Which statement best describes how the author of “The Train to Somewhere” alters historical details to tell her story?
A.The author includes historical facts, such as when the Children’s Aid Society was formed.
B.The author describes the experiences and feelings of an imaginary orphan who was sent west on an orphan train.
C. The author provides specific details about families who agreed with Brace’s beliefs about ways to help needy orphan children.
D.The author explores the adventures of two young children as they start their new lives on a farm in rural America.
Answers
Answer:
The statement that best describes how the author of "The Train to Somewhere" alters historical details to tell her story is option B;
B. The author describes the experiences and feelings of an imaginary orphan who was sent west on an orphan train
Step-by-step explanation:
The author included the experiences of one of the children who according to the historical details in the historical account of the Orphan Train Riders were aided by the minister, Charles Loring Brace, to be taken from the New York City streets on the East to other states and Canada to the West
The child, a 5 year old girl, who had lost both parents had been living on the street with her brother for some months
The author also highlighted the taught by the child, of being separated from her brother at one of the destination towns of the train, and the manifestation of the beliefs of the minister, Brace, of the children finding loving families that would help them become productive members of society.
Related Questions
The following data repite the resundew of students to short-zule test (out of 10) of cours Alb. X. and Cae). X 7 10 3 8 3 0 9 8 Sum 9 G 8 5 2 9 10 1. Calculate the correlation coeffici
Answers
The correlation coefficient between the scores of students in courses Alb. X and Cae is approximately -0.333.
Correlation refers to the strength of the relationship between two variables while coefficient refers to the numerical value that measures the strength of the correlation.
To calculate the correlation coefficient between the scores of students in courses Alb. X and Cae, we need to first organize the data into two separate lists or arrays representing the scores in each course. Let's denote the scores in Alb. X as X_scores and the scores in Cae as C_scores:
X_scores: 7, 10, 3, 8, 3, 0, 9, 8
C_scores: 8, 5, 2, 9, 10, 1
Next, we need to calculate the mean (average) of both sets of scores.
Mean of X_scores (denoted as X_mean):X_mean = (7 + 10 + 3 + 8 + 3 + 0 + 9 + 8) / 8
X_mean = 48 / 8
X_mean = 6
Mean of C_scores (denoted as C_mean):C_mean = (8 + 5 + 2 + 9 + 10 + 1) / 6
C_mean = 35 / 6
C_mean ≈ 5.83
Now, we calculate the covariance between the two sets of scores using the formula:cov(X_scores, C_scores) = Σ((X_i - X_mean) * (C_i - C_mean)) / (n - 1)
where Σ denotes the sum, X_i and C_i are individual scores, X_mean and C_mean are the means calculated above, and n is the number of scores.
Let's calculate the covariance:cov(X_scores, C_scores) = ((7-6)(8-5.83) + (10-6)(5-5.83) + (3-6)(2-5.83) + (8-6)(9-5.83) + (3-6)(10-5.83) + (0-6)(1-5.83) + (9-6)(8-5.83) + (8-6)(0-5.83)) / (8-1)
cov(X_scores, C_scores) ≈ -3.39
Next, we calculate the standard deviations of both sets of scores:
Standard deviation of X_scores (denoted as X_std):X_std = √(Σ(X_i - X_mean)² / (n - 1))
Let's calculate X_std:
X_std = √(((7-6)² + (10-6)² + (3-6)² + (8-6)² + (3-6)² + (0-6)² + (9-6)² + (8-6)²) / (8-1))
X_std ≈ 3.20
Standard deviation of C_scores (denoted as C_std):C_std = √(Σ(C_i - C_mean)² / (n - 1))
Let's calculate C_std:
C_std = √(((8-5.83)² + (5-5.83)² + (2-5.83)² + (9-5.83)² + (10-5.83)² + (1-5.83)²) / (6-1))
C_std ≈ 3.18
Finally, we can calculate the correlation coefficient (r) using the formula:r = cov(X_scores, C_scores) / (X_std * C_std)
Let's calculate r:
r ≈ -3.39 / (3.20 * 3.18)
r ≈ -3.39 / 10.176
r ≈ -0.333
Therefore, the correlation coefficient between the scores of students in courses Alb. X and Cae is approximately -0.333.
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By using the method of variation of parameters to solve a nonhomogeneous DE with W = -3 W2 = e 112 and W = er, we have ---- Select one: 42 Ou= 41 O U2= O None of these. -4 Ou2 = O U =
Answers
By using the method of variation of parameters to solve a nonhomogeneous DE with W = -3 W2 = e 112 and W = er, we have
Given: W1=-3, W2=e^t and W3=er.The general solution of the non-homogeneous differential equation, y" + p(t) y' + q(t) y = g(t) , where p(t) and q(t) are functions of t and g(t) is non-zero function is given by;{eq}y = y_c + y_p {/eq}Where {eq}y_c {/eq} is complementary function and {eq}y_p {/eq} is particular function obtained by using variation of parameters.The solution is as follows:The given differential equation is{eq}y''+3y'+2y=-3e^{-t}+e^{t}+re^t{/eq}Characteristic equation is{eq}m^2+3m+2=0{/eq}Solving above equation gives us, {eq}m=-1,-2{/eq}Therefore, complementary function {eq}y_c=c_1e^{-t}+c_2e^{-2t} {/eq}Now, we find the particular solution by using the method of variation of parameters.Let {eq}y_p=u_1e^{-t}+u_2e^{-2t}{/eq}be a particular solution where {eq}u_1{/eq} and {eq}u_2{/eq} are functions of {eq}t.{/eq}Here W is a Wronskian and is given as:{eq}W=\begin{vmatrix}W_1&W_2\\W_1'&W_2'\\\end{vmatrix}=\begin{vmatrix}-3&e^t\\-1&e^t\\\end{vmatrix}=2e^{2t}+3e^{t}{/eq}Now, we find {eq}u_1{/eq} and {eq}u_2{/eq} as follows:{eq}u_1=\frac{-\int W_2 g(t) dt}{W}=\frac{-\int e^t(-3e^{-t}+e^{t}+re^t)dt}{2e^{2t}+3e^{t}}=-\frac{r}{5}-\frac{7}{10}+\frac{3}{10}e^{t}{/eq}Similarly,{eq}u_2=\frac{\int W_1 g(t) dt}{W}=\frac{\int -3e^{-t}(-3e^{-t}+e^{t}+re^t)dt}{2e^{2t}+3e^{t}}=-\frac{r}{5}-\frac{1}{10}+\frac{3}{10}e^{-2t}{/eq}Hence, the general solution of the differential equation is {eq}y=y_c+y_p=c_1e^{-t}+c_2e^{-2t}-\frac{r}{5}-\frac{7}{10}+\frac{3}{10}e^{t}-\frac{r}{5}-\frac{1}{10}+\frac{3}{10}e^{-2t}{/eq}So, Option D, {eq}-4u_2=0,~u_1=-\frac{r}{5}-\frac{7}{10}+\frac{3}{10}e^{t},~u_2=-\frac{r}{5}-\frac{1}{10}+\frac{3}{10}e^{-2t}{/eq} is correct.
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The radius of a circle is 4 feet. What is the area?
r=4ft
Give the exact answer in simplest form.
Answers
Answer:
100.571429.
Step-by-step explanation:
2*22/7*(4)^2
=44/7*16
=100.571429
Question (5 points): Using Laplace transform to solve the IVP: y" + 5y = eat, y(0) = 0, y' (O) = 0, then, we have Select one: y(t) =(-1 1 93 – 4s2 + 5s – 20 O y(t) = 2-1 1 482 33 5s + 20 O None of these. Ο Ο 1 yt 3 – (t) = c{+60-60-20) {{+40 + 5a + 20 O 1 y(t) = 2-1
Answers
Given the differential equation is y''+5y = e^(at) with initial conditions y(0) = 0 and y'(0) = 0, the correct answer is: y(t) = (-1/5√(5)) cos (√(5)t)+(1/5) sin (√(5)t).
To solve the given initial value problem using Laplace transform, we need to apply Laplace transform on both sides of the differential equation.
y''+5y=e^(at) L{y''+5y} = L{e^(at)) s^2Y(s)-sy(0)-y'(0)+5Y(s)=1/(s-a) [by Laplace transform formula] s^2Y(s)+5Y(s)=1/(s-a) ... [i]
Applying Laplace transform on both sides, we get:
L{y''+5y}=L{e^(at))
Using the initial conditions, we get Y(s)=1/[(s-a)(s^2+5)] Y(s) = [A/(s-a)] + [(Bs+C)sin(t)+ (Ds+E)cos(t)]/√(5) (i)
To find the values of A, B, C, D, and E, we take the inverse Laplace transform of both sides of equation (i) using partial fraction expansion. Let's solve for A:
Y(s)=A/(s-a)+(Bs+C)sin(t)/√(5)+(Ds+E)cos(t)/√(5)
Multiplying by s-a on both sides: (s-a)Y(s)=A+Bssin(t)/√(5)+Csincos(t)/√(5)+Dscos(t)/√(5)+Esin(t)/√(5)
Taking the inverse Laplace transform: y(t)=Ae^(at)+(B/√(5))sin(√(5)t)+(C/√(5))cos(√(5)t)+(D/√(5))cos(√(5)t)+(E/√(5))sin(√(5)t)
Differentiating y(t) with respect to t, we get:
y'(t)=Aae^(at)+Bcos(√(5)t)-Csin(√(5)t)-Dsin(√(5)t)+Ecos(√(5)t)
Using the initial conditions, y(0)=0 and y'(0)=0 in equation (iii), we get:
0=A+E ...(iv)0=A+B/√(5)+D/√(5) ...(v)
Solving equations (iv) and (v) simultaneously, we get A=0, B=√(5)/5, D=-√(5)/5, and E=0
Substituting these values in equation (iii), we get: y(t)=(√(5)/5)sin(√(5)t)-(√(5)/5)cos(√(5)t)
Therefore, the correct answer is: y(t)= (-1/5√(5))cos(√(5)t)+(1/5)sin(√(5)t).
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Find the area. 14 m 4.5 m 4.5 m 9m 12 m 3 m 3 m
plzzz help meeee
Answers
Answer:
52
Step-by-step explanation:
Is 0.25 greater or less than 0.03?
Answers
Answer:
0.25 is greater than 0.03
Step-by-step explanation:
You can solve this simply by looking for the position of the decimal point.
For example, 0.30 is greater than 0.25, but 0.03 is less than 0.250.25 > 0.03
Answer:
Step-by-step explanation:
Which of the following is NOT true for 6s + 25 + 5? *
A. Represents an algebraic expression
B. There is only one value for s
C. A phrase that simplifies to two terms
D. There is a solution for s = 5
Answers
Answer:
B. There is only one value for s
Step-by-step explanation:
I hope this works for u.. :3
Can I have a brainliest plz :))
Alberto invested $5,000 at 6% interest
compounded annually. What will be the
value of Alberto's investment after 8 years?
Answers
Answer:
$7969.24
Step-by-step explanation:
5000*1.06 to power of 8 = 7969.24037265
round to 2dp = $7969.24
Answer:
7400
Step-by-step explanation:
Can you help me for these 3 questions.
Answers
Answer:
Step-by-step explanation:
1) a + a
2) 2n+4 = 6n
3) 1
4n = 4
n = 1
please help dont answer with random
Answers
Answer:
Step-by-step explanation:
17x + 14 + 4x -2 = 21x + 12
21x + 12 = 180
-12 -12
21x = 168
x = 8 degrees
[tex]\boxed{\large{\bold{\green{ANSWER~:) }}}}[/tex]
Here,
The two lines l and m are parallel,
cut by a transversat line t
So The two angles are supplementary each other.
we know that,The sum of two supplementary angles are 180°
According to the question,(17x+14)°+(4x-2)°=180°
17x+14°+4x-2°=180°
17x+4x+14°-2°=180°
21x+12°=180°
21x=180°-12°
21x=168°
x=168°/21
x=8°
Therefore,The value of x is 8°
Let A(x)=∫x0f(t)dtA(x)=∫0xf(t)dt, with f(x)f(x) as in figure.
A(x)A(x) has a local minimum on (0,6)(0,6) at x=x=
A(x)A(x) has a local maximum on (0,6)(0,6) at x=x=
Answers
To determine the local minimum and local maximum of the function A(x) = ∫₀ˣ f(t) dt on the interval (0, 6), we need to analyze the behavior of A(x) and its derivative.
Let's denote F(x) as the antiderivative of f(x), which means that F'(x) = f(x).
To find the local minimum and maximum, we need to look for points where the derivative of A(x) changes sign. In other words, we need to find the values of x where A'(x) = 0 or A'(x) is undefined.
Using the Fundamental Theorem of Calculus, we have:
A(x) = ∫₀ˣ f(t) dt = F(x) - F(0)
Taking the derivative of A(x) with respect to x, we get:
A'(x) = (F(x) - F(0))'
Since F(0) is a constant, its derivative is zero, and we are left with:
A'(x) = F'(x) = f(x)
Now, let's analyze the behavior of f(x) based on the given figure to determine the local minimum and maximum of A(x) on the interval (0, 6). Without the specific information about the shape of the graph, it is not possible to determine the exact values of x that correspond to local minimum or maximum points.
To find the local minimum, we need to locate a point where f(x) changes from decreasing to increasing. This point would correspond to x = x_min.
To find the local maximum, we need to locate a point where f(x) changes from increasing to decreasing. This point would correspond to x = x_max.
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Roger brought some sponges. The number of packages he bought was 14 less than the number of sponges per package. Roger bought 51 sponges in all. How many packages of sponges did roger buy?
Answers
Answer:
the number of sponges per package bought be 32.5
Step-by-step explanation:
Let us assume the number of sponges per package be x
So the number of packages he bought be x - 14
And, the overall he bought 51 sponges
So
the number of packages of sponges did roger buy is
x + x - 14 = 51
2x = 51 + 14
2x = 65
x = 32.5
So the number of sponges per package bought be 32.5
−x+9y=
\,\,-19
−19
3x-3y=
3x−3y=
\,\,9
9
Answers
Answer:
9!
Step-by-step explanation:
Which describes the graph of the inequality g(x)>2√3x+2?
A. Shading above a solid line
B. Shading above a dotted line
C. Shading below a dotted line
D. Shading below a solid line
Answers
Answer:
A. Shading above a solid line.
Step-by-step explanation:
Let [tex]f(x) = 2\sqrt{3}\cdot x + 2[/tex], whose domain is all real numbers, since it is a first order polynomial (linear function) and meaning that for all element of [tex]x[/tex] exists one and only one value for [tex]f(x)[/tex], meaning a solid line. If [tex]g(x) > f(x)[/tex], then the range of all possible results is a shade area above the solid line.
Hence, the correct answer is A.
Ming le invited 12 people to her chrismas party.(that is,there are total 13 people at her party )Each person have each other person a present.How many presents were given
Answers
Answer:
There will be 13 gifts given in the party.
Step-by-step explanation:
Given that Ming invited 12 people to her chrismas party, with a total of 13 people at her party, and each person have each other person a present, to determine how many presents were given the following logical reasoning must be performed:
Given that there are 13 people at the party, and each of them will bring a gift, by mathematical logic there will be 13 gifts distributed in the party.
Identify the type of conic that follwoing equation represents and write the standard form of each equation.
25x² + 100y² - 450x - 400y - 75 = 0
Answers
The standard form of the equation for the ellipse is ((x - 9)²/376) + ((y - 2)²/94) = 1.
The given equation represents an ellipse. The standard form of the equation is ((x-h)²/a²) + ((y-k)²/b²) = 1, where (h,k) is the center of the ellipse, 'a' is the semi-major axis, and 'b' is the semi-minor axis.
To determine the type of conic represented by the equation, we examine the coefficients of the x² and y² terms. In the given equation, both the x² and y² terms have positive coefficients, indicating that it represents an ellipse.
To write the equation in standard form, we need to complete the square for both the x and y terms. Let's rearrange the equation:
25x² - 450x + 100y² - 400y = 75
Now, we group the x and y terms and complete the square separately:
25(x² - 18x) + 100(y² - 4y) = 75
To complete the square for the x term, we take half of the coefficient of x (-18/2 = -9) and square it to get 81. Similarly, for the y term, we get 4.
25(x² - 18x + 81) + 100(y² - 4y + 4) = 75 + 25*81 + 100*4
Simplifying further:
25(x - 9)² + 100(y - 2)² = 9400
Dividing both sides by 9400, we get:
((x - 9)²/376) + ((y - 2)²/94) = 1
Therefore, the standard form of the equation for the ellipse is ((x - 9)²/376) + ((y - 2)²/94) = 1.
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WILL GET BRAINLIEST The scatterplot shows the weight and miles per gallon of the nation's 40 best-selling cars.
Vehicle Weights and Miles
Per Gallon
Miles Per Gallon
Vehicle Weight
Which statement is most strongly supported by the scatterplot?
Answers
The last one as we can see that as the wight increases, the miles per gallon decreases.
Which statements are true based on the diagram?
Select three options.
Answers
Help, help, help! Quick Answer, please!
Answers
Answer:
3. 102
4. c
Step-by-step explanation:
For number 3:
(c^2 - a) + b becomes (10^2 - 3) + 5
10^2 = 100
100 - 3 + 5 = 102
For number 4:
Usually when you see distributive property, you're multiplying into parentheses. This time you're factoring out.
