what is precision?what is precision? ​

Answer1. :(20/25)*200/*25 2. Increase the radius or apply the force perpendicular to the wrench

Explanation:torque =force*distance*sine of the angle between applied force and axis of wrench

the fossil informed us about the climatic and geographical changes that occurs in the environment over time.

We can infer about the climate and geographical changes in the environment over time at the mystery fossil dig site because the fossil provides us information about the climatic condition as well as the geography of land when this fossil organism were alive.

So we can conclude that the fossil informed us about the climatic and geographical changes that occurs in the environment over time.

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The pitch of the sound is perceived to be lower when an object is approaching you while making a sound.

Sound is a type of vibration capable of propagating in a suitable media (e.g., air or water).

The sound waves are called acoustic waves and they have a well-defined frequency and amplitude.

In conclusion, the pitch of the sound is perceived to be lower when an object is approaching you while making a sound.

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The sign associated with the average velocity of the object is negative.

The average velocity of the object is calculated as follows;

Average velocity = (v1 + v2)/2

v1 = -20/30 = -0.667 m/s

v2 = 20/50 = 0.4 m/s

Average velocity = (-0.667 + 0.4)/2

Average velocity  = -0.134 m/s

Thus, the sign associated with the average velocity of the object is negative.

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The angular speed can't be determined without knowing the rotational inertia of the disk. The correct option is D.

 It is the quantitative measure of the inertia when a body is rotating.

Given, radius of disk R= 0.5 m, Force F=2N, then torque developed will be

τ = F x R = 2 x 0.5 =1N..m

If m is the mass of disk, the rotational moment of inertia about center of disk is

I = mR²/2 = m(0.5)²/2 = m/8 kg.m²

The angular acceleration is α =τ/I = 1/(m/8) =8/m

Angular velocity ω =ω₀ +αt = 0+(8/m) x 1 =8/m rad/s

Thus, the correct option is D.

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The angular acceleration of the magnetic disk is determined as 35 rad/s².

The angular acceleration of the disk is determined from the principle of conservation of angular momentum.

τ = Iα

where;

I = ¹/₂MR²

I = ¹/₂ x 0.2 x 2²

I = 0.4 kgm²

α = τ/I

α = (14)/(0.4)

α = 35 rad/s²

Thus, the angular acceleration of the disk is determined as 35 rad/s².

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Answer:

20s

Explanation:

t=d/(V2-V1)

t= 80000m/(6000-2000)

t= 20s

Answer:

The answer would be A

Explanation:

The statement 'diverse crops can become vulnerable to pests, disease, and climate change' is considered false regarding this last point (climate change).

Adaptation is an evolutionary process where a species fits certain environmental conditions.

Plant species are intrinsically vulnerable to climate change because they are adapted to certain climate (temperature) conditions.

In conclusion, the statement 'diverse crops can become vulnerable to pests, disease, and climate change' is considered false regarding this last point (climate change).

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The magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

The magnetic field strength is found as;

[tex]B = \frac{\mu_0I}{2r} \\\\ \mu_0 = 4 \PI \times 10^{-7}[/tex]

In the formula,I denote current, and r denotes the distance between the point and the current carrying wire and magnetic field due to current in the bottom wire.

At point 1, the net magnetic field is found as the sum of magnetic field due to current in the top wire.

[tex]\rm B_{net} = B1_+(-B_2)[/tex]

[tex]B = \frac{ 4 \PI \times 10^{-7}I}{2r} \\\\ \rm B_{net} = B_1_+(-B_2)\\\\ \rm B_{net} = \frac{4 \times \pi \times 10^{-7} \times 10}{2 \times \pi \times 0.02} -\frac{4 \times \pi \times 10^{-7} \times 10 }{2 \times \pi \times 0.06} \\\\\ \rm B_{net} = 6.67 \times 10^{-5} T[/tex]

Hence, the magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.

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Answer:

5161.26

Explanation:

5.09X1014=5161.26

Answer:

[tex]9.8\; {\rm J}[/tex], assuming that the gravitational field strength is [tex]g = 9.8\; {\rm N \cdot kg^{-1}}[/tex].

Explanation:

Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.

By Newton's Second Law, the net force on this block would be [tex]0[/tex]. External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.

Let [tex]m[/tex] denote the mass of this block. It is given that [tex]m = 1\; {\rm kg}[/tex]. The weight of this block would be:

[tex]\begin{aligned}\text{weight} &= m\, g \\ &= 1\; {\rm kg} \times 9.8\; {\rm N \cdot kg^{-1}} \\ &= 9.8\; {\rm N}\end{aligned}[/tex].

Hence, the force that the boy applies on this block would be upward with a magnitude of [tex]F = 9.8\; {\rm N}[/tex].

The mechanical work that a force did is equal to the product of:

The displacement of this block (upward by [tex]s = 1\; {\rm m}[/tex]) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:

[tex]\begin{aligned}\text{work} &= F\, s \\ &= 9.8\; {\rm N} \times 1\; {\rm m} \\ &= 9.8\; {\rm J}\end{aligned}[/tex].

Answer:

OPTION D 5 m/s

Explanation:

0.5 × 12 × v² = 150

sqrt(150/6) = v

v = 5 m/s

The object which requires the greatest change in momentum in order to stop its motion is object Z.

Momentum of any object is the product of the velocity of the object and its mass.

p =mv

Given is the chart lists the masses and velocities of four objects.

Object       Mass (kg)     Velocity (m/s)

  W               58                     1

  X                34                     2

  Y                89                    0.5

  Z                60                     2

Calculate the momentum for all the objects.

Momentum for W, p = 58 x 1 = 58 kg.m/s

Momentum for X, p = 34 x 2= 68 kg.m/s

Momentum for Y, p = 89 x 0.5 = 44.5 kg.m/s

Momentum for Z, p = 60 x 2 = 120 kg.m/s

On comparing the data from calculated momentum, we have a conclusion that highest momentum is for object Z.

Therefore, the object which requires the greatest change in momentum in order to stop its motion is object Z.

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Answer:

z

Explanation:

:)

The time it would take a 2500 W electric kettle to boil away 1.5 Kg of water is 2400 seconds

Use the formula:

Power × time = mass × specific heat

Given mass = 1. 5kg

Specific latent heat of vaporization = 4000000 J/ Kg

Power = 2500 W

Substitute the values into the formula

Power × time = mass × specific heat

2500 × time = 1. 5 × 4000000

Make 'time' the subject

time = 1. 5 × 4000000 ÷ 2500 = 6000000 ÷ 2500 = 2400 seconds

Therefore, the time it would take a 2500 W electric kettle to boil away 1.5 Kg of water is 2400 seconds.

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Answer:

Earth has a smaller mass than the Sun, but it is much closer to you than the Sun, allowing for a stronger attraction.

Explanation:

Science :)

Answer:

the clock hand of watch which have radium-226 for luminance

A PUC test would be the most likely course of action for a chemist. It is the most effective method for figuring out how the components of gasoline impact the kinds of pollutants.

The vapors created by gasoline evaporation and the chemicals produced by gasoline combustion cause impurity in the air known as air pollution.

When gasoline is burned, it emits carbon dioxide, a greenhouse gas.

Hence, the chemist's most likely action would be to do a PUC test.

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Answer:

Bullying in the schools has negative effects on individual students and on the school climate as a whole. Bullying can cause long-term problems for both the victims of bullying and the bullies themselves. To explore the effects of bullying on adolescents, we will define bullying, identify the characteristics of bullies and victims, outline the extent and consequences of bullying, and present resources for further information and assistance.

Bullying is any behavior that is initiated by one or more students against a victim or victims that causes physical or psychological intimidation. Bullying behaviors can be classified as either direct (such as teasing, threatening, hitting, or stealing) or indirect (such as rumor spreading or social isolation). Boys typically employed direct methods of bullying, while girls tend to use in direct methods. Either way, behaviors must occur repeatedly overtime to be classified as bullying.

Characteristics of Bullies and Victims

There are specific behaviors that bullies tend to exhibit. The bullies often need to feel powerful and in control. They may feel no remorse when they inflict injury and suffering on others. Bullies tend to defy authority and are likely to break school rules. They seem to have little anxiety and appear to possess high self-esteem. Students who come from homes characterized by physical punishment tend to be more likely to exhibit these types of behaviors.

Victims also tend to exhibit specific characteristics. They are often anxious, insecure, cautious, and have low self-esteem. Victims tend to be socially isolated, and may lack social skills and friends. Because they tend to be weaker than their peers, either physically or socially, victims rarely retaliate against bullies. Students who have close ties with their parents/guardians or who have overprotective parents/guardians are more likely to be victimized by bullies.

Velocity after 20s for both

Distance traveled for car

Distance traveled by truck=

#b

Distance from Q

for car

For truck

The truck will meet the car after 75/21≈4s

Then for 6s the car keeps meeting because after 7 s Truck will archive 22m/s velocity

We have the relation

[tex]\vec v_{B \mid E} = \vec v_{B \mid R} + \vec v_{R \mid E}[/tex]

where [tex]v_{A \mid B}[/tex] denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.

We're given speeds

[tex]v_{B \mid R} = 5.10 \dfrac{\rm m}{\rm s}[/tex]

[tex]v_{R \mid E} = 3.70 \dfrac{\rm m}{\rm s}[/tex]

Let's assume the river flows South-to-North, so that

[tex]\vec v_{R \mid E} = v_{R \mid E} \, \vec\jmath[/tex]

and let [tex]-90^\circ < \theta < 90^\circ[/tex] be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that

[tex]\vec v_{B \mid R} = v_{B \mid R} \left(\cos(\theta) \,\vec\imath + \sin(\theta) \, \vec\jmath\right)[/tex]

Then the velocity of the boat relative to the Earth is

[tex]\vec v_{B\mid E} = v_{B \mid R} \cos(\theta) \, \vec\imath + \left(v_{B \mid R} \sin(\theta) + v_{R \mid E}\right) \,\vec\jmath[/tex]

The crossing is 153.0 m wide, so that for some time [tex]t[/tex] we have

[tex]153.0\,\mathrm m = v_{B\mid R} \cos(\theta) t \implies t = \dfrac{153.0\,\rm m}{\left(5.10\frac{\rm m}{\rm s}\right) \cos(\theta)} = 30.0 \sec(\theta) \, \mathrm s[/tex]

which is minimized when [tex]\theta=0^\circ[/tex] so the crossing takes the minimum 30.0 s when the boat is pointing due East.

It follows that

[tex]\vec v_{B \mid E} = v_{B \mid R} \,\vec\imath + \vec v_{R \mid E} \,\vec\jmath \\\\ \implies v_{B \mid E} = \sqrt{\left(5.10\dfrac{\rm m}{\rm s}\right)^2 + \left(3.70\dfrac{\rm m}{\rm s}\right)^2} \approx 6.30 \dfrac{\rm m}{\rm s}[/tex]

The boat's position [tex]\vec x[/tex] at time [tex]t[/tex] is

[tex]\vec x = \vec v_{B\mid E} t[/tex]

so that after 30.0 s, the boat's final position on the other side of the river is

[tex]\vec x(30.0\,\mathrm s) = (153\,\mathrm m) \,\vec\imath + (111\,\mathrm m)\,\vec\jmath[/tex]

and the boat would have traveled a total distance of

[tex]\|\vec x(30.0\,\mathrm s)\| = \sqrt{(153\,\mathrm m)^2 + (111\,\mathrm m)^2} \approx \boxed{189\,\mathrm m}[/tex]

Answer:

A quasar is an extremely luminous active galactic nucleus, powered by a supermassive black hole, with mass ranging from millions to tens of billions of solar masses, surrounded by a gaseous accretion disc.

Explanation:

first!

Answer:

B. The image can either be virtual or real.

Explanation:

Concave mirrors can either produce real or virtual images. The image is upright given that it is virtual or real given that it is in front of the mirror. The images produced by the concave mirrors can also be reduced (in height), enlarged (in terms of size) or having same size as that of the object.

I hope this helps you understand about the images formed by concave mirrors.

Have a nice studies.

The forces necessary for calculating the total force are Fp and Fg. The correct option is d.

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

The gravitational force, Fg is the attractive force exerted by the Earth on the object that is equal to the mass of the object times the gravitational acceleration.

Emmett is lifting a box vertically. There are only vertical forces acting on the box.

The vertical force must counteract the weight of the object, is the upward force applied on the object.

Thus, the forces necessary for calculating the total force is Fp - Fg.

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Answer:

V / T    is the slope of the graph

S = V / T       so the slope of the graph will be the displacement at that point

Even tho the above assumes uniform quantities, the instantaneous displacement at any time is the slope of the graph at that point in case one has a graph that is not a straight line.

Answer:

B

Explanation:

The answer is B, because the waves are farther apart then the others. And it also looks like radio waves, which carries the least energy.

Answer: The third one

Explanation: there isnt many waves in that one les waves = less energy and i took the quiz/test.

Answer:

It formed from the same cloud of dust that our entire galaxy is made from

Answer:

[tex]\huge\boxed{\sf P = 12,000 \ Pa}[/tex]

Explanation:

Force = F = 1200 N

Area = A = 0.1 m²

Pressure = P = ?

[tex]\displaystyle P = \frac{F}{A}[/tex]

[tex]\displaystyle P = \frac{1200 \ N}{0.1 \ m^2} \\\\P = 12,000 \ Pa\\\\\rule[225]{225}{2}[/tex]

Answer:

P=3750

Explanation:

P=F/A

P=1200N/0.1m²

Find the square root of 0.1

square root of 0.1=0.316622776601

Approximate it =0.32

P=1200N/0.32M

Cross multiple=1200N=P0.32M

divide both side by

3750=P, P=3750

Figure 4 is the graph which best represents the relationship between the acceleration of an object falling freely near the surface of Earth and time taken.

This is defined as a pictorial representation of data in an organized and defined manner.

The acceleration of an object falling freely near the surface of Earth is constant which is why option D was chosen.

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