Answer:
Your answer is in the pic
10 points
Calculate the force of attraction between the moon and the earth, if their masses and distance apart are 10^22Kg, 10^24kg and 6.4x10^6m. Take g = 6.67x10^-11Nm^2Kg^-2
a) 0.63x10^24N
b) 1.63x10^22N
c) 2.63x10^20N
d) 3.63x10^18N
Answer:
Explanation:
You didn't fill in the proper masses which is why you never got an answer to this. But that's ok...I got you. I happen to know what they are! We will use the universal law of gravitation and the gravitational constant to solve this.
[tex]F_g=\frac{Gm_1m_2}{r^2}[/tex] and filling in:
[tex]F_g=\frac{(6.67*10^{-11})(5.98*10^{24})(7.36*10^{22})}{(3.84*10^8)^2}[/tex] The denominator is the radius of the earth plus the radius of the moon plus the distance between their surfaces, just FYI.
That gives us that
[tex]F_g=1.99*10^{20}N[/tex] Not sure what your choices entail, but I'd have to say, taking into consideration that maybe your problem didn't figure in the distance between the surfaces, you'd be at choice B.
The motor of a boat develops 48 kW when the boat's speed is 12 km/h. With how much force does the water resist the motion of the boat?
2 um means
(A)
(B)
(C)
(D)
2 x 10 m
2 x 10 m
2 x 103 m
2 x 10-6 m
Answer:
Looks like its c 2x 10 m
Explanation:
i do see the question
If an object's surface area is smaller does it create more or less pressure?
Answer:
When the surface area is less the pressure exerted by the object is more. However, when the surface area is large, the points of contact between the object and the pressure. Thus, less pressure is exerted by the body on the surface.Explanation:
hope it helpsIf the surface area of an object is smaller, it will create more pressure
An object's surface area is inversely proportional to its pressure.
This can be demonstrated from the formula below
Pressure:The can be defined as the perpendicular force acting per unit area. the S.I unit of pressure is N/m².
Formula:P = F/A.................. Equation 1Where: P = Pressure of the objectF = Force acting on the objectA = Surface area of the object.In View of the above equation, It can be seen that as the surface area of an object reduces the pressure created by the object will increase.
Hence, If the surface area of an object is smaller, it will create more pressure
Learn more about pressure here: https://brainly.com/question/25736513
When should a bar graph be used?
A. When the independent variable is composed of categories and does not show a
relationship
B. When the independent variable is continuous and does not show a relationship to the
dependent variable.
C. When the independent variable is continuous and shows a causal link to the
dependent variable,
D. When there is no independent variable.
Answer:
B. When the independent variable composed of categories and does not show a relationship to the dependent variable
Explanation:
A bar graph, is a graph used for presenting data grouped into categories, which are the independent variables of the graph, and the measurement of each category, which are represented as rectangular bars having lengths proportional to the value of the category, on a chart
In the bar graph or chart, there is no direct relationship between the categories, which are the x-values and the dependent variables , which are the length of the bars, the y-values, as the length of the rectangular bar in one category, cannot be obtained from another category through a relationship
Therefore, the correct option is option is when the independent variable composed of categories and does not show a relationship to the dependent variable
(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg.
Complete question:
(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C
Answer:
The energy that must be supplied to boil the given mass of the water is 672,000 J
Explanation:
Given;
mass of water, m = 2 kg
heat of vaporization of water, L = 330 kJ/kg
initial temperature of water, t = 20 ⁰C
specific heat capacity of water, c = 4200 J/kg⁰C
Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;
Q = mc(100 - 20)
Q = 2 x 4200 x (80)
Q = 672,000 J
Q = 672,000 J
Q = 672,000 J
Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J
Martha is telling her teacher how an animal cell is like a house. Which part of an animal cell is like the doors and windows in Marthas house
Answer:
cell membrane.
Explanation:
A cell can be defined as the fundamental or basic functional, structural and smallest unit of life for all living organisms. Some living organisms are unicellular while others are multicellular in nature.
A unicellular organism refers to a living organism that possess a single-cell while a multicellular organism has many (multiple) cells.
Generally, cells have the ability to independently replicate themselves. In a cell, the "workers" that perform various functions or tasks for the survival of the living organism are referred to as organelles. Some examples of cell organelles found in all living organisms such as trees, birds, and bacteria include; nucleus, cytoplasm, cell membrane, golgi apparatus, mitochondria, lysosomes, ribosomes, chromosomes, endoplasmic reticulum, vesicles, etc.
Cell membrane is the wall of a cell in living organisms and it typically functions as a door and window in a house by controlling what leaves and enters the cell at any given time. Also, the cell membrane opens selectively and as such it would only open at certain times and to certain chemical changes or signals.
This ultimately implies that, the part of an animal cell that is like the doors and windows in Martha's house is the cell membrane.
Answer:
give the guy above brainlist
he did a very good job.
Explanation:
please help me with this question.... thank u ❤️
Answer:
20 degrees
Explanation:
Because projectile has the same range on both angles which on summation gives 90 degrees as a total.
Two examples of chemical reactions that involved a thermal energy change:
1. NH4NO3 (s) + heat ---> NH4+ (aq) + NO3 (aq)
2. CaCl2 (s) + 2H20 ---> Ca(OH)2 (aq) + 2HCl (g) + heat
Which is exothermic? Which is endothermic? How do you know?
Answer:
Option 1 is endothermic
Option 2 is exothermic
Explanation:
In Chemistry, Exothermic reactions are reactions whereby heat energy is transferred to the surroundings and the temperature of the surroundings increases. Endothermic reactions are those whereby heat energy from the surroundings is absorbed and thereby making the temperature of the surroundings to decrease.
This means in simple terms that endothermic reactions will have heat on the reaction side of the equation while exothermic will have heat on the product side of the equation.
Thus;
Option 1 is endothermic since it has heat absorbed on the reactant side.
Option 2 is exothermic since it gives off heat on the product side.
Q.2.
Write the unit to measure the following.
a) Length of edge of a table
b) Weight of your body
c) Quantity of milk
Answer:
a) Metres (m)
b) Kilogram (kg)
c) litres (l)
metre is the unit of dash.
Answer:
Length is the unit of metre
Answer:
From the meter, several other units of measure are derived such as the: unit of speed is the meter per second (m/s).
...
Units of Length
10 millimeters (mm) = 1 centimeter (cm)
10 decimeters = 1 meter (m)
10 decimeters = 1000 millimeters
10 meters = 1 dekameter (dam)
Can someone explain to me why Ohms law stops working when the temperature of the component increases?
Answer:
Ohm's law verifies that current directly varies with voltage, when resistance increases, current current decreases.
When temperature increases, the electrons gain more average kinetic energy increases and current increases as well.
In the same situation, resistance also increases because atoms of a component vibrate at higher amplitudes about their mean positions hence reducing the free path of electrons. This increases resistance, hence ohms law violated or disobeyed.
This generates the temperature coefficient of resistance
Which circuit component usually acts as a switch or amplifier?
O A. A transistor
O B. A capacitor
O C. A resistor
D. A battery
Answer:
The answer is A. A transistor
Answer:
a transistor
Explanation:
A P E X
A 45000 watt crane operating at full power lifts a 2100 kg object vertically for 17.4 seconds. How high has the crane lifted the object?
Answer:
Explanation:
We need the power equation here, which is:
Power = (F * Δx)/time
where F * Δx is the amount of work done.
F is a force which is measured in Newtons. We are given the mass of the object, but since we need a Force measure, we need the weight of the object:
F = 2100(9.0)
F = 21000 to the correct number of sig dig.
Now we can plug in the values we have and solve for the displacement, Δx:
[tex]45000=\frac{21000x}{17.4}[/tex] and isolating x:
[tex]\frac{17.4(45000)}{21000}=x[/tex] so
x = 37 m
An airplane is .68 Kilometers long. How many Millimeters long is the plane?
a. 680 mm
b. 6,800 mm
c. 68,000 mm
d. 680,000 mm
Given : Airplane is 0.68 kilometers long
We know that :
⊕ 1 km = 1000 meters
⊕ 1 m = 1000 millimeters
⇒ 1 km = (1000 × 1000) millimeters
⇒ 0.68 km = (0.68 × 1000 × 1000) millimeters
⇒ 0.68 km = 680,000 millimeters
Answer: Airplane is 680,000 millimeters long
If an airplane is 0.68 Kilometers long, the length of the airplane in millimeters would be 680000 Millimeters, therefore the correct answer is option D.
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.
As given in the problem, If an airplane is 0.68 Kilometers long, then we have to find out the length of the airplane in millimeters,
1 kilometers = 1000 meters
1 meter = 100 centimeters
1 centimeters = 10 millieters
As given the length of the plane is 0.68 Kilometers.
