What is the answer to this problem?

Answer:

he has more pushing force than the truck there for pushing it forword.

Explanation:

Answer:

A constant volume gas thermometer works on a thermometric property of " change in pressure with temperature at a constant volume"

Answer:

6.8 N.m

Explanation:

The computation of the magnitude of the magnetic torque on the coil is given below:

Given that

n = 400

d =  6.0 cm

Current  is I = 7.0 A

Angle is [tex]\theta[/tex] = 30 degree

Now

We know that

the magnitude of the magnetic torque is

= nIABsin[tex]\theta[/tex]

= (400) (7.0) π ÷ 4 (0.06m)^2 sin(90° - 30°)

As

[tex]\theta[/tex] = (90° - Ф)

=  (400) (7.0) π ÷ 4 (0.06m)^2 sin 60°

= 6.8 N.m

Answer:

Grams

Explanation:

Because that is the definition

Answer:

65 grams

Explanation:

Answer:

bubble wrap in stuff animal

Explanation:

did it

Answer:

i would say putting like pillows around it i had to do it once and i won like that so

Explanation:

yes ,each piece will remain a magnet because the small pieces will cut into north and south

Answer:

The final angular velocity is rev/s is 0.293 rev/s.

Explanation:

Given;

mass of the merry-go-round, m₁ = 120 kg

radius of the merry-go-round, r = 1.8 m

initial angular velocity, ω = 0.4 rev/s

mass of the child, m₂ = 22 kg

Apply the principle of conservation angular momentum to determine the final angular velocity;

[tex]I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2 + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2 + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1 + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\[/tex]

Therefore, the final angular velocity is rev/s is 0.293 rev/s.

Explanation:

A push or pull of an objecr

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

A force is described as push or pull on an object.

Answer:

Material that allow the electrons to move freely in order to produce a current

Please mark as brainliest if answer is right

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Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

[tex]\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}[/tex]

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

[tex]\Delta t = \frac{0.18\ m}{340\ m/s}[/tex]

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Answer:

the percentage of heat lost by the window is 93.18%

Explanation:

Given the data in the question;

Area of glass [tex]A_{glass[/tex] = 0.10 m²

Thickness of glass [tex]t_{glass[/tex] = 8 mm = 0.008 m

Area of Styrofoam [tex]A_{styrofoam[/tex] = 11 m²

Thickness of Styrofoam [tex]t_{styrofoam[/tex] = 0.15 m

we know that;

Thermal conductivity of glass [tex]k_{glass[/tex] =  0.80 J/smC°

Thermal conductivity of Styrofoam  [tex]k_{styrofoam[/tex] =  0.010 J/smC°

Now, temperature difference between outside and inside the walls and window is ΔT

So, In time t, heat lost due to conduction in the window will be;

[tex]Q_{glass[/tex] = [[tex]k_{glass[/tex] × [tex]A_{glass[/tex]  × ΔTt] / [tex]t_{glass[/tex]

we substitute

[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008

[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008  

[tex]Q_{glass[/tex] = 10(ΔT)t J

Also, the heat lost due to conduction in the wall be;

[tex]Q_{styrofoam[/tex] =  [[tex]k_{styrofoam[/tex] × [tex]A_{styrofoam[/tex] × ΔTt] / [tex]t_{styrofoam[/tex]

we substitute

[tex]Q_{styrofoam[/tex] =  [ 0.010 × 11 × ΔTt] / 0.15

[tex]Q_{styrofoam[/tex] =  0.7333(ΔT)t J

Now, Net heat lost in the wall and window is;

Q = [tex]Q_{glass[/tex] + [tex]Q_{styrofoam[/tex]

Q = 10(ΔT)t J + 0.7333(ΔT)t J

Q = 10.7333(ΔT)t J

So, the percentage of heat lost by the windows will be;

% of heat lost = [tex]Q_{glass[/tex] / Q

= 10(ΔT)t J / 10.7333(ΔT)t J

= 0.93167

= ( 0.93167 × 100 )%

= 93.18%

Therefore, the percentage of heat lost by the window is 93.18%

Explanation:

Work done= MGH

180=m×10×3

180/30=m

m=6kg

Answer:

0.187 m

Explanation:

We'll begin by calculating the acceleration of the ball. This can be obtained as follow:

Mass (m) = 0.450 Kg

Force (F) = 38 N

Acceleration (a) =?

F = m × a

38 = 0.450 × a

Divide both side by 0.450

a = 38 / 0.450

a = 84.44 m/s²

Finally, we shall determine the distance. This can be obtained as follow:

Initial velocity (u) = 2.20 m/s.

Final velocity (v) = 6 m/s

Acceleration (a) = 84.44 m/s²

Distance (s) =?

v² = u² + 2as

6² = 2.2² + (2 × 84.44 × s)

36 = 4.4 + 168.88s

Collect like terms

36 – 4.84 = 168.88s

31.52 = 168.88s

Divide both side by 168.88

s = 31.52 / 168.88

s = 0.187 m

Thus, the distance is 0.187 m

Answer:

Sexual reproduction.

Explanation:

Reproduction can be defined as a biological process which typically involves living organisms producing an offspring.

Basically, there are two (2) methods of reproduction and these are;

I. Asexual reproduction: it involves the cloning of a living organism to produce an offspring because there is only a single parent.

II. Sexual reproduction: it involves the combination of the genome (gamete) of a male and female living organism during fertilization.

In this scenario, the botanist from the nursery plans to develop a large number of new spider plants that has larger flowers. Thus, the type of reproduction the botanist should use to develop the new spider plants is sexual reproduction because it would help the parent plant reproduce offsprings with different traits such as spider plants with large flowers. Also, the botanist should use sexual reproduction rather than asexual reproduction because asexual reproduction will only make the parent plant reproduce that have the same type of traits as themselves.

Answer:

the answer is M=29.6kg

Explanation:

your welcome:)

Answer: Electrons move from the potassium atoms to the sulfur atoms.

Explanation:  2 K + S ⇒ 2 K^+ + S^2-   . Usually metals donor electrons to non-metals

Answer:

6.62m/s

Explanation:

Given data

M1= 120kg

U1= 5.5m/s

M2= 105kg

U2= 7.9m/s

The system experiences an inelastic collision, the expression for inelastic collision is

M1U1+ M2U1= (M1+M2)V

Subsitute

120*5.5+ 105*7.9= (120+105)*V

660+ 829.5= (225)*V

1489.5= (225)*V

Divide both sides by 225

V= 1489.5/225

V= 6.62m/s

Hence the common velocity is 6.62m/s

Answer:

2xy-12xy+15x3y?-3x?y?by3l 3x2y

Answer:

iek

Explanation:

Answer:

the answer to your questions above is 3 x 4 = 12 volts

Explanation:

Voltage =  Current × Resistance

If ' c ' is the speed of light, then the formula for it is . . .

c = 299,792,458 meters per second

In order to make it all the way from the opening to the detector, a wave has to travel through air, glass, water, plastic, and vacuum.

-- The siren and the tuning fork are sounds.

-- Sound cannot travel through vacuum.

-- That knocks out choices B, C, and D.

The answer is A.

Note:  Making a big exception here.  We don't do test questions on Brainly. That would be cheating. Don't let me catch you doing it again.

Answer:

0 degrees Celsius

Explanation:

Answer:

Materials like air, water, and clear glass are called transparent. When light encounters transparent materials, almost all of it passes directly through them. ... When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials.

Explanation:

Answer:

[tex]56.5\ \text{s}[/tex]

[tex]21.13\ \text{m/s}[/tex]

Explanation:

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Displacement

Here the kinematic equations of motion are used

[tex]v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}[/tex]

Time the car is at constant velocity is 39 s

Time the car is decelerating is 5 s

Total time the car is in motion is [tex]12.5+39+5=56.5\ \text{s}[/tex]

Distance traveled

[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}[/tex]

[tex]s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}[/tex]

[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2[/tex]

[tex]s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}[/tex]

The total displacement of the car is [tex]156.25+975+62.5=1193.75\ \text{m}[/tex]

Average velocity is given by

[tex]\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}[/tex]

The average velocity of the car is [tex]21.13\ \text{m/s}[/tex].