Answer:
Points on the inverse are [tex](1,-1), (4,2), \text{and } (0,0)[/tex]
Step-by-step explanation:
When writing the inverse function of a set of points, you simply switch the coordinates:
[tex]\text{Function}: (x,y)\\\text{Inverse}: (y,x)[/tex]
We are given the points
[tex](-3,9), (-1,1), (0,0), \text{and } (2,4)[/tex]
Using our rule for function, our new points will be
[tex](9,-3), (1,-1), (0,0), \text{and } (4,2)[/tex]
From the list, the points we have for the graph of the inverse are
[tex](1,-1), (4,2), \text{and } (0,0).[/tex]
What substitution should be used to rewrite 6(x 5)2 5(x 5) – 4 = 0 as a quadratic equation?
Solve 7p+ 13 = 30 Give your answer as a fraction in its simplest form.
Answer: p = 2 3/7
Step-by-step explanation:
7p+13 = 30
7p = 17
p = 17/7
p = 2 3/7
A fraction is written in the form of a numerator and a denominator where the denominator is greater than the numerator.
The value of p as a fraction in its simplest form is 17/7
What is a fraction?A fraction is written in the form of a numerator and a denominator where the denominator is greater than the numerator.
Example:
1/2, 1/3 is a fraction.
2/4 is a fraction but we can simplify further since there is a common factor of 2 with 2 and 4.
2/4 = 1/2 is a fraction.
4/16 = 4/(4x4) = 1/4 is a fraction.
We have,
7p + 13 = 30
Solve for p.
Subtract 13 on both sides.
7p + 13 - 13 = 30 -13
7p = 17
Divide both sides by 7.
p = 17/7
We can not further simplify the fraction as there are no common factors between 17 and 7.
Thus,
The value of p as a fraction in its simplest form is 17/7
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A bag has 4 red marbles,5 blue, 3 green and 1 yellow. what is the probability of pulling a red marble.
Answer as a fraction, decimal and percent
Answer:
4/13 is the answer
total = 4+3+5+1= 13
let a be the event of getting red marbles= total is 4
probability=4/13
Karen purchased a used vehicle that depreciates under a straight line method the initial value if the car is 4400 and the salvage value is 800 if the car is expected to have a useful life of another six years how much will it depreciate each year?
Answer:
Karen expects the vehicle to depreciate by 600 each year.
Step-by-step explanation:
Given:
- initial value: 4400
- salvage value: 800
- another six years
It is expected to depreciate from 4400 to 800 in 6 years.
The depreciation per year is the ratio
depreciation per year = (total depreciation) / (number of years)
Total depreciation is the change in value, so the depreciation per year is
(4400 - 800)/6 = 600
What is value of x in the equation 6x+7-2x=3+5x-9
Answer: x = 13
Step-by-step explanation: First, we simplify the equation to get 4x + 7 = 5x - 6. Then, from there, we subtract 7 on both sides to get 4x = 5x - 13. Then we subtract 5x from both sides, which would give us -x = -13. Finally, we can divide both sides by -1 (because remember, x = 1) to get that x = 13. Hope this helps!
Solve the system by elimination. 8x+3y=4 2x+y=2
Answer:
x = -1
y = 4
Step-by-step explanation:
Solving system of linear equations by elimination method.
8x + 3y = 4 ---------------(I)
2x + y = 2 --------------(II)
Multiply the second equation by (-3) and then add them.Thus y will be eliminated and we will obtain the value of 'x'.
(I) 8x + 3y = 4
(II)*(-3) -6x - 3y = -6 {Now add}
2x = -2
x = -2/2
[tex]\sf \boxed{\bf x = -1}[/tex]
Plugin x = (-1) in any one of the equations. Here I have chosen equation (II)
2*(-1) + y = 2
-2 + y = 2
y = 2 + 2
[tex]\sf \boxed{\bf y = 4}[/tex]
B Christian installed an electric pump to pump water from a borehole into a 30 000 litre cement dam. If the water is pumped at a rate of 75 litres per minute. How long does it take to fill the dam?
A.4 h
B.6 h 40 min
C.6 h 20 min
D.3h 40 min
Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.
Option B)6h 40min is the correct answer.
