From summation and resultant of forces, the four answers are:
i. ∅ = 34 degrees
ii. M = 0.48 kg
iii. V = 37.5 m/s
iv. V = 37.5i + 0j + 0k
Given that Three forces acting on an object are
F1 = (−2.00 i + 2.00 j) N
F2 = (5.00 i − 3.00 j) N
F3 = (−45.0 i) N.
If the object experiences an acceleration of magnitude 3.75 m/s2.
i. The direction of the force will be the direction of the acceleration.
Sum of the forces = (-2 + 5 - 4.5)i + (2 - 3 + 0)j
Sum of the forces = -1.5i -j
The acceleration direction will be
tan∅ = [tex]\frac{y}{x}[/tex]
tan∅ = [tex]\frac{1}{1.5}[/tex]
∅ = [tex]tan^{-1}[/tex] (0.67)
∅ = 34 degrees (approximately)
ii. The mass of the object can be calculated from Newton's law.
Resultant force = mass x acceleration.
Resultant force = [tex]\sqrt{1.5^{2} + 1^{2} }[/tex]
Resultant force = [tex]\sqrt{3.25}[/tex]
Resultant force = 1.8N
Then,
1.8 = 3.75M
M = 1.8 / 3.75
M = 0.48 kg
iii. If the object is initially at rest, the speed of the object after 10.0 will be calculated by using first equation of motion.
V = U + at
Where U = 0
V = 0 + 3.75 x 10
V = 37.5 m/s
Therefore, the speed of the object after 10.0 is 37.5 m/s
iv. The velocity components of the object after 10.0 are
V = 37.5i + 0j + 0k
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A 2 kg wagon is being pulled by a kid with a force of 0.1 N to the right. Determine the acceleration of the wagon
Answer:
0.2 m/s^2
Explanation:
a = fm
a = 2 x .1
a = 0.2 m/s^2
what is the capaceter
Answer:
capacitor, device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other. A simple example of such a storage device is the parallel-plate capacitor.
Explanation:
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plssssss look at the picture i need it right hurry pls
Answer:
it is B
Explanation:
Answer:
CO and H20
Explanation:
Which is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA?
Answer:
Space Launch System (SLS)
Explanation:
Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.
-TheUnknownScientist 72
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able
to slide past each other.
What is most likely the phase of the substance?
gas
o liquid
O solid
anggas
liquid and solid
Help
Me please I search this and there was only an asian answer
Answer:
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. What is most likely the phase of the substance?
gas. NO. Gases have expansibility, that is, they occupy all the space available, so they wouldn't occupy just one half of the container.
liquid. YES. The description fits the liquid phase.
solid and gas. NO. Solids occupy fixed positions and their atoms can't slide past each other.
liquid and solid. NO. Solids can't be present due to their lack of movement.
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.
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Explanation:
1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.
Answer:
C
Explanation:
because the concave mirror is always inverted
d ) when object is between focus and mirror , image formed is always virtual and erect
What is a Concave mirror ?
A concave mirror has a reflective surface that is curved inward and away from the light source .
a) Incorrect because image can be equal to , smaller then , and bigger then the object
b) and c) Incorrect when object is between focus and mirror , image formed is virtual and erect
d ) Correct option when object is between focus and mirror , image formed is always virtual and erect
e) Incorrect except one case in all other cases nature is real and inverted
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if vector b is added to vector a under what conditions does the resultant vector has magnitude a+b?
Explanation:
hope it's useful for you knows
Suppose that the Sun started shrinking in size, without losing any mass. What would be the effect of the Sun's change on the orbits of the planets
Answer:
F = G M m / R^2 gravitational force on planet of mass m.
None of these quantities change in the given hypothesis so
there will be no change in the orbit of mass m
a 3 kg rock is falling from a rock ledge in the absence of air resistance how much force will the rock strikes the ground with
Answer:
papi sus
Explanation:
John does 3.2J of work to lower the window shade in her bedroom a distance of 0.8m. How much force must John exert on the window shade?
Answer:
[tex]\boxed {\boxed {\sf 4 \ Newtons}}}[/tex]
Explanation:
Work is energy transferred when an object is moved. It is the product of force and distance.
[tex]W= F*d[/tex]
John did 3.2 Joules of work or 3.2 Newton meters of work (the units are equivalent). The window shade was lowered a distance of 0.8 meters.
W=3.2 N*m d= 0.8 mSubstitute the values into the formula.
