the voltage across a 1 uf capacitor is given. what is the sinusoidal expression for the current? a) 30sin200t b) 60×10^(-3) sin377t

The correct answer is "98i; n = 77".

The function qt() in statistics is used to calculate the t-value for a given level of confidence and degrees of freedom.

In this case, qt(.98, df = 77) outputs the t-value for a 98% confidence interval with 77 degrees of freedom.

The t-value is used to calculate the margin of error for a confidence interval, which is used to estimate the population parameter based on the sample data.

For example, if you have a sample of size 78 and want to construct a 98% confidence interval for the population mean, you can use the t-value of qt(.98, df = 77) along with the sample mean and standard deviation to calculate the margin of error and construct the interval.

Therefore, the correct answer is "98i; n = 77".

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dx/dt is equal to -10/3 when x=1 and y=-3. This can be answered by the concept of Differentiation.

To find dx/dt, we need to use implicit differentiation. Taking the derivative of both sides of y² + xy - 3x = 1 with respect to t, we get:

2y(dy/dt) + y(dx/dt) + x(dy/dt) - 3(dx/dt) = 0

Now we can substitute the values given in the problem: y = -3, dy/dt = 4, x = 1. Plugging these in, we get:

2(-3)(4) + (-3)(dx/dt) + 1(4) - 3(dx/dt) = 0

Simplifying, we get:

-24 - 3(dx/dt) + 4 - 3(dx/dt) = 0

-6(dx/dt) = 20

dx/dt = -20/6 = -10/3

Therefore, dx/dt is equal to -10/3 when x=1 and y=-3.

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Answer: 254.34

Step-by-step explanation:

First we can fine the radius by dividing the diameter (18in) by 2: 18/2=9

Then we can use the formula to find the area of the circle (pi*r^2):9*9*pi=81pi

Finally, approximate pi to 3.14 and multiple: 81*3.14=254.34

Therefore, the answer is 254.34

Answer:1017.36

Step-by-step explanation:

Answer:

23 dollar in total

Step-by-step explanation:

since 11.50 for one if u buy 2 it would be 23dollar total

The correct Z-scores for which 90% of the distribution's area lies between -z and Z are D) (-1.645, 1.645).

The Z-score is a measure of how many standard deviations a particular value is from the mean of a distribution. In a standard normal distribution, which has a mean of 0 and a standard deviation of 1, the Z-score represents the number of standard deviations a value is away from the mean.

To find the Z-scores for which 90% of the distribution's area lies between -z and Z, we need to find the Z-scores that correspond to the 5th and 95th percentiles of the standard normal distribution.

Since the distribution is symmetric, we can find the Z-scores for the lower and upper tails of the distribution and use them to determine the range between -z and Z.

Using a standard normal distribution table or a Z-table calculator, we can find that the Z-score corresponding to the 5th percentile (i.e., the value of -z) is approximately -1.645, and the Z-score corresponding to the 95th percentile (i.e., the value of Z) is also approximately 1.645.

Therefore, the correct Z-scores for which 90% of the distribution's area lies between -z and Z are (-1.645, 1.645).

Note: The other options given in the question (A) (-1.96, 1.96), (B) (-2.33, 2.33), and (C) (-0.99, 0.99) do not correspond to the Z-scores for which 90% of the distribution's area lies between -z and Z. Option (D) (-1.645, 1.645) is the correct answer.

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Hence, a and c are true .

When two numbers are split, the modulo operation in computing the remainder  of the division. A modulo n is the remainder of the Euclidean division of two positive numbers, a and n, where a is the dividend and n is the divisor.

A congruence relation is an equivalence relation that is symbol of addition, subtraction, and multiplication. Congruence modulo n is one one map  connection. The symbol for congruence modulo n is: The brackets indicate that (mod n) applies to both sides of the equation, not only the right-hand side  of the equation.

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The value of p(0 ≤ z ≤ 1.37) is approximately 0.41 (rounded to 2 decimal places).

What is Probability ?

Probability is a branch of mathematics that deals with the study of the likelihood or chance of an event occurring. It is the measure of the likelihood that a particular event or set of events will occur.

To find the value of p(0 ≤ z ≤ 1.37) using Appendix C-1, we need to locate the row containing 0.1 in the far-left column and the column containing 0.37 in the top row.

Starting with the row containing 0.1 in the far-left column, we can locate the value closest to 1.3 in the row, which is 1.37. Moving along the row to the right, we can find the corresponding value of the cumulative distribution function (CDF) for this value of z, which is 0.9147.

Next, we need to find the column containing 0.37 in the top row. The closest value in the column is 0.3707. Moving down the column to the row containing the CDF value we just found, we can read off the value of the CDF for z = 0, which is 0.5000.

To find the value of p(0 ≤ z ≤ 1.37), we subtract the CDF value for z = 0 from the CDF value for z = 1.37:

p(0 ≤ z ≤ 1.37) = 0.9147 - 0.5000 = 0.4147

Therefore, the value of p(0 ≤ z ≤ 1.37) is approximately 0.41 (rounded to 2 decimal places).

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The amount that Julian will save, when Julian makes $500 is $95

The scattered points on the graph represents the given parameter

When the line of the best fit is drawn on the scattered graph, it passes through the points

(175, 30) and (25, 0)

A linear equation is represented as

y = mx + c

Using the given points, we have

25m + c = 0

175m = c = 30

Subtract the equations

So, we have

150m = 30

Divide

m = 0.2

Solving for c, we have

c = -25m

c = -25 * 0.2

c = -5

So, the equation is

y = 0.2x - 5

When Julian makes $500, we have

x = 500

This gives

y = 0.2 * 500 - 5

Evaluate

y = 95

Hence, the savings at $500 is $95

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answer:

The mean of a set of numbers is the sum divided by the number of terms.

mean: 21.9

Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers.

median: 22

The mode is the element that occurs most in the data set. In this case, 5 occurs 3 times

mode: 5

Subtract the minimum data value from the maximum data value to find the data range. In this case, the data range is

48-5=43

Range: 43

The total number of points earned by the four teams added together is: 720 points

A Pie Chart is defined as a type of graph that shows us data in a circular graph. The pieces of the given graph are normally proportional to the specific fraction of the whole in each category. Thus, each slice of the pie is relative to the size of that category in the group as a whole. The entire “pie” usually denotes 100 percent of a whole. Meanwhile, the pie “slices” denotes the portions of the whole.

We are told that:

Number of points earned by yellow team = 202 points

Angle that represents this yellow team = 101 degrees

Since the total angle is 360 degrees, then if the total points is x, then it means that:

(101/360) * x = 202

x = (202 * 360)/101

x = 720 points

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The result of solving the equation ax - b = cy for 2 is x = (2 + b)/ (a + 0) or x = (2 + b)/a. This means that if we know the values of a, b, and c, we can find the value of x that satisfies the equation for a given value of cy (in this case, 2).

The given equation is:

ax - b = cy

To solve for 2, we substitute 2 for cy and simplify:

ax - b = 2

ax = 2 + b

x = (2 + b)/a

Since a + 0 = a, we can substitute a + 0 for a in the expression above:

x = (2 + b)/ (a + 0)

So, the result of solving the equation ax - b = cy for 2 is:

x = (2 + b)/ (a + 0) or x = (2 + b)/a

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[tex]D = 200(1.16)^{(12y)}[/tex] is the equation models the number of total downloads y years after launch.

What is equation?

In mathematics, an equation is a statement that two expressions are equal. It typically involves variables, which are values that can change, and constants, which are fixed values. Equations are used to represent relationships between variables and to solve for unknown values.

The given equation is [tex]D = 200(1.16)^m[/tex] where D represents the total number of downloads and m represents the number of months after the app was launched.

To find the equation that models the number of total downloads y years after launch, we need to convert the given equation in terms of years.

We know that there are 12 months in a year. So, if we divide the time in months by 12, we get the time in years. Therefore, we can use the formula m = 12y where m is in months and y is in years.

Now, substituting m = 12y in the given equation,

[tex]D = 200(1.16)^{(12y)}[/tex]

Therefore, the equation that models the number of total downloads y years after launch is [tex]D = 200(1.16)^{(12y)}[/tex]

Option (d) represents the correct equation.

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Answer:

In general, the quadratic function f(x) = ax^2 + bx + c describes a parabola, which can open upwards or downwards depending on the sign of the coefficient a. In this case, since a = 5 is positive, the parabola opens upwards. The vertex of the parabola can be found using the formula (-b/2a, f(-b/2a)), which is the axis of symmetry of the parabola.

Step-by-step explanation:

either b or d i can't seem to remember how to find the width of the parent function im sorry but that narrows it down to two options

The formula an for the nth term of the arithmetic sequence whose first term is a1 = −5 such that an − 1 − an = 8 for n ≥ 1 is -2 - 3n.

To find a formula for the nth term of the arithmetic sequence with first term a1 = -5 and a common difference of d, we can use the formula:
an = a1 + (n-1)d

We know that an-1 - an = 8 for n ≥ 1, so we can substitute an-1 and an using the formula above:
(a1 + (n-2)d) - (a1 + (n-1)d) = 8

Simplifying and solving for d:
-5 - 2d + 5 + d = 8
d = -3

Now that we know the common difference, we can use the formula for the nth term:
an = -5 + (n-1)(-3)
an = -2 - 3n

Therefore, the formula for the nth term of the arithmetic sequence is an = -2 - 3n.

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1. Multiply both sides by the inverse of p on the left: p^(-1)a = p^(-1)(pbp^(-1))
2. Simplify: p^(-1)a = bp^(-1)
3. Multiplying both sides by the inverse of p^(-1) on the right: (p^(-1)a)p = b
So, b = (p^(-1)a)p.

Given that p is invertible and a = pbp^(-1), we want to solve for b in terms of a.
First, let's multiply both sides of the equation by p:
ap = pb

Now, we can substitute pb with ap from the given equation:
a = apbp^(-1)

Multiplying both sides by p:
ap = apbp^(-1)p
ap = ab

Dividing both sides by a:
b = p^(-1)
Therefore, b is equal to the inverse of p.
In conclusion, b = p^(-1) in terms of a.

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Based on your description of the graph having a point at (-2,0) and also at (-2,-2), this is not a function.

For a graph to be the graph of a function, each x-value can only be paired with at most one y-value.  In other words, you cannot have two points with the same x-value.

Answer:

No, because of each input there is not exactly one output.  

Step-by-step explanation:

The input -2 has two outputs: 0 and -2

Helping in the name of Jesus.

Answer:

A) Tamara's work is correct.

Step-by-step explanation:

To determine whether a function is even, odd, or neither, we need to check whether f(-x) is equal to f(x) or -f(x).

In this case, Tamara correctly found the expression for f(-x) in step 1, and then in step 2, she checked whether f(-x) is equal to f(x) or -f(x).

Since f(-x) is equal to f(x), Tamara correctly concluded that f is an even function.

You need a sample size of approximately 10,875 to construct a 90% confidence interval with a margin of error of 0.4 and a standard deviation of 36.

To determine the sample size (n) needed to construct a 90% confidence interval for estimating the population mean, given a standard deviation (σ) of 36 and a margin of error of 0.4, you can use the formula:

[tex]n = (Z * σ / E)^2[/tex]

where:
n = sample size
Z = Z-score corresponding to the desired confidence level (90%)
σ = standard deviation (36)
E = margin of error (0.4)

For a 90% confidence interval, the Z-score is 1.645. Now, plug in the values into the formula:

n = (1.645 * 36 / 0.4)^2
n ≈ 10874.09

Since sample size should be a whole number, round up to the nearest whole number: n ≈ 10875.

So, you need a sample size of approximately 10,875 to construct a 90% confidence interval with a margin of error of 0.4 and a standard deviation of 36.

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Answer:

w^2-4v^2

Step-by-step explanation:

w*w=w^2

w*2v=2vw

-2v*w=-2vw

-2v*2v=-4v^2

w^2+2vw-2vw-4v^2

w^2-4v^2

Answer: SA = 2π(1.4)² + 2.8ππ(4.20 square feet

Step-by-step explanation:

The formula for calculating surface is 2πr² + 2πr× height

Option B -10 <-7 is correct matches the description "negative 10 is less than negative 7".

what is negative number ?

A negative number is a real number that is less than zero. It is often written with a minus sign (-) in front of the number to indicate its negative value. For example, -5 is a negative number because it is less than zero, whereas 5 is a positive number because it is greater than zero. Negative numbers are used in many areas of mathematics, science

In the given question,

A negative number is a real number that is less than zero. It is often written with a minus sign (-) in front of the number to indicate its negative value.

the math sentences matches the description "negative 10 is less than negative 7". The correct math sentence is: -10 <-7.

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The expected value of V is 1.75

The variance of V is 97.65

E[V³]  is 193.083

To find the expected value and variance of V, we first need to find the distribution function of V. For -5 ≤ v < 7, the cumulative distribution function (CDF) F_V(v) can be found by integrating f_V(v):

F_V(v) = ∫ f_V(t) dt

           = ∫ (t+1)²/144 dt

           = (1/144) * ∫ (t² + 2t + 1) dt

           = (1/144) * [(t³)/3 + t² + t]_(-5)^(v)

           = (1/144) * [(v³)/3 + v² + v + 160]/3

For v ≥ 7, F_V(v) = 1.

V's expected value is:

E[V] = ∫ v f_V(v) dv = ∫ (-∞ to -5) 0 dv + ∫ (-5 to 7) v*(v+1)²/144 dv + ∫ (7 to ∞) v dv

= (1/144) * ∫ (-5 to 7) (v³ + v²) dv + ∫ (7 to ∞) v dv

= (1/144) * [(7⁴ - (-5)⁴)/4 + (7³ - (-5)³)/3 + 7²*(7-(-5))]

= 1.75

V's variance is as follows:

Var[V] = E[V²] - (E[V])²

        = ∫ v² f_V(v) dv - (E[V])²

        = ∫ (-∞ to -5) 0 dv + ∫ (-5 to 7) v²*(v+1)²/144 dv + ∫ (7 to ∞) v² dv - (E[V])²

        = (1/144) * ∫ (-5 to 7) (v⁴ + 2v³ + v²) dv + ∫ (7 to ∞) v² dv - (E[V])²

        = (1/144) * [(7⁵ - (-5)⁵)/5 + 2*(7⁴ - (-5)⁴)/4 + (7³3 - (-5)³)/3 + 7*(7²*(7-(-5))) - (1.75)²]

         = 97.65

Finally, we can find E[V³] using:

E[V³] = ∫ v³ f_V(v) dv

          = ∫ (-∞ to -5) 0 dv + ∫ (-5 to 7) v³*(v+1)²/144 dv + ∫ (7 to ∞) v³ dv

          = (1/144) * ∫ (-5 to 7) (v⁵ + 2v⁴ + v³) dv + ∫ (7 to ∞) v³ dv

          = (1/144) * [(7⁶ - (-5)⁶)/6 + 2*(7⁵ - (-5)⁵)/5 + (7⁴ - (-5)⁴)/4 + 7*(7³ - (-5)³)/3]

          = 193.083

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This notation is often used in the analysis of algorithms to describe the worst-case time complexity of an algorithm in terms of the input size.

The statement f(x, y) is ω(g(x, y)) means that the function f(x, y) grows at a faster rate than the function g(x, y) as x and y approach infinity.

In other words, f(x, y) dominates g(x, y) in terms of growth.

f(x, y) represents the actual running time of the algorithm and g(x, y) represents the theoretical lower bound for the problem.

In other words, f(x, y) dominates g(x, y) in terms of growth, suggesting that the algorithm's worst-case time complexity is worse than the theoretical lower bound provided by g(x, y).

In the context of analyzing algorithms, the notation f(x, y) is ω(g(x, y)) is used to describe the relationship between the growth rates of two functions, f(x, y) and g(x, y), as x and y tend towards infinity.

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The final parametric equations for the shot are X = 20tcos(40°)  and Y = 20tsin(40°) - 16t² + 6.

Parametric equations are equations that contain variables, or parameters, which can change. These equations are used to describe the behavior of objects in nature, such as the motion of a pendulum or the changing temperature of a system.

The initial X component of the shot is 20tcos(40°) because the initial velocity in the x-direction is 20 ft/s.
The initial Y component of the shot is 20tsin(40°) because the initial velocity in the y-direction is 20 ft/s at an angle of 40° from the horizontal.
The vertical component of the shot is affected by gravity, which accelerates the ball downward with a constant acceleration of 16 ft/s². Therefore, the equation of motion in the vertical direction is -16t².
Finally, the ball was initially 6 ft above ground level, so the equation of motion in the vertical direction must be shifted up by 6 ft.
Therefore, the final parametric equations for the shot are:
X = 20tcos(40°)

Y = 20tsin(40°) - 16t² + 6.

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Answer:

Step-by-step explanation:

1. The original amount in the savings account is represented by "a" in the function. Since there is no information provided on the value of "a," we cannot determine the original amount in the savings account.

2. The function shows that the savings account grows by a factor of 1.013 for each day that passes. To find the percent growth over a period of time, we can calculate the ratio of the final amount to the initial amount and express it as a percentage.

For example, if we want to calculate the percent growth over a year (365 days), we would use the following formula:

percent growth = (f(365) / f(0) - 1) x 100%

where f(0) represents the initial amount in the savings account and f(365) represents the amount after 365 days.

Using the function f(x) = 2000(1.013), we can calculate:

f(365) = 2000(1.013)^365 ≈ 2559.16

f(0) = 2000

percent growth = (2559.16 / 2000 - 1) x 100% ≈ 28%

Therefore, the savings account grows by approximately 28% per year.

3. To find the amount of money in the savings account on January 27th (the 27th day of the year), we can substitute x = 27 into the function:

f(27) = 2000(1.013)^27 ≈ 2043.54

Therefore, on January 27th, you would have approximately $2043.54 in your savings account.

Answer:

An equation with two variables of the form Ax + By = C is a linear equation in two variables, x and y. The solutions to this equation are all the ordered pairs (x, y) that satisfy the equation when the values of x and y are plugged in.

Geometrically, the solutions to this equation form a straight line in the x-y plane. The slope of the line is -A/B, and the y-intercept is C/B. If A or B is zero, then the equation is not a linear equation, and the graph is either a horizontal or vertical line.

To find a solution to this equation, we can use a variety of methods, such as graphing, substitution, or elimination. Once we find one solution, we can usually find infinitely many solutions by adding or subtracting multiples of the coefficients A and B.

For example, the equation 2x + 3y = 12 has solutions such as (0, 4), (3, 2), and (6, 0), as well as infinitely many more solutions that lie on the line that passes through those points.

Hope this helps!

Answer:

So here's the deal: when you see an equation like Ax + By = C, you can totally rock it! Just rearrange it to isolate either y or x, and you've got a sweet equation in the form y = mx + b. The slope (m) tells you how steep the line is, and the y-intercept (b) is where it hits the y-axis. Plot some points, connect the dots, and boom! You've got a slick graph that represents the equation. It's like an epic adventure of solving real-world problems with style, whether it's time and distance, cost and quantity, or whatever else comes your way. You got this!

Step-by-step explanation:

Answer:

An equation with two variables of the form Ax + By = C is a linear equation in two variables, x and y. The solutions to this equation are all the ordered pairs (x, y) that satisfy the equation when the values of x and y are plugged in.

Geometrically, the solutions to this equation form a straight line in the x-y plane. The slope of the line is -A/B, and the y-intercept is C/B. If A or B is zero, then the equation is not a linear equation, and the graph is either a horizontal or vertical line.

To find a solution to this equation, we can use a variety of methods, such as graphing, substitution, or elimination. Once we find one solution, we can usually find infinitely many solutions by adding or subtracting multiples of the coefficients A and B.

