The rotational kinetic energy (in J) of Jupiter in its orbit around the Sun is 1.613 × 10³⁵ J
What is rotational kinetic energy?Rotational kinetic energy is kinetic energy due to rotation about an axis.
What is the rotational kinetic energy (in J) of Jupiter in its orbit around the Sun?The rotational kinetic energy is given by K = 1/2Iω² where
I = rotational inertia of juptier around sun = MR² where M = mass of Jupiter = 1.898 × 10²⁷ kg and R = distance of jupiter from sun = 7.78 × 10⁸ km = 7.78 × 10¹¹ m, ω = angular speed of Jupiter around sun = 2π/T where T = period of Juptier around sun = 4340 days = 4340 × 24 h/day × 60 min/h × 60 s/min = 374976000 s = 3.74976 × 10⁸ sSo, We have that the rotational kinetic energy of Jupiter is
K = 1/2Iω²
K = 1/2(MR²)(2π/T)²
K = 1/2(MR²)(4π²/T²)
K = 2π²MR²/T²
Substituting the values of the variables into the equation, we have that
K = 2π²MR²/T²
K = 2π² × 1.898 × 10²⁷ kg × (7.78 × 10¹¹ m)²/(3.74976 × 10⁸ s)²
K = 2π² × 1.898 × 10²⁷ kg × 60.5284 × 10²² m²/14.0607 × 10¹⁶ s²
K = 2π² × 114.8829 × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²
K = 229.7658π² × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²
K = 16.3410π² × 10³³ kgm²/s²
K = 161.2791 × 10³³ kgm²/s²
K = 1.612791 × 10³⁵ kgm²/s²
K ≅ 1.613 × 10³⁵ J
So, the rotational kinetic energy is 1.613 × 10³⁵ J
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If Vxi= 10 m/s, then Vxf=_______10m/s
If initial horizontal velocity (Vxi) = 10 m/s, then final horizontal velocity (Vxf) = positive 10m/s.
option B is the correct answer.
What is the horizontal velocity of a projectile?
The horizontal velocity of a projectile is the velocity of the projectile along the x - axis or x - direction.
During the horizontal motion of a projectile, the horizontal velocity of the projectile will be constant since gravity does not act in the horizontal direction.
That is to say, that the initial velocity of the projectile along horizontal direction will be equal to the final velocity of the projectile along the same horizontal direction.
Vxi = Vxf
where;
Vxi is the initial horizontal velocityVxf is the final horizontal velocityThus, If the initial horizontal velocity is 10 m/s. then the final horizontal velocity will be 10 m/s.
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a thin, 100 g disk with a diameter of 8.00 cm rotates about an axis through its center with 0.18 j of kinetic energy. What is the speed of a point on the rim?
According to the given statement, the speed of a point on the rim is 2.68 m/s.
Why is energy so crucial?Energy is a major factor in our everyday routines even though it is an essential need for humans. Our human-made structures are not only heated by energy, but also cooled by it. To lift you finger, climb out of bed, or even stroll down main sidewalk, you need energy.
kinetic energy = E = 0.18 J
mass = m = 100g = 0.1 kg
diameter = d = 8.0 cm = 0.08 m
Speed = v = ?
v = 2.44 m/s
Briefing:
First convert diameter into radius
r = d/2 = 0.08/2 = 0.04 m
The moment of inertia of disc is given by
I = 0.5mr²
In which m is the disk's mass & r is its radius
I = 0.5(0.1)(0.04)²
I = 0.00008 kg.m²
Additionally, since we are discussing rotating motion, rotational kinetic energy is provided by
E = 0.5 I ω²
we have to separate ω
ω² = E/0.5 I
ω = √E/0.5 I
ω = √0.18/0.5(0.00008)
ω = 67.08 rad/sec
Finally we know that speed is given as
v = ω r
v = 67.08 (0.04)
v = 2.68 m/s
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A 3.0 cm diameter water line splits into two 1.0 cm diameter pipes. All pipes are circular and at the same elevation.In the larger diameter section, the water speed is 2.0 and the gauge pressure is 50. What is the gauge pressure at a point in one of the narrower branches?
