Answer:
The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.
Explanation:
1. According to the picture, which is the least dense?
O A. the chess piece
O B. the toy soldier
O C. the liquid in the container
O D. There is no way to tell,
According to the picture, the chess piece is the least dense. The correct option is A.
The amount of mass that a substance has in relation to its volume is referred to as its density. It is a measurement of how closely together the molecules or particles are arranged within a given object or material.
Typically, floating objects are less dense than the liquid they are in. The fact that the chess piece is floating on the water suggests that it is less dense than the liquid.
It might be an alternative, though, if the toy soldier is also floating and not submerged. More visual context is necessary for precise determination.
Thus, the correct option is A.
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Is my answer correct
Answer:
it right congratulations
Answer:
A
Explanation:
Simply option A is correct
It's a bit of a common sense question
At the highest point it's velocity will be automatically 0 since it is in rest and so is the acceleration
4. A gas's solubility is best in a liquid solvent when the solution is under high or low pressure
Answer:
low pressure
Explanation:
Starting from rest, a student pulls a (25.0 A) kg box a distance of (4.50 B) m across the floor using a (134 C) N force applied at 35.0 degrees above horizontal. The coefficient of kinetic friction is 0.220 between the floor and the box. Find the work done by the pulling force. Give your answer in joules (J) and with 2 significant figures.
A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.
Starting from rest, a student pulls a 25.0 kg box a distance of 4.50 m across the floor using a 134 N force applied at 35.0 degrees above horizontal.
We can calculate the work (W) done by the pulling force using the following expression.
[tex]W = F \times d \times cos\theta = 134 N \times 4.50 m \times cos35.0\° = 4.9 \times 10^{2} J[/tex]
where,
F: puling forced: displacementθ: angle between F and dThe friction between the floor and the box. does not influence the work done by the pulling force.
A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.
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Question 2 of 10
You are riding a bicycle. If you apply a forward force of 125 N, and you and
the bicycle have a combined mass of 82 kg, what will be the forward
acceleration of the bicycle? (Assume there is no friction.)
A. 1.67 m/s2
B. 3.37 m/s2
C. 0.66 m/s2
D. 1.52 m/s2
O
Answer:
D - 1.52 m/s2
Explanation:
force: 125 N
Mass: 82 kg
you just divide the force by the mass which would be approximately 1.52
I really need your help I will mark you brainliest!
I have been stuck for 15 minutes!!
Answer the following questions about Hurricane Harvey:
a. Why did hurricane Harvey travel from the east (Africia) twards the west (Florida) when our weather starts in the west and travels east?
B. why did hurricane harvey rotate counterclockwise? Do all hurricanes rotate counterclockwise?
The term that is used to quantity the amount of heat in the evaporator is
Answer:
Enthalpy
The quantity of heat contained in a material as measured from a particular base or point.
HELP
A 3000-kg truck moving with a velocity of 10 m/s hits a 1000-kg parked car. The impact causes the 1000-kg car to be set in motion at 15 m/s . Assuming that momentum is conserved during the collision, determine the velocity of the truck immediately after the collision.
Answer:
Hey I go to GOC send me your number
Explanation:
- The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force on the rocket if it is now accelerating at 12mls²
From your previous question
Mass=30kg
Acceleration=12m/s^2
[tex]\\ \sf\longmapsto F=ma[/tex]
[tex]\\ \sf\longmapsto F=30(12)[/tex]
[tex]\\ \sf\longmapsto F=360N[/tex]
Given,
Acceleration = 12 m/s²
According to your previous question you posted,
Mass = 30 KG
Solution:
We know that the formula of force according to the Newton's second law is:
[tex]\longmapsto \sf \red{f = m \times a}[/tex]
[tex]\sf \longmapsto \ 30 \times 12[/tex]
[tex]\sf \longmapsto \: \boxed {\sf \blue3 \red60}[/tex]
Answer:
[tex]\sf \boxed{ \bf \: force = 360\: N}[/tex]
what is the distance between a(-6,3),b(-2,4),c(-8,3)
Answer:
Explanation:
Appears to be the vertexes of a triangle.
AB = √(-6 - (-2))² + (3 - 4)²) = √17
AC = √(-6 - (-8))² + (3 - 3)²) = 2
BC = √(-2 - (-8))² + (4 - 3)²) = √37
Please show your workmkmmkekdmnesnndndndndn
Answer:
Explanation:
Remark
The question really is how long does the projectile stay in the air if it was just dropped from a height of 46 meters.
Givens
vi = 0
a = 9.81 m/s^2
h = 46 m
t = ?
Solution
d = vi*t + 1/2 a t^2
46 = 0 + 1/2 * 9.81 * t^2 multiply both sides by 2
92 = 9.81 * t^2 divide by 9.81
t^2 = 9.38 Take the square root of both sides
sqrt(t^2) = sqrt(9.38)
t = 3.06 seconds.
In 3.06 seconds the object will hit the ground, thus stopping it. How far horizontally does it go in that time.
d = r * t
d=?
r = 102 m/s
t = 3.06 seconds
d = 102 * 3.06
d = 312.4 meters.
What provides the centripetal force for the moon's orbit around Earth?
Answer:
Gravitational attraction provides the centripetal force needed to keep planets in orbit around the Sun and all types of satellite in orbit around the Earth. This centripetal force is supplied by gravity. The Earth's gravity keeps the Moon orbiting us. Centripetal force is perpendicular to velocity and causes uniform circular motion. The gravitational attraction of the Sun is an inward force acting on Earth. This force produces the centripetal acceleration of the orbital motion. Centripetal forces are always directed toward the center of the circular path.
Explanation:
Answer: C.
the gravitational pull of the Sun
Explanation: plato :3
Hope this helps!
True or False
In newton's 2nd law, f=ma there is a correlation between the force and acceleration. This supports that there is a causal relationship that acceleration has on the net force.
Answer: See explanation
Explanation:
Please see attached picture. Due to the fact one of the words in the equation F=ma contains a word not allowed.
2. In these diagrams, the sunlight is coming from the left, as shown by the arrows. Which
diagram is accurate and why? (1)
a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the
other half is dark.
b) B is accurate because the whole Moon is bright as long as there are no shadows
covering parts of it.
c) C is accurate because the Moon is almost as close as it can be to the sun, and so the
Moon is almost fully lit by the sun.
d) All three diagrams are sometimes accurate because the Moon has some lighter-colored
rock and some darker-colored rock, and the half of the Moon with the lighter-colored
rock rotates to face different directions.
Answer:
Explanation:
a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.
The most accurate diagram of the Sun and Moon is: a. A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.
What is a Moon?A Moon can be defined as the natural satellite of planet Earth that shines due to the Sun's reflected light (sunlight), as it revolves around the Earth from west to east in 29½ days.
The phases of the Moon.Based on astronomical information, there are four (4) primary Moon phases and these are:
New MoonFirst QuarterFull MoonThird Quarter (Last Quarter)In conclusion, diagram A is the most accurate because half of the Moon that faced the Sun is lit by the Sun while the other half is dark.
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What forces act on an airplane to keep it in the air? If the airplane is traveling at a constant velocity, what could be said about the magnitudes of the forces?
Let's see
[tex]\\ \sf\longmapsto \overrightarrow{drag}[/tex]
[tex]\\ \sf\longmapsto \overleftarrow{Thrust}[/tex]
[tex]\\ \sf\longmapsto Lift\:Force\uparrow[/tex]
[tex]\\ \sf\longmapsto Acceleration\:due\:to\: gravity\downarrow[/tex]
Net force is 0
A 3 kg drone starts at 5 meter above the ground and reached 25 meter above the
ground. Find the potential energy of the drone. Formula: PE=mghf-hi
A rock falls to the ground with a force of 300N and air resistance pushes back up on the rock with a
force of 45N. Which is true of the rock?
Answer:
what are the choices
Explanation:
don't worry i'll edit it
If a rock is thrown vertically upward from the surface of Mars with velocity of 20 m/s, its height (in meters) after t seconds is h = 20t − 1.86t2. (a) What is the velocity (in m/s) of the rock after 2 s? 12.56 Correct: Your answer is correct. m/s (b) What is the velocity (in m/s) of the rock when its height is 25 m on its way up? On its way down? (Round your answers to two decimal places.) up 8.07 Incorrect: Your answer is incorrect. m/s down -8.07 Incorrect: Your answer is incorrect. m/s
The velocity of the rock after 2s is 12.56 m/s.
The velocity of the rock at 25 m upwards is 14.68 m/s.
The velocity of the rock at 25 m downwards is -15.97 m/s.
The given parameters;
velocity of the rock, u = 20 m/sheight of the rock, h = 20t - 1.8t²The velocity of the rock after 2s is calculated as follows;
[tex]v = \frac{dh}{dt}= 20 -2(1.86)t \\\\v = 20 - 3.72t\\\\at \ t= 2 \ s \\\\v = 20 - 3.72(2) = 12.56 \ m/s[/tex]
The velocity of the rock when the height is 25 m:
h = 20t - 1.8t²
25 = 20t - 1.8t²
1.8t² - 20t + 25 = 0
solve for the time of motion "t" using quadratic formula
a = 1.8, b = -20, c = 25
[tex]t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-(-20) \ \ +/- \ \ \sqrt{(-20)^2 - 4(1.8\times 25)} }{2(1.8)}\\\\t = 9.67s, \ \ or \ 1.43 \ s[/tex]
The value of t that will give 25 m upwards using the motion model is 1.43 s;
h = 20(1.43) - 1.86(1.43)² = 25 m
The velocity of the rock at 25 m upwards (t = 1.43 s) is calculated as follows;
[tex]v = \frac{dh}{dt} = 20 -3.72t\\\\v = 20 - 3.72(1.43) \\\\v = 14.68 \ m/s[/tex]
The velocity of the rock at 25 m downwards (t = 9.67 s) is calculated as;
[tex]v = \frac{dh}{dt} = 20 - 3.72t\\\\v = 20 - 3.72(9.67)\\\\v = -15.97 \ m/s[/tex]
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Using Newton's First Law, explain why, in a frictionless environment, a car that is under motion will not stop moving?
Answer:
According to Newton's first law of motion, an object maintains its state unless a force acts on it. Therefore, a moving car does not change its direction and keeps its speed unless a force acts on it.
Explain what occurs to satellites when they travel too fast and too slow to keep in orbit
If the satellite goes too slow:
It will crash into it's surrounding things it's orbiting.It would not go forward enough due to pull of gravity.Gravity will pull it back to Earth.The satellite could be knocked or moved closer or farther from the object it is orbiting.If the satellite goes too fast:
It will eventually fly away.It can go forward soo fast.It would go too fastly that gravity can't retain in an orbit.The satellite's inertia would carry it off into space.Does bouncing or sticking produce more impulse?
Answer:
yes
Explanation:
Bouncing is a way to increase impulse. Because an object that bounces changes directions the force of impulse must be absorbed then generated by the target object. (Impulse is nearly doubled.)
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
PLEASE HELP ME!!!!!!!!!!!!!
Answer:
D gravity
Explanation:
please mark me brainliest
Answer:
D. The force that the branch applies to the kitten
Explanation:
I just took the quiz and got it correct!
Two hicers are 13 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walks 1.7 mph faster than the other.
Answer:
Explanation:
Let r be the rate of the slower walker in mph
[r + (r + 1.7)](2) = 13
(2r + 1.7)(2) = 13
4r + 3.4 = 13
4r = 9.6
r = 2.4 mph
r + 1.7 = 4.1 mph
HELP HELP!
Which of the following surfaces would have the lowest amount of friction?
a. Glass
b. Sand
c. Wood
d. Ice
Answer:
d. Ice
Explanation:
PLZ HURRY ANSWER THIS PLZ
Which statement best describes how Greensburg recovered from the tornado? O A. It doubled its population O B. It secured itself against future tornadoes. C. It became an eco-tourism destination © D. It built a new school and hospital.
Answer:
C: it became an eco-tourism destination
Explanation:
Answer: Its C
Explanation:
can anyone heelp me pls pls
Answer:
Explanation:
Answer in the pic.. hope it helps
What landforms are found on the Moon? (Select all that apply.)
mountains
plateaus
lakes
craters
Answer: I think it’s craters
Explanation:
Answer:
MOUNTAINS
CRATERS
PLATEAUS
Explanation:
The Moon has many familiar landforms like mountains, plains, and dark patches that look like seas. We now know that these areas are not seas filled with water. They are deep dry plains.
Compare and contarst the difference between saturated and unsaturated solutions and supersaturated
Answer:
Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible
A 20 kg box rests on the ground. Round all answers to the hundredths, if necessary. What is the weight of the box?
Weight=Applied force
[tex]\\ \sf\longmapsto F=mg[/tex]
[tex]\\ \sf\longmapsto F=20(10)[/tex]
[tex]\\ \sf\longmapsto F=200N[/tex]
Answer:
Weight=200
Explanation:
Given,
[tex]\sf\longmapsto \: mass = 20 \: kilograms[/tex]
We know that–
[tex]\sf\longmapsto \: acceleration \: \: because \: of \: gravity = 10m/s^2[/tex]
[tex]\sf\longmapsto \: Weight= \: is \: F = m•g[/tex]
Let's start solving!
Weight = 20×10
Weight=200