Which of the following equations describes the graph shown below?
(1) y = log5 x
(3) y = log, x
(2) y = log₂ x
(4) y = log₁ x

Answer:56

Step-by-step explanation:20% of 70 is 14 dollars so you have to subtract 70-14=56.

The equation is 2w + 10 = 26.

The number of weeks the driving class lasts is 8 weeks.

With that,

Terrence signed up for the Safe Venture driving school.

He will spend 10 hours driving with an instructor and will also attend weekly 2-hour classes.

When Terrence completes the 26 total hours of instruction, he will take his driver's test.

We have to determine,

Which equation can you use to find w, the number of weeks the driving class lasts.

According to the question,

He will spend 10 hours driving with an instructor and will also attend weekly 2-hour classes.

Then, The equation of the number of weeks the driving class lasts,

= 2w + 10

When Terrence completes the 26 total hours of instruction, he will take his driver's test.

2w + 10 = 26

He spends 10 hours driving and adding on 2 more classes with a total of 26 hours.

Therefore,

The number of weeks the driving class lasts,

2W + 10 = 26

2W = 26 - 10

2W = 16

W = (16/2)

W = 8

Hence, The number of weeks the driving class lasts is 8 weeks.

Answer:

She spend $7 a month on downloads.

Step-by-step explanation:

y = the total spent on downloads

x = number of months

m = the amount spent each month

y = mx

45.50 = m(6.5)  Divide both sides by 6.5

7 = m

The values of the expressions are x = √6, y = 2√3 and z = √2

From the question, we have the following parameters that can be used in our computation:

[tex]x =\sqrt{12-3\sqrt{7} } - \sqrt{12 + 3\sqrt{7} }[/tex]

[tex]y = \sqrt{7-4\sqrt{3 } } - \sqrt{7 + 4\sqrt{3} }[/tex]

[tex]z = \sqrt{2 + \sqrt{3} } - \sqrt{2 - \sqrt{3} }[/tex]

We have

[tex]x =\sqrt{12-3\sqrt{7} } - \sqrt{12 + 3\sqrt{7} }[/tex]

Take the square of both sides

So, we have

[tex]x^2 =12-3\sqrt{7} + 12 + 3\sqrt{7} - 2(\sqrt{12-3\sqrt{7} } * \sqrt{12 + 3\sqrt{7} })[/tex]

This gives

x² = 12 - 3√7 + 12 + 3√7 - 2√81

Evaluate the roots

So, we have

x² = 12 - 3√7 + 12 + 3√7 - 18

Evaluate the sum and the difference

x² = 6

Take the square roots of both sides

x = √6

Using the same steps above, we have

[tex]y = \sqrt{7-4\sqrt{3 } } - \sqrt{7 + 4\sqrt{3} }[/tex]

Square both sides

So, we have

[tex]y^2 = 7 - 4\sqrt 3 + 7 + 4\sqrt 3 - 2 * \sqrt{7-4\sqrt{3 } } * \sqrt{7 + 4\sqrt{3} }[/tex]

This gives

[tex]y^2 = 7 - 4\sqrt 3 + 7 + 4\sqrt 3 - 2 * 1[/tex]

Evaluate

y² = 12

Take the square root of both sides

y = 2√3

Lastly, we have

[tex]z = \sqrt{2 + \sqrt{3} } - \sqrt{2 - \sqrt{3} }[/tex]

Square both sides

[tex]z^2 = 2 + \sqrt 3 + 2- \sqrt 3 - 2 * \sqrt{2 + \sqrt{3} } * \sqrt{2 - \sqrt{3} }[/tex]

This gives

z² = 4 - 2 *1

Evaluate

z = √2

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Answer:

multiple

Step-by-step explanation:

I had the same question and guessed and that was the answer lol

The required values of the compound amount are $56740.76, $56982.05, $57191.25, $57232.60 and $57234.01 respectively.

What is compound interest?

Compound interest is when an amount receives interest on top of it each time interest is paid on the original amount. The main (initial) sum and the interest that has already accrued over the course of prior periods are used to calculate compound interest.

Given, Principal (P) = $42,400

interest rate(r) = 6% per year = 0.06

time(t) = 5 years

The compound amount is given by

[tex]A = P(1+\frac{r}{t} )^{nt}[/tex]

For compounded annually, n=1

[tex]A = 42400(1+0.06)^{1*5}[/tex] = $56740.76

For compounded semi-annually, n=2

[tex]A = 42400(1+\frac{0.06}{2})^{2*5}[/tex] = $56982.05

For compounded monthly, n=12

[tex]A = 42400(1+\frac{0.06}{12})^{12*5}[/tex] = $57191.25

For compounded daily, n=365

[tex]A = 42400(1+\frac{0.06}{365})^{365*5}[/tex] = $57232.60

For compounded continuously,

[tex]A=Pe^{rt} = 42400e^{0.06*5}[/tex] = $57234.01

Hence, these are the required values of the compound amount.