If all pipelines are round and of the same elevation as the question suggests, then point B's gauge pressure is 11.5 KPa.
The definition of elevationDistance above water level is known as elevation. Elevations are often expressed in feet or meters. On charts, they can be represented by contour lines that link points of the same elevation, by colours, or by numbers that indicate the precise elevations of specific places on the Planet's surface.
Briefing:From continuity equation:
Velocity of water at B = (2*pi*3²)/[2*pi*1²] =9 m/s
then from Bernoulli equation;
v² /2 + φ + p/ρ =constant
ρ=1000 kg/m³
3²/2 +φ +50000/1000 = 9²/2 +φ +P/1000
Therefore,
Pressure at B = 11.5 KPa
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The complete question is-
The 3.0 cm-diameter water line in the figure splits into two 1.0 cm-diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 2.0 m/s and the gauge pressure is 50 kPa.
What is the gauge pressure at point B?
Help please!
How can you differentiate someone who has quality hypnosis training and someone who does not?
The Hypnotic Induction Profile (HIP) or the eye roll test, first proposed by Herbert Spiegel, is a simple test to loosely determine if a person is susceptible to hypnosis. A person is asked to roll their eyes upward. The degree to which the iris and cornea are seen is measured.
What is Hypnotic Induction Profile (HIP)?The Hypnotic Induction Profile (HIP) was created as a quick yet comprehensive evaluation of a person's trait hypnotizability and capacity to enter a hypnotic state.An invitation to enter hypnosis is known as a hypnotic induction, and it usually includes instructions and recommendations to make the subject more receptive to hypnosis. Instructions for relaxation are frequently included in the hypnotic induction, but while nice, they are not always necessary.Do I Have a Receptive Mind? Highly hypnotizable individuals frequently have vivid imaginations and can visualize objects clearly in their minds' eye.When they are reading or watching a movie they enjoy, they frequently lose track of time.To learn more about Hypnotic Induction Profile (HIP) refer to:
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The map below shows the path of a river. The arrow
shows the direction the river is flowing. LettersA
and B identify the banks of the river.The water depth is greater near bank A than bank B
because the water velocity near bank A isA) faster, causing deposition to occur
B) faster, causing erosion to occur
C) slower, causing deposition to occur
D) slower, causing erosion to occurAnswer: B
Different landforms are created during the process of water erosion, which flows water downhill. Rills, gullies, streams, rivers, tributaries, waterfalls, floodplains, meanders, lakes, and other natural features
What are the names of a river's beginning and end?
The source and mouth of a river are its beginning and closing, respectively. Before they get to the river's mouth, numerous rivers and streams will converge. The smaller streams and rivers are referred to as tributaries.
A river's beginning is at its mouth, correct?
The mouth of a river is where it flows into an ocean, a lake, or another river. River mouths are extremely dynamic places. The flow of a river collects material from the river, debris through bank erosion, and
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When water flows from section 1 at upstream to section 2 at downstream in an open channel, the water depth decreases by a factor of 2
The answer to the question is 5.66 feet for the channel's diameter after 2 if it is 12 feet wide at 1.
What makes upstream and downstream different?Simply expressed, upstream activities comprise the discovery and production of petroleum and natural gas, whereas downstream activities relate to the procedures used from the extraction phase until the product is given to the client in the desired shape.
Briefing:[tex]$$\begin{aligned}& F r_1=\frac{V_1}{\sqrt{g V_1}}=0.5 \text {, or } \sqrt{g Y_1}=2.0 V_1 \\& \text { and } \\& F_{r_2}=\frac{V_2}{\sqrt{g y_2}}=3.0 \text { where } y_2=0.5 y_1 \\& \text { Thus, } \frac{V_2}{\sqrt{0.5 g Y_1}}=3.0 \text {, or } \sqrt{g y_1}=V_2 /(3 \sqrt{0.5}) \\& \text { By equating Eq. (1) and }(2) ; 2.0 V_1=V_2 /(3 \sqrt{0.5}) \\& \text { or } \\& V_2=4.24 V_1\end{aligned}$$[/tex]
However,
[tex]$Q_1=Q_2$[/tex] or [tex]$b_1 y_1 V_1=b_2 y_2 V_2$[/tex]
where [tex]$b=$[/tex] channel width. Thus, with [tex]$b_1=12 \mathrm{ft}$[/tex]
(12ft)y₁(V₁) = b₂(0.5y₁)(4.24V₁) or b₂ = 12ft/0.5(4.24) = 5.66ft
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The complete question is-
In flowing from section 1 to section 2 along an open channel, the water depth decreases by a factor of 2 and the Froude number changes from a subcritical value of 0.5 to a supercritical value of 3.0. Determine the channel width at 2 if it is 12 ft. wide at 1.
Based on current evidence, decide whether each of the following statements apply to the concept of dark matter, dark energy, both, or neither. Drag each statement into the appropriate bin.
Dark Matter Only:
as mass.
most common form of mass in the halo of the Milky Way Galaxy.
detected through its gravitational attraction.
likely to consist of tiny, weakly interacting particles.
Dark Energy Only:
inferred to exist from the measured acceleration of the universe's expansion.
the proposed source of a universal repulsive force.
Both Dark Matter and Dark Energy:
the universe contains more of this than it contains matter made from atoms.
we do not know what it is made of.
Neither Dark Matter nor Dark Energy
blocks light from stars behind it.
"dark" because it emits only infrared light.
The concept that the information applies to is illustrated below:
Dark matter:
Detected through its gravitational attraction
Has mass
Most common forms of mass in the halo of the Milky way galaxy, likely to consist of subatomic particles.
Dark energy:
Inferred to exist from the measured acceleration of the universe's expansion.
The proposed source of a universal repulsive force.
Dark matter and dark energy:
The universe contains more of this than it contains matter made from atoms.
We do not know what it is made of.
Neither:
Blocks light from stars behind it, 'dark' because it emits only infrared light.
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A gas at a pressure of 2.00 atm undergoes a quasistatic isobaric expansion from 3.00 to 5.00 L. How much work is done by the gas?
Answer:
this video shows how to solve the problem :)
Explanation:
Two physical science classes are playing tug of war. Mrs. Hankinson’s class pulls left with a force of 100 N, while Mrs. Wade’s class pulls with a force of 105 N in the opposite direction.
What is the net force, and which class won?
A. 205 N, Mrs. Wade's class
B. 5 N, Mrs. Wade's class
C. 205 N, it was a tie
D. 5 N, Mrs. Hankinson's class
The net force is 5 N and the class that won is Mrs. Wade's class (Option B)
How do I determine the net force?We can obtain the net force by using the following formula:
Net force = Opposite force - force of pull
Now, we shall determine the net force as illustrated below:
Force by Mrs. Hankinson’s class = 100 NForce by Mrs. Wade’s class = 105 NNet force =?Net force = Opposite force - force of pull
Net force = Mrs. Wade’s class - Mrs. Hankinson’s class
Net force = 105 - 100
Net force = 5 N
From the above calculation, we can say that the net force is 5 N and the class that won given the above data is Mrs. Wade’s class
Therefore, the correct answer to the question is:
5 N, Mrs. Wade's class (Option B)
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I need help on this
A planet has a different meaning than the astronomical understanding of what a planet is. Before the advent of telescopes, the night sky was thought to consist of two very similar components. Fixed stars, which are stationary relative to each other, and moving objects ("wandering stars").
What are planets?
Planets are large, round objects that are neither stars nor remnants. The best theory of planet formation available is the nebular hypothesis, which postulates that interstellar clouds collapse from the nebula, creating young protostars orbiting the protoplanetary disk. Planets grow within this disk by the gradual accumulation of matter by gravity, a process called accretion. The solar system has at least eight planets: the terrestrial planets Mercury, Venus, Earth, and Mars, and the giant planets Jupiter, Saturn, Uranus, and Neptune. Each of these planets rotates around an axis that is tilted with respect to the poles of its orbit. All of them have atmospheres, but Mercury's is faint, and some share features such as ice caps, seasons, volcanism, hurricanes, tectonics, and even hydrology. Except, the planets in our solar system generate magnetic fields, and all planets except Venus and Mercury have natural satellites. Giant planets have planetary rings, most notably Saturn's rings.
Some cultures equate celestial bodies with gods, and these connections to mythology and folklore exist in naming schemes for newly discovered celestial bodies in the solar system. When the heliocentric theory superseded the heliocentric theory in the 16th century and his 17th century, the earth itself was recognized as a planet.
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Given that Shapley calculated the size of the Milky Way based on the stars' apparent brightness, how did not including the effects of gas and dust affect Shapley's calculation?
A. The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too small.
B. The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.
C. The distance calculated to each globular cluster was too small, and thus his size for the Milky Way was too large.
D. The distance calculated to each globular cluster was too small, and thus his size for the Milky Way was too small.Answer:B. The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.
The correct option is, The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.
What main conclusion did Shapley draw from his measurements of the distances to the globular clusters?
Shapley concluded (and other astronomers have since verified) that the center of the distribution of globular clusters is the center of the Milky Way as well, so our galaxy looks like a flat disk of stars embedded in a spherical cloud, or 'halo,' of globular clusters.
How did Shapley estimate the location of the Sun in the Milky Way?
Harlow Shapley determined the position of the Sun in the galaxy by measuring the distances to 93 globular clusters of stars.
What is a globular star cluster?
Globular clusters are stable, tightly bound clusters of tens of thousands to millions of stars. They are associated with all types of galaxies. Globular clusters are typically much larger than open clusters and are tightly gravitationally bound.
What are the characteristics of the stars in globular clusters?
Globular clusters are densely packed collections of ancient stars. Roughly spherical in shape, they contain hundreds of thousands, and sometimes millions, of stars. Studying them helps astronomers estimate the age of the universe or figure out where the center of a galaxy lies.
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An object of 20 kg accelerates at 10 m/s/s into a wall. What amount of force did it hit the wall?
The amount of force that hit the wall is 200N.
What is force?Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body and which has a direction.
The force can be calculated by multiplying the mass by the acceleration as follows:
Force = mass × acceleration
According to this question, an object of 20kg accelerates at 10 m/s² into a wall. The force applied is as follows:
Force = 20kg × 10m/s² = 200N
Therefore, 200N is the force applied by the object on the wall.
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A closed system consists of two adjacent chambers containing the same ideal gas. Initially, one chamber is hot and the other chamber is cold. Which of the following best explains the change in entropy of this closed system over time? A. The entropy increases over time because the process is irreversible B. The entropy stays the same because it is a conserved quantity C. The entropy decreases because the system moves toward a more orderly state of uniform temperature D. Nothing can be determined about the change in entropy without knowing how many moles of gas are in each container
Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy.
define entropy ?
Entropy is a key term in physics and chemistry, and it also has applications in cosmology and economics. It is a branch of physics known as thermodynamics. It is a key idea in physical chemistry.
Entropy is the measure of the disorder of a system. It is a comprehensive feature of a thermodynamic system, which implies that its value varies with the amount of matter present. Entropy is usually denoted by the letter S in equations and has units of joules per kelvin (JK1) or kgm2s2K1. Entropy is low in a highly ordered system.
Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy.
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Assume that the circuit Figure 21-16 has L equal to 0.60 H, R equal to 280 ohms, and C equal to 3.5 μF. The amplitude of the driving voltage is 150 V rms. At a frequency of 60 Hz, what is the rms current in the circuit?
VL (peak) = VL × √2= 2.335 angle (90) volts is the rms current in the circuit.
Rms current is Root-Mean-Square of instantaneous current values. The RMS value of alternating current is given by direct current which flows through a resistance
How to calculate the rms current in circuit?At resonance the capacitive and inductive reactance are such that they cancel each other and the circuit is entirely resistive at that point
Calculation :so,
At resonance the current is given as
I(rms) = Erms/R = 125 /740 = 0.169 A= 1.6 × 10^-1 A
Now for series RLC circuit the resonant frequency is given as
w= 2πf=1/• LC = 1/√41× 10^-3* 0.44××10^-3
f= 37.94 Hz
The inductive reactance at resonant frequency is given as
xL= jwL = j 2πf×L = j×2×π×37.94×41×10^-3 = j9. 77 ohm= 9.77 angle (90)
as 9.77 angle (90) = 9.77 cos 90+ j9. 77 sin (90) = 0+ j9.77
So the voltage across the inductor is given as
VL= I×XL
=0.16 × 9.77 angle (90) = 1.65 angle (90)
Note this is the rns value for the peak value the voltage is to be multiplied by √2
VL (peak) = VL ×√2= 2.335 angle (90) volts
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If the maximum excitation energy gained by an atom is 12.08 eV ,determine all of the wavelengths of light emitted from the tube as atoms return to the ground state.
The wavelength of light emitted from the tube as atom returns to the ground state is 1.02×[tex]10^{-7[/tex]m.
The spectrum of the electromagnetic radiation emitted or absorbed by an electron during transitions between different energy levels within an atom. When an electron gets excited from one energy level to another, it either emits or absorbs light of a specific wavelength.
The wavelength can be determined by either energy or by frequency.
in the question energy of an atom is given, so we will use wavelength energy formula.
λ=hc/E =6.626×10⁻³⁴J⋅s×2.998×10⁸m⋅s⁻¹/12.08 ×1.6×[tex]10^{-19[/tex]
= 19.864×[tex]10^{-7[/tex]/19.328
= 1.02 ×[tex]10^{-7[/tex] m
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An electrical motor spins at a constant 1129.0 rpm. If the armature radius is 2.846 cm, what is the
acceleration of the edge of the rotor?
The accelaration of the edge of the rotor is linear acceleration.
What is accelaration?Accelaration is the rate of the change of the velocity of an object with respect by time.
The electric motor is spinning at a rate of 2695 Devolution Permanent. By two by over 60 is how this can be converted into reading persecond. The value is coming out at 282.08 ingredient per second. The areas of the model is 7.605 cm. The linear acceleration of the by motor is what we have to l find. We have to find out of the tangential acceleration that is given by the formula and omega squared R, if I substitute the values. This will be to 82.08 The motor has a linear Acceleration.
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a ball is dropped from a cliff and falls freely towards earth. which of the following statements are true concerning the ball as it falls? neglect air resistance (aka drag) for this problem.
The acceleration will be constant and in a downward direction. And as the ball moves in direction of the acceleration so the velocity will keep increasing because velocity is inversely proportional to height, when the ball is in free fall.
What is Acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating.
What is Free fall?Free fall is characterized as a condition where an object is only affected by gravity. The ball experiences an external force, which quickens its motion. Gravitational acceleration is another name for this rate of free-fall acceleration. A downward motion without any beginning force or speed is called a free fall.
Hence, the acceleration will be constant and in a downward direction. And as the ball moves in direction of the acceleration so the velocity will keep increasing because velocity is inversely proportional to height, when the ball is in free fall.
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Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. View Available Hint(s) 2000 kg 1000 kg 500 kg 4000 kg 500 kg 1000 kg 5 m/s 10 m/s 20 m/s 5 m/s 10 m/s 20 m/s largest smallest The correct ranking cannot be determinar Submit
Since impulse is defined as a change in momentum, we may conclude that since all autos are based on magnitude, their initial momentum and ultimate momentum are the same. Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5
What is magnitude?Magnitude is a term used in physics to describe an object's maximal size and direction. Magnitude is a factor that is shared by both scalar and vector quantities. We are aware that by definition, scalar quantities are those with only magnitude. It displays an object's size, direction, or motion in absolute or relative terms. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.
How much is a magnitude?One is roughly 10 times greater than the other if two integers are separated by one order of magnitude. They differ by a factor of around 100 if they are separated by two orders of magnitude. The greater value is less than 10 times the smaller value when two numbers are of the same order of magnitude.
Briefing:Automobile-1 Mass= 2000kg = 5m/s
Automobile-2 Mass= 1000kg = 10m/s
Automobile-3 Mass= 500kg = 20m/s
Automobile-4 Mass= 4000kg = 5m/s
Automobile-5 Mass= 500kg = 10m/s
Automobile-6 Mass= 1000kg = 20m/s
Since we now understand that each car's momentum is the result of its mass and velocity, we will have
Automobile-1
P₁ = m × v
P₁ = (2000)(5)
P₁ = 2 × 10⁴kgm/s
Automobile-2
P₂ = m × v
P₂ = (1000)(10)
P₂ = 10⁴kgm/s
Automobile-3
P₃ = m × v
P₃ = (500)(20)
P₃ = 10⁴kgm/s
Automobile-4
P₄ = m × v
P₄ = (4000)(5)
P₄ = 2 × 10⁵kgm/s
Automobile-5
P₅ = m × v
P₅ = (500)(10)
P₅ = 10³kgm/s
Automobile-6
P₆ = m × v
P₆ = (1000)(20)
P₆ = 2 × 10⁵kgm/s
Then the momentum is:
Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5
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you push a 27 kg crate with 1 n of force, and it moves along the floor with constant velocity, the acceleration of the crate is
The acceleration of the crate is 0 m/s2.
This is because the force applied is equal to the force of friction between the crate and the floor, so the crate is not accelerating. The force of friction is equal to the force applied, and since no acceleration is occurring, the force must be equal to the mass of the crate multiplied by the acceleration of gravity (9.81 m/s2).
This means that the force applied (1 N) is equal to the mass of the crate (27 kg) multiplied by the acceleration of gravity (9.81 m/s2). Therefore, the acceleration of the crate is 0 m/s2.
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1. David Purley, a racing driver, survived deceleration from 173 km/h (about 107
mph) to 0 km/h over a distance of 0.660 m when his car crashed. Assume that
Purley's mass is 70.0 kg. What is the average force acting on him during the
crash? Compare this force to Purley's weight.
Average force acting on Purley is -1749m/[tex]s^{2}[/tex].
What is Newton's second law of motion?
According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.
Given,
According to newton's second law of motion:
F =ma
Purley's initial speed = 173km/h
Final speed = 0
Distance traveled = 0.66 m
So, [tex]v_{i}[/tex] = 172 km/h × 1 hr/3600 s × 1000m/1km
[tex]v_{i}[/tex] = 48.1 m/s
By using kinematics
[tex]v^{2} f[/tex] = [tex]v^{2} i[/tex] + 2ad
[tex]0^{2}[/tex] = 48.[tex]1^{2}[/tex] + 2a(0.66)
-1.32a = 2309
a= -1749 m/[tex]s^{2}[/tex]
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In a physics lab, Ray Zuvlite arranges two mirrors with a right angle orientation as shown. Ray then directs a laser line at one of the mirrors. The light reflects off both mirrors as shown. If angle A is 38°, determine the what is the angle measure of angles B, C, and D?
The angle measure of angle B = 25° and angle C = 65° and angle D = 25°.
