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An object with mass m dropped from height H, after travelling a distance and emerged horizontally from the bottom of the track with a velocity v and height of h. what is The work done due to friction while traveling through the track. could someone also please explain the difference between h and H

Answer:

mercury

arsenic

ricin

ddt

Explanation:

pls mark me as brainliest

Among the materials listed, examples of persistent organic pollutants (POPs) are PCBs (Polychlorinated Biphenyls) DDT (Dichlorodiphenyltrichloroethane). The correct option is (2) and (3).

Persistent Organic Pollutants (POPs) are a class of chemicals that are long-lasting, bioaccumulative, and harmful to humans and wildlife. These pollutants are resistant to degradation and can persist in the environment for long periods of time, resulting in long-distance transport and bioaccumulation in the food chain.

PCBs (Polychlorinated Biphenyls): Once utilized in a variety of industrial applications such as electrical transformers and capacitors, PCBs are now prohibited in many countries due to their toxicity.

DDT (Dichlorodiphenyltrichloroethane): An pesticide that was widely used for agricultural and public health objectives in the past but is now restricted or banned due to its environmental and health effects.

Hence, the correct answer is PCBs and DDT. The correct option is (2) and (3).

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Answer:

lol I don't know think u could help me with my mathematics

Answer:

Mass of a object 75 Kilograms

Explanation:

Net force acting on an object, [tex]Fnet = 225N[/tex]

Acceleration produced, [tex]a = 3.0m/s^2[/tex]

According to Newton's second law :

F = m a

[tex]M =\frac{F}{a}[/tex]

[tex]m =\frac{225N}{300m/s^2}[/tex]

[tex]m= 75 Kg[/tex]

So, the mass of an object is 75kg.

Hence, this is the required solution.

Answer:

75 kg.

Explanation:

Net Force

[tex]\sf \longmapsto F_{net} = 225N[/tex]

Acceleration produced

[tex]\sf \longmapsto \: a = 3 .0 m / {s}^{2}[/tex]

According to Newton's 2nd Law –

F = m•a

[tex]\sf \longmapsto \: M = \frac{F}{A} [/tex]

[tex]\sf \longmapsto \: M = \frac{225N}{300m/s ^{2} } [/tex]

[tex]\sf \longmapsto \: M = \: 75 \: kg[/tex]

Therefore, the mass of an object is 75 kg.

Answer: B 19.6J

Explanation: The equation for Potential energy is PE=mgh

PE is the potential energy

m=Mass=0.4kg

g=Gravity=9.81m/[tex]s^{2}[/tex]

h=Height=5 metres

(0.4 kg)*(9.81m/[tex]s^{2}[/tex])*(5 metres)=19.62J

Answer:

Lotion : semisolid

Suspension : liquid

capsule : solid

Explanation:

Answer:

Explanation:

ASSUMING the clay is moving horizontally and friction is negligible.

momentum is mass times velocity

9a)

m₁v + m₂(0) = m₁vf + m₂vf

            m₁v = (m₁ + m₂)vf

               vf = m₁v / (m₁ + m₂)

9b)

ASSUMING the positive direction is also the original direction of the clay ball

m₁v + m₂vb = (m₁ + m₂)vf

vf = (m₁v + m₂vb) / (m₁ + m₂)

9c)

vf = (0.37(25) + 4.6(3.4)) / (0.37 +4.6)

vf = (9.25 + 15.64) / 4.97

vf = 5.0080482897...

vf = 5.0 m/s

Answer: These apparent star tracks are in fact not due to the stars moving, but to the rotational motion of the Earth. As the Earth rotates with an axis that is pointed in the direction of the North Star, stars appear to move from east to west in the sky.

Explanation: why do the star constellations seem to move across the sky

Answer:

because the world moves around and around rotating in a circle and circling around the sun so as we move the stars stay the same but to our view it looks like their moving but in reality we are.

