In a population of 2000 male students with weights following a normal distribution (mean = 200, standard deviation = 20), we can calculate the number of students falling within specific weight ranges. (i) Between 120 and 130 pounds, approximately 5 students. (ii) At most 250 pounds, approximately 1970 students. (iii) Between 150 and 175 pounds, approximately 841 students. (iv) At least 200 pounds, approximately 841 students.
To calculate the number of students falling within specific weight ranges, we can use the properties of the normal distribution.
(i) To find the number of students between 120 and 130 pounds, we need to calculate the probability of a weight falling within this range. We can standardize the values using the formula z = (x - mean) / standard deviation and find the corresponding z-scores for 120 and 130 pounds. Then, we can use a standard normal distribution table or a calculator to find the probability. Multiplying this probability by the total number of students (2000) gives us the approximate number of students falling within this range.
(ii) To find the number of students at most 250 pounds, we can calculate the probability of a weight being less than or equal to 250 pounds using the z-score and the standard normal distribution table. Again, multiplying this probability by the total number of students gives us the approximate number of students.
(iii) To find the number of students between 150 and 175 pounds, we follow a similar approach as in (i) to calculate the probability within this range and multiply it by the total number of students.
(iv) To find the number of students at least 200 pounds, we can calculate the probability of a weight being greater than or equal to 200 pounds using the z-score and the standard normal distribution table, and multiply it by the total number of students. These calculations provide us with approximate estimates of the number of students falling within each weight range based on the given mean and standard deviation of the population.
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Find the radius of the button.
28 mm
radius:
mm
Answer:
14 mm
Step-by-step explanation:
Just write down the answer.
Answer:
28mm
Step-by-step explanation:
is the right answer
Given the coordinates for the function below, which of the following are coordinates for its inverse?
The inverse of the given function is represented by Data Table B.
What is a Function?A function is a law that relates a dependent and an independent variable.
The Inverse of the function is determined by interchanging the values of a and y in an f(x,y) function and then express the equation of y in terms of x.
Th table of the function is
Miles to go Miles Travelled
0 0
100 310
200 450
340 550
650 650
The inverse of this data table will be
Miles Travelled Miles to go
650 650
340 550
200 450
100 310
0 0
This is represented by Data Table B.
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Verify that Rolle's Theorem can be applied to the function f(x) = 3 - 102 +31-30 on the interval [2, 5]. Then find all values of c in the interval such that f' (c) = 0.
Enter the exact answers in increasing order.
To enter √a, type sqrt(a).
c =
C=
Show your work and explain, in your own words, how you arrived at your answers.
Equation Editor A- A T I
BIUS X₂ x²
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Words: 0
The exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3
To verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5], we need to check if the following conditions are satisfied:
f(x) is continuous on [2, 5].f(x) is differentiable on (2, 5).f(2) = f(5).Let's check each condition:
f(x) = x³ - 10x² + 31x - 30 is a polynomial function and is continuous for all real values of x. So, it is continuous on [2, 5].
To check the differentiability, we need to find f'(x):
f'(x) = 3x² - 20x + 31.
The derivative f'(x) exists and is continuous for all real values of x. So, f(x) is differentiable on (2, 5).
Now, let's evaluate f(2) and f(5):
f(2) = (2)³ - 10(2)² + 31(2) - 30 = -10
f(5) = (5)³ - 10(5)² + 31(5) - 30 = 95
Since f(2) = -10 is not equal to f(5) = 95, we can conclude that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5] after differentiable.
To find the values of c in the interval (2, 5) such that f'(c) = 0, we need to solve the equation f'(c) = 3c² - 20c + 31 = 0.
Using quadratic formula:
c = (-(-20) ± sqrt((-20)² - 4(3)(31))) / (2(3))
c = (20 ± sqrt(400 - 372)) / 6
c = (20 ± sqrt(28)) / 6
c = (20 ± 2sqrt(7)) / 6
c = (10 ± sqrt(7)) / 3
The values of c in the interval (2, 5) such that f'(c) = 0 are:
c = (10 + sqrt(7)) / 3
c = (10 - sqrt(7)) / 3
Therefore, the exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3.
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Incomplete question:
Verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² +31x-30 on the interval [2, 5]. Then find all values of c in the interval such that f' (c) = 0.
Enter the exact answers in increasing order.
To enter √a, type sqrt(a)
c = ?
I asked some friends how old they think they will be when they get married. Here are their answers:
{42, 38, 27, 53, 39, 29, 52}
Put this data in order from least to greatest.
Answer:
27,29,38,39,42,52,53
Step-by-step explanation:
PLS HELP ME QUICK I NEED THIS GOOD GRADE PLS HELPPPP! Tell whether each statement is true or false. If false, provide a counterexample. The set of whole numbers contains the set of rational numbers. Every terminating decimal is a rational number. Every square root is a rational number. The integers are closed under addition.
Answer:
1. The set of whole numbers contains the set of rational numbers. FALSE.
The set of integers contains the set of rational numbers
2. Every terminating decimal is a rational number. TRUE
3. Every square root is a rational number. FALSE
Many square roots are irrational numbers, meaning there is no rational number equivalent.
4. The integers are closed under addition. TRUE
a local ice cream shop has a special deal on thursdays: buy a waffle cone for $3 and get each scoop of ice cream for $1.50. what would be the rate of change in this word problem?
In the given word problem, the rate of change is the change in the cost of the ice cream concerning the change in the number of scoops.
That is, the rate of change is the ratio of the change in the cost of ice cream and the change in the number of scoops. Let's first calculate the initial rate of change or slope of the given deal: When we buy a waffle cone, the cost is $3, and we can buy one scoop of ice cream for $1.50.So, for one scoop of ice cream, the total cost would be 3 + 1.50 = $4.50.
We can represent the cost of one scoop of ice cream with the help of a linear equation: y = mx + b. Here, the slope or the rate of change, m = Change in cost of ice cream/ Change in the number of scoops= 1.5/1= 1.5Therefore, the rate of change of the ice cream with respect to the number of scoops is $1.50/scoop.
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For the quadratic function show below the coordinates of its vertex are
Answer: 0,2
Step-by-step explanation:
Tbh you can guess for the fractions
Answer:
4:1 ratio
Sugar: 1 cup
Butter: 3/4 cups
Eggs: 2
Baking powder: 3/8 tsp
Flour: 5/8 tsp (you need way more flour for cookies)
Salt: 1/8 tsp (original # was hard to make out but I think it was 1/2 tsp)
a triangle with an area of 23 cm² is dilated by a factor of 6. what is the area of the dilated triangle?
When a triangle is dilated by a scale factor, the area of the dilated triangle is equal to the scale factor squared times the area of the original triangle. The area of the dilated triangle is 828 cm².
In this case, the original triangle has an area of 23 cm². The triangle is dilated by a factor of 6, so the scale factor is 6.
To find the area of the dilated triangle, we use the formula:
Area of Dilated Triangle = (Scale Factor)^2 * Area of Original Triangle
Plugging in the values:
Area of Dilated Triangle = 6^2 * 23 cm²
= 36 * 23 cm²
= 828 cm²
Therefore, the area of the dilated triangle is 828 cm².
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SOLVE THIS PLEASE I WILL GIVE BRAINLIEST AND 5 STAR RATING! AND GIVING 70 POINTS!!!!!
Answer:
[tex]L^{2} + W^{2} = d^{2}[/tex]
d = 31.6
Step-by-step explanation:
[tex]L^{2} + W^{2} = d^{2}[/tex]
[tex]30^{2} + 10^{2} = d^{2}[/tex]
[tex]d^{2}[/tex] = 900 + 100
= 1000
d = [tex]\sqrt{100}[/tex] = 31.6
5. How many mililiters of a 3.5 M iron (II) nitrite (Fe(NO2)2) solution are needed to provide a tot
of 0.13 kg of Fe(NO),?
need help plss
Answer:
try this link!
Step-by-step explanation:
https://www.wylieisd.net/cms/lib09/TX01918453/Centricity/Domain/783/Math%20Connections%20Key.pdf
Kai has 8 pints of buttermilk. He uses 4 ounces of buttermilk in
his receipe for a loaf of bread. How many loaves of bread can he make with the buttermilk that he has?
A. 2 loaves
B. 16 loaves
C. 24 loaves
D. 32 loaves
2. A wooded area is in the shape of a a trapezoid whose bases measure 128 m and $2 m and its height is 40 m. A 4 m wide walkway is constructed which runs perpendicular from the two bases. Calculate the area of the wooded area after the addition of the watkway
Correction in the Question:
A wooded area is in the shape of a a trapezoid whose bases measure 128 m and 92 m and its height is 40 m. A 4 m wide walkway is constructed which runs perpendicular from the two bases. Calculate the area of the wooded area after the addition of the walkway.
Answer:
The wooded area after the addition of the walkway is 4240 [tex]m^2[/tex].
Step-by-step explanation:
we are given
length of the two bases = 128m and 92m
height of the trapezoid = 40m
the approximate figure of the given trapezoid is given as:
__ __ __ 92 __ __ _
/ | | | \
/ | 40 |4| \
/__ _| __ __ | |__ __ __ __ \
128
Area of a trapezoid = [(a + b)/2] * height, where a and b are representing the bases of the given trapezoid.
Area = [(92 + 128)/2] * 40
= [220/2] * 40
= 110 * 40
= 4400 [tex]m^2[/tex]
Now there is a 4m wide walkway is to be constructed in that trapezoid. The pathway will be a rectangle as it has 4m width and 40m height as it is perpendicular to both the bases.
Area of a rectangle = length * width
Area = 40 * 4
= 160
Since the walkway will reduce the area of the trapezoid as it is constructed upon it therefore the wooded area after the addition of the walkway is
4400 + (-160) = 4240 [tex]m^2[/tex].
whata 10 divided by 100
Answer:
it 10000
Step-by-step explanation:
79ib dlndokveik dinfl. kwbfb
how do I solve sin(4x)=sin(2x)?
Answer:
sin(4x) = sin(2x) is unsolvable.
Step-by-step explanation:
The two sides are not equal.
OMG HELP PLS IM PANICKING OMG OMG I GOT A F IN MATH AND I ONLY HAVE 1 DAY TO CHANGE MY GRADE BECAUSE TOMORROW IS THE FINAL REPORT CARD RESULTS AND I DONT WANNA FAIL PLS HELP-
AND CAN ANYONE PLS DRAW ME THE ANSWERS I CANT UNDERSTAND ANYTHING PLS I BEG U ILL GIVE U BRAINLEST
Answer:
here, i can help you out!
Step-by-step explanation:
Answer:
For 1. 2/5 is less full then 1/2
consider the polynomial function q(x)=-2x^8+5x^6-3x^5+50
What is the end behavior of the graph of q?
Choose 1 answer:
(Choice A) As x→∞, q(x)→∞, and as x→−∞, q(x)→∞
(Choice B) As x→∞, q(x)→-∞, and as x→−∞, q(x)→∞
(Choice C) As x→∞, q(x)→-∞, and as x→−∞, q(x)→-∞
(Choice D) As x→∞, q(x)→∞, and as x→−∞, q(x)→-∞
Answer:
C.
Step-by-step explanation:
Answer A and D are definitely incorrect. Hope this helps Zoey. #Zoeyiscute:)
x is 40% of 60
x=?
please help!!
Answer:
x = 24
Step-by-step explanation:
x = .4(60)
x = 24
40% of 60 can be found by converting 40% to a decimal and multiplying it by 60.
40% = 0.4
60x0.4=2.4
Now move the decimal point right one.
So x is 24.
---
hope it helps
Use completing the square to find the equation of the following circle in standard form.
x2 + y2 - 4x + 12y - 16 = 0
Answer:
Here's a calculator that should help
Step-by-step explanation:
https://www.calculatorsoup.com/calculators/algebra/completing-the-square-calculator.php
A race was 993 meters. If 28 people ran in the marathon how many meters would they
have run total?
Answer:
27,804
Step-by-step explanation:
28x993= 27,804
The distribution of white blood cell count per cubic millimeter of whole blood is approximately Normal with mean 7500 and standard deviation 1750 for healthy patients Include an appropriately labeled and shaded Normal curve for each part. There should be three separate curves. 4. What is the probability that a randomly selected person will have a white blood cell count of between 2000 and 10,000?
The probability that a randomly selected person will have a white blood cell count of between 2000 and 10,000 is 0.9223 approximately.
The given mean, standard deviation, and the range of values are as follows:
Mean = 7500
Standard deviation = 1750
Range of values = Between 2000 and 10000
We are required to calculate the probability of a random person having a white blood cell count between 2000 and 10000.
Let's find the Z values for 2000 and 10000.Z1 = (2000 - 7500) / 1750 = -3Z2 = (10000 - 7500) / 1750 = 1.43
The required probability is the sum of the probability of the given range of values.
The probability of the first value is:P(X < 2000) = P(Z < -3) = 0.00135
The probability of the second value is:P(X > 10000) = P(Z > 1.43) = 0.0764
To find the probability for the given range, we will subtract the probability of the second value from the probability of the first value.
P(2000 < X < 10000) = 1 - P(X < 2000) - P(X > 10000)P(2000 < X < 10000)
= 1 - 0.00135 - 0.0764P(2000 < X < 10000) = 0.9223
The probability that a randomly selected person will have a white blood cell count between 2000 and 10,000 is 0.9223, approximately.
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Need help as soon as possible pls help
1. The value of x is:
180° - 40° - 30° = 110°
2. The value of x is:
90°- 38° = 52°
Answer:
Step-by-step explanation:
180 = 40 + x + 30
110 = x
90 = 38 + x
52 = x
If A, B and M are three collinear points, such that M divides AB internally in the ratio of 7:5 and P is any point not on the line AB, show that PM = PA + PB (4 marks] = 12 12
Given collinear points A, B, and M, with M dividing AB internally in the ratio of 7:5, and a point P not on the line AB, it can be shown that PM is equal to the sum of PA and PB.
Let's consider the line segment AB, where M is a point that divides it internally in the ratio of 7:5. This means that the ratio of AM to MB is 7:5.
Now, let's consider the triangle PAB, where P is a point not on the line AB. We want to show that PM is equal to the sum of PA and PB.
Since M divides AB internally in the ratio of 7:5, we can express AM and MB in terms of their lengths. Let's assume the length of AM is 7x and the length of MB is 5x.
Using this information, we can express the lengths of PA and PB in terms of x as well. Let's denote the length of PA as y and the length of PB as z.
Since M divides AB internally in the ratio of 7:5, we can write:
AM/MB = 7x/5x = 7/5
Similarly, we can express the ratios of PM to PA and PM to PB:
PM/PA = 7x/y
PM/PB = 5x/z
We need to show that PM is equal to PA + PB:
PM = PA + PB
Substituting the ratios we derived earlier:
(7x/y) = (5x/z) + 1
To simplify the equation, we can multiply both sides by yz:
7xz = 5xy + yz
Next, we can factor out the common factor of y:
7xz = y(5x + z)
Now, we can divide both sides by (5x + z):
PM = y
Therefore, we have shown that PM is equal to PA + PB.
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(3)(0.2)+9 help please
Answer:
9.6
Step-by-step explanation:
Answer:
[tex]9.6[/tex]
Step-by-step explanation:
1) Simplify 3 × 0.2 to 0.6.
[tex]0.6 + 9[/tex]
2) Simplify.
[tex]9.6[/tex]
Hence, the answer is 9.6
find the range of f(x)=2/5x + 5 for the domain (-4, -2, 0 3)
my answer is 3.4, 4.2, 5, 6.2 but im not fully sure
Answer:
Your answers are correct
Step-by-step explanation:
Solve -72 = 8 (y - 3) pls
Step-by-step explanation:
Given
- 72 = 8 ( y - 3 )
or - 72 / 8 = y - 3
or, - 9 = y - 3
y = - 9 + 3
Therefore X = - 6
Hope it will help :)❤
Answer:
Step-by-step explanation:
-72=8y-24
-72+24=8y
-48=8y
-48/8=y
-6=y
9. (10%) Consider a linear block code whose generator matrix G is. 1 0 0 1 1 1 0 0 1 0 1 1 0 1 0 0 1 1 0 1 1 (a) (2%) Find the parity check matrix H. (b) (3%) What is the minimum distance of the code?
(a) The parity check matrix H is:
1 1 1 0 1
0 1 0 1 1
0 1 1 0 0
To find the parity check matrix H, we can use the fact that H is the transpose of the generator matrix G with an identity matrix on the right side.
Given the generator matrix G:
1 0 0 1
1 1 1 0
1 0 1 1
0 1 0 0
1 1 0 1
We can rewrite G as:
1 0 0 1 1 1 0 0
1 1 1 0 0 1 1 0
1 0 1 1 1 0 1 1
0 1 0 0 1 1 0 0
1 1 0 1 0 1 1 1
Now, we can obtain the parity check matrix H by taking the transpose of G and removing the rightmost identity matrix:
H = Transpose(G without the rightmost identity matrix)
H =
1 1 1 0 1
0 1 0 1 1
0 1 1 0 0
Therefore, the matrix H is:
1 1 1 0 1
0 1 0 1 1
0 1 1 0 0
(b) The minimum distance of a linear block code is the smallest number of bit positions in which any two codewords differ. It determines the error detection and correction capability of the code.
To find the minimum distance of the code, we can examine the columns of the parity check matrix H. The number of non-zero entries in the smallest column gives us the minimum distance.
Looking at the parity check matrix H, we see that the smallest column has two non-zero entries in positions 1 and 2. Therefore, the minimum distance of the code is 2.
In conclusion, the minimum distance of the code is 2.
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Prove that for a normal matrix A, eigenvectors corresponding to different eigenvalues are necessarily orthogonal.
Eigenvalues and eigenvectors play a crucial role in the study of linear transformations and matrices. For a normal matrix A, it can be proven that eigenvectors corresponding to different eigenvalues are necessarily orthogonal.
To understand why eigenvectors corresponding to different eigenvalues are orthogonal for a normal matrix, we need to consider the properties of normal matrices. A matrix A is normal if it commutes with its conjugate transpose A* (i.e., A * A* = A* A).
Now, let's consider two eigenvectors v₁ and v₂ corresponding to different eigenvalues λ₁ and λ₂, respectively. We want to show that v₁ and v₂ are orthogonal, meaning their dot product is zero (v₁ · v₂ = 0).
Let's denote the conjugate transpose of A as A*, and the eigenvalues and eigenvectors as follows:
A * A = A * A* (1)
Multiplying both sides of equation (1) by v₂* (the conjugate transpose of v₂) from the left gives:
v₂* A * A = v₂* A * A* (2)
Since v₂ is an eigenvector of A, we can express it as:
A * v₂ = λ₂ v₂ (3)
Substituting equation (3) into equation (2) gives:
v₂* λ₂ A = v₂* A * A* (4)
Now, let's multiply equation (4) by v₁ from the right:
v₂* λ₂ A v₁ = v₂* A * A* v₁ (5)
Since v₁ is an eigenvector of A, we can express it as:
A * v₁ = λ₁ v₁ (6)
Substituting equation (6) into equation (5) gives:
v₂* λ₂ λ₁ v₁ = v₂* λ₁ A* v₁ (7)
Notice that λ₁ and λ₂ are scalars, so we can move them around. Taking the conjugate transpose of equation (7), we get:
(λ₂ λ₁) v₁* v₂ = (λ₁ v₁)* A v₂ (8)
Now, we have v₁* v₂ on the left-hand side and (λ₁ v₁)* A v₂ on the right-hand side. If v₁ and v₂ are not orthogonal (v₁ · v₂ ≠ 0), then v₁* v₂ ≠ 0. However, the right-hand side of equation (8) is proportional to (λ₁ v₁)* A v₂, which is proportional to A v₂. This implies that A v₂ is a scalar multiple of v₁, which contradicts the assumption that v₁ and v₂ correspond to different eigenvalues.
Therefore, we conclude that eigenvectors corresponding to different eigenvalues for a normal matrix are necessarily orthogonal.
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Find the mean, median, and mode of the data set.
{0,9, 3, 6, 10, 10, 7,1
MEAN:
MEDIAN:
MODE:
Please help me out you can just give me the answer! PLEASE AND THANK YOU!
Answer:
(Disclaimer: all digits in the answers are in the measuring unit degrees)
1) 15
2) 16
3) 46
4) 59.
Step-by-step explanation:
The first one is said to add up to 89, so you have to do 89 subtract 44 and 30 as they are told. That = 15
The second one is a right angle, meaning it adds up to 90. You do 90 - 74 as that is the value told. That = 16
Angles on a straight line = 180 so you have to do 180 - 134 as that is the value told. This = 46
This is 54 as opposing angles on two lines are =. That means this = 59 too.