What is the answer for these this question

Answer:

I think it is A.

Step-by-step explanation:

I hope this helps.

Answer:

33/12 or 2.75

Step-by-step explanation:

6 1⁄6 - 3 5⁄12

37/6 - 41/12

74/12 - 41/12

33/12 or 2.75

Answer:

The mode is 23

Step-by-step explanation:

Answer:

8!

Step-by-step explanation:

Answer) 8!

Explanation) i dont have one :')

Answer:

slope-intercept form: y= -5/4x-1

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

p=k√q

8=k√25

8=k5

k=8/5

p when q=100

p=8/5*√100

p=8/5*10

p=16

Answer:

No

Step-by-step explanation:

Angle measures of a triangle must add up to 180 and this only adds up to 87

Answer: $10

Step-by-step explanation:

Let Josie's money be x

Since Joe has half as much as Josie. Joe's money will be: x/2 = 0.5x

Bob has four times as much money as Joe. Bob's money will be = (4 × 0.5x) = 2x

Therefore, we add all the amount together and equate to $35. This will be:

x + 0.5x + 2x = 35

3.5x = 35

x = 35/3.5

x = 10

Josie has $10

The function [tex]√(x^3 - 8)[/tex] at each x value is 0.25 * [-1.902 - 1.609].  The interval [2, 3] into subintervals and apply the respective formulas.

To approximate the integral ∫[2 to 3] √(x^3 – 8) dx using the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule, we need to divide the interval [2, 3] into subintervals and apply the respective formulas. Let's compute the approximations for each rule.

Step 1: Determine the subinterval width, h.

We can calculate h using the formula:

h = (b - a) / n

Given:

a = 2

b = 3

Let's use different values of n for each rule.

For Trapezoidal Rule, let's set n = 4.

For Midpoint Rule, let's set n = 4.

For Simpson's Rule, let's set n = 2.

Step 2: Compute the approximations for each rule.

Using the Trapezoidal Rule:

Approximation = (h / 2) * [f(a) + 2f(x1) + 2f(x2) + ... + 2f(xn-1) + f(b)]

For n = 4:

h = (3 - 2) / 4 = 0.25

Approximation = (0.25 / 2) * [f(2) + 2f(2.25) + 2f(2.5) + 2f(2.75) + f(3)]

Evaluate the function √(x^3 - 8) at each x value:

f(2) ≈ √(2^3 - 8) ≈ -2

f(2.25) ≈ √(2.25^3 - 8) ≈ -1.726

f(2.5) ≈ √(2.5^3 - 8) ≈ -1.414

f(2.75) ≈ √(2.75^3 - 8) ≈ -1.125

f(3) ≈ √(3^3 - 8) ≈ -0.464

Approximation = (0.25 / 2) * [-2 + 2(-1.726) + 2(-1.414) + 2(-1.125) + (-0.464)]

≈ (0.125) * [-2 - 3.452 - 2.828 - 2.25 - 0.464]

≈ (0.125) * [-11.994]

≈ -1.49925

Using the Midpoint Rule:

Approximation = h * [f(x1) + f(x2) + ... + f(xn)]

For n = 4:

h = (3 - 2) / 4 = 0.25

Approximation = 0.25 * [f(2.125) + f(2.375) + f(2.625) + f(2.875)]

Evaluate the function √(x^3 - 8) at each x value:

f(2.125) ≈ √(2.125^3 - 8) ≈ -1.902

f(2.375) ≈ √(2.375^3 - 8) ≈ -1.609

f(2.625) ≈ √(2.625^3 - 8) ≈ -1.335

f(2.875) ≈ √(2.875^3 - 8) ≈ -1.073

Approximation = 0.25 * [-1.902 - 1.609]

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Answer:

Step-by-step explanation:

Question 13.

By applying cosine rule,

cos(45°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{10}{y}[/tex]

y = 10√2

By applying sine rule,

sin(45°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{x}{y}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{x}{10\sqrt{2} }[/tex]

x = 10

Question 15.

By applying sine rule,

sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{y}{32}[/tex]

y = 16√3

By applying cosine rule,

cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{2}=\frac{x}{32}[/tex]

x = 16

Question 17.

By applying sine rule,

sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{11\sqrt{3} }{y}[/tex]

y = 22

By applying cosine rule,

cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{2}=\frac{x}{y}[/tex]

[tex]\frac{1}{2}=\frac{x}{22}[/tex]

x = 11

Answer:

B

Step-by-step explanation:

cus thats the formula

Answer:

3.9mm

Step-by-step explanation:

The five-number summary for the given data is as follows: Minimum = 45, First Quartile (Q1) = 71, Median (Q2) = 89, Third Quartile (Q3) = 108, Maximum = 125.

The five-number summary provides key descriptive statistics that summarize the distribution of the data. It consists of the minimum value, the first quartile (Q1), which represents the lower 25% of the data, the    median (Q2), which represents the middle value or the 50th percentile, the third quartile (Q3), which represents the upper 25% of the data, and the maximum value.

To draw a boxplot based on this five-number summary, a box is drawn from Q1 to Q3, with a line indicating the median (Q2). Whiskers extend from the box to the minimum and maximum values. Outliers, if present, are represented as individual data points beyond the whiskers.

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Answer:

*Pew Pew*

Step-by-step explanation:

Answer:

28 i think

Step-by-step explanation:

The number of people who received fewer than 100 spam messages in the university department is calculated below:

Total number of messages tagged as spam = 6693

Total number of people = 12

Total number of people who received more than 100 spam messages = 11

Number of people who received fewer than 100 spam messages = 1

The number of people who received fewer than 100 spam messages can be calculated by subtracting the total number of people who received more than 100 spam messages from the total number of people in the department.

Thus, the other 1 person received a total of: 6693 - (1818 + 1358 + 442 + 416 + 399 + 389 + 304 + 251 + 251 + 178 + 158 + 103) = 474

Graph illustrating the data collected from students and faculty in the department. it is clear that the majority of students and faculty members in the department received more than 100 spam messages. One person received fewer than 100 spam messages. The number of spam messages received seems to decrease with time, which may indicate that the spam filter is effective.

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Answer: 180 ft^3

Step-by-step explanation:

Answer: 180 ft is the answer

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

Angle A=68

Step-by-step explanation:

68+x+(x-24)=180

68+x+x-24=180

2x+44=180

2x=136

x=68

Answer:

i think ist D correct me if im wrong

Step-by-step explanation:

Answer:

22.7

Step-by-step explanation:

if ∡M is 90° then you can do:

sin 65 = h/25

h = 25(sin 65°)

h = 22.65

The chi-square test is used to test the claim of independence between marital status distribution in California and the expected distribution.

To test the claim that the distribution of marital status in California is as expected, the appropriate statistical test to use is the chi-square test for independence. The null hypothesis (H0) states that marital status and residency are independent, meaning the distribution of marital status in California is the same as it is nationally. The alternative hypothesis (Ha) suggests that the distribution of marital status in California is not the same as it is nationally.

The degrees of freedom for this test is calculated as (r - 1) * (c - 1), where r is the number of rows (4) and c is the number of columns (2). In this case, the degree of freedom is 3.

Using the observed frequencies and the expected frequencies, the chi-square test statistic is calculated. The p-value is then determined based on the test statistic and the degrees of freedom. The final conclusion is made by comparing the p-value to the significance level.

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Answer:

(1,5) because, before it was at (3,8) and  

3 – 2 = 1      

8 – 3 = 5

For further explanation:

(3,8) / (2,3) = (1,5)

2 for 2 units left and 3 for 3 units down

the answer would be b on scholar

Answer:

3 (x² + 5) (x - 2)

Step-by-step explanation:

3x³- 6x² + 15x - 30

=> 3 (x³ - 2x² + 5x - 10)

=> 3 [x²(x - 2) + 5 (x - 2)]

=> 3 (x² + 5) (x - 2)

Answer:

A is the answer.

Step-by-step explanation: It would go up about 2.2 i hope i helped! <3

Answer: A is your answer

Step-by-step explanation:

Answer:

d . 19528

Step-by-step explanation:

maaf jika salah

The proportion of Shohei Ohtani's hitting the ball (batting average) decreased from 2018 to 2019. In 2018, Ohtani hit the ball 103 times out of 195 at-bats, resulting in a batting average of approximately 0.528.

In 2019, he hit the ball 54 times out of 179 at-bats, yielding a batting average of approximately 0.302. To determine whether Ohtani's batting average decreased from 2018 to 2019, we compare the proportions of hitting the ball in each year. Using a 1% significance level and assuming the Central Limit Theorem conditions hold, we can conduct a hypothesis test. The null hypothesis (H0) states that there is no difference in Ohtani's batting average between 2018 and 2019, while the alternative hypothesis (Ha) suggests a decrease in batting average.

To test the hypotheses, we can use a two-sample z-test for proportions. We calculate the sample proportions for hitting the ball in each year: p1 = 103/195 ≈ 0.528 in 2018 and p2 = 54/179 ≈ 0.302 in 2019. The standard error for the difference in proportions is given by the formula sqrt((p1(1-p1)/n1) + (p2(1-p2)/n2)), where n1 and n2 are the sample sizes.

Next, we calculate the test statistic z using the formula z = (p1 - p2) / sqrt((p1(1-p1)/n1) + (p2(1-p2)/n2)). The calculated z-value can be compared to the critical z-value at the 1% significance level (zα/2) to determine if we reject or fail to reject the null hypothesis.

In this case, the z-value is negative, indicating that the proportion of hitting the ball decreased from 2018 to 2019. By comparing the calculated z-value to the critical z-value, we can conclude that the decrease in Ohtani's batting average is statistically significant.

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Answer:

B

Step-by-step explanation: