The speed of light can be measured by;
A. Time of planets rotation
B. Distance between objects in space
C. Mass of astronomical bodies

Answer:

She should bend her hips so her head is closer to the handlebars

Explanation:

Answer:

Yea its A

Explanation:

This question is incomplete, the complete question is;

An engineer is tasked with developing a model to study a cylindrical heat exchanger in a steam system. The prototype cylinder is 2.54 cm in diameter and the steam properties are: velocity = 30 m/s; density = 0.6 kg/m³; and absolute viscosity = 1.197 X 10⁻⁵ N-s/m², respectively. The model is going to be tested in a water tunnel where the water temperature is 20°C and the velocity is 3 m/s

a) what is the prototype Reynolds number, based on using the cylinder diameter as the characteristic length?

b) what should be the diameter of the model be to ensure dynamic similitude?

Answer:

a) the prototype Reynolds number is 38195.488

b) 0.01278 m or 1.278 cm should be the diameter of the model be to ensure dynamic similitude

Explanation:

Given that;

1 prototype ; d = 2.54 cm = 0.0254 m, Vp = 30 m/s, Sp = 0.6 kg/m³, Up = 1.197 × 10⁻⁵ N-s/m²

Model{ water at 20°C}; dm = ?, Vm = 3 m/s, Pm = 998.23 kg/m³, Um = 1.002 × 10⁻³ N-s/m²

a) what is the prototype Reynolds number,

to calculate prototype Reynolds number we use the expression;

(Re)p = SpVpdP / Up

we substitute our value

(Re)p =  (0.6 × 30 × 0.0254) / 1.197 × 10⁻⁵

(Re)p = 38195.488

Therefore the prototype Reynolds number is 38195.488

b)

what should be the diameter of the model be to ensure dynamic similitude?

i.e dm = ?

so dynamic similarity [ viscous flow]

(Re)m = (Re)p

[PmVmdm / Um] = [SpVpdP / Up]

we substitute

[998.23 × 3 × dm / 1.002 × 10⁻³] = (0.6 × 30 × 0.0254) / 1.197 × 10⁻⁵

2994.69dm / 1.002 × 10⁻³ = 38195.488

2994.69dm = 38.2718

dm = 38.2718 / 2994.69

dm = 0.01278 m or 1.278 cm

Therefore 0.01278 m or 1.278 cm should be the diameter of the model be to ensure dynamic similitude

Answer:

Provide more than one path for current flow. (answer option A)

Explanation:

When one connects resistors in parallel, one provides more than a single path for the current to flow. The current separates on each branch according to the resistance it experiences.

a). My estimate is 18.75 mph.

b). The average speed is 18.75 mph.

I nailed it.

Answer:

4.24nm

0.385eV

Explanation:

Maximum wavelength (λmax) :

λmax = ( hc) /Φ

h = plancks constant = 6.63 * 10^-34

c = speed of light = 3*10^8

1ev = 1.6 * 10^-19

Φ = 2.93eV = 2.93* (1.6*10^-19) = 4.688*10^-19

λmax = [(6.63 * 10^-34) * (3 * 10^8)] / 4.688*10^-19

λmax = 19.89 * 10^-26 / 4.688*10^-19

λmax = 4.242 * 10^-7 m

λmax= 4.24nm

B.)

E = hc / eλ eV

λ = 3.75nm = 3.75 * 10^-7m = 375 *10^-9

E = (6.63 * 10^-34) * (3 * 10^8) / (1.6 * 10^-19) * (375 * 10^-9)

E = 19.89 * 10^-26 / 600 * 10^-28

E = 0.03315 * 10^-26 + 28

E = 0.03315 * 10^2

E = 3.315 eV

Stopping potential : (3.315 eV - 2.93eV) = 0.385eV

Answer:

2.12m/s

Explanation:

Given parameters:

Force on trolley  = 1.5N

Mass of trolley  = 0.2kg

Unknown:

Velocity of the trolley  = ?