What is meant by measure?Through the use of a protractor, angles are measured in degrees (°). In order to calculate or draw angles in terms of degrees, a protractor is a measuring tool that is utilized. Using a protractor, for instance, we can observe that the black arrow in the image below crosses the 90° line at 100°. Thus, the angle has a 100° measurement. A degree is a unit of measurement for a plane angle in which one complete rotation equals 360 degrees, generally indicated by the symbol °. It is included in the SI brochure as an acceptable unit even though it is not a SI unit—the radian is the SI unit of angular measure.
The given parameters are;
The orientation of the two mirrors = At right angle to each other
The laser light is directed at one of the mirror
The measure of angle, A = 25°
The measures of angle B, C, and D are found as follows;
We have;
∠A = ∠B = 25°, by angle of incidence equals angle of reflection
∠B = 25°
∠B + ∠C = 90° by sum of the acute angles of a right triangle
25° + ∠C = 90°
∴ ∠C = 90° - 25° = 65°
∠C = 65°
∠E = ∠C = 65° by angle of incidence equals angle of reflection
∴ ∠E = 65°
Line 'L' is perpendicular to the second mirror, therefore, the angle between line 'L' and the second mirror = 90° = ∠E + ∠D
∠E + ∠D = 90°, by angle sum property
Therefore;
65° + ∠D = 90°
∴ ∠D = 90° - 65° = 25°
∠D = 25°
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help helphelphelphelp plssssssss
Answer:
heat and pressure is the correct answer
establish the relation among energy, density, strain and stress
Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation.
If it requires 9 J of work to stretch a spring by 2 cm from its equilibrium length, how much more work will be required to stretch it an additional 4 cm
A spring will therefore need 72 J of work to stretch an additional 4 cm from its equilibrium length if it takes 9 J to stretch it that far.
What is equilibrium length?The length of a multi-mode optical fiber required to achieve a static mode distribution from a particular excitation condition is known as the equilibrium length, and it is sometimes used to characterize stationary mode distributions. There is a location where the weight and spring force are equal in magnitude but in the opposite direction. The equilibrium position is where you are at this moment. There is a net force known as the restoring force that is directed toward the equilibrium position if the mass is in any other position.
How do you find the equilibrium length of a spring?F = -kx. The proportional constant k is referred to as the "spring constant". It gauges the stiffness of the spring. When a spring is stretched or compressed to a length that differs by an amount equal to or greater than x, it produces a force F = -kx in the direction of its equilibrium position. From its equilibrium length.
Briefing:Knowing that the results of the work done to lengthen the springs will be reported as
U=1/2kx
so here we have
9= 1/2 k〖(0.02)〗^2
so we have
K=45000N/m
Now, we must locate the work completed to extend the spring from x = 2 cm to x = 4 cm
here we have
U=1/2 k(x 2/1-x 2/2
now we have
U=1/2(45000)(〖0.06)〗^2-〖0.02〗^2)
U= 72J
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Marvin is moving furniture in his house , including the 52.8 kg dresser. he is applying a force of 90 N to the left to overcome 24 N of friction to accelerate the dresser.
1. What is the horizontal acceleration of the dresser?(value only, round to two decimal places, no units, or direction. example: 97.50)
Answer: 3.81 m/s^2.
Explanation: use the equation for acceleration, which is a = (F - f)/m. In this case, we are given the force applied by Marvin (F), the force of friction (f), and the mass of the dresser (m). Plugging in the given values, we get a = (90 N - 24 N)/(52.8 kg) = 3.81 m/s^2.
A moving object collides with a second object at rest on a frictionless surface, resulting in an elastic collision. Is the momentum of each individual object the same before and after the collision?
A. No - the momentum of each object is not bound by conservation - only the system as a whole. B. Not enough information is given. C. Yes - the conservation of momentum is a universal law.
According to statement no, only system in general is constrained by conservation of momentum.
What does the scientific term frictionless mean?A surface is said to be frictionless if it has a loads applied on any thing that is virtually zero or insignificant, i.e., there is no resistance between the surface and the substance, allowing that object simply slide & freely move without any friction.
Is there no friction at all in space?Although gas, sand, radiation, fields, and minuscule particles are present in outer space, their concentration is too low for them to have a significant impact on spacecraft. As a consequence, traveling objects cannot be slowed down in space by any kind of friction.
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Dark matter was first detected because the ______ for the amount of gravity that could be present due to the luminous mass.
Dark matter was first detected because the excess for the amount of gravity that could be present due to the luminous mass.
Since, by measuring the rotation of the galaxies and their gravitational attraction, the scientists determined that there appeared to be an excess of gravity, which could not be explained by the amount of luminous mass present. This led to the conclusion that dark matter must exist to explain this excess gravity.
The role of dark matter in the formation of galaxiesDark matter plays a fundamental role in the formation and evolution of galaxies. This invisible matter is composed of subatomic particles that interact with gravity, but does not emit light, so it cannot be detected directly. Despite this invisibility, advances in technology have allowed scientists to determine the amount of dark matter present in the Universe and its contribution to the evolution of galaxies.
Studies of galaxies suggest that dark matter plays an important role in their formation, this means that dark matter is responsible for the formation of galactic structures, such as disks and the central bar.
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A new pump can drain your pool 4 times faster than the old pump.
Running the two together, it takes 4 hours to drain the pool.
How long will it take the old pump on its own just to drain the pool water?
it is 20 4×5 trust me i did this for like 30 min
A straight, nonconducting plastic wire 9.50cm {\rm cm} long carries a charge density of 125nC/m {\rm nC/m} distributed uniformly along its length. It is lying on a horizontal tabletop.
A) Find the magnitude and direction of the electric field this wire produces at a point 5.50 {\rm cm} directly above its midpoint.
B) If the wire is now bent into a circle lying flat on the table, find the magnitude and direction of the electric field it produces at a point 5.50cm {\rm cm} directly above its center.
Part A. The midway magnitude of the electric field is 17.2 * 10³ N/C.
Part B. The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.
The intensity of an Electric Field
Given this, the wire length is 9.50 cm and the charge density is 125 nC/m.
Part A
The electric field at the wires halfway is
E = q/4πε * 1/ (z(z²/a²+1)¹/²)
Where E is the intensity of the electric field, 8.85*10⁻¹² is the permittivity, z is 5.5 cm, a is the midpoint, 9.5/2 cm, and q is the charge density.
Substituting the value in the above equation
E = 17.2 * 10³N/C
The midway magnitude of the electric field is 17.2 * 10³ N/C
Part B
When the wire is a circle then, the charge density at the wire is
Q = q*l
Q= 1.235 * 10⁻⁸ * 0.095
Q = 1.235*10⁻⁸ C
And to calculate the radius
r = l/2π
r = 9.50/ 2*3.14
r = 1.512cm
r = 0.015m
The electric field density at the midpoint of the circle is,
E = Q/4π * z(z²+r²)¹/² * E
Substituting the values in the above equation, we get
E = 47.17 * 10³ N/C
The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.
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a force of 300N is applied to a 1500kg car at rest. a)what is its acceleration. b)what will its velocity be 5secs later
The acceleration will be 0.2m/s^2 while the velocity will be 1m/s
Acceleration and VelocityGiven DataForce = 300N
Mass = 1500kg
Time = 5 seconds
We know that
Force = ma
a = F/m
a = 300/1500
a = 0.2 m/s^2
Also, the expression for Velocity is given as
Ft = mv
300*5 = 1500*v
Making velocity the subject of the formula we have
1500 = 1500*v
v = 1 m/s
The rate of change of an object's velocity with respect to time is defined as acceleration.
Acceleration implies that the speed is changing, but this is not always the case. When an object moves in a circular path at a constant speed, it is still accelerating because its velocity direction changes.
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