Answer:
Applications:
- silence gene expression of target genes
- activate gene expression of target genes
- determine the role of DNA methylation and histone modifications (methylation, acetylation, etc) on specific regulatory sites (e.g., enhancer sequences)
Explanation:
The CRISPR/Cas9 system can be repurposed to edit the epigenome of living cells. For this purpose, it is required 1-to fuse a catalytically inactive 'dead' Cas9 enzyme with enzymes involved in epigenetic mechanisms (e.g., DNA methyltransferases, histone deacetylases, etc) capable of activating or deactivating gene expression, and 2-to design single-guide RNAs (sgRNAs) complementary to the sequence of interest (i.e., target sequences whose epigenome landscape we are trying to modify). For example, dCas9 gene has been fused with the DNA methyltransferase 3a (Dnmt3a) gene to create a dCas9-DNMT3A complex which can be combined with a specific sgRNA in order to study the effects of DNA methylation at a particular gene. These CRISPR/Cas9-mediated epigenome editing systems have shown to be very useful to understand how epigenome drives chromatin folding and dynamics at specific genomic sites (loci), and thus regulate gene expression at the transcriptional level.
What is the rapid change in a membrane's potential caused by the depolarization of a neuron?
Answer:
During depolarization, the membrane potential rapidly shifts from negative to positive. As the sodium ions rush back into the cell, they add positive charge to the cell interior, and change the membrane potential from negative to positive.
Explanation:
Which of the following statements explains how N-formylmethionine (fMet) is only associated with the 5' AUG initiation codon and not with internal AUG codons, given that methionine in both cases in encoded by an AUG in the mRNA. Select all that apply. Group of answer choices Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. There are more than one tRNA with the 5' CAU 3' anticodon. fMet is always incorporated at interior AUG sites and then deformylated after translation. The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide.
Answer:
Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A ) There are more than one tRNA with the 5' CAU 3' anticodon. ( B ) The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )Explanation:
The statements that explains how N--formyl methionine (fMet) is only associated with the 5' AUG initiation codon and not with internal AUG codons, given that methionine in both cases in encoded by an AUG in the mRNA are :
Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A )
There are more than one tRNA with the 5' CAU 3' anticodon. ( B )
The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )
While statement C is wrong.
how do allosteric enzymes activate and inhibit chemical reactions in a living organism?
Answer:
Allosteric activators bind to locations on an enzyme away from the active site, inducing a conformational change that increases the affinity of the enzyme's active site(s) for its substrate(s). Allosteric inhibitors modify the enzyme's active site so that substrate binding is reduced or prevented.
Explanation:
thank me later
its also nice to keep a _______ in my purse
Answer:
its also nice to keep a __phone_____ in my purse
Explanation:
Pls help I’ll brainlest
You can pick more than one I think
Answer:
I say the correct answers are C and D and E maybe.
Explanation:
But I say both good and right answer are C and D. And just E for backup!
Reading- vocabulary quiz
Answer:
b- it describes how the tourist took the pictures.
Which best describes cells at the end of mitosis (cell division)?
A) Two daughter cells are identical at the end of mitosis
B) Two daughter cells are completely different at the end of mitosis
C) Four daughter cells are completely different at the end of mitosis
D) Four daughter cells are identical at the end of mitosis
Answer:
A - two daughter cells are identical at the end of mitosis
Pregnancy comes with a unique set of diet and lifestyle guidelines. Some substances are particularly beneficial for the mother or baby, others are harmful, and some should be used with caution.
a. True
b. False
Answer:
I believe it it A. True
Hope this helps
Answer:
a
Explanation:
the concentration of substances contained in e.g some medicines might be okay for a woman who is not expecting but the the impact is totally different to someone who has a baby growing in their uterus,this is so because babies are very delicate and reactive to strong chemicals
The authors describe an important experiment in which scientists showed strong support for the hypothesis that bdelloid rotifers have reproduced asexually for millions of years. Briefly describe the results from their experiment that supported this conclusion
Answer:
Bdelloid rotifers are small metazoans, a class of very small invertebrates that can visible through a microscope only. They reproduce asexually and found in temporary or permanent freshwater.
Bdelloid rotifers population shows only females in this population and Males not found yet, which suggests that females asexually produce identical progeny. The process called parthenogenesis. The organisms that sexually produced their DNA has two copies of the genome that may or may not be identical but in case of asexual reproduction, there are always identical copies produce.
Some aquatic animals possess stinging cells. These cells are called: Hypothocysts. Nematocysts. Psoriacysts. None of the above.
Answer:
The correct answer is - Nematocycst.
Explanation:
Nematocysts are aquatic animals that contain stinging cells known as cnidocytes. These organisms are members of the phylum Cnidaria. These carry a organelle called cnida or cnidocyst.
An example of such an organism is Jellyfish. Sting cells are specialized neural cells that release extensive Golgi secretion venom that causes a stinging experience to the prey the nematocyst.
Briefly explain the characteristics of vertebrates?
Answer:
A vertebrate is anything with a backbone. Mammals, Amphibians, Reptiles, Birds, and some fish. These organisms with a backbone would be categorized as Phylum Chordata. (Chordates, meaning chord, or spinal chord).
Explanation:
Which of the following was unknown to the agent Greeks
Answer: i’m sorry but where is the Answers
Explanation:
B. Absorbs water
C. Stores solid waste
c. Soft Goupik
B Р
(D) Filter waste products from blood
CF
D
7. What system is composed of these five parts, heart, blood vessels, lymph vessels, blood
and lymph?
A. Excretory System
B. Lymphatic System
C. Nervous System
D. Circulatory System
In guinea pigs, the color of the fur is determined by a single gene with two alleles control. The brown allele (B) is dominant over the white allele (b). Two heterozygous guinea pigs are crossed. Draw a genetic diagram with the genotypic, phenotypic and ratio information of the P₁ and F ₁ generations of this cross.
Answer:
B b
B BB Bb
b Bb bb
Genotype:
ratio - 1:2:1
1 BB = 25%
2 Bb = 50%
1 bb = 25%
Phenotype:
ratio - 3:1
3 Brown: 75%
1 White:25%
HOpe this helps
146. The ATP/CP Pathway is best for which of the following activities? A. Running a marathon B. 100m sprint C. 30 minutes steady state cardio D. - Tabata workout
Answer:
100m sprint
Explanation:
The ATP/CP Pathway is best for in 100m sprint activity.
what is ATP ?Adenosine Triphosphate (ATP) is the energy carrier in every living organisms on earth which capture and store energy metabolized from food and light sources in the form of ATP.
ATP is broken down through hydrolysis during energy required by a cell, The high energy bond is broken and removal of a phosphoryl group occurred.
The energy released from this process is used to drive various cellular processes.
ATP is constantly participates in biological reactions and central to the health and growth of all life, transfer energy from one location to another,.
For more details regarding ATP, visit
https://brainly.com/question/29775560
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In chipmunks, the dominant allele (H) codes for short-haired fur and the recessive allele (h) codes for long-haired fur. What is the probability that the offspring of a cross between a male chipmunk (Hh) and a female
chipmunk (hh) will have either furtype?
A. 50% of alfspring will have long haired fur.
B. 25% of offspring will have short-haired fur.
C. 100% of offspring will have long-haired fur.
D. 100% of offspring will have short-haired fur.
Answer:
50% will have long hair!
Explanation:
When you cross between Hh and hh, two out of four are Hh, which is long hair, and two are hh, which is short hair.
Answer:
A I think
Explanation:
What is brine rejection?
Answer:
Brine rejection is a process that occurs when salty water freezes.
Explanation:
The age of rock as determined by the other rock surrounding it is known as ______________.
A) absolute age
B) carbon dating
C) Law of Superposition
D) relative age
Answer:
B)CARBON DATING
Explanation:
Climate has to do with the amount of energy that is in Earth's System
True/False
explain Why?
Answer: false
Explanation:
The protective covering of seeds; used to attract animals to the plant to disperse the seeds is called the ?
Stamen
Fruit
Root System
Fungi
Answer:
Fruit
Explanation:
Fruit is a ripened ovary of a plant which contains one or more seeds
The ____________________ produce(s) hormones that cause you to feel frightened during a horror movie.
What is the mean protein in bone
Answer: Made mostly of collagen, bone is living, growing tissue. Collagen is a protein that provides a soft framework, and calcium phosphate is a mineral that adds strength and hardens the framework. This combination of collagen and calcium makes bone strong and flexible enough to withstand stress.
Which of the following is a type of adaptation that animals can have? 1. Physical characteristics II. Behaviors III. Life cycle differences O1 and 11 OI I and III O II and III O1, II, and III
Gerard lives in a tropical region where the average
annual temperature is 77°F and the average annual
rainfall is more than 100 inches a year. He surveys 25
people in his neighborhood about items they regularly
use and records the data into a table.
Product Number of People
Umbrellas
25
Insulated gloves
22
Raincoats
19
Rubber boots
13
Hats
8
For which products has Gerard most likely recorded
the data with an error?
O umbrellas
O insulated gloves
raincoats
O rubber boots
Gametes contain how many copies of each chromosome?
Answer:
Explanation:
each gamate carries 22 ordinary chromosome and one sex chromosome,altogether they carry 23 chromosome each.
what is shown on the y-axis in this figure variation within treatment
Explanation:
Temperature is shown on y-axis
True or False
humans can survive longer without food than they can without water
Answer:
False.
Explanation:
The human can typically go two to three days without water and 30 to 40 days without food.
I hope this helps, have a nice day.
Answer:
False
a human can go a month without food but cannot go a week without water
According to modern cell theory, all cells arise from pre-
existing cells by what process?
a
Cell division
b DNA replication
С
Sexual reproduction
d Cellular respiration
A child is born with hemophilia (inherited as an X-linked recessive) and Klinefelter's syndrome to parents who both have normal blood clotting. In which parent (mother or father) and during which round of meiosis (I or II) did the nondisjunction event occur
Answer:
mother
Explanation:
Hemophilia is a sex-linked recessive disorder caused by a mutation in one of the genes responsible for encoding the clotting factor proteins (factor VIII or factor IX), which are located on the X chromosome. Moreover, the Klinefelter syndrome is caused by men having an additional X chromosome. In this case, the nondisjunction occurred from the mother because her gamete included an extra X, it is for that reason that all genes localized on the X chromosome, including the defective gene involved in hemophilia, can cause all of her sons to be affected by the disease in some generation. Thus, sister chromatids did not separate during meiosis (Anaphase II) and caused two copies of the defective allele for the hemophilia trait.
What structures in the Ammocoetes (lamprey larvae) and adult lamprey are homologous to the gill bars and jaws of the shark (dogfish
Answer: The homologous structure between shark and lamprey is that:
--> Both are fishes and
--> possess skeletons that are at least partially made of cartilage.
Explanation:
The class PISCES belongs one of the five classes of vertebrate with the following features:
--> it is cold- blooded animal.
--> it's body is covered with scales and a layer of slime.
--> it had fins
--> it carries out gaseous exchange by hills.
--> it has a well developed sense of smell
--> it had a two - chambered heart.
The HOMOLOGOUS structures are those features that are present in the lamprey that are also seen in the shark. This can simply be referred to as the similarities between the lamprey and the shark. These similarities include:
--> Both are fishes and
--> both possess skeletons that are at least partially made of cartilage. This is a feature that is lacking in bony fishes such as Tilapia and carp.