Explanation:

Answer: Yes Because it matches with the mass and the amount of force Hope this helps :>

Explanation:

Answer:

Soldering is a technique or a process to bond metals with the help of solder. Solder is a metal alloy with a low melting point and is often regarded as the base metal for soldering. The piece or structure that is being bonded together does not get hot enough to melt and this is where solder (base metal) comes into play and creates the connection.

Explanation:

Hope this helps :)

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And have an amazing day <3

Answer:

E.Mass

Explanation:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Answer:

Part A: By using the formula, distance = speed x time

Part B: By using the formula, time = distance ( calculated in the first part) ÷ speed

Answer:

wool maybe, I was a bit confused in silk and wool but wool

Answer:

s times t

Explanation:

The equation for distance is D = st

Answer:

D is the correct answer (D=S*T)

This is an algebraic law; if you are to move the denominator or numerator to the other side of the equation, you must multiply it by the other side.

S=D/T is the same as D=S*T.

so distance=speed times time.

so if you are going 50 miles per hour, you multiply that times time, say one hour. you get your D distance which is 50 miles.

Answer:

They are the same.

Both have potential energy of M g H   and that is the energy that will be converted to kinetic energy for each twin,

Vf² = V₁² + 2ad

(12 m/s) ² = (0 m/s) ² + 2 (a) (50m)

a = 1.44 m/s ²

Answer:

[tex]\boxed {\boxed {\sf 1.44 \ m/s^2}}[/tex]

Explanation:

We are asked to find the block's rate of acceleration.

We are given the final velocity, initial velocity, and distance. Therefore, we will use the following kinematic equation:

[tex]{v_f}^2={v_i}^2+2ad[/tex]

The block starts at rest or 0 meters per second. The block reaches a final velocity of 12 meters per second. The distance traveled is 50 meters.

Substitute the values into the formula.

[tex](12 \ m/s)^2 = (0 m/s)^2 + 2a (50 \ m)[/tex]

Solve the exponents.

[tex]144 \ m^2/s^2= 0 m^2/s^2 + 2a (50 \ m)[/tex]

The 0 can be subtracted from both sides, or simply canceled.

[tex]144 \ m^2/s^2 = 2a (50 \ m)[/tex]

Multiply 2 and 50 meters.

[tex]144 \ m^2/s^2 = (2 *50 \ m)* a[/tex]

[tex]144 \ m^2/s^2 = (100 \ m)* a[/tex]

We are solving for a, so we must isolate the variable. It is being multiplied by 100 meters. The inverse of multiplication is division, so we divide both sides by 100 meters.

[tex]\frac {144 \ m^2/s^2}{100 \ m}= \frac{(100 \ m)*a}{100 \ m}[/tex]

[tex]\frac {144 \ m^2/s^2}{100 \ m}=a[/tex]

[tex]1.44 \ m/s^2 =a[/tex]

The block's rate of acceleration is 1.44 meters per second squared.

Answer:

Explanation:

Provided the car did not collide with anything during its slide,

Kinetic energy will convert to work of friction

½mv² = Fd

½mv² = μmgd

       v = √(2μgd)

       v = √(2(0.300)(9.81)(28.0))

       v = 12.8377...

       v = 12.8 m/s

El análisis de un grafico de velocidad versus tiempo permite encontrar los resultados para las preguntas son:

a) La velocidad es v= 0,6 m/s

b) La distancia recorrida  dₐ = 1,5 m

c) La distancia recorrida entre t= 5 y 10 s es  [tex]d_b[/tex] = 3,0 m

d) La aceleración   a = -0,4 m/s²

e) La distancia total recorrida  es [tex]d_{total}[/tex] = 5,3 m

f) La velocidad media es  [tex]v_{media}[/tex] = 0,44 m/s

La cinemática estudia el movimiento de los cuerpos, buscando relaciones entre la posición, la velocidad y la aceleración de los cuerpos.

La velocidad es definida como el cambio de la posición en función del tiempo y la aceleración es el cambio de la velocidad en el intervalo de tiempo.

           .[tex]v= \frac{\Delta x}{t} \\a = \frac{\Delta v}{t}[/tex]

Donde v y a son la velocidad y aceleración, respectivamente, t es el tiempo y Δx y Δv son la variación de la posición y la velocidad, respectivamente.  

En el adjunto muestran un grafico de la velocidad en función del tiempo, donde del área bajo la curva obtenemos la distancia recorrida y la pendiente corresponde a la aceleración del cuerpo.

Respondamos las preguntas:

a)  La velocidad de la bola a los 5 s.

Como es un grafico de velocidad versus tiempo, la velocidad puede ser leída directamente, en el grafico tenemos un valor de

          v= 0,6 m/s  

b) La distancia recorrida corresponde al área bajo la curva.

         [tex]d_a = \frac{v_f - v_o}{2} t \\d_a = \frac{0.6-0}{ 2}\ 5[/tex]  

         d = 1,5 m

c) La distancia en el intervalo de 5 a 10 s.

En este intervalo la velocidad es constante, el área es

        [tex]d_b = v \Delta t\\d_b = 0.6 \ 5\\[/tex]  

        d =  3 m

d) La aceleración en el intervalo  10 a 12 s.

La aceleracion es la pendiente del grafico

        a = [tex]\frac{\Delta v}{\Delta t}[/tex]  

        a = [tex]\frac{-0.2 - 0.6}{12-10}[/tex]

        a = -0,4 m/s²

El signo negativo indica que la aceleración se opone a la velocidad del cuerpo.

e) La distancia total recorrida  

       [tex]d_{total} = d_a + d_b + d_c[/tex]

      dₐ = 1,5 m

      [tex]d_b[/tex] = 3,0 m

Busquemos la distancia en el ultimo intervalo

         [tex]d_c = \frac{0.6 + 0.2}{2} ( 12-10)[/tex]

       [tex]d_c[/tex] = 0,8 m

Substituimos

     [tex]d_{total}[/tex] = 1,5 + 3,0 + 0,8

     [tex]d_{total}[/tex]  =  5,3 m

f) La rapidez  de la bola

La rapidez prmedio es la relación entre la distancia recorrida en el tiempo.

         [tex]v_{avg} = \frac{\Delta x}{\Delta t }[/tex]  

         [tex]v_{avg} = \frac{5.3}{12}[/tex]

         [tex]v_{avg}[/tex]  =0,44 m/s

En conclusión usando el análisis de un grafico de velocidad versus tiempo podemos encontrar los resultados para las preguntas son:

         a) La velocidad es v= 0,6 m/s

         b) La distancia recorrida  da = 1,5 m

         c) La distancia recorrida entre t= 5 y 10 s es  db = 3,0 m

         d) La aceleración   a = -0,4 m/s²

         e)  La distancia total recorrida  es [tex]d_{total}[/tex] = 5,3 m

          f) La velocidad media es  [tex]v_{avg}[/tex] = 0,44 m/s

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Answer:

The spheres interact with one another, and a change in one might result in a change in another. Humans (biosphere) plough the fields with agricultural machinery made of geosphere materials, while the atmosphere (hydrosphere) provides precipitation to water the plants. The biosphere is home to all living organisms on the earth.

Explanation:

don't ask qestionsmm

To increase the mechanical advantage of incisors (front teeth) so that they act as wedges in the human body is through 2. an increase in the distance of the teeth from the fulcrum.

The decrease in the distance will decrease the mechanical advantage of incisors. The increase in the thickness at the widest part of the teeth will not necessarily support the incisors to become more effective wedges.  

Thus, incisors will acquire some mechanical advantage by increasing the force that it exerts. This advantage can be achieved by increasing the distance of incisors from the fulcrum.

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Answer:

4 aka D

Explanation:

Answer:  

1N  

Explanation:

Pretty simple Divide 23 by 23 which gives you 1.

23N ÷ 23N = 1N

Answer:

[tex]\sf \longmapsto \: 1 \: N[/tex]

Explanation:

[tex]\sf \longmapsto \frac{23N}{23N} [/tex]

[tex]\sf \longmapsto1 \: N[/tex]

Answer:

a. massa final

Explanation:

eu escolhi isso porque essa é a resposta espero que ajude você pode me dar uma ideia?

Answer:

Force= 1000 Newtons. Distance= 150 metres. Work= 150000 Joules. So, the work done by crane that lowers 1000 Newton's of a material a distance of 150 meters is 150000 Joules.

Answer:

D

Explanation:

Sum of the concentrations of each of reactant species is equal to the sum of the concentrations of each of the product species

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

Time = Distance / speed

Time = 7 / 3×10⁸

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

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Answer:

Atoms.

Explanation:

The fundamental structure obstructs that make matter are called molecules. What are the various particles found in iotas? (Reply: electrons, protons and neutrons) Where are they found? (Reply: Protons and neutrons are found in the core, and electrons are found in shells around the outside of the core.)

Really hope this helps! :D

Explanation:

The basic components of matter are called atoms. What are the various particles present in an atom?

(Answer: electrons, protons, neutrons) Where are they? (Answer: Protons and neutrons are in the nucleus, and electrons are in the shell around the nucleus.)

As the time of motion increases, the velocity of the object increases downwards.

The given parameters;

The final velocity of the object at different time is calculated as follows;

when the time = 1 second;

v = v₀ - gt

v = 9.8  - 9.8(1)

v = 0

when the time = 2 second;

v = v₀ - gt

v = 9.8 - 9.8(2)

v = -9.8 m/s

when the time = 3 second;

v = v₀ - gt

v = 9.8 - 9.8(3)

v = -19.6 m/s

Thus, we can conclude that as the time of motion increases, the velocity of the object increases downwards.

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Answer:

A. scatter plot?

Explanation:

I dont really know if I'm right... sorry.

Answer:

True statements a, b, and c

Explanation:

Answer d is false because in any collision, each object receives the same impulse. Also the momentum of car 1 is mv, while the momentum of car 2 is 0.5m(1.5v) = 0.75mv

The impulse of collision of cars depends on the mass and velocity of the cars. The statements which are true about the car collisions are option a, b, c.

Impulse is a physical quantity expressed as the product of force and time. The change in momentum mΔV is numerically equals to the impulse F t.

If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall. Because they have equal mass and velocity.

The bigger acceleration is experienced by the one which have lighter mass thus car 1 with lower mass experience higher acceleration .

The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy.

Converting this energy into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.

The momentum change is proportional to the velocity. The one which have higher velocity is having the higher momentum. Thus car 2 have higher velocity. Thus option d is false.

Therefore, the statements which are true are a, b and c.

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Answer:

= 3.87 m/s

Explanation:

Since momentum is conserved, momentum right before and after the boy jumps onto the skateboard should be the same.

Initial momentum = momentum of boy = 43.2 x 4.10 = 177 kg·m/s

Final momentum = momentum of boy and skateboard = (43.2 + 2.50) x v = 45.7v

177 = 45.7v

v = 177 / 45.7 = 3.87 m/s

(Hope this helps can I pls have brainlist (crown)☺️)

The combined velocity of the boy and the skateboard just after the boy lands on it will be equal to 3.87 m/s.

Momentum is the product of a particle's mass and velocity. Being a vector quantity, momentum possesses both direction and magnitude. According to Isaac Newton's second equation of motion, the force applied on a particle is equivalent to the temporal rate at which momentum changes. 

According to Newton's second law, the product of the energy and the time interval is equal to the shift in momentum if a constant force acts on a molecule for a specified amount of time.

Momentum should be the same both before and after the boy gets onto the skateboard because it is preserved.

Initial momentum = momentum of boy

= 43.2 × 4.10 = 177 kg m/s

Final momentum = momentum of boy as well as skateboard

= (43.2 + 2.50) × v = 45.7 v

177 = 45.7 v

v = 177 / 45.7 = 3.87 m/s

Therefore, the combined velocity of boy and skateboard is 3.87 m/s.

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