Answer: D
Step-by-step explanation:
For a given confidence interval and significance level, and assuming a relatively small sample size, say 25, the relationship between a T critical value and a Z critical value can be best expressed as: a T-Value > Z-Value a True O False
T-value is not always greater than Z-value. Therefore, the statement is false
False. The relationship between a T critical value and a Z critical value is not that a T value is always greater than a Z value. The choice between using a T critical value or a Z critical value depends on the specific context and assumptions of the statistical analysis.
In general, when the sample size is small (typically below 30) and the population standard deviation is unknown, a T critical value is used. The T distribution accounts for the additional uncertainty introduced by the smaller sample size, resulting in wider confidence intervals and more conservative hypothesis tests compared to the Z distribution.
On the other hand, when the sample size is large (typically above 30) or the population standard deviation is known, a Z critical value is used. The Z distribution assumes a large sample size, and it is based on the known population standard deviation or the approximation of the sample standard deviation to the population standard deviation.
Therefore, it is incorrect to state that a T-value is always greater than a Z-value. The choice between T and Z critical values depends on the specific conditions and assumptions of the statistical analysis being performed.
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Can someone help out? No BS please.
Answer:
Angle EHG
Step-by-step explanation:
If you want explanation tell me in comments
Answer:
the correct answer is angle EHB
• The ratio of cookies to eggs was 9 to
1, which means that?
? cookies
could be made using 3 eggs.
A combination lock has 38 numbers from zero to 37, and a combination consists of 4 numbers in a specific order with no repeats. Find the probability that the combination consists only of even numbers. (Round your three decimal places). The probability that the combination consists only of even numbers is.
The probability represents the combination consists only of even numbers as per given condition is equal to 0.020.
Total numbers in combination lock = 38
Numbers from 0 to 37.
To find the probability that the combination consists only of even numbers,
Determine the total number of combinations that can be formed using only even numbers
And divide it by the total number of possible combinations.
Total number of even numbers in the lock
= 19 (since there are 19 even numbers from 0 to 37)
Calculate the total number of combinations using only even numbers,
Use the concept of combinations (nCr).
Since there are 19 even numbers to choose from,
Choose 4 numbers without repetition, the number of combinations is,
Number of combinations
= ¹⁹C₄
= 19! / (4!(19-4)!)
= (19 × 18 × 17 × 16) / (4 × 3 × 2 × 1)
= 3876
Now, calculate the total number of possible combinations without any restrictions.
Since we have 38 numbers to choose from,
and choose 4 numbers without repetition, the number of combinations is,
Number of total combinations
= ³⁸C₄
= 38! / (4!(38-4)!)
= (38 × 37 × 36 × 35) / (4 × 3 × 2 × 1)
= 194,580
Finally, find the probability by dividing the number of combinations using only even numbers by the total number of combinations,
Probability
= Number of combinations using only even numbers / Total number of combinations
= 3876 / 194580
≈ 0.0199
≈ 0.020 Rounded to three decimal places.
Therefore, the probability that the combination consists only of even numbers is approximately 0.020.
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Suppose that the average screen time for all students at this middle school is 2 hours, with a standard deviation of 0.6 hours. A random sample of 36 students turns out to have an average of 2.2 hours? Calculate a standardized score for this sample average.
The calculated value of the standardized score for this sample average is 2
How to calculate a standardized score for this sample average.From the question, we have the following parameters that can be used in our computation:
Population mean = 2
Population standard deviation = 0.6
Sample size = 36
Sample mean = 2.2
The standardized score for this sample average can be calculated using
z = (Score - Sample mean)/(Sample standard deviation)
Where
Standard deviation = Population standard deviation/√n
So, we have
Standard deviation = 0.6/√36
Evaluate
Standard deviation = 0.1
So, we have
z = (2.2 - 2)/0.1
Evaluate
z = 2
Hence, the standardized score for this sample average is 2
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Glenn needs to cut pieces of ribbon that are each 1 meter long to make ribbon key chains. If he has 6 pieces of ribbon that are each 1 dekameter long, how many 1−meter pieces of ribbon can he cut?
