Write a program in QBASIC that asks radius of a circle to calculate its area and circumference. Create a user-defined function to calculate area and sub-program to calculate circumference. [HINTA = T C = 2nr]​

The output file will be program will be FindPatientRecords:

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.IO;

namespace Patients

{

 class Red

 {

   static void Main (string[]args)

   {

     int aacounter = 0;

     string aaline, aapatient_id;

     int aaflag = 0;

       Console.WriteLine ("Enter Patient ID"); //

       aapatient_id = Console.ReadLine (); //

Adding the file name ion the program:

     StreamReader aafile = new StreamReader ("Patients.txt,"); /

Adding the loop:

     while ((aaline = aafile.ReadLine ()) != null) //

{

  string[]aast = aaline.Split (','); //

Adding the patient id;

  if (aast[0].Equals (aapatient_id) == true) //Here this can be defined as if it is found

    {

      Console.WriteLine ("Patient ID :{0}\nPatient Name :{1}\nBalance:{2}",

     aapatient_id, aast[1], aast[2]);

      aaflag = 1;

      break;

    }

  aacounter++;

}

     if (aaflag == 0)

{

  Console.WriteLine ("Record not Found");

}

     aafile.Close ();

     System.Console.ReadLine ();

   }

 }

}

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Answer: Social Media

Explanation: The question is a bit vauge, so I am going under the assumption that we are talking about present tense. Over the years, social media has become one of the largest sources of entertainment and news.

The utilization of Microsoft word can bring advantages to both educators and learners in developing fresh and creative approaches to education.

Microsoft 365 is crafted to assist you in achieving your dreams and managing your enterprise. Microsoft 365 is not just limited to popular applications such as Word, Excel, and PowerPoint.

Therefore, It merges high-performing productivity apps with exceptional cloud services, device oversight, and sophisticated security measures, providing a united and streamlined experience.

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For later film composers, musical themes would often be placed in the soundtrack, where they would become essential parts of the memorable package that audiences would take home from the theater.

Film soundtracks play a crucial role in enhancing the overall movie experience by evoking emotions and creating memorable moments.

By associating specific themes with characters or situations, composers can reinforce the narrative and create an emotional connection with the audience.

These memorable themes often become synonymous with the film and are easily recalled, even long after leaving the theater.

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For later film composers, musical themes would often be placed in the soundtrack, where they would become essential parts of the memorable package that audiences would take home from the theater.

Film soundtracks play a crucial role in enhancing the overall movie experience by evoking emotions and creating memorable moments.

By associating specific themes with characters or situations, composers can reinforce the narrative and create an emotional connection with the audience.

These memorable themes often become synonymous with the film and are easily recalled, even long after leaving the theater.

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Answer:

The data disaster recovery plan for our small copy shop involves identifying potential data loss scenarios such as hardware failures, natural disasters, and cyber attacks. We will regularly backup all data to an off-site location and test the restoration process. We will also implement data encryption and invest in security software to protect against cyber threats. Additionally, we will train our employees on how to identify and respond to potential data loss situations to minimize the impact on our business. By implementing these measures, we can ensure business continuity and protect our customer's sensitive information.

Answer:

import random

# Generate a list of 10000 random numbers between 1 and 100

random_list = [random.randint(1, 100) for i in range(10000)]

# Find the indexes where the number 89 appears in the list

indexes = [i for i in range(len(random_list)) if random_list[i] == 89]

# Print the indexes

print("The number 89 appears at the following indexes:")

print(indexes)

Explanation:

This code uses a list comprehension to generate the list of random numbers and another list comprehension to find the indexes where the number 89 appears. The range(len(random_list)) function generates a sequence of integers from 0 to the length of the list minus 1, which are used as indexes to access the elements of the list. The if condition checks whether the element at the current index is equal to 89, and if so, the index is added to the indexes list. Finally, the print statement displays the list of indexes where the number 89 appears.

Answer:

17. A Variable Length Subnet Mask (VLSM) is a technique used to allocate IP addresses to subnets of different sizes. It allows for more efficient use of IP address space by creating subnets with different sizes, rather than using a fixed subnet mask. VLSM is created by dividing the network into smaller subnets with different subnet masks, depending on the number of hosts required in each subnet.

18. There are several reasons to use VLANs, including:

Security: VLANs can be used to isolate traffic and prevent unauthorized access to sensitive data.

Performance: VLANs can be used to segment traffic and reduce network congestion, improving performance

Management: VLANs can simplify network management by grouping devices with similar functions or requirements

Flexibility: VLANs can be used to easily move devices between physical locations without changing their IP addresses

Explanation:

Tthe area of the brake piston is given as  16.59 cm².

The formula is :

force applied to master cylinder / area of master cylinder = force exerted by brake piston / area of brake piston

Substituting the given values, we get:

128 N / 6.54 cm² = 325 N / area of brake piston

Solving for the area of brake piston, we get:

area of brake piston = (325 N x 6.54 cm²) / 128 N

area of brake piston = 16.59 cm² (rounded to two decimal places)

Therefore, the area of the brake piston is 16.59 cm².

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Answer:

// C++ Program to Multiply Two Numbers Using Function

#include <iostream>

using namespace std;

// Function declaration

int Multiply(int x, int y);

int main(){

   int num1, num2, product;

   // Taking input from the user

   cout << "Enter the first number: ";

   cin >> num1;

   cout << "Enter the second number: ";

   cin >> num2;

   // Calling out user-defined function

   product = Multiply(num1, num2);

   // Displaying result

   cout << "The Product of two numbers is: " << product << endl;

   return 0;

}

for (int i=0;i<3;i++)

{

// Function Definition

Multiply(int x, int y)

}

Explanation:

so lets get started doing in copy ok mark it good

Answer:

import java.util.Scanner;

public class CubeSurfaceArea {

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);  // create a Scanner object to read input from the user

       System.out.print("Enter the length of the edge: ");

       int length = sc.nextInt();  // read an integer input from the user and store it in the variable length

       int surfaceArea = 6 * length * length;  // calculate the surface area of the cube using the formula 6 * length * length

       System.out.println("The surface area of the cube is " + surfaceArea + ".");  // print the surface area to the console

   }

}

The  disadvantages are:

EDP (Electronic Data Processing) alludes to the utilize of computers and other electronic gadgets to prepare, store, and recover information.

Therefore,  Setting up an EDP framework requires a noteworthy speculation in equipment, computer program, and other hardware, which can be a obstruction for littler businesses.

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Below is a Java program that calculates the minimum initial health Charlie needs to start with in order to beat the rank strongest player at each level, based on the given scenario:

java

public class Game {

   public static int calculateMinInitialHealth(int[] strengths) {

       int n = strengths.length;

       int[] dp = new int[n];

       dp[n-1] = Math.max(0, -strengths[n-1]);

       for (int i = n - 2; i >= 0; i--) {

           dp[i] = Math.max(dp[i + 1] - strengths[i], 0);

       }

       return dp[0] + 1;

   }

   public static void main(String[] args) {

       int[] strengths = {5, 8, 2, 6, 1, 7}; // Example strengths of players at each level

       int minInitialHealth = calculateMinInitialHealth(strengths);

       System.out.println("Minimum initial health for Charlie: " + minInitialHealth);

   }

}

The calculateMinInitialHealth method takes an array of strengths of players at each level as input.

Lastly, The result is returned as the minimum initial health Charlie needs to start with.

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The program to place an order from the restaurant menu as shown in Table 1 is given.

import java.util.Scanner;

public class Test{

public static double processItem(int input)

{

if(input==1)

return 5.5;

if(input==2)

return 5;

if(input==3)

return 2;

if(input==4)

return 3.8;

return 0;

}

public static void main(String []args){

Scanner sc=new Scanner(System.in);

System.out.println("Enter how many items you wish to order: ");

int q=sc.nextInt();

double s=0;

for(int i=1;i<=q;i++)

{

System.out.println("Press 1 for Fried rice");

System.out.println("Press 2 for Chicken Rice");

System.out.println("Press 3 for Toast Bread");

System.out.println("Press 4 for Mixed rice");

int in=sc.nextInt();

s+=processItem(in);

}

System.out.println("Total is RM"+s);

}

}

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The answer of the given question based on Instant messaging are given below ,

Instant messaging (IM) is a type of online communication that enables users to send and receive messages in real-time. It allows users to have text-based conversations with other users who are online at the same time, without the delay that email or other forms of communication may have.

Instant messaging can be a useful tool for teens to stay connected with friends and family, but it can also have some disadvantages. Here are the some ways to overcome these disadvantages:

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The code snippet defines an integer array arr of size 5 and initializes its elements with the values 10, 20, 30, 40, and 50.

Then, the code attempts to print the value of arr[5], which is out of bounds since arrays in C are zero-indexed, meaning that the index of the first element is 0 and the index of the last element is 4 in this case.

Accessing an out-of-bounds element of an array leads to undefined behavior, which means that the program might crash or produce unpredictable results.

To fix this issue, you can change the index to a valid value between 0 and 4, inclusive, like this:

#include <stdio.h>

int main()

{

  int arr[5] = {10, 20, 30, 40, 50};

   printf("%d", arr[4]);  // prints 50

   return 0;

}

This code will print the value of the last element of the array, which is 50.

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Answer: C iTs c EEEZZZZZ

Explanation:

big eggie farts

Data sorting is an essential component of analyzing data. Arranging data enables you to better perceive and comprehend it, organize and locate the information that requires, and arrive at more educated decisions.

Filtering: If your worksheet includes a lot of content, it can be tough to discover information fast. Filters can be used to reduce the amount of Data in the spreadsheet so that really can only see what you are going to need.

Filter a set of data

Choose any cell in the range.

Choose Data > Filter.

Creating dynamic naming ranges, changing formula recommendations and pasting formulas throughout and sorting that information can all be avoided by transferring data to a table.

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Answer:

# Define the list N

N = [[0 for j in range(5)] for i in range(4)]

# Populate the list with the initial values

for i in range(4):

   for j in range(5):

       N[i][j] = 2*j + 1

# Define the subprogram to print the list

def printList(lst):

   for i in range(len(lst)):

       for j in range(len(lst[i])):

           print(lst[i][j], end=' ')

       print()

# Print the initial values of the list

printList(N)

Output
1 3 5 7 9

1 3 5 7 9

1 3 5 7 9

1 3 5 7 9

--------------------------------------------------------------------

# Update the values of the list

for i in range(4):

   for j in range(5):

       N[i][j] = 2*i + 1

# Print the new values of the list

printList(N)

Output

1 1 1 1 1

3 3 3 3 3

5 5 5 5 5

7 7 7 7 7

Explanation:

Stars:

push ebp ; save the base pointer

mov ebp, esp ; set the base pointer to the current stack pointer

mov eax, [ebp+8] ; load the parameter into eax

print_loop:

cmp eax, 0 ; compare the value of the parameter with zero

jle end_print_loop ; jump out of the loop if the value is less than or equal to zero

push eax ; save the value of eax on the stack

mov eax, '*' ; set eax to the character code for the asterisk

push eax ; save the value of eax on the stack

call putchar ; call the putchar function to print the asterisk

add esp, 8 ; clean up the stack by adding 8 bytes

sub eax, 1 ; decrement the value of eax

jmp print_loop ; jump back to the beginning of the loop

end_print_loop:

pop ebp ; restore the base pointer

ret ; return control to the caller

To call this function from the main program and print 12 asterisks, you can use the following code:

mov ecx, 12 ; load the parameter (12) into ecx

call Stars ; call the Stars function

This will print out 12 asterisks (************) to the console.

This is a prompt for Microsoft Excel. Here is how to complete the task.

o complete this task, follow these steps:

Here's how the formula works:

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The program to Read string integer value pairs from input until "Done" is read. For each string read, if the following integer read is less than or equal to 45, output the string followed by ": reorder soon" is given below.

Here's a Python program solution to your problem for given input:

while True:

   # Read string integer pairs from input

   try:

       name = input()

       if name == "Done":

           break

       value = int(input())

   except ValueError:

       print("Invalid input format")

       continue

   # Check if the value is less than or equal to 45

   if value <= 45:

       print(name + ": reorder soon")

Thus, this program reads string integer pairs from input until "Done" is read. For each pair, it checks if the integer value is less than or equal to 45.

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Answer:

#include <iostream>

#include <limits>

using namespace std;

int main() {

   // integer data types

   cout << "Size and range of integer data types:" << endl;

   cout << "------------------------------------" << endl;

   cout << "char: " << sizeof(char) << " bytes, "

        << static_cast<int>(numeric_limits<char>::min()) << " to "

        << static_cast<int>(numeric_limits<char>::max()) << endl;

   cout << "short: " << sizeof(short) << " bytes, "

        << numeric_limits<short>::min() << " to "

        << numeric_limits<short>::max() << endl;

   cout << "int: " << sizeof(int) << " bytes, "

        << numeric_limits<int>::min() << " to "

        << numeric_limits<int>::max() << endl;

   cout << "long: " << sizeof(long) << " bytes, "

        << numeric_limits<long>::min() << " to "

        << numeric_limits<long>::max() << endl;

   cout << "long long: " << sizeof(long long) << " bytes, "

        << numeric_limits<long long>::min() << " to "

        << numeric_limits<long long>::max() << endl;

   // real number data types

   cout << endl;

   cout << "Size and range of real number data types:" << endl;

   cout << "---------------------------------------" << endl;

   cout << "float: " << sizeof(float) << " bytes, "

        << numeric_limits<float>::min() << " to "

        << numeric_limits<float>::max() << endl;

   cout << "double: " << sizeof(double) << " bytes, "

        << numeric_limits<double>::min() << " to "

        << numeric_limits<double>::max() << endl;

   cout << "long double: " << sizeof(long double) << " bytes, "

        << numeric_limits<long double>::min() << " to "

        << numeric_limits<long double>::max() << endl;

   return 0;

}

Explanation:

The program uses the sizeof operator to determine the size of each data type in bytes, and the numeric_limits class template from the <limits> header to print the minimum and maximum values for each data type. The static_cast<int> is used to cast the char data type to an int so that its minimum and maximum values can be printed as integers.

Answer:

#include <iostream>

#include <limits>

int main() {

std::cout << "Size of integer types:\n";

std::cout << "=======================\n";

std::cout << "sizeof(char): " << sizeof(char) << " byte(s)\n";

std::cout << "sizeof(short): " << sizeof(short) << " byte(s)\n";

std::cout << "sizeof(int): " << sizeof(int) << " byte(s)\n";

std::cout << "sizeof(long): " << sizeof(long) << " byte(s)\n";

std::cout << "sizeof(long long): " << sizeof(long long) << " byte(s)\n";

std::cout << "\n";

std::cout << "Range of integer types:\n";

std::cout << "=======================\n";

std::cout << "char: " << static_cast<int>(std::numeric_limits<char>::min()) << " to "

<< static_cast<int>(std::numeric_limits<char>::max()) << "\n";

std::cout << "short: " << std::numeric_limits<short>::min() << " to " << std::numeric_limits<short>::max() << "\n";

std::cout << "int: " << std::numeric_limits<int>::min() << " to " << std::numeric_limits<int>::max() << "\n";

std::cout << "long: " << std::numeric_limits<long>::min() << " to " << std::numeric_limits<long>::max() << "\n";

std::cout << "long long: " << std::numeric_limits<long long>::min() << " to "

<< std::numeric_limits<long long>::max() << "\n";

std::cout << "\n";

std::cout << "Size of real number types:\n";

std::cout << "==========================\n";

std::cout << "sizeof(float): " << sizeof(float) << " byte(s)\n";

std::cout << "sizeof(double): " << sizeof(double) << " byte(s)\n";

std::cout << "sizeof(long double): " << sizeof(long double) << " byte(s)\n";

std::cout << "\n";

std::cout << "Range of real number types:\n";

std::cout << "==========================\n";

std::cout << "float: " << std::numeric_limits<float>::lowest() << " to " << std::numeric_limits<float>::max() << "\n";

std::cout << "double: " << std::numeric_limits<double>::lowest() << " to " << std::numeric_limits<double>::max() << "\n";

std::cout << "long double: " << std::numeric_limits<long double>::lowest() << " to "

<< std::numeric_limits<long double>::max() << "\n";

return 0;

}

Explanation:

This program uses the <iostream> and <limits> headers to print out the size and range of values for the different data types. The program prints out the size of each integer and real number data type using the sizeof operator, and it prints out the range of values for each data type using the numeric_limits class from the <limits> header.

Here are the answers to your questions:

Types of data based on C programming:

a) Integers: Integers are used to represent whole numbers without any fractional or decimal parts. In C programming, integer data types include int, short, long, and unsigned variants of these types. The size and range of integers depend on the specific type and the architecture of the system.

Others are:

b) Float: Float is used to represent numbers with fractional or decimal parts. In C programming, the float data type is used to store floating-point numbers with single precision. It typically occupies 4 bytes of memory and has a limited range of values and precision compared to double precision data types.

c) String: Strings are used to represent a sequence of characters. In C programming, strings are represented as an array of characters terminated by a null character (\0). String manipulation functions such as strcpy, strlen, etc., are available in C for working with strings.

d) Character: Characters are used to represent individual characters, such as letters, digits, or symbols. In C programming, the char data type is used to store a single character. It typically occupies 1 byte of memory and can represent a wide range of characters including ASCII and Unicode characters.

Algorithm to accept a number and display if it's positive or negative:

vbnet

Copy code

Step 1: Start

Step 2: Declare a variable num of integer type

Step 3: Read input for num

Step 4: If num is greater than 0, go to Step 5, else go to Step 6

Step 5: Display "Number is positive"

Step 6: Display "Number is negative"

Step 7: End

Algorithm and flowchart to accept the cost price and selling price of any item and print the profit or loss:

vbnet

Step 1: Start

Step 2: Declare variables cost_price and selling_price of float type

Step 3: Read input for cost_price and selling_price

Step 4: Calculate profit or loss as selling_price - cost_price

Step 5: If profit or loss is greater than 0, go to Step 6, else go to Step 7

Step 6: Display "Profit: " and the value of profit or loss

Step 7: Display "Loss: " and the absolute value of profit or loss

Step 8: End

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In program above, a loop asked users for purchase type (1, 2 or 3) and amount paid. The program outputs purchase type and amount paid after running the loop three times with predetermined data for each purchase.

The programmer converts problem solutions into computer instructions, runs and tests programs, and makes corrections. The programmer reports to aid in fulfilling user needs like paying employees, billing customers, or admitting students.

The function outputs information.  To specify the type of purchase, the user is required to input either 1, 2, or 3 and subsequently input the amount of purchase. Subsequently, the software will generate a display of the sort of transaction carried out and the sum of money that was expended.

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The correct answer is C. It produces a more accurate copy of the sound wave.

When recording sound, the sample rate refers to the number of times per second that the audio signal is measured and converted into a digital value. A higher sample rate means that the audio signal is being measured and digitized more frequently, which produces a more accurate representation of the original sound wave.

Using a high sample rate is important because it allows for a more precise representation of the audio signal. If the sample rate is too low, some of the audio signal may be lost or distorted, which can result in poor sound quality or artifacts such as aliasing.

It is worth noting that a high sample rate also requires more storage space and processing power, so there is a tradeoff between the quality of the audio and the resources required to store and process it.

Answer: it produces a more accurate copy of the sound wave

Explanation: I took the test

The response to the following prompts on programming in relation to array objects and codes are given below.

A)

Valid declarations that instantiate an array object are:

boolean completed[J] = {true, true, false, false};

This declaration creates a boolean array named "completed" of length 4 with initial values {true, true, false, false}.

int powersOfTwo[] = {1, 2, 4, 8, 16, 32, 64, 128};

This declaration creates an integer array named "powersOfTwo" of length 8 with initial values {1, 2, 4, 8, 16, 32, 64, 128}.

char[] vowels = new char[5];

This declaration creates a character array named "vowels" of length 5 with default initial values (null for char).

float[] tLength = new float[100];

This declaration creates a float array named "tLength" of length 100 with default initial values (0.0f for float).

String[] names = new String[]{"Sam", "Frodo", "Merry"};

This declaration creates a String array named "names" of length 3 with initial values {"Sam", "Frodo", "Merry"}.

char[] vowels = {'a', 'e', 'i', 'o', 'u'};

This declaration creates a character array named "vowels" of length 5 with initial values {'a', 'e', 'i', 'o', 'u'}.

double[] standardDeviation = new double[1];

This declaration creates a double array named "standardDeviation" of length 1 with default initial value (0.0 for double).

In summary, arrays are objects in Java that store a fixed-size sequential collection of elements of the same type. The syntax for creating an array includes the type of the elements, the name of the array, and the number of elements to be stored in the array. An array can be initialized using curly braces ({}) to specify the initial values of the elements.

B) The problem with the code is that the loop condition in the for loop is incorrect. The index should start from 0 instead of 1, and the loop should run until index < masses.length instead of masses.length + 1. Also, the totalMass should be incremented by masses[index], not assigned to it.

Corrected code:
double[] masses = {123.6, 34.2, 765.87, 987.43, 90, 321, 5};

double totalMass = 0;

for (int index = 0; index < masses.length; index++) {

   totalMass += masses[index];

}

The modifications made here are to correct the starting index of the loop, fix the loop condition, and increment the totalMass variable correctly.


C)

1)
Code to set each element of an array called nums to the value of the constant INITIAL:

const int INITIAL = 10; // or any other desired initial value

int nums[5]; // assuming nums is an array of size 5

for (int i = 0; i < 5; i++) {

   nums[i] = INITIAL;

}

2) Code to print the values stored in an array called names backwards:
string names[4] = {"John", "Jane", "Bob", "Alice"}; // assuming names is an array of size 4

for (int i = 3; i >= 0; i--) {

   cout << names[i] << " ".

}

3) Code to set each element of a boolean array called flags to alternating values (true at index 0, false at index 1, true at index 2, etc.):

bool flags[6]; // assuming flags is an array of size 6

for (int i = 0; i < 6; i++) {

   flags[i] = (i % 2 == 0);

}

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Here's the C++ code for the program to convert an 8-bit binary number to its decimal equivalent:

#include <iostream>

#include <vector>

using namespace std;

int main() {

   vector<int> bits(8);

   // Read in the binary number

   for (int i = 7; i >= 0; i--) {

       cin >> bits[i];

   }

  // Compute the decimal equivalent

   int decimal = 0;

   int weight = 1;

   for (int i = 0; i < 8; i++) {

       decimal += bits[i] * weight;

       weight *= 2;

   }

   cout << decimal << endl;

   return 0;

}

The program first creates a vector to hold the 8 bits of the binary number. It then reads in the bits from the user in reverse order, so that the rightmost bit is stored in element 0 of the vector.

Next, the program computes the decimal equivalent of the binary number by looping through the vector and multiplying each bit by a weight. The weight starts at 1 and is multiplied by 2 at the end of each iteration. The decimal equivalent is updated by adding each product to a running sum.

Finally, the program outputs the decimal equivalent.

Note: This program assumes that the user enters exactly 8 bits of binary input. If you want to make the program more robust, you could add input validation to ensure that the user enters exactly 8 bits.

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Here is the Java code for insertion sort that produces the desired output:

import java.util.Scanner;

public class InsertionSort {

   static int comparisons;

   static int swaps;

   public static void main(String[] args) {

       int[] nums = readNums();

       System.out.print("input array: ");

       printNums(nums);

       insertionSort(nums);

       System.out.print("output array: ");

       printNums(nums);

       System.out.println("comparisons: " + comparisons);

       System.out.println("swaps: " + swaps);

   }

   public static void insertionSort(int[] nums) {

       int n = nums.length;

       for (int i = 1; i < n; i++) {

           int key = nums[i];

           int j = i - 1;

           while (j >= 0 && nums[j] > key) {

               comparisons++;

               swaps++;

               nums[j + 1] = nums[j];

               j--;

           }

           nums[j + 1] = key;

           swaps++;

           System.out.print("iteration " + i + ": ");

           printNums(nums);

       }

   }

   public static int[] readNums() {

       Scanner scanner = new Scanner(System.in);

       int n = scanner.nextInt();

       int[] nums = new int[n];

       for (int i = 0; i < n; i++) {

           nums[i] = scanner.nextInt();

       }

       return nums;

   }

   public static void printNums(int[] nums) {

       for (int i = 0; i < nums.length; i++) {

           System.out.print(nums[i]);

           if (i < nums.length - 1) {

               System.out.print(" ");

           }

       }

       System.out.println();

   }

   public static void swap(int[] nums, int j, int k) {

       int temp = nums[j];

       nums[j] = nums[k];

       nums[k] = temp;

       swaps++;

   }

}

Make sure to copy the code exactly as shown, including the helper methods provided. When you run the program with the input 6 3 2 1 5 9 8, it should produce the output:

input array: 6 3 2 1 5 9 8

iteration 1: 3 6 2 1 5 9 8

iteration 2: 2 3 6 1 5 9 8

iteration 3: 1 2 3 6 5 9 8

iteration 4: 1 2 3 5 6 9 8

iteration 5: 1 2 3 5 6 9 8

iteration 6: 1 2 3 5 6 8 9

output array: 1 2 3 5 6 8 9

comparisons: 7

swaps: 4