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Answer:

A.  1,500

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{7cm}\underline{Sum of the first n terms of a geometric series}\\\\$S_n=\dfrac{a(1-r^n)}{1-r}$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the first term. \\ \phantom{ww}$\bullet$ $r$ is the common ratio.\\ \phantom{ww}$\bullet$ $n$ is the $n$th term.\\\end{minipage}}[/tex]

The given scenario can be modelled as a geometric series.

If Marcus' goal is to sell 15,000 t-shirts during the first 6 months, then:

If he projects that the number of t-shirts he sells will increase by 20% each month then the common ratio is:

Substitute these values into the formula and solve for a:

[tex]\implies 15000=\dfrac{a(1-1.2^6)}{1-1.2}[/tex]

[tex]\implies 15000(1-1.2)=a(1-1.2^6)[/tex]

[tex]\implies a=\dfrac{15000(1-1.2)}{1-1.2^6}[/tex]

[tex]\implies a=1510.586188[/tex]

Therefore, the approximate number of T-shirts Marcus needs to sell during the first month to meet his goal is 1,500.

Check:

Total = 1511 + 1813 + 2176 + 2611 + 3133 + 3760 = 15004

Check:

Total = 1500 + 1800 + 2160 + 2592 + 3110 + 3732 = 14894 ≈ 15000

Answer:

4 916 083

Step-by-step explanation:

population in 1990

1.5 : 100 = x : 4 786 000

x = 1.5 · 4 786 000 / 100

x = 1.5 · 47 860

x = 71 790

4 786 000 + 71 790 = 4 857 790

population in 2000

1.2 : 100 = x : 4 857 790

x = 1.2 · 4 857 790 / 100

x = 0.012 · 4 857 790

x = 58 293.48

4 857 790 + 58 293.48 = 4 916 083.48

The equation of the new function is: f(x) = (x- 3)²

Function is a type of relation, or rule, that maps one input to specific single output.

The translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s range(involving values of y) or in it’s domain(involving values of x).

We know that the function f(x+m) is equals to the function f(x) translated 'm' times to the left.

Therefore, to find the translate the function f(x) = x² twelve units to the right, we have given;

f(x- 3) = (x- 3)²

Therefore, the new function is: f(x) = (x- 3)²

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The subtraction of significant figures between the distance is 5.01 × 10⁷km

In this problem, we have to subtract the difference between the distance of Venus and Mercury. When subtracting significant digits, the amount of significant digits that will be in the final answer is determined by the number of significant digits present after the decimal place in the numbers we are subtracting.

The distance between Venus and Mercury can be calculated as

1.08 × 10⁸ - 5.79 × 10⁷ = 50,100,000km

To express the value in significant figures, we will have

50,100,000 = 5.01 × 10⁷km

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The equation of the parabola that passes through (0, -5) and has a vertex at (-1, 4) will be y = -9(x + 1)² + 4.

Let the point (h, k) be the vertex of the parabola and a be the leading coefficient.

Then the equation of the parabola will be given as,

y = a(x - h)² + k

The vertex of the parabola is at (-1, 4). Then the equation is given as,

y = a(x + 1)² + 4

The equation passes through (0, -5), then we have

y = a(x + 1)² + 4

-5 = a(0 + 1)² + 4

-5 = a + 4

a = -9

Then the equation of the parabola that passes through (0, -5) and has a vertex at (-1, 4) will be y = -9(x + 1)² + 4

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80, 7, and 2.87 are not irrational numbers.

What is an irrational number?

An irrational number is a type of real number which cannot be represented as a simple fraction. It cannot be expressed in the form of a ratio. If N is irrational, then N is not equal to p/q where p and q are integers and q is not equal to 0. Example: √2, √3, √5, etc all are irrational.

Given numbers: 80, 7, 2.87, √59

80 = It is a rational number

7 = It is a rational number

2.87 = It is a rational number

√59 = It is an irrational number.

Hence, 80, 7, and 2.87 are not irrational numbers.

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Answer:

2.4.6.8.10

Step-by-step explanation:

that's the answer

Answer:

1, 4, 9, 16, 25, 36, 49, 64, 81, 100

Step-by-step explanation:

1, 4, 9, 16, 25, 36, 49, 64, 81, 100, multiply all numbers frmo 1 to 10

Answer:

B: 3(x-6) = 3x-18

Step-by-step explanation:

The left and right sides of this equation are actually equal! We can see this by dividing the 3 on the left through the parentheses. This gives us [tex]3x-18[/tex], which is equal to the right-hand side of the equation!

To solidify this, we add 18 to both sides, and subtract 3x from both sides, which gives us that 0=0, so there are infinitely many solutions for x(since no matter what x is, it will result in 0=0 which is always true).

I hope this helps!

To dig the pool, he rents a small backhoe for $95.50 a day. If his total bill comes to $286.50, for  3 days does he rent the backhoe.

What is backhoe?

A backhoe, also known as a rear actor or back actor, is a type of digging apparatus, often known as a digger, that has a digging bucket attached to the end of a two-part articulated arm. Usually, it is attached to the rear of a tractor or front loader, the latter of which is known as a "backhoe loader."

$286.50/$95.50= 3

Henry is building an in-ground pool at his house. He is doing most of the work himself to save money. To dig the pool, he rents a small backhoe for $95.50 a day. If his total bill comes to $286.50, for 3 days does he rent the backhoe.

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An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

1 pound = $1.38

175 pounds = $241.50

The number of pounds for the strawberries order of $241.50 is

175 pounds.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Cost of strawberries per pound = $1.38

The cost of a strawberry order = $241.50

The number of pounds for the order of $241.50.

1 pound = $1.38

Multiply 241.50/1.38 on both sides.

241.50/1.38 x 1 pound = $241.50

175 pounds = $241.50

Thus,

The number of pounds for the strawberries order of $241.50 is

175 pounds.

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The complete question is:

A grocer can buy strawberries for $1.38 per pound.

Write an equation relating c, the cost, and p, the pounds of strawberries.

A strawberry order cost $241.50.

How many pounds did the grocer order?

Answer:

Step-by-step explanation:

Step 1: Use point-slope form and substitute in the x and y values

y-y1=m(x-x1)

y-(1)=2(x-(-3))

Step 2: Simplify the expression

y-1 = 2(x+3)

Add one to the other side

y= 2(x+3)+1

Multiple 2 by (x+3)

y=2x+6+1

Add common terms

y=2x + 7

The probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

Probability defines the likelihood of occurrence of an event. There are many real-life situations in which we may have to predict the outcome of an event. We may be sure or not sure of the results of an event. In such cases, we say that there is a probability of this event to occur or not occur. Probability generally has great applications in games, in business to make probability-based predictions, and also probability has extensive applications in this new area of artificial intelligence.

The probability of an event can be calculated by probability formula by simply dividing the favorable number of outcomes by the total number of possible outcomes. The value of the probability of an event to happen can lie between 0 and 1 because the favorable number of outcomes can never cross the total number of outcomes. Also, the favorable number of outcomes cannot be negative.

[tex]P(50.5 < = X < = 51.25) =\frac{51.25-50.5}{54-49 } = \frac{0.75}{5} = 0.15[/tex]

P = 0.15 means that the probability is 15%.

Thus, the probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

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Answer:

g(x)=3^x+7

Step-by-step explanation:

f(0)=3^0

that is the y-intercept

now we can take the known y-intercept of g(x) which is 8 and then we can get our b in the y=mx+b equation.

Answer: 20

Step-by-step explanation:

Using the side splitter theorem yields:

[tex]\frac{?}{5}=\frac{12}{3}\\\\\frac{?}{5}=4\\\\?=20[/tex]

Answer:

20

Step-by-step explanation:

the scale factor from the little triangle to the larger triangle is 5/4

[tex]\frac{5x}{4}[/tex] = x + 5  Multiple through by 4 to clear the fraction

5x = 4x + 20  Subtract 4x from both sides

x = 20

Answer:

The surface area of cube = 6 side2

According to the question,

Let the side of the cube be x

Each side of the cube increased by 50%.

= x(100 + 50)/100 = 1.5x

The surface area of the cube

⇒6x²

The new surface area of the cube (side = 1.5x)

⇒ 6 × 2.25x²

Increase percentage in the surface area

⇒((6 x 2.25 x²-6x²)/6 x² }× 100

⇒ 125%

The required value of the x₂ is given as -0.500000.