Answer: 60
Step-by-step explanation:
A tank contains 2380 L of pure water. A solution that contains 0.07 kg of sugar per liter enters a tank at the rate 7 U/min The solution is mixed and drains from the tank at the same rate. (a) How much sugar is in the tank initially? 0 (kg) (b) Find the amount of sugar in the tank after t minutes. amount = 166.6(1-e^(-t/340)) your answer should be a function of t) (kg) (c) Find the concentration of sugar in the solution in the tank after 33 minutes. concentration = 166.6 (kg/L)
The concentration of sugar in the solution in the tank after 33 minutes is approximately 0.00734 kg/L or 7.34 g/L.
(a) Initially, the tank contains pure water, so there is no sugar in the tank. Therefore, the amount of sugar in the tank initially is 0 kg.
(b) The amount of sugar in the tank after t minutes can be calculated using the formula:
amount = 166.6(1 - [tex]e^{-t/340}[/tex])
Here, t is the time in minutes. This formula is derived from the exponential decay model, where the rate of sugar leaving the tank is proportional to the amount of sugar present. The constant 166.6 represents the equilibrium amount of sugar in the tank.
As time passes, the term [tex]e^{-t/340}[/tex] approaches 1, and the amount of sugar in the tank approaches the equilibrium amount of 166.6 kg.
(c) To find the concentration of sugar in the solution in the tank after 33 minutes, we need to divide the amount of sugar by the volume of the tank. The volume of the tank is given as 2380 L.
First, let's calculate the amount of sugar in the tank after 33 minutes using the formula from part (b):
amount = 166.6(1 - [tex]e^{-33/340}[/tex])
amount ≈ 166.6(1 - 0.895)
amount ≈ 166.6(0.105)
amount ≈ 17.493 kg
Now, we can calculate the concentration:
concentration = amount / volume
concentration = 17.493 kg / 2380 L
concentration ≈ 0.00734 kg/L
Therefore, the concentration of sugar in the solution in the tank after 33 minutes is approximately 0.00734 kg/L or 7.34 g/L.
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I got correct on this question but I wrote some of the numbers in a different order, is it okay if I wrote it in a different order on every question similar like this?
Answer:
yes and no....It depends if u got the answer correct then u got ur mark but if the teacher expects your answer a certain way then u might lose maybe just 1 mark but dont stress it looks good and u should get full marks
Determine whether the following equation is separable. If so, solve the given initial value problem. dy/dt = 2ty +1, y(0) = -3 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The equation is separable. The solution to the initial value problem is y(t) = ___ B. The equation is not separable. 9.3.28
The equation is separable. The solution to the initial value problem is y(t) = y(0) = -3.
A. The equation is separable. The solution to the initial value problem is y(t) = ___
To determine whether the given differential equation is separable, we need to check if it can be written in the form dy/dt = g(t) * h(y), where g(t) is a function of t only and h(y) is a function of y only.
In this case, the equation is dy/dt = 2ty + 1. We can rearrange it as:
dy = (2ty + 1) dt
Now, we can see that we have both y and t terms on the right-hand side, indicating that the equation is not yet separable.
Therefore, the correct choice is B. The equation is not separable.
Unfortunately, no solution can be provided for the initial value problem y(0) = -3 since the equation is not separable.
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The results of an empirical study reveal the following: n=27, sample mean = 3,000, sample standard deviation = 900. The 90% confidence interval of the true population mean is closet to: = = 2,400 and 3,400 1,200 and 4,800 2,700 and 3,300 0 2,000 and 4,000.
The 90% confidence interval is approximately 2,400 and 3,400.
The 90% confidence interval of the true population mean can be calculated using the formula: sample mean ± (critical value * standard error). Since the sample size is small (n=27), we need to use the t-distribution and its corresponding critical value. For a 90% confidence level with 26 degrees of freedom (n-1), the critical value is approximately 1.706.
Using the given values, the standard error is calculated as the sample standard deviation divided by the square root of the sample size: 900 / sqrt(27) ≈ 171.97.
Substituting the values into the formula, the 90% confidence interval is approximately 3,000 ± (1.706 * 171.97), which yields a range of approximately 2,424.5 to 3,575.5.
Therefore, the closest option to the 90% confidence interval is 2,400 and 3,400.
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Find the absolute maximum and absolute minimum of the function z = f(x, y) = 3x² – 12x + 3y2 – 12y on the domain D: x2 + y2 < 4. (Use symbolic notation and fractions where needed.)
The absolute maximum and minimum of the function z = f(x, y) = 3x² - 12x + 3y² - 12y on the domain x² + y² < 4 are not provided.
To find the absolute maximum and minimum of the function z = f(x, y) = 3x² - 12x + 3y² - 12y on the domain D: x² + y² < 4, we need to locate the critical points and examine the boundaries of the domain.
First, we find the critical points by taking the partial derivatives with respect to x and y, setting them equal to zero, and solving for x and y. However, in this case, the given function is a quadratic expression without any cross-terms, so it does not have critical points.Next, we consider the boundary of the domain D: x² + y² = 4, which represents a circle of radius 2 centered at the origin. To find the extreme values on this boundary, we can use methods like Lagrange multipliers or parametrize the boundary and evaluate the function.Since the absolute maximum and minimum values are not provided, further calculations are needed to determine these values for the given function on the given domain.
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What is the compound ratio of 3:4 and 4:5?
The equation for the rollercoaster before is f(x)=-0.2x^2-2x
Find the vertex algebraically
Hint: x=-b/2a
??? The answer is not able to be found for the fact that there are 3 numbers all coming from x.
Sarah needs to make 3 pies. She needs 6 apples to make one apple pie, 9 peaches to make one peach pie, and 32 cherries to make one cherry pie. The graph shows how many apples, peaches, and cherries Sarah has.
What combination of pies can she make?
The combination of pies she can make are:
one cherry pie, one peach pie and one apple pie
How to Interpret Bar Graphs?A bar graph is defined as a diagram in which the numerical values of variables are represented by the height or length of lines or rectangles of equal width.
We are given the following parameters:
Number of apples to make one apple pie = 6
Number of peaches to make one peach pie = 9
Number of cherries to make one cherry pie = 32
From the bar graph, she has:
26 apples
12 peaches
34 cherries
Since she wants to make 3 pies, then she can make:
one cherry pie, one peach pie and one apple pie
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Help me with this please
Answer:
x = 138
Step-by-step explanation:
Exterior angle thm:
68 + 70 = x
x = 138
I have two questions
1.) what are 3 equivalent ratios for 5/45
2.) what are 3 equivalent ratios for 3/5
Find the particular solution determined by the given condition. ds/dt = 16t^2 + 9t - 6; s = 120 when t = 0 The particular solution that satisfies the given condition is s =
The particular solution that satisfies the given condition is s = (16/3)t³ + (9/2)t² - 6t + 120
To find the particular solution of the differential equation ds/dt = 16t² + 9t - 6 with the condition s = 120 when t = 0, we need to integrate the right-hand side of the equation with respect to t and then solve for the constant of integration using the given condition.
First, let's integrate the right-hand side of the equation:
∫(ds/dt) dt = ∫(16t² + 9t - 6) dt
Integrating term by term, we get:
s = (16/3)t³ + (9/2)t² - 6t + C
Now, we can use the given condition s = 120 when t = 0 to determine the value of the constant of integration C:
120 = (16/3)(0)³ + (9/2)(0)² - 6(0) + C
120 = C
Therefore, the particular solution that satisfies the given condition is:
s = (16/3)t³ + (9/2)t² - 6t + 120
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S someone please help me
Please answer correctly I will mark you Brainliest!
Answer:
1047.12in³
Step-by-step explanation:
The volume of the sphere is:
V= 4/3 πr³
Where r is radius
Therefore the volume of each pinata is:
V= 4/3 x π x 5³
V= 523.6in³
The total:
V = 523.6 + 523.6 = 1047.12in³
Serenity is going to invest $850 and leave it in an account
for 5 years. Assuming the interest is compounded
annually, what interest rate, to the nearest hundredth of a
percent, would be required in order for Serenity to end up
with $1,130?
