There is £80 in a pot which is shared out amongst 3 people. Anne gets £20 Mark gets £35 and Ben gets £25. What ratio of the money do all of the people get?

Using logarithmic properties, the solution to the given logarithmic equation is y = 7

From the question, we are to determine the solution to the given equation

The given equation is

[tex]log_{11}(y+8) + log_{11}(4) = log_{11}(60)[/tex]

Applying the product law of logarithms, we get

[tex]log_{11}(y+8) \times (4) = log_{11}(60)[/tex]

This gives

[tex]log_{11}(4y+32) = log_{11}(60)[/tex]

Applying the equality law of logarithm, we get

[tex]4y + 32 = 60[/tex]

[tex]4y = 60-32[/tex]

[tex]4y =28[/tex]

∴ y = 28/4

y = 7

Hence, the solution to the given logarithmic equation is y = 7

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Answer: Three

Step-by-step explanation:

I am going to assume the first value is 6xy² and not 6xy2

    6xy² − xy + 8 + 12y

   The term with the highest degree is 6xy² because it has three x and y variables (x + y + y is three).

    The degree of the polynomial is the same as the degree of the highest term, so your answer is:

           three

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Answer:

95

Step-by-step explanation:

Step-by-step explanation:

where are the pictures ? or diagram?

Answer:

They Make 50 cents profit a pack

Step-by-step explanation:

1.89-1.35

Answer:

Step-by-step explanation:

((8 x 10) x 3) + ((9 x 8)/2) x2 = (80 x 3) + (72/2) x 2
                                             = 240 + (36 x 2)
                                             = 240 + 72
                                             = 312

Answer:

none of the answers listed are equivalent to b (22/5, 11/8, 2/5, 1/4)

Step-by-step explanation:

[tex]\frac{1}{3b} = \frac{4}{5}[/tex]

to simplify, cross multiply

(1 · 5  =  3b · 4)

(5 = 12b)

divide both sides by 12 to isolate b,

[tex]\frac{5}{12} =\frac{12b}{12}[/tex]

[tex]\frac{5}{12} = b[/tex]

None of the answers listed are equivalent to 5/12

[tex]\frac{5}{12}[/tex] [tex]\neq[/tex][tex]\frac{22}{5}[/tex]

[tex]\frac{5}{12} \neq[/tex][tex]\frac{11}{8}[/tex]

[tex]\frac{5}{12} \neq[/tex][tex]\frac{2}{5}[/tex]

[tex]\frac{5}{12} \neq[/tex][tex]\frac{1}{4}[/tex]

Both M(x) and N(x) are translations of f(x), the equations are:

N(x) = f(x + 4).

M(x) = f(x) + 4.

Remember that for a function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N

And for a function f(x), a horizontal translation of N units is written as:

g(x) = f(x + N).

First, we can see that N is a translation of 4 units to the left, then:

N(x) = f(x + 4).

And M is a translation upwards of 4 units, then:

M(x) = f(x) + 4.

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Answer:

It will be 4 30

Step-by-step explanation:

Mark me as a brainliest.

Answer:

Choice 4^th

Step-by-step explanation:

Given:

1/2+3/4+7/16 = __

To Solve:

Addition equation by finding a common multiple.

Solution:

Let the blank _ be x.

Then,

1/2+3/4+7/16 = x

Flip this equation:

Now solve for x.

Hence,

1/2+3/4+7/16 = 27/16

4^th Choice is accurate.

The true statement about the Internet connection cost is D. Any amount of time over an hour and a half would cost $10.

In this situation, the function is f (t), when t is a value between 0 and 30. The cost is $0 for the first 30 minutes

When t is a value between 30 and 90, the cost is US$ 5 if the connection takes between 30 and 90 minutes.

Here, the true statement about the Internet connection cost is D. Any amount of time over an hour and a half would cost $10.

