X =
(19) Find the values for X and Y, and then solve for the side lengths.

Answer:

All of the following are answers:

B) It has a slope of 2

C) It goes through the origin

D) It is a straight line

Step-by-step explanation:

trust me

Answer:

2ax−2ay−2x2−2xy+2a+4x+2y

Step-by-step explanation:

Let's simplify step-by-step.

(x+y)(2)−2(x+y)(a+x)+(a+x)(2)

Distribute:

=(x)(2)+(y)(2)+−2ax+−2ay+−2x2+−2xy+(a)(2)+(x)(2)

=2x+2y+−2ax+−2ay+−2x2+−2xy+2a+2x

Combine Like Terms:

=2x+2y+−2ax+−2ay+−2x2+−2xy+2a+2x

=(−2ax)+(−2ay)+(−2x2)+(−2xy)+(2a)+(2x+2x)+(2y)

=−2ax+−2ay+−2x2+−2xy+2a+4x+2y

Answer:

=−2ax−2ay−2x2−2xy+2a+4x+2y

Answer:

{-12,0}

Step-by-step explanation:

first to solve this can collect like terms and add

X² +12x=0

and solve it by factorization method

X² +12x=0

x(x+12)=0

it means x multiplied by x = X² then x multiplied by 12 = 12x

so this means x or (x+12) equals to zero

x=0 and (x+12)=0

x+12=0

x=-12

so the solution set is {-12,0}

but can also be done by formula method

Answer:

y = 32.

Step-by-step explanation:

y = k/x^2    where k is the constant of variation

When y = 50 x = 4, so

50 = k / (4)^2

f = 50 * 4^2 = 800.

So the relation is

y = 800/x^2

When x = 5

y = 800/5^2

  =  32.

The equivalent expressions of 2n + (8 + 32)are 2n + 40 and 2(n + 20)

The expression is given as:

2n + (8 + 32)

The first equivalent expression

Evaluate the sum of the numbers in the bracket

2n + (8 + 32) = 2n + 40

This means that 2n + 40 and 2n + (8 + 32) are equivalent.

The second equivalent expression

In (a), we have:

2n + (8 + 32) = 2n + 40

Factor out 2 from the expression

2n + (8 + 32) = 2(n + 20)

This means that 2(n + 20) and 2n + (8 + 32) are equivalent.

Hence, the equivalent expressions are 2n + 40 and 2(n + 20)

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Answer:

Width = 2

Length = 5

Step-by-step explanation:

let A be the area of the rectangle

   L be the length of the rectangle

   w be the width of the rectangle

Formula: ‘area of a rectangle’

A = L × w

…………………………………………………

A = L × w

⇔ 10 = (w + 3) × w

⇔ 10 = w² + 3w

⇔ w² + 3w - 10 = 0  

Solving the quadratic equation w² + 3w - 10 =  0 :

Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49

then √Δ = 7

[tex]\Longrightarrow w=\frac{-b+\sqrt{\Delta } }{2a} =\frac{-3+7}{2} =2[/tex]

  [tex]or\ w=\frac{-b-\sqrt{\Delta } }{2a} =\frac{-3-7}{2} =-5[/tex]

-5 is not valid ,because w represents the width

which must be a positive number

Then  w = 2

Conclusion:

Width = 2

Length = 2 + 3 = 5

Answer:

$10955.6157151671

Step-by-step explanation:

Amount [A] = [tex]P(1+r)^{t}[/tex]

Here, P = principal (which is $5000)

r = rate of interest in decimal form(which is 0.04)

t = time in years (which is 20)

Substituting,

[tex]$5000(1+0.04)^{20}[/tex] = $10955.6157151671

Using the combination formula, it is found that there are 47,040 ways to form a soccer team.

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

[tex]^mC_k = \dfrac{m!}{k! \times (m-k)!}[/tex]

A soccer team consisting of 3 forwards, 4 midfield players, and 3 defensive players, if the players are chosen from 8 forwards, 6 midfield players and 8 defensive players

Since they are independent of each other, the total number of combinations will be;

[tex]^mC_k = \dfrac{8!}{3! \times (5)!} \times \dfrac{6!}{4! \times (2)!} \times \dfrac{8!}{3! \times (5)!} \\\\^mC_k =47,040[/tex]

Hence, There are 47,040 ways to form a soccer team.