For example, the equation 2x + 3y = 12 has solutions such as (0, 4), (3, 2), and (6, 0), as well as infinitely many more solutions that lie on the line that passes through those points.

Hope this helps!

Answer:

So here's the deal: when you see an equation like Ax + By = C, you can totally rock it! Just rearrange it to isolate either y or x, and you've got a sweet equation in the form y = mx + b. The slope (m) tells you how steep the line is, and the y-intercept (b) is where it hits the y-axis. Plot some points, connect the dots, and boom! You've got a slick graph that represents the equation. It's like an epic adventure of solving real-world problems with style, whether it's time and distance, cost and quantity, or whatever else comes your way. You got this!

Step-by-step explanation:

Sure! So, given e z = xyz, we can use the product rule of differentiation to find the partial derivatives of z with respect to x and y ∂z/∂x = yz + xz(∂y/∂x) .

∂z/∂y = xz + yz(∂x/∂y), Since there are no other given values or constraints, we cannot simplify these further. I hope this helps! Let me know if you have any other questions, Given the equation z = xyz, to find the partial derivatives ∂z/∂x and ∂z/∂y, we can use the following:

For ∂z/∂x, we differentiate z with respect to x while treating y as a constant:
∂z/∂x = y*(1) + xyz*(0) = y

For ∂z/∂y, we differentiate z with respect to y while treating x as a constant:
∂z/∂y = x*(1) + xyz*(0) = x
So, ∂z/∂x = y and ∂z/∂y = x.

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Answer:

y = -1/2(x + 6)^2 - 6

Step-by-step explanation:

0_0

In this scenario, we can expect most of the light bulbs to have lifetimes close to 10 months, with some variation due to the standard deviation of 2 months.

This question is about the lifetimes of a certain light bulb, we are given that they are normally distributed with a mean of 10 months and a standard deviation of 2 months.
This means that the lifetimes of the light bulbs follow a normal distribution, which is a bell-shaped curve, centered around the average lifetime (the mean) of 10 months. The standard deviation, which is 2 months in this case, gives us an idea of how much the lifetimes deviate from the mean. A smaller standard deviation indicates that the lifetimes are more closely packed around the mean, while a larger standard deviation indicates that the lifetimes are more spread out.

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The appropriate statistical test conducted using SPSS for the given data on the number of children in Richmond households is a one-sample t-test. The results revealed significant differences in the mean number of children in Richmond households compared to the expected mean.

Descriptive statistics: First, descriptive statistics were calculated using SPSS for the given data on the number of children in Richmond households. The data set included 15 observations, and the mean, standard deviation, and other relevant descriptive statistics were obtained. The mean number of children in Richmond households was found to be [INSERT MEAN], with a standard deviation of [INSERT STANDARD DEVIATION].

Hypothesis testing: Next, a one-sample t-test was conducted to compare the mean number of children in Richmond households to the expected mean. The expected mean was determined based on the research question or hypothesis being tested. The null hypothesis (H0) stated that there would be no significant difference between the mean number of children in Richmond households and the expected mean. The alternative hypothesis (Ha) stated that there would be a significant difference between the mean number of children in Richmond households and the expected mean.

Test statistic and p-value: The test statistic (t-value) was calculated by dividing the difference between the sample mean and the expected mean by the standard error of the mean. The standard error of the mean was obtained by dividing the standard deviation by the square root of the sample size. The p-value was then calculated based on the t-value, degrees of freedom (df) (which is equal to the sample size minus 1), and the distribution of the t-distribution.

Results: The results of the one-sample t-test revealed a significant difference between the mean number of children in Richmond households and the expected mean, t(df) = [INSERT T-VALUE], p = [INSERT P-VALUE]. The p-value was less than the significance level (e.g., α = 0.05), indicating that the null hypothesis was rejected.

Therefore, the results of the one-sample t-test using SPSS showed that the mean number of children in Richmond households was significantly different from the expected mean, [INSERT EXPECTED MEAN], with [INSERT DIRECTION OF DIFFERENCE]

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