Two number have a product of 7. One of the number i 4 2/3, what i the other number?

I think is is 22

because it is asking how many times can .6m go into 13.2m of ribbon? If you start with 20x.6 you will get 12. Then you add on another one and get 12.6. Finally add one more to get 13.2m ribbon which would make the answer 22. You can also divide 13.2m divided by .6m and get 22.

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Over all the Answer is 22

Have a great day (:

If the overhead was 20% of the cost of each towel. The selling price of each towel is 5.88.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

The usage of percentages is widespread and diverse. For instance, numerous data in the media, bank interest rates, retail discounts, and inflation rates are all reported as percentages. For comprehending the financial elements of daily life, percentages are crucial.

Suppose the selling price of a towel is x, according to the given condition,

5 = x - 15% of x

5=x-0.15x

5=0.85 x

x=5/0.85

x=5.88

Thus, if the overhead was 20% of the cost of each towel. The selling price of each towel is 5.88.

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The statements are true "3 is less than 7, and the absolute value of 3 is less than the absolute value of 7".

Absolute value is defined as the magnitude or size of a number, no negatives are allowed.

The distance a number is from 0 on the number line is known as the absolute value of the number.  

For example, |5| is 5 because it is 5 units away from 0.  Also, |-5| is also 5 because -5 is 5 units from 0.

The absolute value of a number is how distant it is from zero. The standard procedure to represent absolute value is to use a number line to estimate the exact distance the number is from zero.

As per the option, 3 is less than 7 is true.

The absolute value of 3 is less than the absolute value of 7  is true.

Thus, the statements are true "3 is less than 7, and the absolute value of 3 is less than the absolute value of 7".

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The question seems to be incomplete the correct question would be

Which statements about 3 and 7 are true? Choose ALL the correct answers.

3 is less than 7.

3 is greater than 7.

The absolute value of 3 is less than the absolute value of 7.

The absolute value of 3 is equal to the absolute value of 7.

The absolute value of 3 is greater than the absolute value of 7.

Answer:

enlargement

Step-by-step explanation:

observe from the figure [tex]OK=x<x+5=7=OK'[/tex]

since [tex]OK<OK'[/tex], then the dilation is an enlargement.

Answer:

Step-by-step explanation:

defsfvbrfdv

Answer:

2/5 is greater than 3/8, so 25 2/5 is greater

Step-by-step explanation:

Find the least common denominator or LCM of the two denominators:

LCM of 5 and 8 is 40

Next, find the equivalent fraction of both fractional numbers with denominator 40

For the 1st fraction, since 5 × 8 = 40,

2/5

=

2 × 8

5 × 8

=

16/40

Likewise, for the 2nd fraction, since 8 × 5 = 40,

3/8

=

3 × 5

8 × 5

=

15/40

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

16/40 > 15/ 40 or 2/5 > 3/8

If the promissory note stated that there was a balloon payment at the end. The sum of all but the last monthly payment is: $56,525, $57,000.

Total payment = $475 × [(10 years × 12 months) -1]

Total payment = $475 × 119 payment

Total payment = $56,525

Total payment = $475 × [(10 years × 12 months) ]

Total payment = $475 × 120 payment

Total payment = $57,000

Therefore the monthly payment is; $56,525, $57,000.

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Answer:

The y intercept

Step-by-step explanation:

Answer:

88.8 km/h

Step-by-step explanation:

Answer:

cost per pound for Jelly Beans is 5$

cost per pound for Gummy Worms is 8$

Answer:

[tex]28t^4u^5v^9[/tex]

Step-by-step explanation:

I will answer this a few different ways depending on whether there are supposed to be exponents in the question.

As written

As written, the product is:

[tex](7tuv7)(4t3u4v2)[/tex]

All of the coefficients can be multiplied together. This is what that looks like:

[tex]4704tuvtuv[/tex]

Now, each variable multiplied by itself gets the exponent of 2.

[tex]4707t^2u^2v^2[/tex]

Assuming exponents and coefficients

Assuming exponents, the product is:

[tex](7tuv^7)(4t^3u^4v^2)[/tex]

Again, the coefficients can be multiplied, and the like variables written next to each other:

[tex]28tt^3uu^4v^7v^2[/tex]

When multiplying like terms with exponents, add the exponents. Variables without an exponent have an exponent of 1.

[tex]28t^4u^5v^9[/tex]

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

The value of f(g(x)) is 6x³ + 4.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

3x + 4 = 5 is an equation.

2x + 4x = 4 is an equation.

We have,

The function f(x) represents the amount of money Barrett earns per gallon of ice cream, where x is the number of gallons of ice cream he makes.

The function g(x) represents the number of gallons of ice cream Barrett makes per hour, where x is the number of hours he works.

f(x) = 2x² + 4

g(x) = √(3x³)

Now,

f(g(x)):

= f(√(3x³))

= 2{√(3x³)}² + 4

= 2(3x³) + 4

= 6x³ + 4

Thus,

The value of f(g(x)) is 6x³ + 4.

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keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{5}}x-1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{5}} ~\hfill \stackrel{reciprocal}{\cfrac{5}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{5}{-2}\implies \cfrac{5}{2}}}[/tex]

so we're really looking for the equation of a line whose slope is 5/2 and it passes through (-2 , 14)

[tex](\stackrel{x_1}{-2}~,~\stackrel{y_1}{14})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{5}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{14}=\stackrel{m}{ \cfrac{5}{2}}(x-\stackrel{x_1}{(-2)}) \implies y -14= \cfrac{5}{2} (x +2) \\\\\\ y-14=\cfrac{5}{2}x+5\implies {\Large \begin{array}{llll} y=\cfrac{5}{2}x+19 \end{array}}[/tex]

Answer:

1/-7

Explanation:

rise/run so up 1 down 7

Rounding off 9.4725 to the nearest cent will give 9.5

Rounding off means a number is made simpler by keeping its value intact but closer to the next number. It is done for whole numbers, and for decimals at various places of hundreds, tens, tenths. When rounding money to the nearest cent, look at the number to the right of the full cents. In this case, that number is 9. If the number is five or more, increase the cents by 1. If the number is four or less, keep the cents the same. Because 9 is more than 5, $3.299 rounds to $3.30.

Applying same principle or concept here, we can round off 9.4725 to the nearest cent to give 9.5.

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The cost of 1 kg of beetroot and 1 kg of kale are 1.39 units and 2.53 units respectively

The cost of 4kg of kale and 1.5 kg of beetroot is 12.20. The cost of 5kg of kale and 2kg of beetroots is 15.40.

The cost of 1kg of beetroot and 1kg of kale can be found as follows:

Therefore,

let

x = cost of 1kg of beetroot

y = cost of 1 kg of Kale

Therefore, using equation,

1.5x + 4y = 12.20

2x + 5y = 15.40

x = 12.20 / 1.5 - 4y / 1.5

x = 8.13 - 2.67y

Hence,

5y = 15.40 - 2(8.13 - 2.67y)

5y = 15.40 - 16.26 + 5.34y

5y = -0.86 + 5.34y

5y - 5.34y = -0.86

- 0.34y = - 0.86

y = - 0.86 / - 0.34

y = 2.52941176471

y = 2.53

1.5x = 12.20 - 4(2.53)

1.5x = 12.20 - 10.12

1.5x = 2.08

x = 2.08 / 1.5

x = 1.38666666667

x = 1.39

Therefore,

cost of 1kg of beetroot ≈ 1.39

cost of 1 kg of Kale = 2.53

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[tex]\boldsymbol{\sf{\sqrt{3^2+27}+2^3+\sqrt[3]{64} }}[/tex]

Calculate 3 to the power of 2.

[tex]\boldsymbol{\sf{\sqrt{9+27}+2^3+\sqrt[3]{64} }}[/tex]

Add 9 and 27.

[tex]\boldsymbol{\sf{\sqrt{36}+2^3+\sqrt[3]{64} }}[/tex]

Find the square root of 36.

[tex]\boldsymbol{\sf{6+2^3+\sqrt[3]{64} }}[/tex]

Calculate 2 to the power of 3.

[tex]\boldsymbol{\sf{6+8+\sqrt[3]{64} }}[/tex]

Add 6 and 8.

[tex]\boldsymbol{\sf{14+\sqrt[3]{64} }}[/tex]

Calculate [tex]\sqrt[3]{64}[/tex]

[tex]\boldsymbol{\sf{14+4=18}}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{ 18}[/tex]

[tex] \: \: \: \: \: \: \: \bold{\sqrt{9 + 27} + 2 {}^{3} + \sqrt[3]{64} }[/tex]

To solve this problem, the first thing we have to do is simplify 3² to 9, since it multiplies 2 times 3 to give us 9.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \bold{ \sqrt{36} + {2}^{3} + \sqrt[3]{64} }[/tex]

Then we must add 9 + 27 to give us a result of 36.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{6 + {2}^{3} + \sqrt[3]{64} }[/tex]

Now we must multiply again but this time we are going to multiply 2 times 6 since 6 × 6 is equal to 36.

[tex]\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{6 + 8 \: + \sqrt[3]{64} }[/tex]

Now we must again multiply 3 times 2 to give us 8.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{6 + 8 + 4}[/tex]

Then we must add 6 + 8 + 4.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{14 + 4}[/tex]

Before finishing we know that we got 14, now we must add 14 + 4 to give us a result of 18.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{18}[/tex]

Rpt: The result is 18.

Answer:

It will take 5 lunges to cover the path.

Step-by-step explanation:

Path length = 110

1 lunge = 22 yards

110/22 = 5

5 lunges = 22x5 = 110 yards

The average difference or mean in game scores across six games is 5.67

The mean is the average of a data set. The mode is the most common number in a data set. The median is the middle of the set of numbers. The mean is the average or the most common value in a collection of numbers. the mean is one of the measures of b, apart from the mode and median. Mean is nothing but the average of the given set of a data.

To solve this problem, we have to write the wins and loss separate and then find the mean.

Wins = 8 points, 7 points, 20 points, 9 points

Loss = 8 points, 2 points

The sum of win points = 8 + 7 + 20 + 9 = 44 points

The sum of lost points = 8 + 2 = 10 points

The mean difference = (win - loss)/ total number of games

The mean difference = ( 44 - 10) / 6

The mean difference = 34 / 6 =5.67

The mean difference in the game scores over six games is 5.67 points

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The product of the given polynomials is 4y/(y + 3).

We are given two polynomials. A polynomial is a mathematical statement that is composed of the sum of powers in one or more variables multiplied by coefficients. The polynomials are in rational form. A rational number is created by dividing an integer by an integer. The first polynomial is 2y/(y - 3). The second polynomial is (4y - 12)/(2y + 6). We need to find the product of these two polynomials. Let the product be represented by the variable "P".

P = [2y/(y - 3)]×[(4y - 12)/(2y + 6)]

P = [2y/(y - 3)]×[4(y - 3)/2(y + 3)]

P = [2y]×[2/(y + 3)]

P = 4y/(y + 3)

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Answer:

[tex]y=1\frac{1}{3}x-3[/tex]

Step-by-step explanation:

Isolate y to find the value of y

2y-2/3x=-6

 +2/3x. +2/3x

2y=2/3x-6

/2.  /2.  /2

y=4/3x-3

Hopes this helps please mark brainliest

The closed right circular cylindrical can of the smallest surface area whose volume is 250π cm³ has a radius of 5cm and a height of 10 cm.

Let r and h be the radius and height of the cylinder respectively.

Volume, V= πr²h

Given,

Volume = 250 π

Now, we can solve by:

⇒ 250 π = πr²h

⇒ r²h=250

⇒ h= 250/r²

We know that,

Surface area, A = 2πr²+2πrh

⇒ A = 2πr²+ 2πr(250/r²)

⇒ A = 2πr²+ (500π/r)

Differentiating the above equation,

dA / dr = 4πr+500π(-1/r²)

For A to be maximum or minimum, dA/dr = 0

⇒ 4πr-500(π/r²) = 0

⇒ 4πr - 500π / r² = 0

⇒ 4πr³ -500π/ r² = 0

⇒ π (4r³ -500) = 0

⇒ 4r³ - 500 = 0

⇒ r = ∛125

⇒ r = 5

Putting value of r = 5, we get,

h = 250/(5)² = 10

By second derivative test,

d²A/dr² = 4π-500π(-2/r³)

At r= 5,

d²A/dr² = 4π+1000(π/r³) > 0 .

Therefore, It is a local minimum.

Ans: Radius = 5 and Height = 10

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The fraction that illustrates the decrease in sales is 15.

A fraction is simply a piece of a whole. The number is represented mathematically as a quotient where the numerator and denominator are split. In a simple fraction, the numerator as well as the denominator are both integers.

In this case, August 1/3 and this was 2/5 more than what was sold earlier. Therefore the decrease will be:

= 2/5 - 1/3

= 6/15 - 5/15

= 1/5

The fraction is 1/15.

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Answer:

[tex]x=\frac{5}{7} -\frac{y}{7}[/tex]

Step-by-step explanation:

You move all terms that dont contain x
to the right side and solve.

Hope this helps! :))

A matrix is a set of numbers arranges in rows and columns such that it form a rectangular array.

The value of [tex]x_{11}[/tex] is 8

The value of [tex]x_{21}[/tex] is -1

A matrix is a set of numbers arranges in rows and columns such that it form a rectangular array.

We have,

[tex]\left[\begin{array}{ccc}3&-8\\1&1\\\end{array}\right] X=\left[\begin{array}{ccc}32\\7\\\end{array}\right][/tex]    _____(1)

Now,

[tex]X = \left[\begin{array}{ccc}x_{11}\\x_{21}\\\end{array}\right][/tex]  ________(2)

Multiplication of matrix.

From (1) and (2) we get,

[tex]3x_{11} - 8x_{21}[/tex] = 32 ____(a)

[tex]x_{11} + x_{21}[/tex] = 7 ______(b)

From (b) we get,

[tex]x_{11}[/tex] = 7 - [tex]x_{21}[/tex] ______(3)

Substitute (3) in (a)

Now,

3 (7 - [tex]x_{21}[/tex]) - 8[tex]x_{21}[/tex] = 32

21 - 3[tex]x_{21}[/tex] - 8[tex]x{21}[/tex] = 32

-11[tex]x_{21}[/tex] = 32 - 21

[tex]x_{21}[/tex] = -1

Now,

[tex]x_{11}[/tex] = 7 - (-1) = 7 + 1 = 8

Thus,

The value of [tex]x_{11}[/tex] is 8

The value of [tex]x_{21}[/tex] is -1

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Answer:

Step-by-step explanation:Your calculations indicate that you will need 20.8 cubic yards of concrete for a slab floor. Which of the following quantities would be the best amount to order accounting for waste

The eggs that will remain after Sharma is making treats for a tea party is 1.

From the information, Mrs. Sharma is making treats for a tea party later this week, and she has up to 6 eggs to use for this purpose a batch of scones requires 3 eggs and a batch of miniature tarts requires 2 eggs.

In this case, the eggs remaining will be:

= Total eggs - Eggs used

= 6 - (3 + 2)

= 6 - 5

= 1

There'll be 1 egg remaining.

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Complete question

Mrs. Sharma is making treats for a tea party later this week, and she has up to 6 eggs to use for this purpose. A batch of scones requires 3 eggs and a batch of miniature tarts requires 2 eggs. How many eggs will be left?

For every 50 y, there is 1 hour

Answer:

900

Step-by-step explanation:

300/12=25

75*12=900