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Answer:

19 cents or 0.199

Step-by-step explanation:

Hope it helped!

Answer:

19 cents

Step-by-step explanation:

divide total cost by amount of items

Answer:

50% to pull either a black or pink marble.

Step-by-step explanation:

The reason for this is due to the fact you have an equal amount of marbles of 2 different colors, so the chance of pulling one marble is not over another unless you remove say 1 pink marble, therefore the black marbles would have a higher percentage of being pulled instead of pink.

Answer:

1 is answer

Step-by-step explanation:

2*3/5*3___6/5

Im going to assume that you want the area of a circle.

We already have radius, which is the only variable that we need, now we just have to plug it into the area for the circle:

π(28²)

Multiplying this, you get 2461.76 cm³

Because of the vertical asymptote and the change in concavity, we conclude that the correct option is B.

Remember that cot(x) = 1/tan(x).

Then we can rewrite:

cot(x) = cos(x)/sin(x).

We know that for x = 0, we have:

cot(0) = cos(0)/sin(0) = 1/0

Then we have a vertical asymptote that tends to ± infinity.

The only graph that meets this condition is the second and the third one, and by the curvature (we need to have a change of concavity/convexity) in the tangent function.

From that, we conclude that the correct option is B.

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Answer:

I feel that is would be D

Step-by-step explanation:

This is the most reasonable awnser.

Answer:

1,120 cm³

Step-by-step explanation:

Hello!

Think about it this way: There is a rectangular prism, with lengths of 20cm, 12cm, and 10cm, and another rectangular prism cut out of it with lengths, of 8cm, 8cm, and 20cm.

Volume = L * W * H

V = L * W * H

Subtract:

The total volume is 1,120cm³

#1

Length in cm

Total length

#2

Total notes

Total money

|

Total suits per month=120

per year

#4

Total 5mins

total distance

Answer: 8

Step-by-step explanation:

Using the formula [tex]A=\frac{1}{2}bh[/tex],

[tex]A=\frac{1}{2}(8)(2)=\boxed{8}[/tex]

Answer: 27

Step-by-step explanation:

Use PEMDAS (Parenthesis,Exponents,Multiplication,Division,Addition,Subtraction)

to solve this problem. First multiply 5 times 4 to get 20. Then divide 14 by 2 to get 7. Lastly, add those two answers to get 27 as the final answer.

Answer:

  yes, it can be of odd degree

Step-by-step explanation:

The local maxima and minima correspond to zeros in the derivative of the function. The degree of the polynomial will be 1 more than some multiple of 2 greater than the number of zeros in the derivative.

__

For 2 each of local maxima and minima, the derivative will have 2+2 = 4 real zeros. The degree of the polynomial will be 1 greater, hence of degree 5 (or more). The polynomial must be of odd degree.

__

The local extrema must alternate: a maximum must be followed by a minimum, or vice versa. When there are an even number of each kind, the end extrema will be of opposite kinds. The end behavior of the function will be upward from a minimum and downward from a maximum. Hence the end behaviors must be in opposite directions--characteristic of an odd-degree polynomial.

The polynomial must be of odd degree.

_____

Additional comment

A polynomial with real coefficients will have an even number of complex roots. The complex roots of the derivative of a polynomial have no effect on the number or kind of extrema.

__

Attached is an example of a polynomial with 2 maxima and 2 minima. It is of 5th degree.

Answer:

a)b= 5

b)45

Step-by-step explanation:

a) 5 times ten is 50 . the two factors of 50 are 25 and 2. The square root of 25 is 5, so that's the answer.

b) 27 × 75 is 2025 and the base root is 45², then with the radical and exponent we reduce the index by 2 to get 45.

