two actors who are pretending to be ningas are flying towards eachother with help of wires.Pretend ninja#1 is flying at 10 feet per second, and pretend ninja #2 is flying at 12 feet per second. If the two are 88 feet apart,how many seconds will it be before they collide

[tex](\stackrel{x_1}{-19}~,~\stackrel{y_1}{17})\hspace{10em} \stackrel{slope}{m} ~=~ - 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{17}=\stackrel{m}{- 1}(x-\stackrel{x_1}{(-19)}) \implies y -17 = - 1 ( x +19) \\\\\\ y-17=-x-19\implies {\Large \begin{array}{llll} y=-x-2 \end{array}}[/tex]

Answer:

y = -x - 2

Step-by-step explanation:

We are given that a line has a slope (m) of -1 and passes through (-19,17).

We want to write the equation of this line in slope-intercept form.

Slope-intercept form is given as y=mx+b, where m is the slope and b is the value of y at the y intercept, hence the name

As we are already given the slope of the line, we can plug it into the equation.

Replace m with -1.

y = -1x + b

This can be rewritten to:

y = -x + b

Now, we need to find b.

As the equation passes through (-19,17), we can use its values to help solve for b.

Substitute -19 as x and 17 as y.

17 = -(-19) + b

17 = 19 + b

Subtract 19 from both sides.

-2 = b

Substitute -2 as b into the equation.

y = -x - 2

The arc length by the given data is 4π cm.

We are given that;

AC≅AD,  ∠C =∠D = 30°

Now,

The arc length formula is:

s = rθ

where s is the arc length, r is the radius, and θ is the central angle in radians.

To use this formula, we need to convert the angle of 120° to radians. We can use the fact that 180° = π radians, so:

120° × π/180° = 2π/3 radians

Then we can plug in the values of r = 6 cm and θ = 2π/3 radians into the formula:

s = 6 × 2π/3 s = 4π cm

Therefore, by the given angle the answer will be 4π cm.

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Two events are

Whether the page number was even.

Whether the page number was odd.

A number that can be divided by two without leaving a remainder is an even number. Even numbers, in the context of book pages, are those that begin with 0, 2, 4, 6, or 8. For instance, page numbers 10, 12, and 14 are even numbers.

An odd number, on the other hand, is one that cannot be divided by 2 without leaving a remainder. Odd numbers, in the context of book pages, are those that begin with 1, 3, 5, 7, or 9. Page numbers 9, 11, and 13 are examples of odd numbers.

Mina is gathering information regarding the frequency of each event by noting whether the page numbers are even or odd. After that, this data can be used to figure out probabilities and make predictions about what will happen in the future, like whether the next page will be even or odd.

Mina opened the book 15 times to determine whether the page number was even or odd, so she conducted 15 trials.

She documented the following two events:

Whether the page number was even.

Whether the page number was odd.

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Answer:

See below

Step-by-step explanation:

Since the side length are proportional, the figures are similar. Helping in the name of Jesus.

Part A:

The new deck will be a 4:5 scaled version of the original deck. This means that every dimension of the new deck will be 4/5 times the corresponding dimension of the original deck.

The original deck has a base of 15 feet and a height of 9 feet.

The new deck will have a base of (4/5) * 15 = 12 feet and a height of (4/5) * 9 = 7.2 feet.

Therefore, the dimensions of the new deck are 12 feet for the base and 7.2 feet for the height.

Part B:

To find the area of the original deck, we use the formula for the area of a triangle:

Area = (1/2) * base * height = (1/2) * 15 * 9 = 67.5 square feet.

To find the area of the new deck, we use the same formula with the new dimensions:

Area = (1/2) * 12 * 7.2 = 43.2 square feet.

Therefore, the area of the original deck is 67.5 square feet, and the area of the new deck is 43.2 square feet.

