URGRENNTTT PLSS HELPP 50 POINTSS!!!!! Students were asked to simplify the expression cotangent theta plus tangent theta over cotangent theta. Two students' work is given.


Student A

Step 1: cotangent theta over cotangent theta plus tangent theta over cotangent theta

Step 2: 1 plus tangent theta over the quantity 1 over tangent theta end quantity

Step 3: 1 + tan2 θ

Step 4: sec2 θ Student B

Step 1: the quantity 1 over tangent theta end quantity plus tangent theta over the quantity cotangent theta

Step 2: the quantity 1 plus tangent squared theta end quantity over tangent theta all over cotangent theta

Step 3: secant squared theta over tangent squared theta

Step 4: csc2 θ

Part A: Which student simplified the expression incorrectly? Explain the errors that were made or the formulas that were misused. (5 points)

Answer:

[tex]\frac{7\sqrt{65}}{65}[/tex]

Step-by-step explanation:

Cosine is the ratio of the side adjacent to the angle and the right triangle hypotenuse.

[tex]cos[/tex] B = [tex]\frac{7}{\sqrt{65}}[/tex] = [tex]\frac{7\sqrt{65}}{65}[/tex]

In function notation, f(x) is used instead of the letter y to represent the output variable.

A function is represented as:

f(x)

The above means that:

The function of x

As a general rule, the function can be rewritten using the letter y (i.e. the output variable)

Hence, the words that complete the blanks are y and output

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The distance that Greg is from home after 12 hours is given as follows:

300 miles.

To calculate the numeric value of a function or of an expression, we substitute each instance of any variable or unknown on the function by the value at which we want to find the numeric value of the function or of the expression presented in the context of a problem.

The function for this problem is given as follows:

y = 25x.

Hence the distance after 12 hours is given as follows:

y = 25 x 12

y = 300 miles.

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Solution :

[tex]x = \frac{4 + \sqrt{43} }{2} .x = 4 + \frac{4 - \sqrt{43} }{2} [/tex]

[tex] \frac{1}{(x - 5)} + \frac{3}{(x - 2)} - 4[/tex]

[tex]x = 2 + 3( x - 5) = 4 - (x - 5)(x + 2)[/tex]

[tex]x = \frac{4 + \sqrt{43} }{2} .x = 4 + \frac{4 - \sqrt{43} }{2} [/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{x-5}+\dfrac{3}{x+2}=4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x+2+3x-15}{(x-5)(x+2)}=4[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x-5)(x+2)[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x(x+2)-5(x+2))[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x^2+2x-5x-10)[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4(x^2-3x-10)[/tex]

[tex]\\ \rm\Rrightarrow 4x-13=4x^2-12x-40[/tex]

[tex]\\ \rm\Rrightarrow 4x^2-16x-53=0[/tex]

On solving we get

[tex]\\ \rm\Rrightarrow x=2\pm\dfrac{69}{2}[/tex]

The point −20, 21 is on the terminal arm of an angle = in standard position. Hence, sinФ = 21/29 and cos Ф = -20/29

Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.

Given Data

A (-20 , 21)

We have to find sin = ? and cos = ?

The point is in the fourth quadrant

We have the Opposite side and the Adjacent side

Calculate the hypotenuse

     c² = (-20)² + (21)²

       c² = 400 + 441

       c² = 841

       c = 29

Hence,

sinФ = 21/29

cos Ф = -20/29

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The exercise is designed to test the students knowledge of prepositions. The correct answer thus is (Option D) Yo estudio (which translates) "I study".

To understand the answer, you need to know what a preposition is. A preposition, in simple terms, is a word or group of words that comes before a noun.

The function of a preposition (much like an adjective) is to give clarity to the noun that it precedes.

Let us complete the Preposition phrase to give meaning to it:

"I study Mathematics". Where;

"Mathematics" is the noun;

"I Study" is the prepositional phrase. Hence the correction answer to the question above is Option D.

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Answer:

[tex]\dfrac a{b^2} + \dfrac b{a^2} = 10[/tex]

Step-by-step explanation:

[tex]\text{Given that, the roots are a,b and } ~ x^2 -4x+2 = 0\\\\\text{So,}\\\\a+b = -\dfrac{-4}1 = 4\\\\ab = \dfrac 21 = 2\\\\\text{Now,}\\\\~~~~~\dfrac a{b^2} + \dfrac b{a^2}\\\\\\=\dfrac{a^3 +b^3}{a^2b^2}\\\\\\=\dfrac{(a+b)^3 -3ab(a+b)}{(ab)^2}\\\\\\=\dfrac{4^3 -3(2)(4)}{2^2}\\\\\\=\dfrac{64-24}{4}\\\\\\=\dfrac{40}{4}\\\\\\=10[/tex]

Answer:

[tex]\dfrac{a}{b^2}+\dfrac{b}{a^2}=10[/tex]

Step-by-step explanation:

Given equation:   [tex]x^2-4x+2=0[/tex]

The roots of the given quadratic equation are the values of x when [tex]y=0[/tex].

To find the roots, use the quadratic formula:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Therefore:

[tex]a=1, \quad b=-4, \quad c=2[/tex]

[tex]\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}[/tex]

[tex]\textsf{Let }a=2+\sqrt{2}[/tex]

[tex]\textsf{Let }b=2-\sqrt{2}[/tex]

Therefore:

[tex]\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}[/tex]

Substitute -2 for x

[tex]f( - 2) = 2( - 2) + 3 \\ y = - 4 + 3 \\ y = - 1[/tex]

Hope it helps

Please give brainliest

Answer:

-1

Step-by-step explanation:

Hi student! Let me help you out on this question.

_____________________

To find the value of f(-2), we need to stick in -2 for x.

[tex]\mathsf{f(-2)=2\cdot(-2)+3}[/tex]. Multiply first.

[tex]\mathrm{f(-2)=-4+3}[/tex]. Now simplify completely.

[tex]\mathsf{f(-2)=-1}[/tex]. Which is our final answer.

Hope that this helped you out! have a good day ahead.

Best Wishes!

[tex]\star\bigstar\underline{\underline{\overline{\overline{\textsf{Reach far. Aim high. Dream big.}}}}}\bigstar\star[/tex]

◆◈-Greetings!-◆◈

__________________

Answer:

(-∞,19)

Definition: The domain of a function is the set of input or argument values for which the function is real and defined

Answer:

(-∞, 19]

Step-by-step explanation:

The domain of this function is only true for all real values of f(x).

That means the lower limit of the function is -∞ as the values are positive, and the upper limit is 19, because that is the greatest value it can become before becoming negative.

The domain is : (-∞, 19]

Answer:

Place the squares on the rectangle.

Step-by-step explanation:

Hello!

The area of the 1cm by 1cm square is 1 square cm.

We can solve for the area by placing multiple of those squares in the larger rectangle.

If we place it, we get 15 placed squares, with a total area of 15 square cm. This relies on the meaning of area, as we are simply measuring the number of square cm taken up by the object.

We would place 3 rows of 5 squares, representing a height of 3 cm (side length of 3 squares), and a length of 5 cm (side length go 4 squares).

This also proves the area formula A = L * W, as we multiple the side lengths to find the number of square units.

a. If A is the coefficient matrix, solve det(A - λI) = 0 for the eigenvalues λ :

[tex]\det\begin{bmatrix}-6-\lambda & -4 \\ 12 & 8-\lambda\end{bmatrix} = (-6-\lambda)(8-\lambda)+48 = 0 \implies \lambda(\lambda-2)=0[/tex]

[tex]\implies \lambda = 0, \lambda = 2[/tex]

Let v = [v₁, v₂]ᵀ be the eigenvector corresponding to λ. Solve Av = λv for v :

[tex]\lambda=0 \implies \begin{bmatrix}-6&-4\\12&8\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix} = \begin{bmatrix}0\\0\end{bmatrix} \implies 3v_1 + 2v_2 = 0[/tex]

If we pick v₂ = -3, then v₁ = 2, so [2, -3]ᵀ is the eigenvector for λ = 0.

[tex]\lambda = 2 \implies \begin{bmatrix}-8&-4\\12&6\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix} = \begin{bmatrix}0\\0\end{bmatrix} \implies 2v_1 + v_2 = 0[/tex]

Let v₁ = 1, so v₂ = -2.

b. λ = 0 and v = [2, -3]ᵀ contributes a constant solution,

[tex]\vec y_1 = e^{\lambda t} v = \begin{bmatrix}2\\-3\end{bmatrix}[/tex]

while λ = 2 and v = [1, -2]ᵀ contribute a solution of the form

[tex]\vec y_2 = e^{\lambda t} v = e^{2t} \begin{bmatrix}1\\-2\end{bmatrix}[/tex]

c. Yes; compute the Wronskian of the two fundamental solutions:

[tex]W(1, e^{2t}) = \det\begin{bmatrix}1 & e^{2t} \\ 0 & 2e^{2t}\end{bmatrix} = 2e^{2t} \neq 0[/tex]

The Wronskian is non-zero, so the solutions are independent.

Answer:

x²-12x+36

x²-6x-6x+36

x(x-6)-6(x-6)

(x-6)(x-6)

=(x-6)²

Answer:

9 children were jumping then.

Step-by-step explanation:

6+5 equals to 11 - 2 of the children left would equal 9 children left.

Answer:

x = 2

Step-by-step explanation:

Q1 = 7, Q2 = 10, Q3 = 13.5

=============================================================

Explanation:

Start with {5,7,7,8,10,11,12,15,17}

Notice how this data set is already sorted for us from smallest to largest.

Cross off the first and last items to get {7,7,8,10,11,12,15}

Repeat the last step to get this smaller set {7,8,10,11,12}

Repeat again: {8,10,11}

Repeat one more time: {10}

The 10 is at the very center, so it is the median aka the value of Q2.

-------------

An alternative way to get the median is to follow these steps:

There are n = 9 numbers in the original set before we crossed off any items. The middle number is in slot 5 because n/2 = 9/2 = 4.5 rounds up to 5. The value in the fifth slot is 10, so 10 is the median.

There are 4 items below the median and 4 items above it, giving n = 4+1+4 = 9 items total.

-------------

Next, break the data set into two smaller groups

L = lower set = every value below the median

L = {5, 7, 7, 8}

U = upper set = every value above the median

U = {11, 12, 15, 17}

The median itself is in neither set L nor set U.

The median of set L is (7+7)/2 = 7, so this is the value of Q1

The median of set U is (12+15)/2 = 13.5 which is the value of Q3

-------------

Summary:

Q1 = 7

Q2 = 10 (aka the median of the original set)

Q3 = 13.5

Answer:

B. Q1=7, Q2=10, Q3=13.5

Step-by-step explanation:

First Solution:

The first quartile of the data set is 7.

The first quartile (or lower quartile or 25th percentile) is the median of the bottom half of the numbers. So, to find the first quartile, we need to place the numbers in value order and find the bottom half.

5   7   7   8   10   11   12   15   17  

So, the bottom half is

5   7   7   8  

The median of these numbers is 7.

Second Solution:

The median of the data set is 10.

Quartile 2, also known as the median, is the middle number in a sorted list of numbers.   So, to find the median, we need to place the numbers in value order and find the middle number.

Ordering the data from least to greatest, we get:

5   7   7   8   10   11   12   15   17  

So, the median is 10 .

Third Solution:

The third quartile of the data set is 13.5.

The third quartile (or upper quartile or 75th percentile) is the median of the upper half of the numbers. So, to find the third quartile, we need to place the numbers in value order and find the upper half.

5   7   7   8   10  11   12   15   17  

So, the upper half is

11   12   15   17  

The median of these numbers is 13.5.

Answer: Heyaa! ~

Your Answer Is... 13

Step-by-step explanation:

Hopefully this helps you! ~

Answer: 2041 meters

A bicycle wheel is a circular object.

The circumference of a circle is 2π(radius)

Here given:

Hence find the length for each revolution:

Then for 1000 revolutions:

Answer:

Kite is not a parallelogram

Step-by-step explanation:

The sides aren't evenly lined up properly to be a parallelogram

ANSWER:

kite

STEP BY STEP EXPLANATION

A kite isnerally not a parallogram because it is a quadrilateral whose four sided can be grouped into two pairs of sideame length that arch other

Answer: 103/15

Step-by-step explanation:

We can simplify the right-hand side to be [tex]2 \left(\frac{1}{3}+6 \right)=2 \left(\frac{19}{3} \right)=\frac{38}{3}[/tex].

This means we need to solve:

[tex]\frac{1}{2}(5x-9)=\frac{38}{3}\\5x-9=\frac{76}{3}\\5x=\frac{103}{3}\\x=\boxed{\frac{103}{15}}[/tex]

Answer:

El número equivalente de 25/50 es 1/2

Step-by-step explanation:

According to the above information, it can be stated that the pressure on the man's shoulders is directly proportional to the distance between the shoulder and the load, since the greater the distance he will feel the more weight due to instability.

A directly proportional relationship is a term that refers to the relationship between two variables in which if one of the variables increases, the other also increases.

According to the information, it can be inferred that the man will feel more weight on his shoulders if the load is more distant because this causes greater instability on his shoulders, so he will have to make a greater effort to move the load.

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Answer: B 3.0

Step-by-step explanation:

∠72

Step-by-step explanation:

Therefore Two sides will be equal

∠b = ∠c ------ ☆

=> ∠b = 2∠a

=> ∠a = ∠b/2 -------(1)

=> ∠a + ∠b + ∠c = 180

Put value of ∠a from equation (1)

=> ∠b/2 + ∠b + ∠b =180

[ look equation marked - ☆ ]

=> 5∠b/2 = 180

=> 5∠b = 180 × 2

=> 5∠b = 360

=> ∠b = 360 / 5

=> 72

Some properties of Triangle-

Answer:

y = 15

Step-by-step explanation:

Given :

3 + y = 18

This a simple algebraic equation.

Subtract 3 from both sides :

⇒ 3 + y - 3 = 18 - 3

⇒ y = 15

Answer:

y = 15

Step-by-step explanation:

Given equation:

To Find:

Solution:

We can rewrite this equation as:

[This'll ain't change the answer]

Now we could solve on a easy way.

STEPS:

Transpose +3 to the RHS, make sure to change it's sign from “+” to “-”.

=> y = 18-3

Subtract the integers which's on the RHS:

=> y = 15

Hence,the value of y will be 15.

[tex] \rule{225pt}{2pt}[/tex]

Answer:

[tex]x=2/7695[/tex]

≡ Small number, yes, but the steps explain why x is equal to this.

Step-by-step explanation:

simplify

[tex]24x\cdot 321-x=8x+2\\\left(24\cdot 321\right)x-x=8x+2\\7703x=8x+2[/tex]

group

[tex]7703x=8x+2\\7703x-8x=8~x+2-8x\\7695x=8x+2-8x\\7695x=8x-8x+2\\7695x=2[/tex]

isolate

[tex]7695x=2\\\frac{7695x}{7695}=\frac{2}{7695}\\x=\frac{2}{7695}[/tex]

The fraction is in its simplest form, so that is the final answer.

Answer:

Step-by-step explanation:

Let ∠A and ∠B and ∠C.

be the three interior angles of the triangle.

∠A + ∠B + ∠C = 180

If ∠A = 68  and  ∠B = ∠C .

Then

∠B + ∠C = 180 - 68 = 112

Then

2∠B  = 112

Then

∠B = 112 ÷ 2 = 56°

change in emitter current, ∆l(E) = 4 mA

change in collector current,∆I(C) = 3.5 mA

value of B

∆I(E) = ∆I(C) + ∆l(B), here ∆l(B) is the change in base current.

4 = 3.5 + ∆l(B)

∆I(B) = 0.5 mA

B = 3.5 ÷ 0.5

B = 7.0

The choice shows 19 + 32 + 11 rewritten correctly using the commutative property and then simplified correctly is option B; 19+11+32= 30+32 = 62.

The commutative property of addition says that it doesn't matter how we add two numbers, the result of the addition would be same.

For two numbers x and y, we have:

x + y = y + x

WE have given

19 + 32 + 11

The sum would be 62.

We know that by commutative property of addition,

For two numbers x and y,

x + y = y + x

Thus, if we take 3 numbers as a,b and c, then:

c + a + b = c + b + a

Similarly,

19 + 32 + 11 = 19+11+32

= 30+32

= 62

Therefore, the option B  is the correct answer.

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