[tex]\textbf{a)}\\\\~~~\sqrt 5 \times \sqrt{10}\\\\=\sqrt{5} \times \sqrt{5 \times 2}\\\\=\sqrt{5} \times \sqrt 5 \times \sqrt 2\\\\=\left(\sqrt 5 \right)^2 \times \sqrt 2\\\\=5\sqrt 2\\\\\text{It is now in a form of} ~ b\sqrt2 ~ \text{where} ~b = 5.\\\\\\[/tex]

[tex]\textbf{b)}\\\\~~~\sqrt{27} \times \sqrt{75}\\\\=\sqrt{9 \times 3} \times \sqrt{25 \times 3}\\\\=\sqrt 9 \times \sqrt 3 \times \sqrt{25} \times \sqrt 3\\\\=3\times 5 \times \left(\sqrt 3 \right)^2\\\\=15 \times 3\\\\=45[/tex]

Using trigonometric ratios, the measure of side n to one decimal is 6.6 units.

Using the trigonometric principle

SOHCAHTOA,

cos 20 = adjacent / hypotenuse

adjacent side = n

hypotenuse side = 7

Therefore,

cos 20° = n / 7

cross multiply

n = 7 cos 20°

n = 7 × 0.93969262078

n = 6.5778483455

n = 6.6 units

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This function shows a horizontal translation of the parent function to the left and 2 units up.

The parent function of a square root function is expressed as:

f(x) = √x

According to the question, we are to plot the expression f(x) = √x+ 3 - 2

This function shows a horizontal translation of the parent function to the left and 2 units up. The required graph will be in the 2nd quadrant of the graph as shown;

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Answer:

It should be the first one.

Work Shown:

A = area of the rectangle

A = length*width

A = 26*15

A = 390 square feet

B = area of the triangle

B = base*height/2

B = 8*9/2

B = 72/2

B = 36 square feet

C = total area

C = A+B

C = 390+36

C = 426 square feet

Answer: 134°

Step-by-step explanation:

Since angle ABC is equal to 75, we know that the arc in front of it (arc AC) is 150. We then start to add all the know arc angle measures together. So, our equation to finding arc BEC 360-150+76= BEC arc.

Answer:

134

Step-by-step explanation:

cause yeah

[tex]\text{According to the factor theorem,}\\\\x-a~ \text{is a factor of}~ f(x)~ \text{if}~ f(a) = 0, ~ \text{where}~ a \in\mathbb{R}\\\\\text{Given that,}\\ \\P(x) = x^7 -5x^5 +2x^4 -x^2 +9\\\\P(6) = 6^7 -5\cdot 6^7 +2 \cdot 6^4 -6^2 +9 = 243621 \neq 0\\\\\text{Since} ~ P(6)\neq 0~, ~ x -6 ~ \text{is not a factor of P(x).}[/tex]

Answer:

1) p ≥ -6

2) p ≤ -38/5

Step-by-step explanation:

3p + 4 ≥ -14

Subtract 4 to both sides

3p ≥ -14 - 4

3p ≥ -18

Divide 3 to both sides

p ≥ -18/3

p ≥ -6

[tex]\rule[225]{225}{2}[/tex]

1 - 5p ≥ 39

Subtract 1 to both sides

-5p ≥ 39 - 1

-5p ≥ 38

Divide -5 to both sides

p ≤ -38/5

[tex]\rule[225]{225}{2}[/tex]

Answer:

the prime numbers between 30 and 40 are 31 and 37 come on its so easy

Given the following formula, w=x-y/2 -z. The value of y is y = x - 2w + wz .

Usually, simplification involves proceeding with the pending operations in the expression.

Like, 5 + 2 is an expression whose simplified form can be obtained by doing the pending addition, which results in 7 as its simplified form.

Simplification usually involves making the expression simple and easy to use later.

Given the following formula,

w=x-y/2 -z

We need to solve for y.

[tex]w = \dfrac{x-y}{2 -z}[/tex]

By cross multiplication

[tex]w\times (2 -z)= {x-y}\\\\2w - wz = x - y[/tex]

subtract x both side

2w - wz -x = x - y -x

y = x - 2w + wz

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Answer:

zero

Step-by-step explanation:

pemdas