowing that the results of the work done to lengthen the springs will be reported as
U=1/2kx
so here we have
9= 1/2 k〖(0.02)〗^2
so we have
K=45000N/m
Now, we must locate the work completed to extend the spring from x = 2 cm to x = 4 cm
here we have
U=1/2 k(x 2/1-x 2/2
now we have
U=1/2(45000)(〖0.06)〗^2-〖0.02〗^2)
U= 72J
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Marvin is moving furniture in his house , including the 52.8 kg dresser. he is applying a force of 90 N to the left to overcome 24 N of friction to accelerate the dresser.
1. What is the horizontal acceleration of the dresser?(value only, round to two decimal places, no units, or direction. example: 97.50)
Answer: 3.81 m/s^2.
Explanation: use the equation for acceleration, which is a = (F - f)/m. In this case, we are given the force applied by Marvin (F), the force of friction (f), and the mass of the dresser (m). Plugging in the given values, we get a = (90 N - 24 N)/(52.8 kg) = 3.81 m/s^2.
Given that Shapley calculated the size of the Milky Way based on the stars' apparent brightness, how did not including the effects of gas and dust affect Shapley's calculation?
A. The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too small.
B. The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.
C. The distance calculated to each globular cluster was too small, and thus his size for the Milky Way was too large.
D. The distance calculated to each globular cluster was too small, and thus his size for the Milky Way was too small.Answer:B. The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.
The correct option is, The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.
What main conclusion did Shapley draw from his measurements of the distances to the globular clusters?
Shapley concluded (and other astronomers have since verified) that the center of the distribution of globular clusters is the center of the Milky Way as well, so our galaxy looks like a flat disk of stars embedded in a spherical cloud, or 'halo,' of globular clusters.
How did Shapley estimate the location of the Sun in the Milky Way?
Harlow Shapley determined the position of the Sun in the galaxy by measuring the distances to 93 globular clusters of stars.
What is a globular star cluster?
Globular clusters are stable, tightly bound clusters of tens of thousands to millions of stars. They are associated with all types of galaxies. Globular clusters are typically much larger than open clusters and are tightly gravitationally bound.
What are the characteristics of the stars in globular clusters?
Globular clusters are densely packed collections of ancient stars. Roughly spherical in shape, they contain hundreds of thousands, and sometimes millions, of stars. Studying them helps astronomers estimate the age of the universe or figure out where the center of a galaxy lies.
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Help please!
How can you differentiate someone who has quality hypnosis training and someone who does not?
The Hypnotic Induction Profile (HIP) or the eye roll test, first proposed by Herbert Spiegel, is a simple test to loosely determine if a person is susceptible to hypnosis. A person is asked to roll their eyes upward. The degree to which the iris and cornea are seen is measured.
What is Hypnotic Induction Profile (HIP)?The Hypnotic Induction Profile (HIP) was created as a quick yet comprehensive evaluation of a person's trait hypnotizability and capacity to enter a hypnotic state.An invitation to enter hypnosis is known as a hypnotic induction, and it usually includes instructions and recommendations to make the subject more receptive to hypnosis. Instructions for relaxation are frequently included in the hypnotic induction, but while nice, they are not always necessary.Do I Have a Receptive Mind? Highly hypnotizable individuals frequently have vivid imaginations and can visualize objects clearly in their minds' eye.When they are reading or watching a movie they enjoy, they frequently lose track of time.To learn more about Hypnotic Induction Profile (HIP) refer to:
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1. David Purley, a racing driver, survived deceleration from 173 km/h (about 107
mph) to 0 km/h over a distance of 0.660 m when his car crashed. Assume that
Purley's mass is 70.0 kg. What is the average force acting on him during the
crash? Compare this force to Purley's weight.
Average force acting on Purley is -1749m/[tex]s^{2}[/tex].
What is Newton's second law of motion?
According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.
Given,
According to newton's second law of motion:
F =ma
Purley's initial speed = 173km/h
Final speed = 0
Distance traveled = 0.66 m
So, [tex]v_{i}[/tex] = 172 km/h × 1 hr/3600 s × 1000m/1km
[tex]v_{i}[/tex] = 48.1 m/s
By using kinematics
[tex]v^{2} f[/tex] = [tex]v^{2} i[/tex] + 2ad
[tex]0^{2}[/tex] = 48.[tex]1^{2}[/tex] + 2a(0.66)
-1.32a = 2309
a= -1749 m/[tex]s^{2}[/tex]
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