0.68 kilometers = 680 meters
0.68 kilometers = 680×100 centimeters
0.68 kilometers = 680×100×10 millimeters
= 680,000 millimeters
Thus, the correct answer is option C.
To learn more about the unit of measurement from here, refer to the link;
brainly.com/question/12629581
#SPJ2
Water can exist in three states: solid (ice), liquid and gas (steam).In which state, or states, is the motion of the molecules only vibrational?
Answer:
solid
Explanation:
Answer:
In the solid state, the motion of molecules is only vibrational, because solids are very tightly packed together and cannot move other than by vibrating
Which statement best compares potential and kinetic energy?
O Objects always have more potential energy than kinetic energy.
O Kinetic energy increases and potential energy decreases when the velocity of an object increases.
O Only potential energy decreases when an object's height increases.
O Objects always have more kinetic energy than potential energy.
Mark this and return
Save and Exit
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Submit
Answer:
B . Kinetic energy increases and potential energy decreases when the velocity of an object increases.
Explanation:
The statement with best compares potential energy and kinetic energy is that only kinetic energy increases when the velocity of the object increases.
Convert 162 km/h into m/s.
Answer:
45 m/s
Explanation:
162 / 3.6 = 45 m/s
Divide by 3.6 to convert km/h to m/s.
The wind blows a leaf at 37.9 m/s for 118 s left. How are does the leaf go in that period of time.
A) 3.11 m, left
B) 4470 m, left
C) 80.1 m, left
D) 0.321 m, left
Explanation:
distance = velocity * time
d = 37.9 * 118
distance = 4472.2
find the magnitude and angle of a vector given the components: Bx=7, By=-5
Answer:
Magnitude = 8.6
Angle = 324.5 degree from + X axis in counter clock wise direction.
Explanation:
X component of B, Bx = 7
Y component of B, By = - 5
The magnitude of the resultant is
[tex]B =\sqrt{7^{2}+(-5)^2}\\\\B =\sqrt{49+ 25}\\\\B = 8.6[/tex]
The angle is given by
[tex]tan\theta=\frac{By}{Bx}\\\\tan\theta = \frac {-5}{7}\\\\\theta = 324.5^{o}[/tex]
Un reloj de péndulo de largo L y período T, aumenta su largo en ΔL (ΔL << L). Demuestre que su período aumenta en: ΔT = π ΔL /√(L g)
Answer:
ΔT = [tex]\pi \ \frac{\Delta L}{\sqrt{Lg} }[/tex]
Explanation:
In a simple harmonic motion, specifically in the simple pendulum, the angular velocity
w = [tex]\sqrt{\frac{g}{L} }[/tex]
angular velocity and period are related
w = 2π / T
we substitute
2π / T = \sqrt{\frac{g}{L} }
T = [tex]2\pi \ \sqrt{\frac{L}{g} }[/tex]
In this exercise indicate that for a long Lo the period is To, then and increase the long
L = L₀ + ΔL
we substitute
T = [tex]2\pi \ \sqrt{\frac{L + \Delta L}{g} }[/tex]
T = [tex]2\pi \ \sqrt{\frac{L}{g} } \ \sqrt{1+ \frac{\Delta L}{L} }[/tex]
in general the length increments are small ΔL/L «1, let's use a series expansion
[tex]\sqrt{1+ \ \frac{\Delta L}{L} } = 1 + \frac{1}{2} \frac{\Delta L}{L} + ...[/tex]
we keep the linear term, let's substitute
T = [tex]2\pi \ \sqrt{\frac{L}{g} } \ ( 1 + \frac{1}{2} \frac{\Delta L}{L} )[/tex]
if we do
T = T₀ + ΔT
T₀ + ΔT = [tex]2\pi \sqrt{\frac{\Delta L}{g} } + \pi \ \sqrt{\frac{L}{g} } \ \frac{\Delta L}{L}[/tex]
T₀ + ΔT = T₀ + [tex]\pi \sqrt{\frac{1}{Lg} } \ \Delta L[/tex]
ΔT = [tex]\pi \ \frac{\Delta L}{\sqrt{Lg} }[/tex]
A cyclist goes around a circular track once every 2 minutes. If the radius of the circular track is 110m,calculate the speed of the cyclist.
Answer:
5.76 m/s
Explanation:
Applying,
S = d/t............... Equation 1
Where S = speed, d = distance, t = time.
For circular motion,
d = 2πr............ Equation 2
Where r = radius of the circular track, π = pie
Substitute equation 2 into equation 1
S = 2πr/t.............. Equation 3
From the question,
Given: r = 110 m, t = 2 minutes = (2×60) = 120 s
Constant: π = 3.14
Substitute these values into equation 3
S = (2×3.14×110/120)
S = 690.8/120
S = 5.76 m/s
A spiral spring is compressed by 0.1cm. calculate the elastic potential energy in the spring if the stiffness of the spring is 100Nm^1
Answer:
[tex]E=5\times 10^{-5}\ J[/tex]
Explanation:
Given that,
A spring is compressed by 0.1 cm or 0.001 m
The spring constant of the spring, k = 100 N/m
The elastic potential energy in the spring is given by :
[tex]E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 100\times 0.001^2\\\\E=5\times 10^{-5}\ J[/tex]
So, the elastic potential energy of the spring is equal to [tex]5\times 10^{-5}\ J[/tex].
An astronaut wearing a space suit floats in the middle of a room with no air (i.e. vacuum) and is 20.0 m from any wall, the floor and the ceiling. She needs to get to the door so she can go with her NASA friends to eat a hamburger. She has only a book and a pencil in her possession. She cannot call for help since something is interfering with her signal. Under these conditions, how can she get to the door
Answer:
To get to the door, the astronaut has to throw the book and pencil away from her in the direction opposite to that of the door.
Explanation:
Since no net force acts on her and she floats in the center of the room, if she throws the book and pencil away from her, since both her, the book and the pencil have an initial momentum p = 0, and since momentum is conserved, then after throwing the book and pencil away from her, the momentum of both her, the book and pencil is still zero.
The astronaut will thus develop a momentum which is opposite to that of the book and pencil. This is shown below.
Since p = p' where p = initial momentum of astronaut, book and pencil = 0 and p' = final momentum of astronaut, book and pencil = mv + m'v' where m = mass of book and pencil, v = velocity of book and pencil, m' = mass of astronaut and v' = velocity of astronaut.
So, p = p'
0 = mv + m'v'
mv = -m'v' where mv = momentum of book and pencil and m'v' = momentum of astronaut
v' = -mv/m
We see that the astronaut develops a momentum opposite in direction but equal in magnitude to that of the book and pencil and will thus develop a velocity opposite to that of the book and pencil.
Thus, to get to the door, the astronaut has to throw the book and pencil away from her in the direction opposite to that of the door.
A cyclist is taking part in the Tour de France, which is a bicycle race that takes place every year.
a Two forces acting on the cyclist are weight and reaction. Name two other forces acting on him
as he cycles along.
as light passes from water into air it has a refracted angle of 35 degrees. calculate the incident angle of the light.
Do only number 2 and thank
Answer:
Quantity of charge = 0.8 Coulombs
Explanation:
Given the following data;
Current = 0.4 A
Time = 2 seconds
To find the quantity of electricity transferred;
Mathematically, the quantity of electricity (charge) passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
Quantity of charge = 0.4 * 2
Quantity of charge = 0.8 Coulombs
A gas in a sealed container has a pressure of 50 kPa at 27°C. What will the pressure of the gas be if the temperature rises to 87°C?
Answer:
the final pressure of the gas is 60 kPa.
Explanation:
Given;
initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa
initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k
final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K
Let the final pressure of the gas = P₂
Apply pressure law;
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} = \frac{50,000 \times 360}{300} = 60,000 \ Pa = 60 \ kPa[/tex]
Therefore, the final pressure of the gas is 60 kPa.
when two resistors, having resistance R1 and R2, are connected in parallel, the equivalent resistance of the combination is 5Ω. what statement would be true about the resistances?
Answer:
The correct option is: (A) Both R 1 and R 2 are greater than 5 Ω. Explanation: The equivalent resistance in parallel is smaller than the smallest resistance.
Explanation:
hopefully it helps- ^^
the value of 'g' changes as per its position on the earth's surface.justify the statement
Answer:
PLEASE MARK ME AS A BRAINLIEST
Explanation:
There are slight variations in the value of g about earth's surface. These variations result from the varying density of the geologic structures below each specific surface location. They also result from the fact that the earth is not truly spherical; the earth's surface is further from its center at the equator than it is at the poles. This would result in larger g values at the poles. As one proceeds further from earth's surface - say into a location of orbit about the earth - the value of g changes still.