The two energy sources that combined together to provide more than 50 percent of the energy needs of the USA in the year 1980 is: b) Oil and coal.
What is energy?In Science, energy can be defined as a measure of the ability of a physical body to do work. This ultimately implies that, energy must be possessed or transferred to a physical object or physical body before it can be used in doing a work or heating a system.
The forms of energy.In Science, there are different forms of energy and these include the following;
Wind energyKinetic energy.Gravitational energy.Potential energy.Elastic energyChemical energy.Solar energy.Nuclear energy.Based on the information provided, the two energy sources that would provide more than 50 percent of the energy needs of the USA in the year 1980 when added together should be calculated as follows:
Nuclear and natural gas = 4% + 25% = 29% (less than 50 percent).
Oil and coal = 42% + 23% = 75% (more than 50 percent).
Hydropower and oil = 5% + 42% = 49% (less than 50 percent).
Natural gas and coal = 25% + 23% = 48% (less than 50 percent).
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Please help. I'm not too sure!
Answer:
I think it would be 83% because petroleum, natural gas, and coal are fossil fuels.
What is a shotstring?
Answer:
837
Explanation:
Answer: What you see when you test a gun on a pattern plate.
Explanation: A guess
Your job is to order and connect lead-acid cells used to supply an uninterruptible power supply (UPS). The battery output voltage must be 126 V and have a current capacity of not less than 250 A-hr. Each cell has a rating of 2 V and 100 A-hr. How many cells must be ordered and how would you connect them?
189 cells must be ordered and how would you connect them.
What is lead acid cells?Lead acid batteries are affordable, practical, and suitable for a wide range of battery power applications. They are arguably best recognized for their use in traditional internal combustion automobiles, where they provide the power for all of the electronics, starting, and other functions.
The lead acid battery has several benefits for starting internal combustion engines as well as many other applications. They have a big current and surge capability, which is perfect.
Lead acid batteries are a well-recognized technology that may be produced with ease using tools that are rather low-tech.
Therefore, 189 cells must be ordered and how would you connect them.
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A condition in which body temperature drops a few degrees below normal is known a
1. heat stress
2. cold stroke
3. cold stress
4. heat exhaustion
You are working on an electronic circuit. The circuit current is 5 mA. A resistor is marked with the following bands: brown, black, red, gold. A voltmeter measures a voltage drop of 6.5 V across the resistor. Is this resistor within its tolerance rating?
It should be noted that the resistor is NOT within its tolerance rating since the value of R = 1,300Ω.
What is a Tolerance Rating?The tolerance of a resistor is its variation from its nominal value. It is presented as a percentage and was tested at 25°C with no load applied. Tolerances on certain resistor designs are exceedingly tight. Precision wire-wound resistors, for example, are manufactured with tolerances as fine as 0.005%.
The resistor value may be estimated using the resistor color coding table. The value of resistance may be calculated using Ohm's law.
Ohm's law asserts that if all physical conditions and temperatures are constant, the voltage across a conductor is precisely proportional to the current flowing through it. The proportionality constant, R, is denoted by the symbol Ω and has units of ohms in the equation.
With regard to the above problem, we know that:
The markings of the resistor (bands) are:
Brown = 1
Black = 0
Red = 10²
Gold ± 5%
Hence, the value of the resistor is:
Rt (Resistance True Value) = 10 x 10² ± 5%
Where ±5 is the tolerance level
Rt = 1000 ± 5% ⇒ 950Ω to 1050Ω
Referencing Ohms Law,
R = V/I
Where
R = Resistance
V = Voltage
I = Current
R = 6.5/5mA
R = (6.5/5) x 10³
R = 1.3 x 10³
R = 1, 300Ω
Since Measure Resistance 1, 300Ω is greater than the Resistance True value, we can conclude that the resistor is NOT within its tolerance rating.
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