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Answer:

Step-by-step explanation:

Answer:

B. [tex]\frac{14}{625}[/tex]

Step-by-step explanation:

Total paper in the hat:

2 blue + 6 red + 10 yellow + 7 purple = 25 total pieces of paper

P(AB) = 7 / 25 x 2 / 25

A is the probability of pulling a purple paper

B is the probability of pulling a blue paper

Answer:

14/625

Step-by-step explanation:

probability = favorable outcomes/total number of outcomes

First find the probability of drawing a purple piece of paper.

There are 7 pieces of purple paper.

Add all the amounts of colored paper together to get the total number of outcomes.

2 + 6 + 10 + 7 = 25

The probability of drawing purple is 7/25

Now find the probability of drawing  blue. There are 2 blue pieces of paper. Since he replaces the purple paper the total stays at 25.

The probability of drawing blue is 2/25

This is a compound probability problem, so multiply the two probabilities together.

7/25 x 2/25

14/625

Answer:

[tex]1 \div {3}^{( 30)} [/tex]

Step-by-step explanation:

There are exponent rules I posted above that are being used here.

We have (3^-6)^-5

Since we have a power times a power, we multiply 6 and 5 to get -30. Look at the first example in the photo.

So, we're left with 3^-30.

If you look at the photo, there's a rule for negative exponents.

Take the inverse of the base number, so 3 in this case:

1 / 3

and then make the exponent positive after taking the inverse.

So, we should get 1 / 3^30

Hope this helps!

For part A, we will see that the distance is 7 units. For part B, the distance from Nina's house to the school to the grocery store is larger.

Remember that the distance between two points (a, b) and (c, d) is:

[tex]D = \sqrt{(a - c)^2 + (b - d)^2}[/tex]

A) Her house is at (-4, 10), and her school is at (-4, 3), so the distance is:

[tex]D = \sqrt{(-4 - (-4))^2 + (10 - 3)^2} = \sqrt{7^2} = 7[/tex]

The distance is 7 units.

B) In the first case, the distance between the school and the grocery store is:

[tex]D' = \sqrt{(-4 - (-4))^2 + (3 - (-6))^2} = 9[/tex]

So the total distance is 9 + 7 = 16

And the distance between the school and the community center is:

[tex]D'' = \sqrt{(-4 - 2)^2 + (3 - 3)^2} = 6[/tex]

So the total distance is 6 + 7 = 13

So we can see that the total distance from Nina's house, to the school, to the grocery store is larger than the other.

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Answer: what question i don't see it but you can try reading it again and writing it down

Answer:

2/9

Step-by-step explanation:

8/12 you pick an office worker

4/12 chance you pick a manager

8/12 multiplied by 4/12 is 32/144

We can simplify this to 16/72

We can simplify this to 8/36

We can simplify this to 4/18

We can simplify this to 2/9

Answer:

y=4/3x+6

Step-by-step explanation:

[tex]\underline{\boxed{\sf{-7x^2 - \frac{13}{10} x +5}}}[/tex]

[tex]\sf{(-11x^2 + 1.4x - 3) + (4x^2 - 2.7x + 8)}[/tex]

Remove the parentheses:

[tex]\sf{-11x^2 + 1.4x - 3 + 4x^2 - 2.7x + 8}[/tex]

Convert decimal to fraction:

[tex]\sf{-11x^2 + \frac{14}{10} x - 3 + 4x^2 - \frac{27}{10} x + 8}[/tex]

Reduce fraction to the lowest term by canceling the greatest common factor:

[tex]\sf{-11x^2 + \frac{7}{5} x - 3 + 4x^2 - \frac{27}{10}x + 8}[/tex]

Combine like terms:

[tex]\sf{-7x^2 - \frac{13}{10} x +5}[/tex]

Answer:

[-11/4, ∞)

Step-by-step explanation:

Given :

y = √(4x + 9 + 2)

Simplifying :

y = √(4x + 11)

Now, the term in the bracket has to be greater than or equal to 0 to be real.

Hence,

⇒ 4x + 11 ≥ 0

⇒ 4x ≥ -11

⇒ x ≥ -11/4 [Lower limit]

Infinity will be the upper limit as the numbers increase indefinitely.

The domain will be :

⇒ [-11/4, ∞)

The maximum height of the  pumpkin is 3 feet

We have given that,

A catapult hurls a pumpkin from a height of 32 feet at an initial velocity of 96 feet per second.

The function h(t)=-16t^2+96t+32 represents the heights of the pumpkin h(t) in terms of time t.

We have to determine the maximum height.

At the point of maxima f'(x)=0

first, find the maxima

Therefore differentiate the given function with respect to t we get,

[tex]h'(t)=-32t+96[/tex]

h'(t)=0

Then we get,

[tex]0=-32t+96\\-32t=-96\\t=\frac{-96}{-32} \\t=3[/tex]

Therefore the maximum height of the pumpkin is 3 feet.

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Step-by-step explanation:

P means the center of the circle.

any point on the circle has therefore a constant distance from the center : the radius r.

r = 5 m

what we need to find is the length of the circle arc between the 2 points that represents 90° of the overall circle (360°).

90/360 = 1/4

so, we are looking for 1/4 of the overall circle circumference :

2×pi×r × 1/4 = 2×pi×5 × 1/4 = pi×10/4 = pi×5/2 =

= 7.853981634... m ≈ 7.85 m

Check the picture below.

well, the volume of the craft prism will simply be length * width * height, and we know that is 7140.

[tex]\textit{volume of a rectangular prism}\\\\ V=Lwh ~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=17\\ h=28\\ V=7140 \end{cases}\implies \begin{array}{llll} 7140=(17)w(28)\implies \cfrac{7140}{(17)(28)}=w \\\\\\ 15=w \end{array}[/tex]

we know the area of the top is just w * 17, and the circle is just 2/5 of that, well that's just

[tex]\cfrac{2}{5}(15)(17)\implies (2)(17)\cfrac{15}{5}\implies (2)(17)3\underset{\textit{area of the circle}}{\implies 102~in^2}[/tex]

Answer:

  (d)  108°

Step-by-step explanation:

An inscribed angle is half the measure of the arc it subtends. Conversely, the arc is twice the measure of the inscribed angle it subtends.

__

We can define the vertex of the marked angle as point Q. Arc XY is twice the measure of inscribed angle XQY:

  arc XY = 2(54°) = 108°

Step-by-step explanation:

I think angle A = 21 degree

because in the question there is angle A Is twice means angle a + angle a= 4G degree

2 angle a=42 degree

42 divides by 2

answer is 21 degree

The equation that produces the circle in the given graph is; x² + y² = 16. The correct answer is option B.

The complete graph is attached with the answer below.

A circle is a two-dimensional geometry on the plane having a centre point and the circular line is drawn equidistant from the centre point.

The general form of the equation of a circle is;

(x - h)² + (y - k)² = r²

where;

h, k are coordinates of the circle centre r is the radius

From the graph, we can see that the coordinates of the centre are; (0, 0).

Also, the radius is;

r = √(4² - 0²)

r = √16

Thus, our equation of the circle in the graph is;

(x - 0)² + (y - 0)² = (√16)²

⇒ x² + y² = 16

Therefore the equation that produces the circle in the given graph is; x² + y² = 16. The correct answer is option B.

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[tex]\text{L.H.S}\\\\=\dfrac{1+\tan x}{ 1+ \cot x}\\\\\\=\dfrac{1+ \tan x}{ 1+ \tfrac 1{\tan x}}\\\\\\=\dfrac{1+\tan x}{\tfrac{\tan x+1}{\tan x}}\\\\\\=(1+\tan x) \times \dfrac{\tan x}{1+ \tan x}\\\\=\tan x\\\\=\text{R.H.S}\\\\\text{Proved.}[/tex]