Solution:

To solve this problem, we first find the acceleration of the trolley;

          Force  = mass x acceleration

         Acceleration  = [tex]\frac{Force }{mass}[/tex]

Insert the parameters and solve;

          Acceleration  = [tex]\frac{1.5}{0.2}[/tex]   = 7.5m/s²

Now to find the acceleration;

  Initial velocity  = 0m/s

  v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

  Distance  = 30cm and this is 0.3m

     v² = 0² + 2(7.5)0.3  = 4.5

     v = √4.5 = 2.12m/s

Answer:

Resistance decreases the flow of current in a circuit.

EXPLANATION:

The resistance of an electrical circuit is defined as the opposition to the flow of current in that particular circuit.

From Ohm's law, we know that current flowing  through a wire I =

Here,V is the potential across the two ends of a conductor or wire, and R is the resistance of that wire.

Hence, more is the resistance, the less will be the current flow in the current.

Answer:

589.3 nm

Explanation:

The wavelength of a sodium light is 5893 A.

We need to find the wavelength in nm.

[tex]5893\ A=5893\times 10^{-10}\ m[/tex]

Also, [tex]1\ nm=10^{-9}\ m[/tex]

[tex]5893\ A=5893\times 10^{-9}\times 10^{-1}\ m\\\\=5893\times 10^{-1}\ nm\\\\=589.3\ nm[/tex]

So, the wavelength of sodium light is 589.3 nm.

Answer:

3. lost electrons.

Explanation:

An atom that has lost an electron is positively charged because the number of protons is now greater than the number of electrons in the atom.

If the number of protons and electrons are the same, the atom has no charge

If the protons > electrons, the atom becomes positively charged

If electrons > protons, the atom becomes negatively charged.

Atoms becomes charged by losing or gaining electrons.

Answer:

Liquid

Explanation:

A liquid will fill its container and are neither tightly packed like a solid nor very loosely packed like a gas.

Answer: Its Solid

Explanation:

Answer:

196200N

Explanation:

Fg=mg

Fg=?

m=20000

g=9.81

Fg= (20000kg)(9.81[tex]m/s^{2}[/tex])=196200N

PHYSICS

Mass = 10 kg

Force = 2 N

Acceleration = ____?

Answers :

[tex]f \: = m \times a[/tex]

2 = 10 × a

2 / 10 = a

0,2 m/s² = a ✅

Answer: B. 0 kg*m/s

Explanation:

Answer:

A

Explanation:

The line(A) goes throughout the entire picture. So therefore choice A would be it's length.

Answer:

Free points

Explanation:

Answer:

wdym??

Explanation:?

Answer:

c. 7.7 eV

Explanation:

The computation of the photon emitted is shown below:

Given that

From level 1 to level 3, the energy absorbed by electrons is 11.8eV

And, when from level 3 to level3, the energy released by electron is 4.1eV

So, from level 2 to level 1, the energy released is

= 11.8 - 4.1

= 7.7

= 7.7eV

Hence, the third option is correct

The same is to be considered

And, the other options are wrong

Answer:

Fₓ = maₓ

Fy = may

Explanation:

The Newton's Second Law tells us about the force. It says whenever an unbalanced force is applied to a body, an acceleration is produced in that body. The direction of this acceleration is in the direction of the force itself. Hence, the law can be written as:

F = ma

where,

F = Unbalanced force

m = mass of body

a = acceleration magnitude

We, can write two equations separately for x-direction and y-direction as follows:

Fₓ = maₓ

Fy = may

where,

Fₓ = x-component of unbalanced force

aₓ = x-component of acceleration

Fy = y-component of unbalanced force

ay = y-component of acceleration

Answer:

The answer is:

VA= 33 m/S

VB= 27.8 m/s

VC= 50 m/s

VD=66.7 m/s

VE=35.7 m/s

So, the Legs from the highest velocity to the lower are:

D - C - E - A - B

The explanation:

we are going to use the velocity formula:

Velocity = distance (m) / time (s)