Given that,
xₙ₊₁ = [[xₙ]³ - 1]/4, x₁ = -1

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
xₙ₊₁ = [[xₙ]³ - 1]/4, x₁ = -1
put n = 2
x₂ = [[x₁]³ - 1]/4
    =  -1 - 1 /4
    = -2/4
    = -1/2 = 0.500000

Thus, the required value of the x₂ is given as -0.500000.

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Answer:

Step-by-step explanation:

24-29=-5

using the number line:)

Answer:

4-23=4b

Step-by-step explanation:

The 4th proportional of the given ratio is 4/3. option C

The range of the data 112, 121, 184, 189, 177, 190 is 78. option A

It follows from the concept of proportions that the ratios can be represented as follows;

21 : 7 = 4 : 3a + 1

21/7 = 4 / (3a + 1)

cross product

21 × (3a + 1) = 4 × 7

63a + 21 = 28

subtract 21 from both sides

63a = 28 - 21

63a = 7

a = 7/63

a = 1/9

So,

3a + 1

= 3(1/9) + 1

= 3/9 + 1

= 1/3 + 1

= 1 ⅓

= 4/3

21 : 7 = 4 : 4/3

Range of the data:

112, 121, 184, 189, 177, 190

Recall, the range of a dataset is the difference between the maximum and minimum data values and hence, we have;

Range = Highest data value - Lowest data value

= 190 - 112

= 78

Therefore, the range of the given set of data is 78.

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The constant that must be added to both sides of the equation to find the perfect square is b/2a.

The 2nd equation in x is known as a quadratic function. Ax2 + Bx + c = 0 is the quadratic equation in standard form, wherein there a and b are the coefficient, x is the constant, and c is the constant.

The presence of a non-zero component in the coefficient of x2 (a ≠ 0) is the first prerequisite for an expression to be a quadratic equation.

As per the given information in the question,

The equation for the quadratic equation is,

Ax² + Bx + c = 0

And for finding the roots,

d = b² - 4ac

Then, use the formula (-b±√d)/2a.

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The lines C and D are parallel.

What is a line?

In pure mathematics, a line is an infinitely long object with no dimension, depth, or curvature. Thus, lines ar one-dimensional objects, although they'll exist in 2, three, or higher dimension areas

Main body:

As Line LM cuts the line at C the angle made by both line is 48°

and line NP cuts the line at D , the angle made by line is 132°

we know that to make a line parallel , the sum of angle on one side of the line should be 180°

∠C +∠D = 48° +132°

             = 180°

Hence , the lines C and D are parallel.

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The solution of the given quadratic equation is x = 1.37, - 1.37.

What is a quadratic equation?

A quadratic equation is a second-order polynomial equation in one variable using the formula x = ax2 + bx + c = 0 and a 0.

                            The fundamental theorem of algebra ensures that it has at least one solution because it is a second-order polynomial problem. Real or complex solutions .

Given quadratic equation:

9x² = 17

⇒ x² = (17 / 9)

⇒ x = ± √(17 / 9)

⇒ x = ± (√17) / 3

⇒ x = 1.37, - 1.37

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Answer:

13.3=c

Step-by-step explanation:

The hypotenuse can be found with the equation [tex]a^2+b^2=c^2[/tex].  For this problem, let

a=8.3

b=10.4

So,

[tex](8.3)^2+(10.4)^2=c^2\\177.05=c^2\\\sqrt{177.05}=\sqrt{c^2}\\13.31=c[/tex]

Answer:

39.05 miles

Step-by-step explanation:

0.05+0.1+38

The required polynomial function is f(x) = (x + i)² which is degree 2 with the zeros x = √2 and x = -i.

We have to determine a polynomial function for each set of zeros:

x = √2, -i

To write a polynomial function with the zeros x = √2 and x = -i, we can start by setting the function equal to zero and substituting in the zeros:

f(√2) = 0

f(-i) = 0

We can then solve for the coefficients by expressing the polynomial function in terms of (x - √2) and (x + i).

For example, we can write:

f(x) = (x - √2)(x + i)q(x)

for some polynomial q(x).

Substituting in the zeros, we get:

f(√2) = (√2 - √2)(√2 + i)q(√2) = 0

f(-i) = (-i - √2)(-i + i)q(-i) = 0

Solving for q(x), we find:

q(x) = (x + i)/(x - √2)

Substituting this back into the original equation, we get:

f(x) = (x - √2)(x + i)(x + i)/(x - √2)

f(x) = (x + i)²

This is a polynomial function of degree 2 with the zeros x = √2 and x = -i.

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