While on vacation in Belmont, Lara went out for a dinner that cost $75. If sales tax in Belmont is 8% and Lara left a 20% tip on $75, what was the total cost of her meal?

Answer:

131.95yd squared

Step-by-step explanation:

A=2πrh+ 2 r(2)=2*π*3*4+2*π*3(2)~131.94689yd(2)

Answer:

The neighborhood the home is located in

The factors which does not affect the mortgage payment is the neighborhood the home is located in.

The correct option is D.

We are aware of this;

A mortgage is a loan when the borrower's property is used as security. The mortgage payment is determined by the cost of the property, the interest rate, the down payment, the length of the loan, taxes, and various insurances like homeowners insurance, among other factors.

Hence, It's not depend on ''The neighborhood the home is located in.''

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The spherical coordinates for the point (0, -3, -3) are (3√2, -π/2, π/4).

(a) To change from rectangular coordinates to spherical coordinates, we use the following formulas:

rho = √(x² + y² + z²)

theta = atan2(y, x)

phi = acos(z / rho)

Given the rectangular coordinates (5, 5√3, 10√3), we can substitute the values into the formulas to find the corresponding spherical coordinates:

rho = √((5)² + (5√3)² + (10√3)²)

= √(25 + 75 + 300)

= √(400)

= 20

theta = atan2(5√3, 5)

= atan(√3)

≈ 1.0472 radians

phi = acos((10√3) / 20)

= acos(√3 / 2)

= π/6 radians

Therefore, the spherical coordinates for the point (5, 5√3, 10√3) are (20, 1.0472, π/6).

(b) Given the rectangular coordinates (0, -3, -3), we can apply the formulas for spherical coordinates:

rho = √((0)² + (-3)² + (-3)²)

= √(0 + 9 + 9)

= √(18)

= 3√2

theta = atan2(-3, 0)

= -π/2 radians

phi = acos((-3) / (3√2))

= acos(-1/√2)

= π/4 radians

Hence, the spherical coordinates for the point (0, -3, -3) are (3√2, -π/2, π/4).

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Answer:

1/2 x 1/2 = 1/4

Step-by-step explanation:

P(H,H) = 1/2 x 1/2 = 1/4

P(T,T) = 1/2 x 1/2 = 1/4

P(H,T) = 1/2 x 1/2 = 1/4

P(T,H) = 1/2 x 1/2 = 1/4

The types of transformation in this problem is given as follows:

Vertical and horizontal translation.

The four translation rules are defined as follows:

The translations for this problem are given as follows:

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Answer:

B = 48.7°

C = 61.3°

b = 12

Step-by-step explanation:

Given:

A = 70°

a = 15

c = 14

Required:

B, C, and b

Solution:

✔️Using the law of sines, let's find C:

Sin C/c = Sin A/a

Plug in the values

Sin C/14 = Sin 70/15

Cross multiply

Sin C × 15 = Sin 70 × 14

Divide both sides by 15

Sin C = (Sin 70 × 14)/15

Sin C = 0.8770

C = Sin^{-1}(0.8770)

C = 61.282566° = 61.3° (nearest tenth)

✔️Find B:

B = 180 - (70 + 61.3) (sum of triangle)

B = 48.7°

✔️Find b using the law of sines:

b/sinB = a/sinA

Plug in the values

b/sin 48.7 = 15/sin 70

Cross multiply

b*sin 70 = 15*sin 48.7

Divide both sides by sin 48.7

b = (15*sin 48.7)/sin 70

b = 11.9921789

b = 12.0 (nearest tenth)

Answer:

(X+6)(x-5) + (X-5)(X+6)

Answer:

[tex]2x ^{2} - 22x + 60[/tex]

Answer:The diagram that models the ratio in the story is:

Mermaid book: Princess book = 3:2

To find out how many times Nolan has read the mermaid book, we can set up the following proportion:

3/2 = x/20

Cross-multiplying, we get:

2x = 3 * 20

2x = 60

Dividing both sides by 2, we find:

x = 60/2

x = 30

Therefore, Nolan has read the mermaid book 30 times this month.

[tex]\Large\boxed{\tt Answer:~A:~y=-3x+5}[/tex]

All we have to do in order to find the equation that is equivalent to 6x + 2y = 10 is to solve for y.

Step 1: Keep y on one side of the equation and move the rest to the other.

[tex]\tt 6x + 2y = 10\\2y = -6x + 10[/tex]

Step 2: Divide all terms by 2 to isolate y.

[tex]\tt 2y \div 2=y\\-6x \div 2 = -3x\\10 \div 2 =5\\\\y=-3x+5[/tex]

Answer:

5.318 * 10 to power of 8

Step-by-step explanation:

Answer:

5.318 × [tex]10^{8}[/tex]

Step-by-step explanation:

Answer:

(x - 3)^2 + (y - 6)^2 = 17

Step-by-step explanation:

The standard form of a circle's equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

(x - 3)^2 + (y - 6)^2 = 17

Given that a hockey tournament consists of 16 teams. In the first round, every team is randomly assigned to one of 8 games (2 teams per game). We are supposed to find the probability that all three Alberta teams are randomly assigned to different games. Let A be the event of assigning all three Alberta teams to different games.

Then the number of ways to select 3 teams from 16 teams is $\ dbinom {16}{3}$, the number of ways to assign 3 teams to different games is $8\times7\times6$, and the number of ways to assign the remaining 13 teams to games is $(13!) / (2^6\times6!)$.The probability of event A is given by;$$

P(A) = \frac{\text{number of ways to assign 3 teams from Alberta to different games}}{\text{number of ways to assign all teams to games}} = \frac{8\times7\times6 \times (13!) / (2^6\times6!)}{\dbinom{16}{3} \times (14!) / (2^7\times7!)}
$$Simplifying the above expression,$$
P(A) = \frac{8\times7\times6 \times 13! \times 2}{\dbinom{16}{3} \times 14!} = \frac{8\times7\times6 \times 2}{\dbinom {16}{3}} = \frac{336}{560} = \frac{3}{5}

Therefore, the probability that all three Alberta teams are randomly assigned to different games is $\frac{3}{5}$.

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I think that the answer would be two triangles.

The correct statement is : M spans P2.

The set M = {[tex]x+1, x^2-2, 3x[/tex]} consists of three polynomials in the variable x.

To determine whether M spans P3 or P2, we need to consider the highest degree of the polynomials in M.

The highest degree of the polynomials in M is 2 (from [tex]x^2-2[/tex]), which means that M can span at most the space of polynomials of degree 2 or less, i.e., P2.

To check whether M spans P2 or not, we need to see if any polynomial of degree 2 or less can be expressed as a linear combination of the polynomials in M.

We can write any polynomial of degree 2 or less as [tex]ax^2 + bx + c[/tex], where a, b, and c are constants.

To express this polynomial as a linear combination of the polynomials in M, we need to solve the system of equations:

[tex]a(x^2-2) + b(x+1) + c(3x) = ax^2 + bx + c[/tex]

This can be written as:

[tex]ax^2 + (-2a+b+3c)x + (b+c) = ax^2 + bx + c[/tex]

Equating the coefficients of [tex]x^2, x,[/tex] and the constant term, we get:

[tex]a = a,\\-2a+b+3c = b,\\b+c = c.[/tex]

The first equation is always true, and the other two equations simplify to:

[tex]-2a+3c = 0,\\b = 0.[/tex]

Solving for a, b, and c, we get:

[tex]a = 3c/2,\\b = 0,\\c = c.[/tex]

Therefore, any polynomial of degree 2 or less can be expressed as a linear combination of the polynomials in M. This means that M spans P2.

However, M cannot span P3, because P3 includes polynomials of degree 3, which cannot be expressed as a linear combination of the polynomials in M (since the highest degree polynomial in M is [tex]x^2[/tex]).

Therefore, the correct statement is: M spans P2.

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Answer:

9/2 = 4 1/2

Step-by-step explanation:

Answer:

60 mins

Step-by-step explanation:

15+45=60

The time needed to make 138 pancakes if both Mark and Charlotte work together is 227.142 minutes.

A fraction is a way to describe a part of a whole. such as the fraction 1/4 can be described as 0.25.

As it is given that Mark can make 9 pancakes in 15 minutes, therefore, the number of pancakes that Mark can make in one minute,

[tex]\text{Number of Pancake in one minute} = \dfrac{9}{15}[/tex]

Now, for Charlotte, it is given that he makes 42 pancakes in 45 minutes, therefore, the number of pancakes that Charlotte can make in one minute,

[tex]\text{Number of Pancake in one minute} = \dfrac{42}{45} = \dfrac{12}{15}[/tex]

Further, the total pancakes that can be made in one minute,

[tex]\text{Total Number of Pancake in one minute} = \dfrac{9}{15} +\dfrac{12}{15} = \dfrac{21}{15}[/tex]

As they both need to make 138 pancakes together, therefore, the time they need is,

[tex]\rm Time\ Needed = \dfrac{\text{Total number of pancakes}}{\text{Total number of pancakes in one minute}}[/tex]

[tex]\rm Time\ Needed = \dfrac{138}{\frac{21}{15}} = \dfrac{138\times 15}{21} = 227.142[/tex]

Hence, the time needed to make 138 pancakes if both Mark and Charlotte work together is 227.142 minutes.

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Shape a = 6 x 4 x 3 = 72

Shape b = 4 x 4 x 4 = 64

72 + 64 = 136

A

Answer:

A

Step-by-step explanation:

Answer:

12.6

Step-by-step explanation:

divide the length value by 3

Answer:

267/500

Step-by-step explanation:

0.534 = 534 / 1000

Simplify to 267/500

Step-by-step explanation:

537/1000

this is the correct answer

Answer:

models

Step-by-step explanation:

Answer: B.) Models

Edge

Answer:

38

Step-by-step explanation:

(10*2)+(9*2)

Mathematical induction can be used to prove that for every non-negative odd integer n, the expression [tex]24 / (2^{(3n+1)}+1+1) * (n^2+1)[/tex] holds true.

To prove the statement using mathematical induction, we need to follow two steps: the base case and the induction step.

First, we verify if the statement holds true for the base case, which is typically the smallest value of n. In this case, let's consider n = 0. Plugging in n = 0 into the expression, we get [tex]24 / (2^{(3*0+1)}+1+1) * (0^2+1)[/tex]. Simplifying, we have 24 / (2+1+1) * 1, which equals 24 / 4 * 1, resulting in 6. Therefore, the statement holds true for n = 0.

Next, we assume that the statement is true for some arbitrary odd integer k, and we will prove that it holds true for k+2. Assume that [tex]24 / (2^{(3k+1)}+1+1) * (k^2+1)[/tex] holds true.

Now, we substitute k+2 into the expression and aim to show that it holds true for k+2 as well. We have [tex]24 / (2^{(3(k+2)+1)}+1+1) * ((k+2)^2+1)[/tex]. Simplifying the expression, we get [tex]24 / (2^{(3k+7)}+1+1) * (k^2 + 4k + 5)[/tex].

We can manipulate the equation further to demonstrate that it is equal to the assumed expression for k. By performing algebraic manipulations and simplifications, we can equate the expressions and conclude that the statement holds true for k+2.

Since we have verified the base case and shown that the statement holds true for k+2 when it holds true for k, we can conclude that the statement is true for every non-negative odd integer n.

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Answer:

Yay fun day :DDDDDD

Step-by-step explanation:

Answer:

5 batches

Step-by-step explanation:

1/6 oatmeal  can make 1 batch, so 5/6 makes 5 batches

To calculate[tex]2^2873686243768478237864767208[/tex] mod 101 using Fermat's little theorem, we can simplify the exponent by taking it modulo 100, since 100 is the Euler's totient function value of 101. Therefore,[tex]2^2873686243768478237864767208[/tex] mod 101 is equal to 57.

Fermat's little theorem states that if p is a prime number and a is any integer not divisible by p, then a^(p-1) ≡ 1 (mod p). In this case, p = 101, and we need to find[tex]2^2873686243768478237864767208[/tex]mod 101.

First, we simplify the exponent by taking it modulo 100, since 100 is the Euler's totient function value of 101. The exponent 2873686243768478237864767208 is congruent to 8 modulo 100. So, we need to calculate 2^8 mod 101. Applying Fermat's little theorem, we know that 2^(101-1) ≡ 1 (mod 101), since 101 is prime. Therefore, 2^100 ≡ 1 (mod 101).

We can express [tex]2^8[/tex] in terms of 2^100 as [tex](2^100)^0.08[/tex]. Simplifying this, we get [tex](2^100)^0.08 ≡ 1^0.08[/tex]≡ 1 (mod 101).

Thus, we conclude that[tex]2^8[/tex] ≡ 1 (mod 101), and therefore 2^2873686243768478237864767208 ≡ [tex]2^8[/tex] (mod 101).

Finally, evaluating [tex]2^8[/tex] mod 101, we find that [tex]2^8[/tex] ≡ 57 (mod 101).

Therefore,[tex]2^2873686243768478237864767208[/tex] mod 101 is equal to 57.

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(a) If there are 4 candidate,  the smallest number of votes that a plurality candidate could have is 33.

(b) If there are 8 candidate,  the smallest number of votes that a plurality candidate could have is 17.

The smallest number of votes that a plurality candidate could have is calculated as follows;

(a) If there are 4 candidate, the number of votes for each candidate;

= 129 / 4

= 32.25

The least number of votes for the plurality candidate = 33

(b) If there are 8 candidate, the number of votes for each candidate;

= 129 / 8

= 16.125

The least number of votes for the plurality candidate = 17

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To have a horizontal asymptote at y = 3 and vertical asymptotes at x = 4 and x = -3, the rational function should have the following form:

f(x) = (a polynomial in x) / ((x - 4)(x + 3))

The polynomial in the numerator can have any degree, but it must be of lower degree than the denominator.

Therefore, among the given rational functions, the one that satisfies these conditions would be the one in the form:

f(x) = (a polynomial) / ((x - 4)(x + 3))

Please provide the specific options you have, and I can help you determine which of those options matches this form.

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Answer:

41.7feet

Step-by-step explanation:

From the question we are given the following

angle of depression = 50°

Distance of the pole from the base of the feet = 35feet (Adjacent)

Required

height of the school (opposite)

Using the SOH CAH TOA identity

Tan theta = opp/adj

Tan 50 = H/35

H = 35tan 50

H = 35(1.1918)

H = 41.7feet

Hence the height of the school is 41.7feet

Answer:

x axis

Step-by-step explanation: