When a new highway is formed, the smoothness of the surface must be verified. A contractor is making a bid for this job and has a truck with the relevant detector. This detector must meet minimum standards for detecting irregularities in the road surface. If there is a roadway irregularity, there is a probability of 0.99 the detector will detect it. If there is no irregularity, there is a 0.06 probability detector will identify it as irregular (a false positive). It is known through experience that 3 miles out of 100 miles actually contain irregularities.
a. What is the probability the detector will identify a random mile of roadway as irregular? Give your answer to four decimal places.
b. Given a randomly selected miles has been identified as irregular by the detector, what is the probability it actually is irregular? Give your answer to four decimal places.

Answers

Answer 1

Answer:

a) 0.0879 = 8.79% probability the detector will identify a random mile of roadway as irregular.

b) 0.3379 = 33.79% probability it actually is irregular

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

a. What is the probability the detector will identify a random mile of roadway as irregular?

99% of 3%(it is irregular).

6% of 97%(false positive). So

[tex]p = 0.99*0.03 + 0.06*0.97 = 0.0879[/tex]

0.0879 = 8.79% probability the detector will identify a random mile of roadway as irregular.

b. Given a randomly selected miles has been identified as irregular by the detector, what is the probability it actually is irregular? Give your answer to four decimal places.

Conditional probability:

Event A: Identified as irregular

Event B: It is irregular.

0.0879 = 8.79% probability the detector will identify a random mile of roadway as irregular, which means that [tex]P(A) = 0.0879[/tex]

99% of 3% arre irregulars identified as, which means that [tex]P(A \cap B) = 0.03*0.99 = 0.0297[/tex]

The desired probability is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0297}{0.0879} = 0.3379[/tex]

0.3379 = 33.79% probability it actually is irregular


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use Photomath and then you can get your answer!

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Step-by-step explanation:

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Answers

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Your answer would be A and B

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Answers

Answer:

his salary per game is  669,643

Step-by-step explanation:

The computation of the salary per game in the year 2009 is shown below

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The same is relevant

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Answers

Answer:

No they do not.

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If it did, it would be 9/18

Hope that helps!

Step-by-step explanation:

Distance between Train 1 and Train 2 = 95 miles.
Average speed of Train 1 = 45 mph.
Average speed of Train 2 = 60 mph.
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Answers

9514 1404 393

Answer:

  19/21 hours, about 54 minutes 17 seconds

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

How many kilometers does Saturn travel in its orbit in one hour? ​

Answers

Answer:

Hey!! I found this online for you :)

Step-by-step explanation:

Saturn revolves or orbits around the Sun once every 29.4 Earth years, or once every 10,755.7 Earth days. Saturn travels at an average speed of 21,637 miles per hour or 34,821 kilometers per hour in its orbit around the Sun.

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Have a nice day <3

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Answers

Answer:

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Step-by-step explanation:

1357/59

23

1357/59=23

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answer:

Step-by-step explanation:

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Answers

Answer:

612 cm²

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Answers

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Answers

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

[tex]( {m}^{15} )( {m}^{3} ) ^ {- 4} \\ = ( {m}^{15} )( {m}^{3 \times - 4} ) \\ = ( {m}^{15} )( {m}^{ - 12} ) \\ = {m}^{15 + ( - 12)} \\ = {m}^{15 - 12} \\ = {m}^{3} \\ {m}^{x} = {m}^{3} \\ x = 3[/tex]

Q2.
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Answers

Answer:

The equality is only true for [tex]a = 0\ and\ 1[/tex], not for all values

Step-by-step explanation:

Given

[tex](\sqrt a)^4 = a[/tex]

Required

Determine if it is valid

[tex](\sqrt a)^4 = a[/tex]

Evaluate the exponent

[tex](a^\frac{1}{2})^4 = a[/tex]

[tex]a^\frac{1*4}{2} = a[/tex]

[tex]a^2 = a[/tex]

Rewrite as:

[tex]a^2 - a = 0[/tex]

Factorize

[tex]a(a- 1) = 0[/tex]

[tex]a =0\ or\ a - 1 = 0[/tex]

[tex]a =0\ or\ a = 1[/tex]

The equality is only true for [tex]a = 0\ and\ 1[/tex], not for all values

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