What is the temperature of 0.750 mol of a gas stored in a 6,050 mL cylinder al 221 atm?
atm
Use and
molek
5.24K
138 K
246 K

Explanation:

The boiling point of alcohols also increase as the length of hydrocarbon chain increases

The boiling point of alcohols also increase as the length of hydrocarbon chain increases.

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Answer:

El cloruro de litio se utiliza para fabricar litio metálico. El cloruro de litio se funde y electroliza. Esto produce litio metálico líquido.

Explanation:

sowwy si mi español es malo

Answer:

give him brainliest

Explanation:

Answer:

hkj

Explanation:

+HF is the answer

Explanation:

Answer:

Your answer would be B because In the first move energy was absorbed, because when energy is gained an electron moves to a higher energy level in the second move energy will be released because that is how an atom moves to a lower energy level.  The jump from level 1 to 4 was bigger than the drop from 4 to 2, because in the first move it moved from more orbitals. thus describing the the energy in the first move had a far energy released in the second move.

Answer:

H

Explanation:

UMMM H2O .. im assuming the H missing

Answer:

1) donate an H+ ion

Explanation:

option 1 is correct

Answer:

Hello, I was doing this and from my caluclations it should be :

Explanation:

3 Moles.

The three moles of MgCO3 are present in 252.939 grams of MgCO3.

So, option B is correct one .

The molar mass of substance is equal to mass of one mole of  that substance.

Example: Molar mass of MgCO3 is equal to mass of one mole of MgCO3.

Molar mass of Mg = 24.305 u

Molar mass of C = 12.011 u

Molar mass of O = 15.999 u

Molar mass of MgCO3 = Molar mass of Mg + Molar mass of C + Molar mass of O*3

Molar mass of MgCO3 = 24.305 + 12.011  +  15.999 * 3

Molar mass of MgCO3 = 84.3139 gram

Molar mass of  MgCO3 contain  84.3139 gram

So, 252.939 grams of MgCO3 = 252.939 grams/84.3139 gram

252.939 grams of MgCO3 = 2.999 moles

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Answer:

Answer:

5 Acids

Chemical

- Hydrochloric acid in gastric juice

- Sulphuric acid

- Nitric acid

- Uric acid

- Acetic acid

Household

- Vinegar

- Lemon

- Milk

- Batteries

- Soft drinks

5 Alkali

Household

- Dishwashwer soaps

- Detergents

- Toothpaste

- Oven cleaner

- Alkaline batteries

- Sodium bicarbonate

Chemicals

- Sodium hydroxide or lye

- Calcium carbonate (limestone)

- Ammonium hydroxide

- Calcium hydroxide

Answer:

D. Fundamental forces acting between two pieces of matter

Answer:

D. Fundamental forces acting between two pieces of matter

We know that [OH⁻] * [H⁺] = 10⁻¹⁴

plugging the value of [H⁺]

[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ * (10³/1.2)

[OH⁻] = 833.3 * 10⁻¹⁴

[OH⁻] = 8.33 * 10⁻¹²

Explanation:

H=mc×∆©

9.86=m×0.902×(30.5-23.2)

m=1.5

Explanation:

The specific heat of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius. The formula for calculating the heat absorbed or released by a substance is `q = mcΔT`, where `q` is the heat absorbed or released, `m` is the mass of the substance, `c` is the specific heat of the substance, and `ΔT` is the change in temperature.

In this case, we can use this formula to solve for the mass of the aluminum sample. We know that `q = 9.86 J`, `c = 0.902 J/g°C`, and `ΔT = 30.5°C - 23.2°C = 7.3°C`. Plugging these values into the formula, we get:

`9.86 J = m * 0.902 J/g°C * 7.3°C`

Solving for `m`, we find that the mass of the aluminum sample is approximately `1.5 g`, rounded to 2 significant figures.

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Answer:

119.5 J

Explanation:

First we calculate the temperature difference:

Then we can calculate the heat released by using the following formula:

Where q is the heat, Cp is the specific heat, ΔT is the temperature difference and m is the mass.

We input the data:

Answer:

1 mole of potassium hydroxide, KOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

KOH + HCl —> KCl + H₂O

Considering the balanced equation above, we can see clearly that 1 mole of potassium hydroxide, KOH reacted with 1 mole of hydrochloric acid, HCl.

Therefore, we can conclude that at every given point, 1 mole of potassium hydroxide, KOH is required to react with 1 mole of hydrochloric acid, HCl.

Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Explanation:

The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.

[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]

Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.

Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Answer:

2

Explanation:

Answer: look at the explanation and try to work it

Explanation: in contrast, our atmosphere blocks most ultraviolet light (UV) and all X-rays and gamma-rays from reaching the surface of Earth. Because of this, astronomers can only study these kinds of light using detectors mounted on weather balloons, in rockets, or in Earth-orbiting satellites.

Answer:

There are 0.195 moles.

Explanation:

1 mol of any gas under STP (meaning 1 atm and 273 K) will occupy 22.4 liters.

With the information above in mind, we can calculate how many moles will occupy 4.38 liters:

In 4.38 liters of a gas at STP there will be 0.195 moles.

Answer: 6.0g x 1 mol/18.02g x 40,65 kJ/mol which is D

Explanation: Just did

The water vapors change from vapor into water in condensation. The energy released by 6 gm of water is 6.0 g x 1 mol/18.02 g x 40.65 kJ/mol. Thus, option D is correct.

The heat of vapourization is the latent heat or enthalpy needed by the liquid to get converted into the vapor or the gaseous phase of the matter. It can be used to determine the energy released or absorbed by the substance.

The heat of vapourization of water is 40.65 kJ/mol, and its molar mass is 18.02 moles.

So, the energy released for the water when it is condensed into vapors will be,

6.0 g x 1 mol/18.02 g x 40.65 kJ/mol

Therefore, the heat of vapourization determines the amount of energy released.

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Answer:

[tex]r=25M^{-1}s^{-1}[A]^2[/tex]

Explanation:

Hello there!

In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:

[tex]r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}[/tex]

Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:

[tex]\frac{1.0}{4.0} =\frac{0.2^n}{0.4^n}\\\\0.25=0.5^n\\\\n=\frac{ln(0.25)}{ln(0.5)} \\\\n=2[/tex]

Which means this reaction is second-order with respect to A. Finally, we calculate the rate constant by using n, [A] and r, to obtain:

[tex]k=\frac{r}{[A]^n} =\frac{1.0M/s}{(0.2M)^2}\\\\k=25M^{-1}s^{-1}[/tex]

Thus, the rate law turns out to be:

[tex]r=25M^{-1}s^{-1}[A]^2[/tex]

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Answer:

baba

Explanation:

ndjshddjdjshshshsushs

Answer:

0.812 L

Explanation:

As this is a dilution process problem, we can solve it by using the C₁V₁ = C₂V₂ formula, where in this case:

We input the data:

And solve for V₁:

This means that 0.812 L of concentrated perchloric acid should be diluted to a final volume of 1.90 L.

Answer:

Fraction ionic = 0.43

Explanation:

To solve this question, we must, as first, find the fraction of the bond that is covalent using the equation:

Fraction Covalent = exp (-0.25*(Enitride - EAl)²)

Fraction covalent = exp (-0.25*(3.0- 1.5)²)

Fraction covalent = exp (-0.25*2.25)

Fraction covalent = exp (-0.5625)

Fraction covalent = 0.57

As:

1 = Fraction Covalent + Fraction Ionic:

Fraction ionic = 1 - 0.57

Fraction ionic = 0.43

Answer:

covalent

valence electrons

Explanation:

The attraction between two atoms that share a pair of valence electrons is known as a covalent bond. The nuclei of both atoms are drawn to the shared electrons. This results in a molecule with two or more atoms. Covalent bonds are formed solely between nonmetal atoms.

Between atoms of the same element or between atoms of different elements, covalent bonds can form. A new substance termed a covalent compound is formed when atoms of various elements create covalent bonds.

Answer:

a endothermic, absorbed

Answer:

B. 4.32 x 10-19 J is correct via a p e x

Explanation: