Describe how the Rube Goldberg device design that you created follows the law of conservation of energy. Be sure to include both parts of the law of conservation of energy in your description.
Answer:
Following are the explanation of the Rube Goldberg device:
Explanation:
According to the Rube Goldberg devices, which conform with "the energy conservation law," choose a chain of events to carry out such a basic task differently, for this unit, a range of instant theatrical resources are converted into possible energy. It is also responsive to an energy conservation law.
It is the unit that produces theatrical power when quartz falls off from the roof. Instead, its marble hits or falls into a plastic bottle, its velocity converted into potential energy which lifts its soda bottle. Its next marble, when the stone came in contact with it, can pass angular momentum to some other marble. Its gravitational force of quartz drops. It has been built into kinetic energy, distributed only to Nando. All energy of every domino becomes passed to another in a domino effect before the last one takes its contraption off because as the mousetrap gets off, all of the stored potential energy is released and the cutters were also removed. Its sequence which binds its puck is cut, which also frees the ballon as well as stores its electricity.What would the force of the Earth on the moon be when the moon is 2.0D from the Earth?
Answer:
Force, [tex]F=7.3\times 10^{36}\ N[/tex]
Explanation:
We need to find the force of the Earth on the moon be when the moon is 2.0D from the Earth.
The force that act between Earth and the Moon is gravitational force. It is given by :
[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]
We have,
[tex]m_1=\text{mass of Earth}=5.972 \times 10^{24}\ kg[/tex]
[tex]m_2=\text{mass of Moon}=7.34\times 10^{22}\ kg[/tex]
So,
[tex]F=\dfrac{6.67\times 10^{-11}\times 5.972 \times 10^{24}\times 7.34\times 10^{22}}{(2)^2}\\\\F=7.3\times 10^{36}\ N[/tex]
So, the force of the Earth on the Moon is [tex]7.3\times 10^{36}\ N[/tex].
The mass percentage of hydrochloric acid within a solution is 28.00%28.00% . Given that the density of this solution is 1.1411.141 g/mL, find the molarity of the solution.
Answer:
8.76M
Explanation:
Given that
Mass from the density = 1141g
According to the given situation the computation of molarity of the solution is shown below:-
we will took HCL solution which is 1000mL
HCl = 28% by mass
So,
Mass of HCl in 1-litre solution is
[tex]= \frac{28}{100} \times 1141[/tex]
Which gives the result of molar mass HCI is
= 319.48g /mol
Now,
Molarity is
[tex]= \frac{319.48}{36.45}[/tex]
Which gives results of molarity is
= 8.76M
Characteristics of this mineral: sheet-silicate mineral with one dominant direction of cleavage (breaks into flakes and sheets), thin sheets are silvery gray and partially transparent, does not effervesce.
Answer: The mineral you are describing is Muscovite Mica
I hope that this helps you !
The Characteristics of the mineral should be Muscovite
What is Muscovite?It is also known as the common mica, etc. It comprises of potassium & almunium. It should be the most common member of the mica group. It is considered as the mineral that contains one dominant direction of cleavage split into the flake & sheets, Also, due to the perfect cleavage, it can arise in thin, transparent, and the durable sheet.
Therefore, The Characteristics of the mineral should be Muscovite
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an engineering team is conducting a trial launch of a few rocket . which part is the engineering process is the team in ?
Answer:
Evaluate the result (Apex)
Explanation:
The sun supplies about 1.0 kilowatt of energy for each square meter of surface area (1.0 kW/m^2 where a watt = 1 kJ/s) Plants produce the equivalent of about 0.20g of sucrose (C_12H_22O_11) per hour per square meter. Assuming that the sucrose is produced as follows, calculate the percentage of sunlight used to produce sucrose12CO2 (g) + 11H2O (I) --> C12H22O11 + 12O2(g) deltaH = 5645 kJ
Answer:
0.092 %
Explanation:
The equation of the reaction can be computed as :
[tex]12CO_2_{(g)} + 11H_2O_{(l)} \to C_{12}H_{22}O_{11} + 12O_{2_(g)}[/tex]
[tex]\Delta H = 5645 \ kJ[/tex]
recall that; the number of moles = [tex]\dfrac{mass}{molar \ mass}[/tex]
By applying the method of enthalpy of combustion for sucrose at the same time changing the time from hours to seconds, we can determine the total energy output.
i.e
[tex]=\dfrac{0.20g \ of \ sucrose }{m^2 \ 3600 \ s}\times \dfrac{1 \ mol}{342.34 \ g}\times 5.645 kJ/mol[/tex]
[tex]= 9.16 \times 10^{-4} \ kJ/m^2 s[/tex]
Given that the sun supplies about 1.0 kilowatt, to KJ/m² s, we have:
[tex]1.0 \dfrac{kW}{m^2 }= 1.0 \dfrac{kJ}{m^2 s}[/tex]
Finally, the percentage of sunlight used to produce sucrose :
= [tex]\dfrac{9.16 \times 10^{-4} \ kJ/m^2 \ s}{1.0 \ kJ/m^2 . s} \times 100\%[/tex]
= 0.092 %
please help asap will give brainiest What is the independent variable in an experiment? A) The variable that remains the same throughout the experiment. B) The variable being tested in the experiment. C) The variable being measured in an experiment.
Denaturation of a protein is always permanent.
A. True
B. False
Answer:
A. True
Explanation:
This process usually cannot be reversed and will lead to the protein being permanently damaged.
Which one of the following properties is NOT a chemical property? (5 points)
a
Density
b
Flammability
c
Heat of combustion
d
Reactivity
Answer:
a
Explanation:
Density is a physical property.
Pick the compound with the highest boiling point in each pair. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.1. For the pair of compounds CO2 or NO2 the one with the highest boiling point is __________ . 2. For the pair of compounds NH3 or CH4 the one with the highest boiling point is _________ 3. For the pair of compounds CS2 or CO2 the one with the highest boiling point is _________
Answer:
1) NO2
2) NH3
3) CS2
Explanation:
CO2 is a nonpolar molecule owing to the fact that the two opposing dipoles in the molecule cancels out. Hence its primary intermolecular forces are the weak dispersion forces. How ever NO2 is polar and its molecules are held together by dipole-dipole interaction this makes the boiling point of NO2 greater than that of CO2
NH3 exhibits hydrogen bonding since nitrogen is far more electronegative than hydrogen. However, CH4 is nonpolar and the only intermolecular forces present are weak dispersion forces. This accounts for the fact that NH3 has a greater boiling point than CH4.
The boiling point of a compound also depends on its molecular mass. CS2 has a greater boiling point than CO2 due to the fact that CS2 has a larger molecular mass. The both compounds- CO2 and CS2 has exactly the same kind of intermolecular forces present between their molecules- the weak dispersion forces.
Processes are always spontaneous when ________ ( H and S refer to the system).
Answer:
Explanation:
A spontaneous chemical process is one in which product formation is favoured under the specified conditions. A spontaneous process yields the product without an external input of energy.
A spontaneous reaction will always occur when ∆H is negative and ∆S is positive. These are the signs of enthalpy and and entropy change that gives rise to a spontaneous chemical process at all temperatures. Recall that a spontaneous process is one in which ∆G<0.
The weak acid HA is 4 % ionized (dissociated) in a 0.30 M solution. A. What is Ka for this acid?B. What is the pH of this solution?
Answer:
[tex]Ka=5x10^{-4}[/tex]
[tex]pH=1.92[/tex]
Explanation:
Hello,
In this case, given the percent ionization and the concentration of the acid, one computes the concentration of hydrogen ions as follows:
[tex]\% ionization=\frac{[H^+]}{[HA]}*100\%[/tex]
[tex][H^+]=\frac{\% ionization*[HA]}{100\%} =\frac{4\%*0.30M}{100\%}=0.012M[/tex]
Therefore the Ka is computed by using the equilibrium expression:
[tex]Ka=\frac{[H^+][A^-]}{[HA]} =\frac{0.012M*0.012M}{0.30M-0.012M}\\ \\Ka=5x10^{-4}[/tex]
And the pH:
[tex]pH=-log([H^+])=-log(0.012)\\\\pH=1.92[/tex]
Regards.
Increasing temperature can
Answer:
increases reaction rates
Explanation:
Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.
when are larger atoms least likely to be reactive
Answer:
when they have eight valence electrons.
Explanation:
When atoms do not have a full valence shell, the atoms are more likely to react with other and vice versa.
Answer:
When they have a full shell of electrons
Explanation:
and or eight valence electrons
The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. What is this distance in millimeters? A) 1.15x 10-8 mm B) 1.15 1013 mm C) 1.15 10-7 mm D) 1.15 x 1017 mm
Answer:
C) 1.15 × 10⁻⁷ mm
Explanation:
Step 1: Given data
Average distance between nitrogen and oxygen atoms: 115 pm
Step 2: Convert the distance to meters (SI base unit)
We will use the conversion factor 1 m = 10¹² pm.
115 pm × (1 m/10¹² pm) = 1.15 × 10⁻¹⁰ m
Step 3: Convert the distance to millimeters
We will use the conversion factor 1 m = 10³ mm.
1.15 × 10⁻¹⁰ m × (10³ mm/1 m) = 1.15 × 10⁻⁷ mm
The measurement 0.020 L is the same as?
Answer:
20 mL
2 cL
Explanation:
We can use the base 10 decimal system to get equivalent measurements:
1 L = 1000 mL
1 L = 100 cL
why is the pull of gravity more at the poles than at than at the equator.
Answer:
Why the gravitational force is greater near the poles and less at equator?
Gravitational force of Earth is minimum at equator because the centrifugal force at the equator is maximum.
Centrifugal force is an outward force exerted on a body revolving in a circular path, to mantain its state of motion.
Explanation:
Here Earth revolves around its axis and the same forces act on it to enable its revolution.
Gravitational force at the equator is less because Centrifugal force, which is also acting at the equator cancels out the Gravitational force to an extent. Whereas at poles, there is no such effect of centrifugal force because earth is sphere (bulged at center; flat at poles )and hence gravitational force is maximum at poles.
The other reason is distance from any place on equator to centre of earth is more than at poles. Because Earth is bulged at centre and flat at poles. Since Gravitational force is given by
F= GMm/ r^2 ; r is the distance between two bodies.
In order to calculate how many neutrons are in an atom, you must subtract the mass number from the number of protons? Neutrons = Mass # - Protons Question 6 options: True False
Answer:
True.
Explanation:
The mass number of an atom can be calculated using no of protons and the no of neutrons.
Mass number = no of protons + no of neutrons
We can rearrange the above formula to find the no of neutrons as follows :
no of neutrons = Mass number - no of protons
or
Neutrons = Mass - protons.
Hence, the given statement is true.
Liquid octane (C8H18), a component of gasoline, reacts with gaseous oxygen to form gaseous carbon dioxide and water vapor. Write the balanced chemical reaction for this process.
Answer:
[tex]2C_{8}H_{18 (l)} + 25O_{2 (g)}[/tex] → [tex]16CO_{2(g)} +18H_{2}O_{(l)}[/tex]
Explanation:
One dose of a liquid medication is 2.5 tablespoons. If a patient takes a dose of this medication four times a day for a week, how many milliliters of this medication is consumed in one week? (1 tbsp = 15 mL)
Answer:
1050 mL
Explanation:
Step 1: Given data
Dosage of the liquid medication: 2.5 tablespoons (tbsp)
Times that the patient takes the medication: 4 times a day for a week
Step 2: Calculate the number of times the patient takes the medication
We will use the relationship 1 week = 7 days.
[tex]1 week \times \frac{7days}{1week} \times \frac{4dose}{1day} = 28 dose[/tex]
Step 3: Calculate the number of tablespoons
We will use the relationship 2.5 tbsp/1 dose.
[tex]28dose \times \frac{2.5tbsp}{1dose} = 70tbsp[/tex]
Step 3. Convert 70 tbsp to mL
We will use the relationship 1 tbsp = 15 mL.
[tex]70tbsp \times \frac{15mL}{1tbsp} = 1050 mL[/tex]
A hybrid car holds 32 gallons of gas in its tank. If it travels from San Diego to Seattle in three tanks of gas, and gas costs $3.29 per gallon, about how much did the trip cost? Report your answer with three significant figures.
3 tanks of gas->32*3->96 gallons in total.
96*3.29->315.84
3 sig. figs. -> $315
A nearly flat bicycle tire becomes noticeably warmer after it has been pumped up. Approximate this process as a reversible adiabatic compression. Take the initial pressure and temperature of the air before it is put in the tire to be Pi = 1.00 bar and Ti = 298 K. The final volume of the air in the tire is Vf= 1.50 L and the final pressure is Pf = 5.00 bar. Calculate the final temperature of the air in the tire.
Complete Question
A nearly flat bicycle tire becomes noticeably warmer after it has been pumped up. Approximate this process as a reversible adiabatic compression. Take the initial pressure and temperature of the air before it is put in the tire to be Pi = 1.00 bar and Ti = 298 K. The final volume of the air in the tire is Vf= 1.50 L and the final pressure is Pf = 5.00 bar. Calculate the final temperature of the air in the tire.
Assume that Cv,m = 5R/2
Answer:
The value is [tex]T_f = 471.978 \ K[/tex]
Explanation:
From the question we are told that
The initial pressure is [tex]P_i = 1.00 \ bar[/tex]
The initial temperature is [tex]T_i = 298 K[/tex]
The final volume is [tex]V_f = 1.50 \ L[/tex]
The final pressure is [tex]P_f = 5.0 \ bar[/tex]
Generally the equation for reversible adiabatic compression is
[tex]P_i V_i^{\gamma} = P_f V_f^{\gamma} [/tex]
Generally from the ideal gas equation we have that
[tex]PV = n RT[/tex]
=> [tex] V = \frac{n RT}{P}[/tex]
So
[tex]P_i *[ \frac{n RT_i}{P_i}]^{\gamma} = P_f [ \frac{n RT_f}{P_f}]^{\gamma}[/tex]
=> [tex]P_i ^{1 - \gamma} * T_i ^{\gamma} = P_f ^{1-\gamma} * T_f^{\gamma}[/tex]
=> [tex]T_f ^{\gamma} = \frac{ P^{1 - \gamma * T_i^{\gamma}}}{ P_f ^{1 - \gamma}}[/tex]
=> [tex]T_f =[ \frac{ P_i ^{1 - \gamma} * T_i^{\gamma}}{P_f^{1 - \gamma}}]^{\frac{1}{\gamma} }[/tex]
=> [tex]T_f = T_i * [\frac{P_i}{P_f} ]^{\frac{1- \gamma}{\gamma}[/tex]
Here [tex]\gamma[/tex] is a constant mathematically represented as
[tex]\gamma = \frac{C_{P,m}}{C_{V, m}}[/tex]
Here
[tex]C_{P,m}} [/tex] is the molar heat capacity at constant pressure
and [tex]C_{V,m}} [/tex] is the molar heat capacity at constant volume given as
[tex]C_{V,m}} = \frac{5R}{2} [/tex]
Generally [tex]C_{P,m}} [/tex] for an ideal gas is mathematically represented as
[tex]C_{P,m}} = R +C_{V,m}} [/tex]
So
[tex]\gamma = \frac{\frac{5R}{2} + R}{ \frac{5R}{2} }[/tex]
=> [tex]\gamma = \frac{7}{5} [/tex]
So
=> [tex]T_f = T_i * [\frac{P_i}{P_f} ]^{\frac{1- \frac{7}{5}}{ \frac{7}{5}}[/tex]
=> [tex]T_f = 298 * [\frac{1}{5} ]^{\frac{1- \frac{7}{5}}{ \frac{7}{5}}[/tex]
=> [tex]T_f = 471.978 \ K[/tex]
The Final temperature of the air in the tire = 471.978k
Given data :
Initial pressure ( [tex]P_{i}[/tex] ) = 1.00 bar
Initial temperature ( [tex]T_{i}[/tex] ) = 298 K
Final volume of air ( [tex]V_{f}[/tex] ) = 1.50 L
Final pressure ( [tex]P_{f}[/tex] ) = 5.00 bar
Assume Cvm = 5r / 2 ( missing data )
Determine the final temperature of the air in the tire
Applying the equation for a reversible Adiabatic compression and general ideal gas equation
[tex]Pi * [ \frac{nRTi}{Pi} ] \alpha = Pf * [ \frac{nRTf}{Pf}] \alpha[/tex] ---- ( 1 )
Resolving equation ( 1 )
[tex]final temperature = Ti * [ \frac{Pi}{Pf}]^{\frac{1-\alpha }{\alpha } }[/tex] ------- ( 2 )
where [tex]\alpha[/tex] ( mathematical constant ) = ( Cpm / Cvm ) --- ( 3 )
Cpm = molar heat capacity at constant pressure = R + Cvm
Cvm = molar heat capacity at constant volume = 5r / 2
∴ Equation ( 3 ) becomes
[tex]\alpha[/tex] = [tex]\frac{7}{5}[/tex]
Final step : Determine the final temperature of the air in the tire
Input values back into equation ( 2 )
[tex]final temperature = 298 + [\frac{1}{5}] ^{\frac{1-\frac{7}{5} }{\frac{7}{5} } }[/tex]
= 471.978 K
Hence we can conclude that the final temperature of the air in the tire is 471.978 K
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Which weak acid would be best to use when preparing a buffer solution with a pH of 9.80?A. An acid with Ka = 7.9 times 10-12.B. An acid with Ka = 2.0 times 10-5.C. An acid with Ka = 2.5 times 10-7.D. An acid with Ka = 1.6 times 10-6.E. An acid with Ka = 2.0 times10-8.F. An acid with Kg = 1.3 times 10-10.
Answer:
An acid with Kg = 1.3 times 10-10.
Explanation:
The formula for pH of a buffer solution is as follows
pH = pKa + log [ A⁻ ] / [ HA ]
HA is acid concentration and A⁻ is concentration of conjugate base .
Generally the the second term is very small so neglecting this figure
pH = pKa
9.8 = pKa
If Ka = 10⁻¹⁰ x 1.3
pKa = - log ( 10⁻¹⁰ x 1.3 )
= 10 - log 1.3
= 9.8 approx .
Hence option F is correct .
what is the name of the salt with the structure K2S
What is the mass grams of 0.0135 mol of the element sodium, Na?
Answer:
Tvfbggbtb
Explanation:
Soil is a heterogeneous mixture. Which of the following
statements best explains why?
a
It is uniformly mixed, so it has an even composition
throughout
b
The components are chemically bound together in
a disordered shape, so it does not have the same
composition throughout the mixture.
c С
The particles are large enough to see, so it looks
the same throughout.
d
It is unevenly mixed, so it does have the exact
same composition throughout the mixture,
S
Answer: D
Explanation:
i just took the ck-12 quiz and that was the right answer
Can I make it rain inside
Answer:
you use your sink and spray the little hose thingy and boom. or you can make it rain with mooney
Explanation:
no u can not make it rain in the house but if u want in the jar, here are the steps
Question: How can you make it rain indoors? 1) First, fill a glass jar with very hot tap water. 2) Then, flip the lid over and fill it with ice. ... In about 15 minutes you will see "rain" fall inside the jar .
hope this helped you
A 75.0 mL sample of water is heated to its boiling point. How much heat (in kJ ) is required to vaporize it?
Given :
A 75.0 mL sample of water is heated to its boiling point.
To Find :
The heat (in kJ ) is required to vaporize it .
Solution :
Heat of vaporization of water , [tex]\Delta H_{vap}=40.65\ kJ/mol[/tex].
Molar mass of [tex]H_2O[/tex] , [tex]M=18\ g/mol[/tex] .
Density of water , [tex]\rho=1\ g/ml[/tex] .
Mass of 75 ml of water sample , [tex]m=75\ g[/tex] .
Moles of 75 g water = [tex]\dfrac{75}{18}=4.17\ mol[/tex] .
Now , heat required to vaporize 4.17 mol of water :
[tex]H=4.17\times 40.65\ kJ\\\\H=169.51\ kJ[/tex]
Therefore , heat required to boil 75 ml sample of water is 169.51 kJ.
Hence , this is the required solution .
The efficiency of the wedge is low because of _____.
Answer:friction
Explanation:
Consider 55 mL of water (H2O) in a beaker and 55 mL of acetone |(CHs)2CO in an identical beaker under identical conditions Complete the sentences to explain the relationship between the vapor pressure of water and acetone. Match the words to the appropriate blanks in the sentences.
larger than
more quickly than
the same as
weaker
smaller than
stronger
more slowly than
at the same rate as
1. Water will evaporate______ acetone
2. The vapor pressure of acetone is__________ than that of water at the same temperature.
3. This is because the intermolecular forces between acetone molecules are ___________than those between water molecules.
Answer:
1. more slowly than
2. larger than
3. weaker
Explanation:
Acetone molecules are bonded by very weak intermolecular forces when compared to that of the hydrogen bond between water molecules. This makes it very easy for acetone molecules to vaporize easily into its gaseous state, much more faster than water molecules (since the acetone molecules need a lesser amount of energy to break these bonds). Also, the boiling point of liquid acetone is much lower than that of water, meaning that it has a higher vapor pressure than that of water.