[tex]3.2 \ N *m = F * 0.8 \ m[/tex]
We are solving for the force, so we must isolate the variable F. It is being multiplied by 0.8 meters. The inverse operation of multiplication is division, so divide both sides of the equation by 0.8 m.
[tex]\frac {3.2 \ N*m}{0.8 \ m}= \frac{ F* 0.8 \ m}{0.8 \ m}[/tex]
The units of meters cancel.
[tex]\frac {3.2 \ N}{0.8 }=F[/tex]
[tex]4 \ N = F[/tex]
John must exert 4 Newtons of force.
You are pulling a friend on a sled with a constant velocity using a rope held
horizontally in the snow. Using a spring scale attached to the rope, you
measure the tension to be 112 N. The combined mass of the sled and your
friend is 57.4 kg. Write the surface force the ground exerts on the sled in
component form, and determine its magnitude.
Here are all the steps.
When you are pulling a sled with constant velocity with a rope then the ground exerts a surface force on the sled will be equal to 573.56 N.
What is tension?The pulling force delivered axially by a cable, string, chain, or by either end of a rod, truss member, or another such 3-D object is known as tension in physics. Tension can be described as the action-reaction pair of forces acting at each end while tension is a polar opposite of compression.
A restoring force causes tension when atoms or molecules are torn apart at the atomic level and build up potential energy.
When you are trying to move upward and push in a positive way,
F = - 112 i + 57.4 (9.8) j
F = -112 i + 562.52 j
[tex]F = \sqrt{(-112)^2+ (562.52)^2}[/tex]
[tex]F =\sqrt{12544 + 316428.7}[/tex]
F = 573.56 N
Therefore, the surface force the ground exerts on the sled is 572.52 N.
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PLEASE HELP!!
5. A 700 kg race car travels
around the track at 65 m/s. The track has a radius of 75 m.
a. What is the centripetal acceleration?
b. What is the centripetal force?
c. Is the net force on the car less than, equal to, or greater than the centripetal force? Why?
Hi there!
a.
The equation for centripetal acceleration is as follows:
[tex]\large\boxed{a_c = \frac{v^2}{r}}}[/tex]
Plug in the given values to solve:
[tex]\large\boxed{a_c = \frac{(65)^2}{75} = 56.33 m/s^2}[/tex]
b.
According to Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}}[/tex]
The acceleration is v²/r, so the net force is:
[tex]\large\boxed{\Sigma F = m(\frac{v^2}{r})}}[/tex]
Multiply by the given mass:
[tex]\large\boxed{\Sigma F = 700(56.33) = 39433.33 N}}[/tex]
c.
There is NO net force in the vertical direction since the object is NOT accelerating in the vertical direction (normal force and weight cancel).
Thus, the ONLY net force experienced by the object is in the horizontal direction and is EQUAL to the centripetal force.
Which does not apply to unbalanced forces?
Net force = 0
Have direction
Net force does not = 0
Changes an object's motion
Answer:
Net force = 0
Explanation:
Whenever there is an unbalanced force, it shows that the net force doesn’t = 0 because if net force = 0, then everything force is balanced by another force. If there is an unbalanced force, acceleration will occur in the direction the net force is towards.
__________ refers to the distinctive character of a sound, or the quality that allows one to distinguish it from other sounds of similar pitch and loudness.
what voltage is measured across the 15 ohm resistor
Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?
Answer:
300 Newtons
Explanation:
Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.
The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have
Force = 12 × 25 = 300 Newtons or 300 N for short.
what are some examples of non-inertial reference frames, and how exactly can we prove they're non inertial?
Answer:Passengers instinctively use the car as a frame of reference, while a physicist uses Earth. ... In such a frame of reference, Newton's laws of motion take the form given in Dynamics: Newton's Laws of Motion The car is a non-inertial frame of reference because it is accelerated to the side.
Explanation: Example of inertial and Noninertial Frame of Reference
Definition of main energy level
Answer:
the orbital in which the electron is located relative to the atom's nucleus.
Explanation:
Answer:
the principal energy level of an electron refers to the shell or orbital in which the electron is located relative to the atom's nucleus.
Block 1, of mass m1
m
1
= 0.500 kg
k
g
, is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2
m
2
, as shown. For an angle of θ
θ
= 30.0 ∘
∘
and a coefficient of kinetic friction between block 2 and the plane of μ
μ
= 0.400, an acceleration of magnitude a
a
= 0.450 m/s2
m
/
s
2
is observed for block 2.
Find the mass of block 2, m2
m
2
.
Answer:
M2=0.52kg
Explanation:
thats rightt
[Ans. 2000 kg /m] f. If the mass of a substance having its volume 80 cm is 68 g. Calculate the density of the substance. Ans. 0.85 g/cm3]
Answer:
The density of the substance is
[tex]0.85\: \: g \: \: \: {cm}^{ - 3}[/tex]
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Two students are sitting on a see-saw. The length of the board is 2 meters with the
pivot point being in the very center. One student sitting on the end of the left side
has a mass of 34 kg. If the student sitting on the right has a mass of 42.5 kg, where
should she sit for the see-saw to be in equilibrium?
To solve the problem it is necessary to apply the concepts of Torque and equilibrium.
The Torque is defined as:
Where
F= Force
d = Distance
In this particular case, the force is caused by the weight of both children.
In turn, when there is equilibrium, the two torques must be equal therefore
Replacing with our values
Re-arrange to find
Therefore the distance that the second kid should sit to balance the see-saw is 1.8m from the pivot.
In a 200.0-m relay race (each leg of the race is 50.0 m long), one swimmer has a 0.450 second lead
and is swimming at a constant speed of 3.90 m/s towards the opposite end of the pool. What minimum
speed must the second swimmer have in order to catch up with the first swimmer by the end of the
pool?
The minimum speed that the second swimmer must have in order to catch up with the first swimmer by the end of the pool is; 4.04 m/s
We are given the following facts;
Both swimmers swim the same distance of 50 m for a leg of the relay race.Swimmer 1 swims at constant speed of 3.9 m/s. Swimmer 1 has a 0.450 second head start.Formula for time taken is;
time = distance/speed
Time taken by swimmer 1 for one leg;
t₁ = 50/3.9
t₁ = 12.82 s
Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;
t₂ = 12.82 -0.45
t₂ = 12.37 s
Thus, speed of swimmer 2;
v = 50/12.37
v = 4.04 m/s
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a 74 kg man jumps from a window 1.6 m above a sidewalk. the acceleration of gravity is 9.81 m/s 2 . a) what is his speed just before his feet strike the pavement? answer in units of m/s
Answer:
5.60 m/s
Explanation:
His initial potential energy is equal to his final kinetic energy.
mgh = 1/2mv^2
2gh = v^2 . . . . . . . multiply by 2/m
v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)
v ≈ 5.60 m/s
_____
Additional comment
The mass is irrelevant in the equations we typically use for this purpose.
If the western component of the wind is half of the south, what is the angle of the wind with the south?
Answer this question in details!
Answer is 26.57 or tan^-1 (1/2) or cot^-1 (2)
no links !
Answer:
This above a triangle that models our situation.
Explanation:
We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.
Let the component that travel in the south be the length of a.
According to the problem, the westard component is half of that so let that length be a/2.
Now we must find the angle of the wind in the South.
This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.
[tex] \tan(x) = \frac{opp}{adj} [/tex]
Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have
[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]
[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]
Now we take the arctan or inverse tan of 1/2.
[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]
Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.
What are the values of the western and southern component of the wind?The western and southern component have a negative displacement as shown in the graph.
Let the southern component be -x
The western component is half of -x = -x/2
What is the angle of the wind with the South?Since the angle is with the south, the trigonometric ratio to be used to find the angle is:
Tan θ = opp/adjTan θ = -×/2 /-x
Tan θ = 1/2
θ = tan^-1(0.5)
θ = 26.6°
Therefore, angle of the wind with the south is 26.57°.
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You're driving your pickup truck around a curve with a radius of 22 m. A box in the back of the truck is pressed up against the wall of the truck. How fast must you drive so that the force of the wall on the box equals the weight of the box?
Answer:
Explanation:
Centrifugal force Fc = m x v2 / r
Weight = mg
As required by the question
Fc = W
v2 /r = g
given radius r = 22 m
v2 /22 = 9.8
Solve for v
required speed v = √(22 * 9.8)
= 14.35 m/s
v=15 m/s
this may help you
The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.
What is centrifugal force?The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.
The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:
[tex]{\displaystyle F=m\omega ^{2}r}[/tex]
Given, the radius of the curve, r = 22m
The acceleration, a = v²/r
The weight of the box, W = mg
We know that, F = ma
mg = m(v²/r)
v = √gr
[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]
v = 14.68 m/s
Therefore, you should drive at a speed of 14.68 m/s
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Calculate the speed of light in a medium whose refractive index is 2.4
Answer:
Approximately [tex]1.3\times 10^{8}\; \rm m\cdot s^{-1}[/tex].
Explanation:
Look up the speed of light in vacuum: [tex]c \approx 3.00\times 10^{8}\; \rm m\cdot s^{-1}[/tex]. Denote the speed as [tex]c[/tex].
If the speed of light in a medium is [tex]v[/tex], the refractive index of that medium would be:
[tex]\displaystyle n = \frac{c}{v}[/tex].
Note, that the refractive index of a medium is inversely proportional to the speed of light in this medium. A medium with a larger refractive index would thus correspond to a slower speed of light.
Rearrange this equation to find the speed of light [tex]v[/tex] in this medium:
[tex]\begin{aligned}v &= \frac{c}{n} \\ &= \frac{3.00\times 10^{8}\; \rm m\cdot s^{-1}}{2.4} \\ &\approx 1.25 \times 10^{8}\; \rm m\cdot s^{-1}\end{aligned}[/tex].
What is the speed of an 800 kg automobile if it has a kinetic energy of 9.00 x 10^J?
Ek = 1/2 mv^2
9 × 10^4 = 1/2 × 800 × v^2
9 × 10^4/400 = 400 v^2 / 400
9 × 10^4/400 = v^2
√225 = v
15 ms⁻¹ = v
That's the only way I know how to work it out
I think in this case velocity and speed would be considered the same because me
s = d/t and v=d/t
one is distance travelled and the other is displacement of a body
e. Observe: notice or perceive
f. Infer:
g. Repetition:
h. Replication:
i. Data
The synonym of a word( observe, infer, repetition, replication and data) means another word that is nearest in meaning to the given word.
The synonym of the words given from the question is given below:
Observe: This means to notice or perceive something. Therefore the synonym is notice or perceive.Infer: This means to conclude something based on evidence and not from explicit statements. Therefore the synonym is deduce or conclude.Repetition: This means doing or saying something again. Therefore the synonym is recurrence.Replication: This means the process of reproduction. Therefore the synonym is duplicate.Data: This means information that is used to make decisions. The synonym is facts.Therefore, synonym of a word means another word that is nearest in meaning to the given word.
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A car is being towed. What is the car’s
mass if the net force on the car is 4,000 N and it has an
acceleration of 2.5 m/s^2?
Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.
What is force ?A physical cause that can change the state of motion or rest of a body is called force. It is the product of mass and acceleration off the body.
Here,
Net force acting on the car, F = 4000 N
Acceleration of the car, a = 2..5 m/s²
We know that,
F = ma
So, m = F/a
m = 4000/2.5
m = 1600 kg
Hence,
Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.
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A 7.5 kg beaver dives horizontally off a 50 kg log at a speed of 4 m/s. What is the speed of the log?
Answer:
[tex]0.6\; \rm m\cdot s^{-1}[/tex], assuming that drag of the water on the log is negligible.
Explanation:
The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity [tex]v[/tex]. That is, [tex]p = m\, v[/tex].
If the drag of water on the log is negligible, momentum of the beaver and the log, combined, would be preserved.
The momentum of the beaver and the log, combined, was initially [tex]0\; \rm kg\cdot m \cdot s^{-1}[/tex].
The momentum of the beaver right after the dive would be [tex]7.5 \; {\rm kg} \times 4\; {\rm m \cdot s^{-1}} = 30\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
The sum of the momentum of the beaver and the log is conserved and should continue to be [tex]0\; {\rm kg\cdot m \cdot s^{-1}}[/tex] even after the dive. Since the momentum of the beaver is [tex]30\; {\rm kg \cdot m \cdot s^{-1}[/tex] after the dive, the momentum of the log should become [tex](-30)\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
Since the mass of the log is [tex]50\; {\rm kg}[/tex], the new velocity of this log would be:
[tex]\begin{aligned}v &= \frac{p}{m} \\ &= \frac{(-30)\; {\rm kg \cdot m \cdot s^{-1}}}{50\; {\rm kg}} \\ &= (-0.6)\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
(The new velocity of the log is negative because the log would be moving away from the beaver.)
The speed of an object is the magnitude of velocity. For this log, a velocity of [tex](-0.6)\; {\rm m \cdot s^{-1}}[/tex] would correspond to a speed of [tex]|(-0.6)\; {\rm m \cdot s^{-1}| = 0.6\; {\rm m \cdot s^{-1}[/tex].