Part C:

The ratio of the areas is:

Area of new deck / Area of original deck = 43.2 / 67.5

Simplifying this fraction, we get:

Area of new deck / Area of original deck = 8 / 15

The scale factor is 4/5, which simplifies to 8/10 or 4/5.

Comparing the ratio of the areas to the scale factor, we see that:

Area ratio / Scale factor = (8/15) / (4/5) = (8/15) * (5/4) = 1

Therefore, the ratio of the areas is equal to the scale factor. This makes sense since the area of a triangle is proportional to the square of its dimensions. In this case, the scale factor is applied to both the base and the height, so the area ratio is equal to the scale factor squared, which is 16/25.

Answer:

Step-by-step explanation:

Part A: To find the dimensions of the new deck, we need to scale the base and height of the original deck by a factor of 4:5.

Scaling factor = 4/5

New base = 15 * (4/5) = 12 feet

New height = 9 * (4/5) = 7.2 feet

Therefore, the dimensions of the new deck are 12 feet for the base and 7.2 feet for the height.

Part B: The area of the original deck can be found by using the formula for the area of a triangle:

Area = (1/2) * base * height = (1/2) * 15 * 9 = 67.5 square feet.

The area of the new deck can also be found using the same formula:

Area = (1/2) * base * height = (1/2) * 12 * 7.2 = 43.2 square feet.

Part C: The ratio of the areas of the two decks can be found by dividing the area of the new deck by the area of the original deck:

Ratio of areas = (43.2 / 67.5) ≈ 0.64

The scale factor is 4:5 or 0.8.

Comparing the ratio of areas to the scale factor:

Ratio of areas / scale factor = (0.64 / 0.8) = 0.8

The ratio of the areas divided by the scale factor is equal to 0.8, which makes sense since the scale factor is the factor by which the dimensions were scaled up, and the ratio of areas tells us how much the area was scaled up.

Answer:

c

Step-by-step explanation:

tysm

Answer:

11.2

Step-by-step explanation:

Subtract the at vector from the acceleration vector a(t) and simplify the result.

To find the tangential and normal components of the acceleration vector for the given function [tex]r(t) = ti + t^2j + 5tk[/tex], we first need to find the velocity and acceleration vectors.

Velocity vector v(t) is the first derivative of r(t):
[tex]v(t) = dr/dt = (1)i + (2t)j + (5)k[/tex]

Acceleration vector a(t) is the second derivative of r(t) or the first derivative of v(t):
[tex]a(t) = dv/dt = (0)i + (2)j + (0)k[/tex]
Now, we need to find the tangential and normal components of the acceleration vector.

Tangential component (at) is the projection of the acceleration vector onto the velocity vector:
[tex]at = (a(t) • v(t)) / ||v(t)||^2 * v(t)[/tex]Dot product[tex]a(t) • v(t) = (0*1) + (2*2t) + (0*5) = 4t[/tex]Magnitude of v(t) squared = (1^2 + (2t)^2 + 5^2) = 1 + 4t^2 + 25

Thus, at =[tex](4t / (1 + 4t^2 + 25)) * (i + 2tj + 5k)[/tex]

Normal component (an) is given by:
an = a(t) - at

To find an, subtract the at vector from the acceleration vector a(t) and simplify the result.

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10 cartons of eggs will contain 8 more broken eggs than 4 cartons if a grocery store worker is checking for broken egg cartons. Each carton of eggs contains 12 eggs. He checks 4 cartons and finds 8 broken eggs.

Assuming that the proportion of broken eggs in the sampled cartons is representative of the entire batch of cartons, the worker can use this information to predict the number of broken eggs in the rest of the cartons.

The worker checked 4 cartons of eggs, each with 12 eggs, for a total of 4 x 12 = 48 eggs. Out of these 48 eggs, 8 were found to be broken.

To estimate the number of broken eggs in the rest of the cartons, the worker can use proportionality. The proportion of broken eggs in the sample is 8/48 = 1/6. Therefore, the worker can predict that out of the marginal cost remaining cartons of eggs, 1/6 of the eggs will be broken.

The closest option is C, which predicts that there will be 16 broken eggs in 10 cartons, which is 8 more broken eggs than in the 4 cartons the worker checked. This implies an average of 2 broken eggs per carton, which is consistent with the prediction of 2x broken eggs in the remaining cartons. Therefore, option C is the best answer.

The linear approximation of f(1.01) is approximately 1.01.

To approximate f(1.01) using a linear approximation, we need to find the equation of the tangent line to the graph of f(x) at x = 1. We can do this by finding the slope of the tangent line and using the point-slope form of a linear equation.

First, we find the derivative of f(x):

f'(x) = e(1-x)

Then, we evaluate f'(1) to find the slope of the tangent line at x = 1:

f'(1) = e(1-1) = e0 = 1

So the slope of the tangent line is 1.

Next, we find the value of f(1):

f(1) = 2 - e(1-1) = 2 - e0 = 2 - 1 = 1

So the point on the graph of f(x) that corresponds to x = 1 is (1, 1).

Using the point-slope form of a linear equation, we can write the equation of the tangent line as:

y - 1 = 1(x - 1)

Simplifying, we get:

y = x

Now, we can use this equation to approximate f(1.01):

f(1.01) ≈ 1.01

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The median of complaints received per week is 2.

To find the median of complaints received per week, we need to arrange the probabilities in ascending order and then find the probability at the middle position.

Arranging the probabilities in ascending order, we get:

Number of complaints 0 1 2 3 4 5
Probability 0.05 0.07 0.09 0.18 0.26 0.35

The median position is (n+1)/2, where n is the total number of probabilities. In this case, n=6, so the median position is (6+1)/2=3.5.

The probability at position 3 is 0.09 and the probability at position 4 is 0.18. Therefore, the median probability is the average of these two probabilities, which is (0.09+0.18)/2=0.135.

To find the median number of complaints, we need to find the number of complaints that corresponds to the median probability. Starting from the first probability, we add up the probabilities until we reach a total of at least 0.135.

0.05 + 0.07 + 0.09 = 0.21

Therefore, the median number of complaints is 2.
So, the answer is 2 (rounded to the nearest integer).

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The median of complaints received per week is 2.

To find the median of complaints received per week, we need to arrange the probabilities in ascending order and then find the probability at the middle position.

Arranging the probabilities in ascending order, we get:

Number of complaints 0 1 2 3 4 5
Probability 0.05 0.07 0.09 0.18 0.26 0.35

The median position is (n+1)/2, where n is the total number of probabilities. In this case, n=6, so the median position is (6+1)/2=3.5.

The probability at position 3 is 0.09 and the probability at position 4 is 0.18. Therefore, the median probability is the average of these two probabilities, which is (0.09+0.18)/2=0.135.

To find the median number of complaints, we need to find the number of complaints that corresponds to the median probability. Starting from the first probability, we add up the probabilities until we reach a total of at least 0.135.

0.05 + 0.07 + 0.09 = 0.21

Therefore, the median number of complaints is 2.
So, the answer is 2 (rounded to the nearest integer).

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Since the limit of the sequence is 0, we can say that the sequence is bounded between 0 and some positive number (since all terms in the sequence are positive). Therefore, the answer is (A) bounded.

To determine whether the sequence is increasing, decreasing, or not monotonic, we need to look at how the terms in the sequence change as n increases.

We can rewrite the sequence as:

an = 1/(5n + 4)

As n increases, the denominator 5n + 4 also increases, which means that the fraction 1/(5n + 4) decreases. Therefore, the terms in the sequence decrease as n increases.

So the answer is (B) decreasing.

To determine whether the sequence is bounded, we need to consider the limit of the sequence as n approaches infinity.

lim (n→∞) an = lim (n→∞) 1/(5n + 4) = 0

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The Laplace transform of [tex]e^{(-4t)}sin(4t)[/tex] is 4/((s+4)² + 16).

In mathematics, the Laplace transform is an integral transform that converts a function of a real variable to a function of a complex variable s. The transform has many applications in science and engineering because it is a tool for solving differential equations.

To find the Laplace transform, denoted as ℒ{[tex]e^{(-4t)}sin(4t)[/tex]}, we'll use the following formula:

ℒ{[tex]e^{(-at)}f(t)[/tex]} = F(s+a)
where ℒ{f(t)} = F(s) is the Laplace transform of the function f(t), and "a" is the constant term in [tex]e^{(-at)}[/tex].

In this case, f(t) = sin(4t) and a = 4.

First, let's find the Laplace transform of f(t) = sin(4t), which is given by:
F(s) = ℒ{sin(4t)} = 4/(s² + 16)

Now, apply the formula for ℒ{[tex]e^{(-4t)}f(t)[/tex]}:

ℒ{[tex]e^{(-4t)}sin(4t)[/tex]} = F(s+4)

Substitute s+4 in the expression for F(s):

ℒ{[tex]e^{(-4t)}sin(4t)[/tex]} = 4/((s+4)² + 16)

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The coordinates of P that partitions AB in the ratio 2 to 3 include the following: [3, 4].

In this scenario, line ratio would be used to determine the coordinates of the point P on the directed line segment that partitions the segment into a ratio of 2 to 3.

In Mathematics and Geometry, line ratio can be used to determine the coordinates of P and this is modeled by this mathematical equation:

P(x, y) = [(mx₂ + nx₁)/(m + n)],  [(my₂ + ny₁)/(m + n)]

By substituting the given parameters into the formula for line ratio, we have;

P(x, y) = [(mx₂ + nx₁)/(m + n)],  [(my₂ + ny₁)/(m + n)]

P(x, y) = [(2(6) + 3(1))/(2 + 3)],  [(2(7) + 3(2))/(2 + 3)]

P(x, y) = [(12 + 3)/(5)],  [(14 + 6)/5]

P(x, y) = [15/5],  [(20)/(5)]

P(x, y) = [3, 4]

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Answer:

  0.0137

Step-by-step explanation:

You want the area under a standard normal probability distribution curve that is not between z = -2.59 and z = 2.37.

The desired area is the complement of the area between the limits -2.59 and 2.37. The value of the desired area is shown by the attached calculator to be about 0.0137.

The values of ∂z/∂x and ∂z/∂y at the point (π, -2π, -4π) are both 0.

To find the values of ∂z/∂x and ∂z/∂y at the point (π, -2π, -4π) for the equation 4sin(xy) + 4sin(xz) + 6sin(yz) = 0, first differentiate the equation with respect to x and y, then evaluate the derivatives at the given point.

Differentiate the equation with respect to x:
∂z/∂x = -[4cos(xy)*y + 4cos(xz)*z]/(4cos(xz)*y + 6cos(yz)*z)

Differentiate the equation with respect to y:
∂z/∂y = -[4cos(xy)*x + 6cos(yz)*z]/(4cos(xz)*x + 6cos(yz)*y)

Now, evaluate the derivatives at the point (π, -2π, -4π):
∂z/∂x = -[4cos(π*-2π)*-2π + 4cos(π*-4π)*-4π]/(4cos(π*-4π)*-2π + 6cos(-2π*-4π)*-4π) = 0

∂z/∂y = -[4cos(π*-2π)*π + 6cos(-2π*-4π)*-4π]/(4cos(π*-4π)*π + 6cos(-2π*-4π)*-2π) = 0

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Answer:

i think it might be 25350¹⁷

or 2⁵x3⁴x5⁴x13⁵

The answer to 3 644 mod 645 is 3.

To solve this problem, we need to find the remainder when 3644 is divided by 645.

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The answer to 3 644 mod 645 is 3.

To solve this problem, we need to find the remainder when 3644 is divided by 645.

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Answer:

area of triangle GHI =16.5 unit ^2

Step-by-step explanation:

triangle B =3 unit^2

triangle A = 9unit^2

triangle C = 7.5 unit^2

so

area of rectangle = 6 unit × 6 unit

= 36 unit^2

area of triangle GHI = 36 unit^2 - ( 3+9+7.5) unit^2

= 36unit^2 - 19.5unit^2

= 16.5 unit ^2

The derivative of y√(1/(t(8t+1))) is (dy/dt √(1/(t(8t+1))) - y * (4t√t+1 + √(8t+1))/(2t√(t(8t+1)))).

To use logarithmic differentiation to find the derivative of y√(1/(t(8t+1))), we can follow these steps:

ln(y√(1/(t(8t+1)))) = ln(y) + 1/2 ln(1/(t(8t+1)))

d/dt ln(y√(1/(t(8t+1)))) = d/dt [ln(y) + 1/2 ln(1/(t(8t+1)))]

d/dt ln(y√(1/(t(8t+1)))) = (dy/dt √(1/(t(8t+1))) - y * (4t√t+1 + √(8t+1))/(2t√(t(8t+1))))

So, the final expression y√(1/(t(8t+1))) is

(dy/dt √(1/(t(8t+1))) - y * (4t√t+1 + √(8t+1))/(2t√(t(8t+1)))).

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The final location of all relative and absolute extrema of the function H(x) is, H has an absolute minimum at (0, 5) and an absolute maximum at (2, 5). no relative extrema.

To find the exact location of all the relative and absolute extrema of the function h(x) = 5(x-1)^(2/3) with domain [0, 2], follow these steps:

1. Find the first derivative of h(x) with respect to x:
h'(x) = d/dx [5(x-1)^(2/3)]
h'(x) = (2/3) * 5(x-1)^(-1/3)

2. Set the first derivative to 0 to find critical points:
(2/3) * 5(x-1)^(-1/3) = 0
No real solutions exist for x.

3. Check the endpoints of the domain for absolute extrema:
h(0) = 5(0-1)^(2/3) = 5(-1)^(2/3) = 5
h(2) = 5(2-1)^(2/3) = 5(1)^(2/3) = 5

4. Compare the function values at the endpoints:
Since h(0) = h(2) = 5, and there are no critical points within the domain, h(x) has an absolute minimum at (0,5) and an absolute maximum at (2,5). There are no relative extrema in this case.

Your answer:
h has an absolute minimum at (0, 5).
h has an absolute maximum at (2, 5).
h has no relative extrema.

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If [tex]P^r[/tex] has all positive entries for some positive integer r, then [tex]P^n[/tex] will also have all positive entries for all integers n greater than or equal to r, due to the irreducibility of the Markov chain and the properties of matrix multiplication.

Given a transition probability matrix P of a Markov chain, if [tex]P^r[/tex] has all positive entries for some positive integer r, then [tex]P^n[/tex] also has all positive entries for all integers n greater than or equal to r.

Here's the explanation:
Let P be the transition probability matrix of a Markov chain, and let [tex]P^r[/tex] have all positive entries for some positive integer r. We want to show that [tex]P^n[/tex] has all positive entries for all integers n greater than or equal to r.

1. Since [tex]P^r[/tex] has all positive entries, the Markov chain is irreducible (meaning that there is a non-zero probability of transitioning between any two states in a finite number of steps).

2. Because the Markov chain is irreducible, there exists a positive integer k such that [tex]P^k[/tex] has all positive entries for all k greater than or equal to r.

3. Let n be an integer greater than or equal to r. We can express n as a multiple of k and some non-negative integer m, i.e., n = mk.

4. Then, [tex]P^n[/tex] = [tex]P^{mk[/tex] = [tex](P^k)^m[/tex]. Since [tex]P^k[/tex] has all positive entries, [tex](P^k)^m[/tex] also has all positive entries as the product of positive entries is always positive.

5. Therefore, [tex]P^n[/tex] has all positive entries for all integers n greater than or equal to r.

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If [tex]P^r[/tex] has all positive entries for some positive integer r, then [tex]P^n[/tex] will also have all positive entries for all integers n greater than or equal to r, due to the irreducibility of the Markov chain and the properties of matrix multiplication.

Given a transition probability matrix P of a Markov chain, if [tex]P^r[/tex] has all positive entries for some positive integer r, then [tex]P^n[/tex] also has all positive entries for all integers n greater than or equal to r.

Here's the explanation:
Let P be the transition probability matrix of a Markov chain, and let [tex]P^r[/tex] have all positive entries for some positive integer r. We want to show that [tex]P^n[/tex] has all positive entries for all integers n greater than or equal to r.

1. Since [tex]P^r[/tex] has all positive entries, the Markov chain is irreducible (meaning that there is a non-zero probability of transitioning between any two states in a finite number of steps).

2. Because the Markov chain is irreducible, there exists a positive integer k such that [tex]P^k[/tex] has all positive entries for all k greater than or equal to r.

3. Let n be an integer greater than or equal to r. We can express n as a multiple of k and some non-negative integer m, i.e., n = mk.

4. Then, [tex]P^n[/tex] = [tex]P^{mk[/tex] = [tex](P^k)^m[/tex]. Since [tex]P^k[/tex] has all positive entries, [tex](P^k)^m[/tex] also has all positive entries as the product of positive entries is always positive.

5. Therefore, [tex]P^n[/tex] has all positive entries for all integers n greater than or equal to r.

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Joe's capital loss is $1,392.

Rounding to the nearest percent, we get that Joe's capital loss was 32%.

Capital loss is the difference between the purchase price and the selling price of an asset when the selling price is lower than the purchase price. It represents the loss incurred by the investor or trader due to the decrease in the value of the asset. Capital loss can be realized or unrealized.

a. Joe's capital loss is the difference between the selling price and the purchase price of the shares.

Purchase price = 200 shares * $22.07 per share = $4,414

Selling price = 200 shares * $15.11 per share = $3,022

Capital loss = Purchase price - Selling price

Capital loss = $4,414 - $3,022

Capital loss = $1,392

Therefore, Joe's capital loss is $1,392.

b. To express Joe's capital loss as a percent, we need to divide the capital loss by the purchase price and then multiply by 100.

Capital loss percent = (Capital loss / Purchase price) * 100

Capital loss percent = ($1,392 / $4,414) * 100

Capital loss percent = 31.51%

Rounding to the nearest percent, we get that Joe's capital loss was 32%.

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a) Poppy's petrol was better value for money as it cost less per liter. b) 20 liters of petrol from the cheaper petrol station (Poppy's petrol station) would cost £26.00.

a) To determine which petrol was better value for money, we need to calculate the price per liter for each petrol station:

Jacob's petrol: £18.90 / 14 litres = £1.35 per litre

Poppy's petrol: £22.10 / 17 litres = £1.30 per litre

Therefore, Poppy's petrol was better value for money as it cost less per litre.

b) To calculate the cost of 20 litres of petrol from the cheaper petrol station, we need to determine which petrol station was cheaper:

Jacob's petrol: £1.35 per litre x 20 litres = £27.00

Poppy's petrol: £1.30 per litre x 20 litres = £26.00

Therefore, 20 litres of petrol from the cheaper petrol station (Poppy's petrol station) would cost £26.00.

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The appropriate measure of center for the data is The median is the best measure of center, and it equals 19.

What are mean and median?

In statistics, both the mean and the median are measures of central tendency, which describe where the center of a distribution of data is located.

The mean, also called the arithmetic mean, is calculated by adding up all the values in a dataset and dividing by the total number of values. It is often used when the data is normally distributed and does not have extreme outliers that could significantly affect the value. The mean is sensitive to extreme values because they can have a large impact on the overall average.

The median is the middle value in a dataset when the values are ordered from smallest to largest. If there is an even number of values, the median is the average of the two middle values. The median is often used when the data has outliers or is skewed, as it is not affected by extreme values in the same way as the mean.

Both measures have their advantages and disadvantages, and the choice between using mean or median as a measure of central tendency depends on the nature of the data and the research question being addressed.

Based on the given information, the box plot shows the distribution of the number of tickets sold for a school dance. The box represents the middle 50% of the data, with the bottom of the box indicating the 25th percentile and the top of the box indicating the 75th percentile. The line inside the box represents the median, which is the middle value when the data is arranged in order. The "whiskers" extending from the box indicate the range of the data outside of the middle 50%.

In this case, the box plot shows that the middle 50% of the data falls within the range of approximately 15 to 21 tickets sold. The median value, indicated by the line inside the box, falls within this range, and based on the given information, it is not possible to determine whether the mean value would be higher or lower than the median. Therefore, the appropriate measure of center for the data is the median, and its value is 19.

So, the appropriate measure of center for the data is The median is the best measure of center, and it equals 19.

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Answer:

  18 square yards

Step-by-step explanation:

You want the area of a garden that fills a back yard that is 4 yd by 6 yd except for a patio that is 3 yd by 2 yd.

The area of the backyard is ...

  A = LW = (6 yd)(4 yd) = 24 yd²

The area of the patio is ...

  A = LW = (3 yd)(2 yd) = 6 yd²

Garden area

The garden area is the area of the backyard that is not taken up by the patio:

  24 yd² -6 yd² = 18 yd²

The garden covers 18 square yards.

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Additional comment

You can compute this many ways. You can divide the garden area into rectangles or trapezoids, or you can recognize that the garden is 3/4 of the area of the back yard.

(You get two trapezoids by cutting the garden along a line between the upper left corner of the yard and the upper left corner of the patio.)

The probability of not selecting a person with blood type B+ is 90/100.

a) To find the probability of selecting a person with blood type A+ or A- (P(A+ or A-)), first count the number of people with each blood type, then divide the sum of those counts by the total number of people (100).

Number of people with blood type A+ = 34
Number of people with blood type A- = 6

P(A+ or A-) = (34 + 6) / 100 = 40/100

So, the probability of selecting a person with blood type A+ or A- is 40/100.

b) To find the probability of not selecting a person with blood type B+ (P(not B+)), first count the number of people without blood type B+ and then divide that count by the total number of people (100).

Number of people with blood type B+ = 10
Number of people without blood type B+ = 100 - 10 = 90

P(not B+) = 90 / 100 = 90/100

So, the probability of not selecting a person with blood type B+ is 90/100.

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The probability value for P(B) is obtained to be, Option (c) : 0.83.

What is probability?

Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence. Using it, we can only make predictions about the likelihood of an event happening, or how likely it is. Probability can range from 0 to 1, with 0 denoting an impossibility and 1 denoting a certainty.

We can use the formula: P(A È B) = P(A) + P(B) - P(A Ç B) to find P(B).

Rearranging the terms, we get -

P(B) = P(A È B) - P(A) + P(A Ç B)

Substituting the given values, we get -

P(B) = 0.72 - 0.55 + 0.66

P(B) = 0.83

The probability of an event A occurring is denoted by P(A) and is a number between 0 and 1, inclusive.

If A and B are two events, then P(A È B) denotes the probability that at least one of A or B occurs.

P(A Ç B) denotes the probability that both A and B occur simultaneously.

The formula used to find P(B) in terms of P(A), P(A È B), and P(A Ç B) is known as the addition rule of probability.

Therefore, the answer is 0.83.

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Step-by-step explanation:

Area B is 4 times Area A

This implies that B = 4 × A

So you take the measurements given and replace it, A is x and B is (x+3) so

(x+3) = 4x

3 = 4x - x

3x = 3

x = 1