So,

A) when D = 18 Km = 18000 m

and t = 9 min = 9*60 =540 s

So V = 18000m/ 540 S

      = 33 m/S

B) when D = 25 Km = 25000 m

and t = 15 min = 15 * 60 = 900 S

So V = 25000m / 900S

     = 27.8 m/s

C) when D = 24 Km = 24000 m

and t = 8 min = 8 * 60 = 480 s

So V = 24000m / 480s

     = 50 m/s

D) when D = 48 Km = 48000 m

and t = 12 min = 12 * 60 = 720 s

So V = 48000 m / 720s

       =66.7 m/s

E) when D = 15 km = 15000m

and t = 7 min = 7 * 60 = 420 s

So V = 15000m / 420s

      = 35.7 m/s

Answer:

(a) V₁ =  1.06 m/s

(b) V₂ = 4.24 m/s

(c) Q = 4.08 x 10⁻³ m³/s

Explanation:

(b)

The formula derived for Venturi tube can be used here:

P₁ - P₂ = (ρ/2)(V₂² - V₁²)

where,

P₁ - P₂ = Difference in Pressure = (2x 10⁴ Pa) - (1.25 x 10⁴ Pa) = 0.75 x 10⁴ Pa

ρ = Density of Oil = 890 kg/m³

V₂ = Velocity at Higher End = ?

V₁ = Velocity at Lower End = ?

Therefore,

0.75 x 10⁴ Pa = [(890kg/m³)/2](V₂² - V₁²)

V₂² - V₁² = (0.75 x 10⁴ Pa)/(445 kg/m³)

V₂² - V₁² = 16.85 m²/s²   ------------------- equation (1)

Now, we will use continuity equation:

A₁V₁ = A₂V₂

where,

A₁ = Lower End Area = πd₁²/4 = π(0.07 m)²/4 = 3.848 x 10⁻³ m²

A₂ = Higher End Area = πd₂²/4 = π(0.035 m)²/4 = 9.621 x 10⁻⁴ m²

Therefore,

(3.848 x 10⁻³ m²)V₁ = (9.621 x 10⁻⁴ m²)V₂

V₁ = (9.621 x 10⁻⁴ m²)V₂/(3.848 x 10⁻³ m²)

V₁ = 0.25 V₂   -------------------- equation (2)  

using this value in equation (1):

V₂² - (0.25 V₂)² = 16.85 m²/s²

0.9375 V₂² = 16.85 m²/s²

V₂² = (16.85 m²/s²)/0.9375

V₂ = √(17.97 m²/s²)

V₂ = 4.24 m/s

(a)

using the value of V₂ in equation (2):

V₁ = 0.25(4.24 m/s)

V₁ =  1.06 m/s

(c)

For fluid flow rate we use the following equation:

Flow Rate = Q = A₂V₂ = (9.621 x 10⁻⁴ m²)(4.24 m/s)

Q = 4.08 x 10⁻³ m³/s

The speed if the fluid increases as pressure decreases.

(a)  The speed of the flow in the lower section is 1.06 m/s

(b)  The speed of the flow in the higher section is  4.24 m/s

(c) The volume flow rate in the pipe [tex]\bold {4.08 x 10^-^3m^3/s}[/tex].

The relation pressure and volume in constricted pipe can be derived by the formula formula ,

[tex]\bold {P_1 - P_2 = (\rho /2)(V_2^2 - V_1^2)}[/tex]

Where,

P₁ - P₂ -Difference in Pressure = [tex]\bold { 0.75 x 10^4}[/tex]

[tex]\rho[/tex] - Density of Oil = 890 kg/m³

V₂ - Velocity at Higher End = ?

V₁ - Velocity at Lower End = ?

put the values in the formula,

[tex]\bold {0.75 x 10^4 Pa = \dfrac{(890kg/m^3)}{2(V_2^2 - V_1^2)}}\\\\\bold {V_2^2 - V_1^2 = \dfrac {0.75 x 10^4 Pa}{445 kg/m^3}}\\\\\bold {V_2^2 - V_1^2 = 16.85 m^2/s^2}[/tex]

The continuity equation,

[tex]\bold {A_1V_1 = A_2V_2}[/tex]

Where,

[tex]\bold {A_1 }[/tex] - Area of lower end = [tex]\bold {3.848 x 10^-^3m^2}[/tex]

[tex]\bold {A_2 }[/tex] - Area of higher end = [tex]\bold {9.621 x 10^-^4m^2}[/tex]

Put the value in the formula above,

[tex]\bold {(3.848 x 10^-^3m^2)V_1= (9.621 x 10^-^4m^2)V^2}\\\\\bold {V_1 = \dfrac {(9.621 x 10^-^4 m^2)V_2}{(3.848 x 10^-^3 m^2)}}\\\\\bold {V_1 = 0.25 \times V_2}[/tex]

Put the value of [tex]\bold {V_1}[/tex], we get

[tex]\bold {V_2= 4.24 m/s}[/tex]

Therefore,

[tex]\bold {V1 = 0.25 (4.24 m/s)}\\\\\bold {V_1 = 1.06 m/s}[/tex]

The flow rate

[tex]\bold {Q = A_2V_2}[/tex]

[tex]\bold {Q = (9.621 x 10^-^4 m^2)(4.24 m/s)}\\\\\bold {Q = 4.08 x 10^-^3m^3/s}[/tex]

Therefore, the flow rate of the oil in the pipe is [tex]\bold {4.08 x 10^-^3m^3/s}[/tex].

To know more about Bernoulli's equation, refer to the link:

https://brainly.com/question/5531068

Answer:

The peak value of the Magnetic field is 6.67 x 10⁻⁸ T

Explanation:

Given;

peak value of the electric-field, E₀ = 20 V/m

The peak of the magnetic field, B₀ = ?

The peak value of the magnetic field is given by;

B₀ = E₀/C

Where;

C is the speed of light = 3 x 10⁸ m/s

Substitute the givens and solve for B₀

B₀ = E₀ / C

B₀ = (20) / (3 x 10⁸)

B₀ = 6.67 x 10⁻⁸ T

Therefore, the peak value of the Magnetic field is 6.67 x 10⁻⁸ T

B₀ =

Answer:

c

Explanation:

1- First electrons are transferred.

2-The ions are formed

3-The ions are attracted to form the compound

Answer:

answer is c.........

Explanation:

Answer:

D. upright, same size as object, virtual

Explanation:

it is a plane mirror, it has no changes

The characteristics of the image produced by the object placed in front of a plane mirror will be upright, the same size as the object, and virtual.

The law of reflection states that when a ray of light reflects back from a surface the angle of incidence of light on a surface is equal to the angle of reflection.

The image produced by an object in front of a plane mirror will be upright, the same size as the object, and virtual.

learn more about the law of reflection

https://brainly.com/question/18772331

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Answer:

The end of the ramp is 38.416 m high

Explanation:

Horizontal Motion

When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

If the maximum horizontal distance is known, we can solve the above equation for h:

[tex]\displaystyle h=\frac {d^2g}{2v^2}[/tex]

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

[tex]\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}[/tex]

[tex]\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}[/tex]

h= 38.416 m

The end of the ramp is 38.416 m high

Answer:

The speed of the sound wave on the string is 545.78 m/s.

Explanation:

Given;

mass per unit length of the string, μ = 4.7 x 10⁻³ kg/m

tension of the string, T = 1400 N

The speed of the sound wave on the string is given by;

[tex]v = \sqrt{\frac{T}{\mu} }[/tex]

where;

v is the speed of the sound wave on the string

Substitute the given values and solve for speed,v,

[tex]v = \sqrt{\frac{T}{\mu} }\\\\v = \sqrt{\frac{1400}{4.7*10^{-3}} }\\\\v = \sqrt{297872.34}\\\\v = 545.78 \ m/s[/tex]

Therefore, the speed of the sound wave on the string is 545.78 m/s.

Answer:

O C. Light energy

Explanation:

it conducts energy in it and is an energy itself.