Answer:
5.86
Step-by-step explanation: its right on delta math
Suppose Nate loses 38% of all thumb wars.
(a) What is the probability that Nate loses two thumb wars in a row?
(b) What is the probability that Nate loses three thumb wars in a row?
(c) When events are independent, their complements are independent as well. Use this result to determine the probability that Nate loses three thumb wars in a row, but does not lose four in a row.
1. The probability that Nate loses two thumb wars in a row is: _______________
2. The probability that Nate loses three thumb wars in a row is:_____________
a. Probability of losing the second thumb war is also 0.38.
b. Probability of losing the third thumb war is also 0.38.
Given that Nate loses 38% of all thumb wars.
We can use the probability of losing the thumb war as
p=0.38.
The probability of winning is
1-0.38=0.62.
a) Probability of losing two thumb wars in a row is:
P(loses two in a row) = P(loses first) × P(loses second)
The probability of losing the first thumb war is 0.38.
The probability of losing the second thumb war is also 0.38
So,
P(loses two in a row) = (0.38) × (0.38)
= 0.1444
b) Probability of losing three thumb wars in a row is:
P(loses three in a row) = P(loses first) × P(loses second) × P(loses third)
The probability of losing the first thumb war is 0.38.
The probability of losing the second thumb war is also 0.38
The probability of losing the third thumb war is also 0.38.
So,
P(loses three in a row) = (0.38) × (0.38) × (0.38)
= 0.054872
c) When events are independent, their complements are independent as well.
If the probability of winning the thumb war is p, then the probability of losing the thumb war is 1-p.
The complement of "losing three in a row" is "not losing three in a row".
P(not loses three in a row) = 1 - P(loses three in a row)P(not loses three in a row)
= 1 - 0.054872
= 0.945128
The probability that Nate loses three thumb wars in a row, but does not lose four in a row is the probability of losing three minus the probability of losing four in a row.
P(loses three but not four in a row) = P(loses three in a row) - P(loses four in a row)
P(loses four in a row) = P(loses three in a row) × P(does not lose the next)
P(loses four in a row) = (0.38) × (0.38) × (0.38) × (0.62)
= 0.02081416
P(loses three but not four in a row) = 0.054872 - 0.02081416
= 0.03405784
The probability that Nate loses two thumb wars in a row is 0.1444
The probability that Nate loses three thumb wars in a row is 0.054872.
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Tamika is making a flag design in the shape of a parallelogram. Which x- and y-values must she use in order to guarantee that the flag is in the shape of a parallelogram?
Answer:
x = 1/2
y = 3
Step-by-step explanation:
Remark
The diagonals of a parallelogram cut each other in half. That means that x lengths are equal and the y lengths are equal
Equations
3y = y + 6
10x = 6x + 2
Solution for x
10x = 6x + 2 Subtract 6x from both sides
10x - 6x = 6x - 6x + 2
4x = 2 Divide by 4
4x/4 = 2/4
x = 1/2
Solution for y
3y = y + 6
3y - y = y- y + 6
2y = 6
y = 3
Answer:
Step-by-step explanation:
What is the area, in square inches of a rectangle will the dimensions with 7/8 3/16 in the diagram below?
Answer:
1 1/16
Step-by-step explanation:
you you have to add 7/8 + 3/16 to get the answer of one whole and 1/16
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!
Answer:
pi, and square root of 2
I don't think you're ACTUALLY going to give me brainliest
Please help if you would want brianleist!! :D ^^
Answer:
384
Step-by-step explanation:
v= L x W x H
v= 4 x 2 x 1.2
v= 9.6
9.6 x 40 = 384
lmk if you have any questions :)
Answer:
A
Step-By-Step Explanation:
Step One: The first step is to figure out the volume of one. The volume formula is length times width times height. We have all the dimensions so: 4 times 2 times 1.2= 9.6.
Step Two: Now, we just mutiply the number by 40 since there are 40 slabs: 384.
what is the longitudinal position latitudinal position of Nepal
Step-by-step explanation:
I think that is your answer because in the Himalayas it lies between latitudes 26.
How many pints is 80 cups
Answer:
40
Step-by-step explanation:
2 cups = 1 pt
therefore
1/2 is the equation
...
80/2 = 40
Find the maximum heigh reached by the rocket
y=-16x^2+146x+137
Answer:
Step-by-step explanation:
se gana 10000 y 2
Given the following facts about the moment generation Max+b) (+) . et My lat). If a normal random Variable, with mean cand stand and deviation d, (I) then My (4) variable and standard with mean Mr deviation bx = 4, and that y=34+5. use the moment generating & unction uniqueness theoren, and facts (I) and (IT) above to prove that is a normal random variable.
Since the mean and variance of y are the same as those of a normal random variable, y is a normal random variable.
The given moment generating function is Mx(t) = e^(t(4 + 5t + 17t^2/2)), where t is the moment. The moment generating function of a normal random variable is given by Mx(t) = e^(μt + σ^2t^2/2).Comparing the two, we get:μ = 4σ^2 = 17/2We can now compute the first and second moments of y, using the moment generating function: My(t) = e^(t(34 + 5t)) × e^(t(4 + 5t + 17t^2/2))= e^(34t + 9t^2 + 17t^3/2 + 4t + 5t^2) = e^(34t + 14t^2 + 17t^3/2)So,μy = My(0) = 1 and σy^2 = My''(0) - My'(0)^2= (17/2) - 4 = 9/2
Since the mean and variance of y are the same as those of a normal random variable, y is a normal random variable.
This completes the proof using the moment generating function uniqueness theorem.
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The moment generating function (MGF) of a random variable is a mathematical function that uniquely defines the probability distribution of that variable. Therefore, if the MGF of a random variable is the same as that of a known distribution, the random variable follows that distribution.
This is known as the uniqueness theorem of moment generating functions.
Using the given moment generating function of a random variable X (Max+b)(+).etMy.lat), we need to prove that X follows a normal distribution. Here, Max+b = a, My = m, and = s (standard deviation).
Using the MGF, we can find the moments of the distribution. Differentiating the MGF 'n' times gives the nth moment about zero. We can use this to find the mean and variance of the distribution.
Therefore, the mean of the distribution is the first derivative of the MGF at t=0,
and the variance is the second derivative of the MGF at t=0.
Using facts (i) and (ii), we can write the MGF of X as:
(Mx(t)) = [(b + mt) + a(s^2 + m^2)/2] / [(s^2/2) + (t^2/2)]
Taking the first derivative of Mx(t) and substituting t=0, we get:
[tex]E(X) = [(b + m*0) + a(s^2 + m^2)/2] / [(s^2/2) + (0^2/2)]E(X) = (b + am) / (s^2/2) + 0E(X) = (2(b + am))/s^2[/tex]
This gives us the mean of the distribution as
(2(b + am))/s^2
Taking the second derivative of Mx(t) and substituting t=0, we get:
[tex]Var(X) = [(b + m*0) + a(s^2 + m^2)/2] / [(s^2/2) + (0^2/2)]Var(X) = [a(s^2 + m^2)/2] / (s^2/2) + 0Var(X) = a(s^2 + m^2)/s^2 - 1[/tex]
We know that the MGF of a normal distribution with mean m and variance s^2 is given by:
[tex](Mn(t)) = e^(mt + s^2t^2/2)[/tex]
Comparing this with the given MGF of X, we see that they are equal.
Therefore, X follows a normal distribution with mean (2(b + am))/s^2 and variance a(s^2 + m^2)/s^2 - 1.
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Hhhhhhhhhhjhhjhhjhjjjjjjhhhhhhhhhh
Answer:
i know right? It's so difficult till I'm brainless when I try to solving it
Answer:
same tbh
Step-by-step explanation: