Write the following ratios in their simplest form.
27:30

Using the symbols in the Venn diagram, we want to find A given that

B = 16

C = 15

D = 30

and given that 25 students don't take any of these courses.

There are 200 students total, so we need to have A plus the total number of students given in the diagram sum to 200. This means

(math only) + (English only) + (biology only) + (math and English, no biology) + (math and biology, no English) + (English and biology, no math) + (all three) + (none of the three) = 200

or

12 + 11 + 16 + 30 + A + 16 + 15 + 25 = 200

Solve for A to get A = 75, making the answer C.

Answer:

5/12

Step-by-step explanation:

im finding answers for hegarty maths and i got it wrong and it said 5/12 was the answers

thank me later

Answer:

2/36

Step-by-step explanation:

i found it on another website

Answer:

Step-by-step explanation:

y = 10/4 x

y = 2.5 x

Answer:

No Solution.

X cannot equal anything in order for these to be equal.

Step-by-step explanation:

Answer:

Any constant that is set to equal x would have an undefined slope.  For example, x=0 is just a horizontal line, so the slope is undefined.  

Step-by-step explanation:

The slope would be undefined because in a horizontal line, the length could be anything, but there is no distance between x-values.

Answer:

X=0

Step-by-step explanation:

The required value is [tex]\csc A=\dfrac{5}{4}[/tex].

Important information:

We need to find the exact value of csc A.

Formulae used: If angle A is in Quadrant I.

[tex]\cos A=\dfrac{1}{\sec A}[/tex]

[tex]\sin A=\sqrt{1-\cos^2 A}[/tex]

[tex]\csc A=\dfrac{1}{\sin A}[/tex]

Using these formulae, we get

[tex]\cos A=\dfrac{3}{5}[/tex]

And,

[tex]\sin A=\sqrt{1-\left(\dfrac{3}{5}\right)^2}[/tex]

[tex]\sin A=\sqrt{1-\dfrac{9}{25}}[/tex]

[tex]\sin A=\sqrt{\dfrac{16}{25}}[/tex]

[tex]\sin A=\dfrac{4}{5}[/tex]

Now,

[tex]\csc A=\dfrac{1}{\sin A}[/tex]

[tex]\csc A=\dfrac{1}{\frac{4}{5}}[/tex]

[tex]\csc A=\dfrac{5}{4}[/tex]

Thus, the required value is [tex]\csc A=\dfrac{5}{4}[/tex].

Find out more about 'Trigonometric Ratios' here:

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The required value of cscA is 1.25

Given,

[tex]secA=\frac{5}{3}[/tex]

Trigonometrical ratios:

In the first quadrant, all ratios are positives.

[tex]sin A=\frac{P}{H}[/tex]

And the value of hypotenuse is,

[tex]P=\sqrt{H^2-B^2} \\=\sqrt{5^2-3^2} \\=\sqrt{16}\\ P=4[/tex]

So, the sine A is,

[tex]sinA=\frac{P}{H}\\ =\frac{4}{5}[/tex]

So, the rational denominator is,

[tex]cscA=\frac{H}{P}\\ =\frac{5}{4}\\=1.25[/tex]

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Answer:

Step-by-step explanation:

Dimensions of the diagram:

Nadia is correct as the diagram of 27 cm × 20 cm will fit in A4 paper

The equation that represents the amount in dollars that she must pay for using the parking lot that month is y = 2x +10, the correct option is B.

An equation is a mathematical statement formed when two algebraic expressions are equated using an equal sign.

The equations are useful in determination of unknown parameters.

The equations are of various types, such as Trigonometric equations, quadratic equations.

The amount Tanesha pays to use the parking lot is $10

The daily amount she pays to use the parking is $2

Let x represents the days in one month.

Let y represents the amount in dollars that she must pay for using the parking lot that month.

The unknown parameters are x and y

The equation that can be formed is

y = 2x +10

It seems that your question is incomplete, the complete question is as follows:

A .  y = 2x

B. y = 2x +10

C. y = 10x +2

D. y = 10x

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Answer: a p e x 2, 15, 29.5, 41, 52

Step-by-step explanation:

Answer: 217 :D I think I did mental math so I might be wrong

Step-by-step explanation:

Answer:

21 (not even joking)

Explanation:

4/6 = .6 repeating

.6 x 32 = 21.3 which rounds to 21

Answer:

[tex]\mathbf{((lnx)(2x^2)) -x^2 +39 =(2y^2 +(\dfrac{4}{3})(8+y^2)^{3/2})}[/tex]

Step-by-step explanation:

Given that:

[tex]x In(x) = y( 1+ \sqrt{8+ y^2}) \ } \ \dfrac{dy}{dx}[/tex]

[tex]xln(x) *dx= (y+y \sqrt{(8+y^2}) \ dy[/tex]

[tex]\int xln(x) dx = \int(y+y\sqrt{(8+y^2})) \ dy[/tex]

[tex]\int lnx (x)dx =(\dfrac{y^2}{2} +\dfrac{1}{3}(8+y^2^{)3/2})[/tex]

[tex](lnx \dfrac{x^2}{2})-\int((\dfrac{x^2}{2})\times \dfrac{1}{x} =(\dfrac{y^2}{2} +\dfrac{1}{3}(8+y^2)^{3/2})[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-\int(\dfrac{x}{2}) =(\dfrac{y^2}{2} +(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-(\dfrac{x^2}{4}) +C= (\dfrac{y^2}{2 }+(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

For  y(1) = 1

[tex]((ln(1))(\dfrac{1^2}{2}))-(\dfrac{1^2}{4}) +C= (\dfrac{1^2}{2 }+(\dfrac{1}{3})(8+1^2)^{3/2})[/tex]

[tex](0)-(\dfrac{1}{4}) +C =(\dfrac{1}{2} +(\dfrac{1}{3})(3)^3)[/tex]

[tex]C=(\dfrac{19}{2}) +(\dfrac{1}{4})[/tex]

[tex]C=\dfrac{39}{4}[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-(\dfrac{x^2}{4}) +(\dfrac{39}{4}) = (\dfrac{y^2}{2} +(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

[tex]\mathbf{((lnx)(2x^2)) -x^2 +39 =(2y^2 +(\dfrac{4}{3})(8+y^2)^{3/2})}[/tex]

Answer:

C multiply by 3, then subtract 5      

B

C m<7

Step-by-step explanation:

Answer: 2.5

Step-by-step explanation:

For this problem, we see that 4km is 1/2 of 8km.

So, we will have to find 1/2 of 5km.

1/2 of 5km = 2.5km

Your answer is 2.5km

Answer:

2.48548 Miles or simplified 2.5

Step-by-step explanation:

You Divide by 1.609 to find the answer.  

Answer:

y = 4 x - 7

The slope is the number multiplied by x, 4

Step-by-step explanation:

;-;

Answer:

The answer is C

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

Its BELOW sea level

Step-by-step explanation:

31.286 i think that its 31.286 bc welp me smart

Answer:

the is option d cause big number is divided by small ones.

Step-by-step explanation:

hope it's right

Answer:

8 thats how many pies and cakes you can do

Step-by-step explanation:

you have 20 minutes and 10 and the most cakes you can get with left over is 8

The pies and cakes should be made to maximize profits is 8 pies.

Profit is defined as the sum of revenue and income after all costs have been deducted by a business. A function with a business-oriented focus is called a profit function. The main goal of a business is to generate income through the sale of goods and services, minus the costs associated with producing those goods and services, in order to turn a profit.

Revenue minus costs equals profit.

Costs comprise both variable costs and fixed costs, whereas revenue is the total amount of positive cash flow that a business generates.

The maximum number of cakes you can get with leftovers in 20 minutes and 10 is 8.

Thus, the pies and cakes should be made to maximize profits is 8 pies.

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Answer:

i  need points

Step-by-step explanation:

i need points ,, hope you find your answer

Answer:

11

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

Answer:

ok? if the question is how many words does he type in a minute the answer is 72

Step-by-step explanation:

Answer:

72 is right i check

Step-by-step explanation:

he/she comment the same so it was there idea

Less than = <

Quotient= Division

4 divided by X(unknown) will be LESS than -1

Answer---> X divided by 4 < -1

Answer:

3/5

First you would need to find the greatest common factor of 15 and 25

which is 5

Then divide the numerator and denominator by the GCF

15 divided by 5

25 divided by 5

Then simplify your answer is

3/5

Answer:

$66.15

Step-by-step explanation:

(9.95x2)+(6.75x3)+26=66.15

Answer:

The Answer is 66.15 By the person above

Answer:

X = 9

Step-by-step explanation:

Answer:

x = 9

Step-by-step explanation:

Move all terms that don't contain x to the right side and solve.

Answer:

[tex]F' = (-3,-3)[/tex]

[tex]G' = (-3,3)[/tex]

[tex]H' = (6,-3)[/tex]

Step-by-step explanation:

Given

The attached graph

[tex]Scale\ Factor = 1\frac{1}{2}[/tex]

Required

Determine the coordinates of F'G'H'

First, we need to get the coordinate of F, G and H from the graph

[tex]F = (-2,-2)[/tex]

[tex]G = (-2,2)[/tex]

[tex]H = (4,-2)[/tex]

The dilated coordinate is then calculated as:

[tex](FGH)' = (FGH) * Scale\ Factor[/tex]

This gives:

[tex]F' = (-2,-2) * 1\frac{1}{2}[/tex]

[tex]F' = (-2* 1\frac{1}{2},-2* 1\frac{1}{2})[/tex]

[tex]F' = (-3,-3)[/tex]

[tex]G' = (-2,2) * 1\frac{1}{2}[/tex]

[tex]G' = (-2 * 1\frac{1}{2},2 * 1\frac{1}{2})[/tex]

[tex]G' = (-3,3)[/tex]

[tex]H' = (4,-2) * 1\frac{1}{2}[/tex]

[tex]H' = (4 * 1\frac{1}{2},-2 * 1\frac{1}{2})[/tex]

[tex]H' = (6,-3)[/tex]