Which of the following best classifies a quadrilateral with coordinates A(7,0), B(3, 1), C(4,7), and D(8, 6)?
A.Rectangle
B.Parallelogram
C.Trapezoid
D.Square

The second difference of this quadratic pattern is 2.

The first term of this quadratic pattern is 10.

A sequence of numbers has a quadratic pattern when its sequence of second differences is constant. Therefore,

let the first and fourth term be a and b.

Therefore,

first difference:

1 - a; - 6 - 1 = -7; b + 6; -14 - b;

Second difference:

The second difference is constant . Therefore,

-7  - (1 - a) = -8 + a; b + 6 + 7 = b + 13; -14 - b - b - 6 = -2b - 20;

Therefore,

b + 13 = -8 + a

b  - a = -21

Then,

-2b - 20  = b + 13

-3b = 33

b = 33 / -3

b = - 11

Therefore,

- 11 - a = - 21

-a = -21 + 11

-a = -10

a = 10

Hence, the second difference = b + 13 = -11 + 13 = 2

First term = a

Therefore,

a = 10

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Answer:

Let's simplify step-by-step.

−2^2 − 13x + 34

= −4 + −13x + 34

Combine Like Terms:

= −4 + −13x + 34

= ( −13x ) + ( −4 + 34 )

= −13x + 30

Answer:

= −13x + 30

Answer:

D

Step-by-step explanation:

Just stating the temperature, hope this helps

Answer:

temperature of 10 degrees

Step-by-step explanation:

every other option is negative, like owing $10 means you will have 10 less dollars, a hole 10 feet deep is 10 feet under the ground's surface, so they would be represented by -10. A temperature of 10 degrees is the only positive option :)

Answer:

96

Step-by-step explanation:

Answer:

96 cm

Step-by-step explanation:

Length + Width + Length + Width = Perimeter

Length + 74 cm + Length + 74 cm = 340 cm

74 + 74 = 148

340 - 148 = 192

192 ÷ 2

96

Check:

74cm + 96cm + 74cm + 96cm = 340 cm

Step-by-step explanation:

70x4=280

12x4=48

48+280=328

Answer:

0.41

Step-by-step explanation:

All probability equals 1. So if the probability that something will happen is x, then the probability that it will not happen is 1-x

Answer:708

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Area of right angle Triangle:

6.5 * 9 * 1/2 = 29.25

2nd way to find area:

1/2 * base * height

Since we have area and base:

1/2 * 11.1 * h = 29.25

= 5.27m

= 5m (nearest tenth)

The height h of the roof to the nearest tenth is 5.3 m

Right angle triangle has one of its angles as 90 degrees. The triangles are likewise similar and can be used to find the height h of the roof.

Therefore,

cross multiply

11.1 h = 9 × 6.5

11.1 h = 58.5

divide both sides by 11.1

11.1 h / 11.1 = 58.5 / 11.1

h = 5.27027027027

h = 5.3 m

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Answer:

I think its 72,000

Step-by-step explanation:

there's 144 months in 12 years and i just multiplied it by 500

Answer:

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]

Step-by-step explanation:

Given

[tex]tan\theta = 3[/tex]

Required

Find

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex]

Calculate [tex]tan(\theta + \pi) \ and\ tan(\theta+2\pi)[/tex]

Using tan rule

[tex]tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}[/tex]

So:

[tex]tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]

[tex]tan(\theta + \pi) = \frac{tan\theta}{1 }[/tex]

[tex]tan(\theta + \pi) = \tan\theta[/tex]

[tex]tan(\theta+2\pi)[/tex]

[tex]tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}[/tex]

[tex]tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]

[tex]tan(\theta + 2\pi) = \tan\theta[/tex]'

'So:

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex] [tex]= tan\theta +tan\theta +tan\theta[/tex]

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3[/tex]

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]

Answer:

Step-by-step explanation:

Volume of water is the difference of volume of vase at 12 in height and the total volume of marbles.

Volume of cylinder up to water level:

Volume of marbles:

Volume of water:

Correct choice is C

Answer:

C. π(3in)2(12in) − 9(four over threeπ(1.5in)3)

Step-by-step explanation:

Vs = πr²h = π(6/2)²(12) = π×(3 in)²×(12 in)

Vm = 9(4/3πr³) = 9×(4/3×π(3/2)³) = 9×(4/3×π×(1.5 in)³)

Vw = Vs - Vm = π×(3 in)²×(12 in) - 9×(4/3×π×(1.5 in)³)

Correct choice is C

Answer:

-4

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

Answer:

Step-by-step explanation:

Its c

Answer:

12.4

Step-by-step explanation:

[tex]AL= 2r\pi (\frac{angle}{360} )[/tex]

[tex]AL= 2(7.9)(\pi )(\frac{90}{360})\\[/tex]

Answer:

3 packages

Step-by-step explanation:

first we need to make this into a equation that we can solve!

x = 21/7

if we use our times tables then we know that

7 * 3

= 21

so knowing what we know, lets go back to the question/ equation!

21/7

= 3

( if you wanted, that could also be a way to double check you answer :)

hope this helped you and if you have any more questions then please ask me! :)

Answer:

3.87

Step-by-step explanation:

2.58/2=1.29=1/3 pounds

1.29*3=3.87

Answer:

=15x-7-23+2

=-8x-7+2

=-8x-5

Step-by-step explanation:

Answer:

Step-by-step explanation:

The equation for volume is incorrect. The volume of a cylinder with radius r and height h is πr²h.

volume = π(2b)²(5b+3)

= π(4b²)(5b+3)

= π(20b³+12b²)

The formula for the volume of the given circular cylinder in terms of b is [tex]V = 20b^3 + 12b^2[/tex]

The given expression:

volume of circular cylinder, V = r²h

r = 2b

h = 5b + 3

To find:

To find the volume of the cylinder in terms of b, we will substitute the given values of r and h as follows;

[tex]V = r^2 h\\\\V = (2b)^2 (5b + 3)\\\\simplify \ the \ expression;\\\\V = 4b^2 (5b + 3)\\\\remove \ the \ bracket \ by \ multiplying \ through \ by \ 4b^2\\\\V = 20b^3 + 12b^2[/tex]

Thus, the volume of the cylinder in terms of b is [tex]V = 20b^3 + 12b^2[/tex]

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Answer:

f(6) =34

Step-by-step explanation:

f(x) = 5x + 4

Let x= 6

f(6) = 5*6 +4

     = 30 +4

     = 34

Answer:

$196 es el precio del articulo

Answer:

B is the correct answer

Answer:

250

Step-by-step explanation:

100 / 22 = 4.54545455

4.54545455 x 55 = 250

Answer: 250

Step-by-step explanation:

Ur welcome

(55x100)/22

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision    Variable        Constraint              Constraint

A                     65                          65                         100

B                     80                          80                         80

C                     90                         90                          90

                      14100                    300                        300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

                             A              B                  C                Unit price

Need of X          2                 1                   1                     $20

Need of Y           2                3                  2                    $30

Need of Z           2                2                  3                    $25

Price of  

manufac -      $200          $240            $220      

turing

Now,  for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.  

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160  

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit  --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

[tex]{(100 - A) + (80 - B) +(90 - C) } + \$40[/tex]

This should be subtracted from profit.

So, we have to maximize the profit  

[tex]Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};[/tex]

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

[tex]2A + B +C \le 300[/tex] due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

[tex]A \le 100[/tex]

[tex]B \le 80[/tex]

[tex]C \le 90[/tex]

and [tex]A, B, C \ge 0[/tex] because they are positive quantities

The objective is:

[tex]\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}[/tex]

A, B, C [tex]\to[/tex] Decision Varaibles;

Constraint are:

[tex]A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0[/tex]