20c - 8d
It's not a, because that would be 20c + 8d
It's not b, because that would be 20c -32d
It is c, because 4 x 5c = 20 c and 4 x -2d = -8d
It's not d, because that would be 20c- 8cd
Answers this plz I need help
Answers
Answer:
y=2x+5
Step-by-step explanation:
u find the slope and since the y intercept is (0,5), that's the b value
hope this helps
Answer: 2x+5
Step-by-step explanation: calculate the slope of the points with the formula m= (y2-y1)/(x2-x1) then use the y-int to complete the equation
Angle W is shown in the diagram.
w
400
What is the measure of Angle w in degrees?
Answers
Answer:
The measure of Angle w in degrees is 50°
Step-by-step explanation:
We know that in a straight line, 180°
So,
90° + 40° + w = 180°
130° + w = 180°
w = 180° - 130°
w = 50°
Thus, The measure of Angle w in degrees is 50°
-TheUnknownScientist
Which expression is equivalent to 1/4m + 3/4m- 3/8(m+1)?
Answers
Answer:
5/8m-3/8
Step-by-step explanation:
thats prolly it
Use the method of variation of parameters to find a particular solution of the differential equation 4y" – 4y +y = 16et/2 that does ' not involve any terms from the homogeneous solution. = Y(t) =
Answers
The particular solution that does not involve any terms from the homogeneous solution is given by:[tex]Y(t) = C3 + C4te^(-t/2).[/tex]
To find a particular solution of the given differential equation using the method of variation of parameters, we follow these steps:
Solve the associated homogeneous equation: 4y" - 4y + y = 0.
The characteristic equation is:
[tex]4r^2 - 4r + 1 = 0.[/tex]
Solving the quadratic equation, we find two repeated roots: r = 1/2.
Therefore, the homogeneous solution is given by: y_h(t) = C1[tex]e^(t/2)[/tex] + C2t[tex]e^(t/2),[/tex] where C1 and C2 are constants.
Find the particular solution using the variation of parameters.
Let's assume the particular solution has the form:
[tex]y_p(t) = u1(t)e^(t/2) + u2(t)te^(t/2).[/tex]
To find u1(t) and u2(t), we differentiate this expression:
[tex]y_p'(t) = u1'(t)e^(t/2) + u1(t)(1/2)e^(t/2) + u2'(t)te^(t/2) + u2(t)e^(t/2) + u2(t)(1/2)te^(t/2).[/tex]
We equate the coefficients of e^(t/2) and te^(t/2) on both sides of the original equation:
[tex](1/2)(u1(t) + u2(t)t)e^(t/2) = 16e^(t/2).[/tex]
From this, we can deduce that u1(t) + u2(t)t = 32.
Differentiating again:
[tex]y_p''(t) = u1''(t)e^(t/2) + u1'(t)(1/2)e^(t/2) + u1'(t)(1/2)e^(t/2) + u1(t)(1/4)e^(t/2) + u2''(t)te^(t/2) + u2'(t)e^(t/2) + u2'(t)(1/2)te^(t/2) + u2(t)e^(t/2) + u2(t)(1/2)te^(t/2).[/tex]
Setting the coefficient of [tex]e^(t/2)[/tex]equal to zero:
[tex](u1''(t) + u1'(t) + (1/4)u1(t))e^(t/2) = 0.[/tex]
Similarly, setting the coefficient of [tex]te^(t/2)[/tex]equal to zero:
[tex](u2''(t) + u2'(t) + (1/2)u2(t))te^(t/2) = 0.[/tex]
These two equations give us a system of differential equations for u1(t) and u2(t):
u1''(t) + u1'(t) + (1/4)u1(t) = 0,
u2''(t) + u2'(t) + (1/2)u2(t) = 0.
Solving these equations, we obtain:
u1(t) = C3[tex]e^(-t/2)[/tex] + C4t[tex]e^(-t/2),[/tex]
u2(t) = -4C3[tex]e^(-t/2)[/tex] - 4C4t[tex]e^(-t/2).[/tex]
Substitute the values of u1(t) and u2(t) into the assumed particular solution:
[tex]y_p(t) = (C3e^(-t/2) + C4te^(-t/2))e^(t/2) - 4C3e^(-t/2) - 4C4te^(-t/2).[/tex]
Simplifying further:
[tex]y_p(t) = C3 + C4te^(-t/2) - 4C3e^(-t/2) - 4C4te^(-t/2).[/tex]
So, the particular solution that does not involve any terms from the homogeneous solution is given by:
[tex]Y(t) = C3 + C4te^(-t/2).[/tex]
Here, C3 and C4 are arbitrary constants that can be determined using initial conditions or boundary conditions if provided.
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The approximation of 1 = integral (x – 3)e** dx by composite Trapezoidal rule with n=4 is: -25.8387 4.7846 -5.1941 15.4505
Answers
The approximation of the integral I is -5.1941 using the composite Trapezoidal rule with n = 4.
We need to divide the interval [0, 2] into subintervals and apply the Trapezoidal rule to each subinterval.
The formula for the composite Trapezoidal rule is given by:
I = (h/2) × [f(x₀) + 2f(x₁) + 2f(x₂) + ... + 2f(xₙ₋₁) + f(xₙ)]
Where:
h = (b - a) / n is the subinterval width
f(xi) is the value of the function at each subinterval point
In this case, n = 4, a = 0, and b = 2. So, h = (2 - 0) / 4 = 0.5.
Now, let's calculate the approximation:
[tex]f\left(x_0\right)\:=\:f\left(0\right)\:=\:\left(0\:-\:3\right)e^{\left(0^2\right)}\:=\:-3[/tex]
[tex]f\left(x_1\right)\:=\:f\left(0.5\right)\:=\:\left(0.5\:-\:3\right)e^{\left(0.5^2\right)}\:=-2.535[/tex]
[tex]f\left(x_2\right)\:=\:f\left(1\right)\:=\:\left(1\:-\:3\right)e^{\left(1^2\right)}\:=\:-1.716[/tex]
[tex]f\left(x_3\right)\:=\:f\left(1.5\right)\:=\:\left(1.5\:-\:3\right)e^{\left(1.5^2\right)}\:=\:-1.051[/tex]
[tex]f\left(x_4\right)\:=\:f\left(2\right)\:=\:\left(2\:-\:3\right)e^{\left(2^2\right)}\:=\:-0.065[/tex]
Now we can plug these values into the composite Trapezoidal rule formula:
I = (0.5/2) × [-3 + 2(-2.535) + 2(-1.716) + 2(-1.051) + (-0.065)]
= (0.25)× [-3 - 5.07 - 3.432 - 2.102 - 0.065]
= -5.1941
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is it A. B. Or C.
please help
Answers
Answer:c?
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Greg and cc went to the burger stand and bought dinner. Greg had 2 cheeseburgers and 5 fries. CC bought 3 cheeseburgers and 2 fries. Greg paid $24.75. CC also paid $24.75. How much would 2 cheeseburgers and 3 fries cost?
Answers
Answer:
20.00
Step-by-step explanation:
For a given norm on Rņwe call the matrix A ∈ Rmxn mxn isometry if ||AX|| = |x|| for all x ER". = • Show that the isometry must be regular. • Show that the set of isometries forms a
Answers
An isometry on R^n must be regular and the set of isometries forms a group under matrix multiplication.
An isometry is a linear transformation that preserves distances, meaning the norm of the transformed vector is equal to the norm of the original vector. To show that an isometry must be regular (i.e., invertible), we can assume there exists a non-invertible isometry matrix A. In this case, there exists a nonzero vector x such that Ax = 0. However, this contradicts the property of an isometry since ||Ax|| = ||0|| = 0, but ||x|| ≠ 0. Thus, an isometry must be regular.
The set of isometries forms a group under matrix multiplication because it satisfies the group axioms: closure (the product of two isometries is an isometry), associativity (matrix multiplication is associative), identity (identity matrix is an isometry), and inverses (the inverse of an isometry is also an isometry).
To learn more about associativity
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Plz help! Due tonight!
During halftime of a football game, a slingshot launches T-shirts at the crowd. A T-shirt is launched from a height of 4 feet with an initial upward velocity of 80 feet per second. The T-shirt is caught 41 feet above the field. How long will it take the T-shirt to reach its maximum height? What is the maximum height? What is the range of the function that models the height of the T-shirt over time?
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Answer? Please help!!
Answers
Answer:
true
Step-by-step explanation:
Solve: |2x − 1| < 11.
Express the solution in set-builder notation.
{x|5 < x < 6}
{x|–5 < x < 6}
{x|x < 6}
{x|–6 < x < 6}
Answers
Answer:
the second one is the answer
Step-by-step explanation:
hope that helps
Answer:
B; {x|–5 < x < 6}
Step-by-step explanation: