Use a 10-by-10 grid to model the percent.
1. 43%

Answer:

20 is the father's 20 is the son

Step-by-step explanation:

20+20=40

40/2=20

40-20=20

another way:

20:n= 40

40-20=20

20:20=40

Answer:

Step-by-step explanation:

let the age of son be x

x+x+20=40

2x=40-20

x=20/2

x=10

since age of a father is 20 more than his son's so,

x+20=father's age

10+20

30

therefore fathers age is thirty years and son age is 10 years

Answer:

Multiply

1/3

Step-by-step explanation:

You can divide by 3 or multiply by 1/3. Since it looks like 3 is grayed out, I guess you have to use the latter.

Answer:

its -4.5??? what is the question you're asking

Answer:

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

1. Let x represent the number of apples left. Then the number of mangosteens left is 1/6x. The starting number in each case is the number left plus the number sold. The starting numbers are equal, so we have ...

  x + 201 = (1/6)x +366

  5/6x = 165 . . . . . . . . . . subtract 1/6x+201

  x = 198 . . . . . . . . multiply by 6/5

198 apples were left.

__

2. Let d represent the cost of a drink. The cost of a drink is 3/5 the cost of a snack, so the cost of a snack is 5/3 the cost of a drink. Then Alice's total expenditure was ...

  15d +12(5/3d) = 42

  35d = 42 . . . . . . . . . . . . . . collect terms

  d = 42/35 = 6/5 = 1.20 . . . divide by 35

The cost of a drink was $1.20.

Answer:

2 doctors to 9 patients

Step-by-step explanation:

Divide each by 3. They cant be simplified more.

Answer Answer:

The scatter plot indicates that a positive linear relationship exists between the age of a car and its maintenance cost. This is depicted by the positive slope direction which indicates the maintainance cost of the car is will increase as the age of the car increases. If the correlation Coefficient of the data was calculated, a correlation Coefficient value of about 0.934 will be obtained.

Step-by-step explanation:

Check answer

Answer:

Therefore WE accept the Null hypothesis [tex]H_0[/tex] That 50.0% versus 52.4%.difference is real

Step-by-step explanation:

Sample size A [tex]n_a=100[/tex]

Sample size B [tex]n_b=250[/tex]

Positive draw from box A [tex]n_a=50[/tex]

Positive draw from box b [tex]n_b=131[/tex]

Generally the equation for Probability of Positive draw from Box A is mathematically given by

 [tex]P_1=\frac{50}{100}[/tex]

 [tex]P_1=50%[/tex]

Therefore

 [tex]1-P_1=50\%[/tex]

Generally the equation for Probability of Positive draw from Box A is mathematically given by

 [tex]P_1=\frac{131}{250}[/tex]

 [tex]P_1=52.4%[/tex]

Therefore

 [tex]1-P_1=47.6\%[/tex]

Generally the equation for Standard error S.E is mathematically given by

 [tex]S.E=\sqrt{\frac{n_1(p_1)*(1-P_1)}{n_1^2}+\frac{n_2(P_2(1-p^2))}{n_2^2}}[/tex]

 [tex]S.E=\sqrt{\frac{100(0.50)*(50)}{100^2}+\frac{(250)(0.524(47))}{250^2}}[/tex]

 [tex]S.E=0.592[/tex]

 [tex]S.E=59.2\%[/tex]

Therefore

 [tex]Z=\frac{50-52.4}{59.2}[/tex]

Generally

 [tex]P value P>0.05[/tex]

Therefore WE accept the Null hypothesis [tex]H_0[/tex] That 50.0% versus 52.4%.difference is real

Answer:

Option D would be the correct answer!

Hope this helps!

Answer:

[tex]0.4138[/tex]

Step-by-step explanation:

Given

[tex]x \to storm[/tex]

[tex]\mu_x = 1.0[/tex]

[tex]y \to fire[/tex]

[tex]\mu_y = 1.5[/tex]

[tex]z \to theft[/tex]

[tex]\mu_z = 2.4[/tex]

Let the event that the above three factors is greater than 3 be represented as:

[tex]P(A > 3)[/tex]

Using complement rule, we have:

[tex]P(A > 3) = 1 - P(A \le 3)[/tex]

This gives:

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

-----------------------------------------------------------------------------------------------------------

The exponential distribution formula of each is:

[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]

So, we have:

[tex]k = 3; \mu_x = 1[/tex]

[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]

[tex]k=3; \mu_y = 1.5[/tex]

[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]

[tex]k = 3; \mu_z = 2.4[/tex]

[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]

-----------------------------------------------------------------------------------------------------------

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]

[tex]P(A > 3) = 1 - 0.5862[/tex]

[tex]P(A > 3) = 0.4138[/tex]

Answer:

You never attached anything so ill just say the answer is 4

Step-by-step explanation:

If you want a serious answer please edit your question so it is answerable.

:) Have a good day

Answer:

y = 0.47

x = 0.91

Step-by-step explanation:

From the right angled triangle Given :

Applying trigonometry :

To Obtain y :

We use :

Tan θ = opposite / hypotenus

Tan 25 = y / 1

y = 1 * tan 25

y = 0.4663076 * 1

y = 0.47

For x :

We use :

Cosθ = adjacent / hypotenus

Cos 25 = x / 1

0.9063077 = x / 1

x = 0.9063077 * 1

x = 0.9063077

Hence, x = 0.91

Answer:

your awnser would be [4, −6]

Step-by-step explanation:

hope this helps

Answer:

50 yard South, 40 yard east 60 yard northwest

Answer:

The average speed of the 747 was of 580 miles per hour.

Step-by-step explanation:

We use the following relation to solve this question:

[tex]v = \frac{d}{t}[/tex]

In which v is the velocity, d is the distance and t is the time.

A small airplane flies 1015 miles with an average speed of 290 miles per hour.

We have to find the time:

[tex]v = \frac{d}{t}[/tex]

[tex]290 = \frac{1015}{t}[/tex]

[tex]290t = 1015[/tex]

[tex]t = \frac{1015}{290}[/tex]

[tex]t = 3.5[/tex]

1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time;

The time of the Boeing 747 is:

[tex]t = 3.5 - 1.75 = 1.75[/tex]

Distance of [tex]d = 1015[/tex], the velocity is:

[tex]v = \frac{d}{t} = \frac{1015}{1.75} = 580[/tex]

The average speed of the 747 was of 580 miles per hour.

Answer:

A: 1 solution: the lines intersect at one point

B: (3,4), reference graph for solution

Step-by-step explanation:

A: solutions are equivalent to how many intersections two lines have, and we can see that these lines intersect once and won't intersect again

B: luckily the intersection point is super easy to plot, so we can just reference the graph for our solution!

Answer: 4

Step-by-step explanation:

I got this same question buddy im here to see the answer but there were not any

Answer:

0.0344 = 3.44% probability that a newborn pup has a weight above 24.0 lbs.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 22.0 lbs and standard deviation of 1.1 lbs.

This means that [tex]\mu = 22, \sigma = 1.1[/tex]

Find the probability that a newborn pup has a weight above 24.0 lbs.

This is 1 subtracted by the p-value of Z when X = 24. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{24 - 22}{1.1}[/tex]

[tex]Z = 1.82[/tex]

[tex]Z = 1.82[/tex] has a p-value of 0.9656.

1 - 0.9656 = 0.0344

0.0344 = 3.44% probability that a newborn pup has a weight above 24.0 lbs.

Answer:

22×2/5=8.8

Step-by-step explanation:

Hope it helps you

Answer:

55

Step-by-step explanation:

2/5n = 22

multiply each side by 5/2 to get:

n = 110/2

n = 55

======================================================

Explanation:

Any vector of the form v = (a,b) will have a length of |v| = sqrt(a^2+b^2).

This is derived from the pythagorean theorem. It's the same as saying the distance from (0,0) to (a,b) is sqrt(a^2+b^2).

In this case, a = 3 and b = -4, which means...

|v| = sqrt(a^2+b^2)

|v| = sqrt(3^2+(-4)^2)

|v| = sqrt(9+16)

|v| = sqrt(25)

|v| = 5

The vector is 5 units long.

Note: we have a 3-4-5 right triangle

Answer:

The number of extra glasses required is 3954.

Step-by-step explanation:

Total volume of water in a bottle = 370 liters

Number of  glasses, N = 46

capacity of each glass = 90 ml = 0.09 liter

The volume of water required to fill 46 glasses is

= 0.09 x 46 = 4.14 liter

The amount of water left = 370 -  4.14 = 355.86 liter

The number of extra glasses required to fill is

n = 355.86/0.09 = 3954

So, the number of extra glasses required is 3954.  

Answer:

l

Step-by-step explanation:

yeha bta hunxa...........

Answer:

y = 4/5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

Identify

7/8y + 1/2 = 1 1/5

Step 2: Solve for y

Answer:

a. 8x+12                      

b.6-x                            

c.20-8x

d.-3-9x

e.65-20x

f.6x^2+14x-8

g. 24x^2-8x

h. 9x^2+30x

1. x^2-13x+42

j. 26+4y

k. x^2-2x-24

l. x^2+13x+30

m. 429+23x

n. 15x-7

o. 2x-40

p. 68-13x

Step-by-step explanation:

Answer:

$1140 or $540

Step-by-step explanation:

450*1.2=540

540+600=1140

Answer:

a) The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b) The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c) The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d) The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

Standard error:

The standard error is:

[tex]s = \sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

Margin of error:

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}} = zs[/tex]

The confidence interval is:

Sample proportion plus/minus margin of error. So

[tex](\pi - M, \pi + M)[/tex]

In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.

This means that [tex]n = 1500, \pi = \frac{1305}{1500} = 0.87[/tex]

a. What is the standard error for this estimate of the percentage of all young Americans who earned a high school diploma?

[tex]s = \sqrt{\frac{\pi(1-\pi)}{n}} = \sqrt{\frac{0.87*0.13}{1500}} = 0.0087[/tex]

0.0087*100% = 0.87%.

The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma.

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

Then

[tex]M = zs = 1.96*0.0087 = 0.0171[/tex]

0.0171*100% = 1.71%

The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c. Report the 95% confidence interval for the percentage of all young Americans who earned a high school diploma.

87% - 1.71% = 85.29%

87% + 1.71% = 88.71%.

The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d. Suppose that in the past, 80% of all young Americans earned high school diplomas. Does the confidence interval you found in part c support or refute the claim that the percentage of young Americans who cam high school diplomas has increased? Explain.

The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

Answer:

y = 5 sin (2x) + 4

Step-by-step explanation:

this is sines function,

the amplitude is [9 - (-1)]/2 = 10/2 = 5

the period is 2πx/π = 2x

the x-axis of actual function is at y = 4

so, the function is :

y = 5 sin (2x) + 4