How long does it take to fill the dam?Given that;
Amount of water needed to fill the dam A = 30000 litresPump rate r = 75 litres per minuteTime needed to fill the dam T = ?To determine how long it take to fill the dam, we say;
Time need = Amount of water needed ÷ Pump rate
T = A ÷ r
T = 30000 litres ÷ 75 litres/minute
T = 400 minutes
Note that; 60min = 1hrs
Hence,
T = 6hours 40minutes
Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.
Option B)6h 40min is the correct answer.
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Help will mark brainliest!
a) The compound interest equation is [tex]C = 4250 \cdot 0.9675^{t}[/tex].
b) There is an approximate loss of $ 987.16.
c) The stock will take approximately 12.979 to decrease by half.
How to find stock losses by compound interest model
Compound interest model represents the gain of a deposit as a function of the number of periods and initial amount. The model is represented below:
[tex]C = C_{o}\cdot (1+r)^{t}[/tex] (1)
Where:
[tex]C_{o}[/tex] - Initial capital, in monetary units.[tex]r[/tex] - Interest rate.[tex]t[/tex] - Period number.[tex]C[/tex] - Current capital, in monetary units.Capital decreases in time when interest rate is a negative number. The equation that models the situation is [tex]C = 4250 \cdot 0.9675^{t}[/tex] and the current capital after eight years is:
C = 4250 · 0.9675⁸
C = 3262.84
That represents an approximate loss of $ 987.16.
And the number of periods required to decrease the capital by half is:
[tex]2125 = 4250 \cdot 0.9675^{t}[/tex]
[tex]0.5 = 0.9675^{t}[/tex]
㏒ 0.5 = t · log 0.9675
t ≈ 20.979
The stock will take approximately 12.979 to decrease by half.
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COSINE LAW: Solve triangle PQR. round angles to the nearest tenth
Answer:
Hi,
Step-by-step explanation:
PR²=PQ²+QR²-2*PQ*QR*cos(51°)
=15²+12²-2*15*12*cos(51°)
=142,444659....
PR=11.9350...
PQ²=QR²+PR²-2*QR*PR*cos(R)
cos(R)=(12²+142.444...-15²)/(2*12*11.9350...)=0,21451112....
angle R=77,61315...°≈77.6°
angle P=180°-51°-77.6°≈51,4°
please, I really need this answer the soon as possible. I'm going to be so thankful if anyone could help me with this...
Answer:
5/6
Step-by-step explanation:
i'm not rly confident,, but i used a calculator and solved it,,
so im sry if im wrong. Good luck!!
NEED ASAP
What is the rule for the function that is graphed?
Answer:
C
Step-by-step explanation:
The y-intercept if the graph is 2 and the slope is 2 so the rule is y=2x+2
Acellus
Type SSS, SAS, ASA, SAA, or HL to
justify why the two larger triangles are
congruent?
What is the perimeter of triangle JKL (same triangle as question #1)?
Answer:
x=30
Step-by-step explanation:
You have to use intercept theorem, also known as Thales's theorem to slvoe this.
A bank converts U.S. dollars to European euros at a rate of $1 for 0.88 euros. Kelsey wants 100 euros for her trip to Europe.
How much money, in dollars, does Kelsey need to give the bank
Answer:
$113.64
Step-by-step explanation:
0.88 x $113.636364 = 100 euros
= $113.64
(Hope this helps ^-^)
3(2x-9) - 4(3x + 4) = 2(x − 12) + 7/3
pls answer the question
Answer:
[tex]\normalsize \textsf{$x = -\dfrac{8}{3}$}[/tex]
Step-by-step explanation:
Given: [tex]\normalsize \textsf{$3(2x - 9) - 4(3x + 4) = 2(x - 12) + \dfrac{7}{3}$}[/tex]
1. Distribute
For 3:
[tex]\normalsize \textsf{$3(2x - 9)$}\\\normalsize \textsf{$3(2x) + 3(- 9)$}\\\normalsize \boxed{\textsf{$6x -27$}}\\[/tex]
For -4:
[tex]\normalsize \textsf{$-4(3x + 4)$}\\\normalsize \textsf{$-4(3x) + -4(4)$}\\\normalsize \boxed{\textsf{$-12x -16$}}\\[/tex]
For 2:
[tex]\normalsize \textsf{$2(x - 12)$}\\\normalsize \textsf{$2(x) + 2(-12)$}\\\normalsize \boxed{\textsf{$2x -24$}}\\[/tex]
Now we have: [tex]\normalsize \textsf{$6x - 27 - 12x -16 = 2x-24 + \dfrac{7}{3}$}[/tex]
2. Combine like terms:
[tex]\normalsize \textsf{$-6x -43 = 2x -\dfrac{72}{3} + \dfrac{7}{3}$}\\\\\normalsize \textsf{$-6x -43 = 2x -\dfrac{65}{3}$}\\\\[/tex]
3. Subtract 2x from both sides:
[tex]\normalsize \textsf{$-6x-2x -43 = 2x -2x -\dfrac{65}{3}$}\\\\\normalsize \textsf{$-8x -43 = -\dfrac{65}{3}$}\\\\[/tex]
4. Add 43 to both sides:
[tex]\normalsize \textsf{$-8x -43 +43 = -\dfrac{65}{3} + 43$}\\\\\normalsize \textsf{$-8x = -\dfrac{65}{3} + \dfrac{129}{3}$}\\\\\normalsize \textsf{$-8x = \dfrac{64}{3}$}[/tex]
5. Divide both sides by -8
[tex]\normalsize \textsf{$-8x = \dfrac{64}{3}$}\\\\\normalsize \textsf{$-8x \div 8 = \dfrac{64}{3} \div -\dfrac{8}{1}$}\\\\\normalsize \boxed{\textsf{$x = -\dfrac{8}{3}$}}[/tex]
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brainly.com/question/27543580brainly.com/question/27759148Answer the follwing grade 5 questions of HFC and LCM
Answer:
give clear image is next question
Step-by-step explanation:
i will give you the answer
A number cube with faces labeled from 1 to 6 will be rolled once.
The number rolled will be recorded as the outcome.
Give the sample space describing all possible outcomes.
Then give all of the outcomes for the event of rolling the number 2.
If there is more than one element in the set, separate them with commas.
The sample space S = {1, 2, 3, 4, 5, 6} describing all possible outcomes and outcomes for the event of rolling the number 2 is E = {2}
What is sample space?It is defined as the space in which all possible outcomes are represented in a list form for a particular event.
We have:
A number cube with faces labeled from 1 to 6 will be rolled once.
Let S is the sample space:
As we know, the sample space is the set of all possible outcomes:
S = {1, 2, 3, 4, 5, 6}
The total number of outcomes:
n(S) = 6
The outcomes for the event of rolling the number 2.
E = {2}
n(E) = 1
Thus, the sample space S = {1, 2, 3, 4, 5, 6} describing all possible outcomes and outcomes for the event of rolling the number 2 is E = {2}
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Write an equation for each translation y=sin x, pi/4 units to the right
The equation of the translation is y = sin(x - π/4)
How to determine the translation?The equation is given as:
y = sin(x)
The rule of translation to the right is:
(x,y) => (x - h,y)
This gives
(x,y) => (x - π/4,y)
So, we have:
y = sin(x - π/4)
Hence, the equation of the translation is y = sin(x - π/4)
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It's always a good idea to check your solutions to any equation in the original equation. When solving an absolute value equation, when must you check for extraneous solutions?
A. Sometimes, when u only get one solution
B. Never
C. Always
D. Sometimes, when the variable appears both inside and outside the absolute value expression
You should must check for an extraneous solution when the variable appears both inside and outside the absolute value expression
What is an extraneous solution?
An extraneous solution is a solution that in obtained after completely solving an equation but it does not work in the original given equation.
You should must check for an extraneous solution when the variable appears both inside and outside the absolute value expression (Option D).
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PLease HELP!!! 20 POINTS!!! WILL GIVE BRAINLIEST!!!
11. 6.2 m B 1.8m Calculate the value of x. NOT TO SCALE
Answer:
24.19
Step-by-step explanation:
[tex] \tan(x) = \frac{6.2}{13.8} \\ x = { \tan}^{1} \frac{6.2}{13.8} \\ x = 24.19320899[/tex]
or the value of x can be 24.20
5. If the longer side of the rectangle is 25.5 in., what are its width, perimeter, and area?
Step-by-step explanation:
1) The width of the rectangle is 10.2 in.
2) The perimeter of the rectangle is 71.4 in.
3) The area of the rectangle is 260.1 sq.in
The financial planner for a beauty products manufacturer develops the system of equations below to determine how many combs must be sold to generate a profit. the linear equation models the income, in dollars, from selling x plastic combs; the quadratic equation models the cost, in dollars, to produce x plastic combs. according to the model, for what price is each comb being sold?
The income that's made based on the equation when 1 comb is sold is $0.5.
How to calculate the price?From the information given, the equation is given as y = x/2. In this case, it was illustrated that the income is depicted based on the combs sold.
Therefore, the income by selling 1 comb will be:
y = 1/2
y = $0.5
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How do you solve this?
[tex]\text{L.H.S}\\\\=\begin{vmatrix} 1 & bc& b+c\\ 1 & ca& c+a\\ 1 &ab&a+b\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & bc& b+c-(a+b+c)\\ 1 & ca& c+a-(a+b+c)\\ 1 &ab&a+b-(a+b+c)\end{vmatrix}~~~~~~~~~~~~~~~;c_3\rightarrow c_3 -(a+b+c)c_1\\\\\\=\begin{vmatrix} 1 & bc& -a\\ 1 & ca& -b\\ 1 &ab&-c\end{vmatrix}\\\\\\=\dfrac 1{abc}\begin{vmatrix} a & abc& -a^2\\ b & abc& -b^2\\ c &abc&-c^2\end{vmatrix}\\\\\\=-\dfrac {abc}{abc}\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\[/tex]
[tex]=-1\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\\\\\=-1 \times -1 \begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\text{R.H.S}\\\\\text{Showed.}[/tex]
Ok help me I don’t understand stand this
Answer:
Step-by-step explanation:
Comment
It is not possible to figure out what choices are are given for the first blank. I will say that the probable choice has the word product in it.
The second blank is the actual number of choices. It is 3 page count times color or 3*4 = 12 different choices.
Answer
product
12
An amusement park charges $5 as an admittance fee and $1.50 per ride. Jason has $20 to spend, but used $3 to buy a
drink and hot dog.
A. Write an inequality that represents the situation,
B. What is the maximum number of rides Jason can go on.
Answer:
a=
b=8
Step-by-step explanation:
20-5=15 (admittance fee)
15-3=12 (food and drink)
12÷1.5=8 rides because 1.50 is price for every ride
Find the solution to each system please show your work!
Answer:
infinite number of solutions
Step-by-step explanation:
x + y = 1 → (1)
3y = - 3x + 3 ( add 3x to both sides )
3x + 3y = 3 ( divide through by 3 )
x + y = 1 → (2)
since the 2 equations are the same, this indicates the system has an infinite number of solutions
A plane has a speed of 840 km/h in still air. It can travel 3120 km with the wind in the same time it would take to travel 1920 km against the wind. Find the speed of the wind.
Answer:
200 KM/H
Step-by-step explanation:
A plane has a speed of 840 km/h in still air. It can travel 3120 km with the wind in the same time it would take to travel 1920 km against the wind. Find the speed of the wind.
let x=speed of wind
(840+x)=speed of plane with wind
(840-x)=speed of plane against wind
Travel time = distance/speed (same with and against the wind)
3120/(840+x)=1920/(840-x)
cross-multiply
3120*840-3120x=1920*840+1920x
3120*840-1920*840=1920x+3120x
5040x=1008000
x=200 km/hr
answer
Speed of wind=200 km/hr
Pls help! I don't get this!!
Answer:
5; 2n + 5 ≤ 15
6; n/5 ≤ 15
7; 5n ≥ 15
Step-by-step explanation:
"a number" means a variable denoted "n"
"product" means to multiply
"quotient" means to divide
"The sum" means to add
"is at least" means greater than or equal to or ≥
"is no greater than" means less than or equal to or ≤
"Is at most" means less than or equal to or ≤
Find the 5th term of the sequence which has a first term of 1 and has a common ratio of 2.3. Round your answer to the nearest hundredth if necessary.
The 5th term of the sequence is 27.98
How to determine the 5th term?The given parameters are:
First term, a = 1Common ratio, r = 2.3The nth term of a geometric sequence is calculated using:
[tex]T_n = ar^{n-1[/tex]
So, we have:
[tex]T_5 = 1 * 2.3^{5-1[/tex]
Evaluate the difference
[tex]T_5 = 1 * 2.3^4[/tex]
Evaluate the product
[tex]T_5 = 27.98[/tex]
Hence, the 5th term of the sequence is 27.98
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