The radius of the front wheel of Paul's
bike is 56cm.
Paul goes for a cycle and travels
75.1km.
How many full revolutions did Paul's
front wheel complete?

Considering the differential equation 2x²y" + 3xy' + (2x - 1)y = 0. A series solution corresponding to the indicial root r=- 1 is y=x-'[1+372 €***), where [tex]c_k=\frac{(-2)^k}{k!(-1)*(2k-3)!}[/tex].

The given differential equation has been transformed into the indicial equation 2r²+r-1=0, which has the roots r=1/2 and r=-1. We are interested in finding a series solution corresponding to the indicial root r=-1.
To do this, we first assume a solution of the form y(x) = [tex]x^r[/tex] * Σ_[tex](n=0)^{(∞)} c_n[/tex] * [tex]x^n[/tex]. Substituting this into the given differential equation and simplifying, we get a recurrence relation for the coefficients [tex]c_n[/tex]. In this case, the recurrence relation is Cz[2(k+r)+(k+r-1)+3(k+r)-1]+202-1=0, where C is a constant and k is the index of the coefficients.
Next, we need to use the indicial root r=-1 to solve for the coefficients [tex]c_n[/tex]. Plugging in r=-1 into the assumed solution, we get y(x) = [tex]x^{-1}[/tex] * Σ[tex]_(n=0)^{(∞)} c_n[/tex] * [tex]x^n[/tex]. We can simplify this to y(x) = Σ_[tex](n=0)^{(∞)}[/tex] c_n * [tex]x^{(n-1)}[/tex]. Then, we can use the recurrence relation to solve for the coefficients.
In this case, the correct answer is [tex]c_k=\frac{(-2)^k}{k!(-1)*(2k-3)!}[/tex].

The complete question is:-

Consider the differential equation 2x²y" + 3xy' + (2x - 1)y = 0. The indicial equation is [tex]2r^2[/tex]+r-1=0. The recurrence relation is [tex]c_k{2(k+r)+(k+r-1)+3(k+r)-1]+2c_{k-1}=0[/tex].

A series solution corresponding to the indicial root r=- 1 is y=x-'[1+372 €***), where

Select the correct answer.

a. [tex]c_k=\frac{(-2)^k}{k!(-1).1.3...(2k-3)}[/tex]

b. [tex]c_k=\frac{-2^k}{k!.1.3...(2k-3)}[/tex]

c. [tex]c_k=\frac{(-2)^k}{k!(-1).1.3...(2k-1)}[/tex]

d. [tex]c_k=\frac{(-2)^k}{k!(-1)*(2k-3)!}[/tex]

e. [tex]c_k=\frac{(-2)^k}{k!(-1).1.3...(2k-5)}[/tex]

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Answer: £46.36.

Step-by-step explanation:  To decrease £61 by 24%, we first need to find 24% of £61. We can do this by multiplying £61 by 0.24: £61 * 0.24 = £14.64. Now, to decrease £61 by 24%, we subtract £14.64 from £61: £61 - £14.64 = £46.36.

So, if you decrease £61 by 24%, the result is £46.36.

(a) The joint probability mass function of X and Y is:

P(X=3,Y=3) = 1/16; P(X=2,Y=3) = 1/16; P(X=2,Y=2) = 2/16; P(X=2,Y=1) = 1/16

(b) The marginal probability mass functions of X and Y are:

P(X=0) = 6/16, P(X=1) = 5/16, P(X=2) = 4/16, P(X=3) = 1/16

(c) X and Y are not independent.

(d) E(X) = 1.25; Var(X) = 0.9375; E(Y) = 1.25; Var(Y) = 0.9375

(e) P(X=0 | Y=1) = 0.2

(a) To find the joint probability mass function of X and Y, we need to consider all possible outcomes of the first four coin tosses and calculate the probability of each combination of values for X and Y. Let H denote heads and T denote tails. Then the possible outcomes of the first four tosses and their corresponding values of X and Y are:

HHHT: X = 3, Y = 3

HHTH: X = 2, Y = 3

HTHH: X = 2, Y = 2

THHH: X = 2, Y = 1

HHTT: X = 2, Y = 2

HTHT: X = 1, Y = 3

HTTH: X = 1, Y = 2

THHT: X = 1, Y = 1

TTHH: X = 1, Y = 0

HTTT: X = 1, Y = 1

THTH: X = 0, Y = 3

TTHT: X = 0, Y = 2

TTTH: X = 0, Y = 1

TTTT: X = 0, Y = 0

The probability of each outcome can be calculated as (1/2)⁴ = 1/16, since each toss is equally likely to be heads or tails. Therefore, the joint probability mass function of X and Y is:

P(X=3,Y=3) = 1/16

P(X=2,Y=3) = 1/16

P(X=2,Y=2) = 2/16

P(X=2,Y=1) = 1/16

P(X=1,Y=3) = 1/16

P(X=1,Y=2) = 2/16

P(X=1,Y=1) = 1/16

P(X=1,Y=0) = 1/16

P(X=0,Y=3) = 1/16

P(X=0,Y=2) = 1/16

P(X=0,Y=1) = 2/16

P(X=0,Y=0) = 1/16

(b) The marginal probability mass functions of X and Y are:

P(X=x) = ∑y P(X=x, Y=y) for x = 0,1,2,3

P(Y=y) = ∑x P(X=x, Y=y) for y = 0,1,2,3

Using the joint probability mass function from part (a), we get:

P(X=0) = 6/16, P(X=1) = 5/16, P(X=2) = 4/16, P(X=3) = 1/16

P(Y=0) = 6/16, P(Y=1) = 5/16, P(Y=2) = 4/16, P(Y=3) = 1/16

(c) To check if X and Y are independent, we need to compare the joint probability mass function from part (a) to the product of the marginal probability mass functions:

P(X=x, Y=y) ≠ P(X=x) * P(Y=y) for some values of x and y

For example, we have:

P(X=2, Y=2) = 2/16 ≠ (4/16) * (4/16) = P(X=2) * P(Y=2)

Therefore, X and Y are not independent.

(d) The expected value of X is:

E(X) = ∑x x * P(X=x) = 0*(6/16) + 1*(5/16) + 2*(4/16) + 3*(1/16) = 1.25

The variance of X is:

Var(X) = [tex]E(X^2) - (E(X))^2[/tex]

[tex]= \sum x x^2 * P(X=x) - (E(X))^2 = 0^2*(6/16) + 1^2*(5/16) + 2^2*(4/16) + 3^2*(1/16) - 1.25^2 = 0.9375[/tex]

Similarly, the expected value and variance of Y are:

E(Y) = ∑y y * P(Y=y) = 0*(6/16) + 1*(5/16) + 2*(4/16) + 3*(1/16) = 1.25

Var(Y) = [tex]E(Y^2) - (E(Y))^2[/tex] = [tex]\sum y y^2 * P(Y=y) - (E(Y))^2 = 0^2*(6/16) + 1^2*(5/16) + 2^2*(4/16) + 3^2*(1/16) - 1.25^2 = 0.9375[/tex]

(e) If there is one head in the last three tosses, the conditional probability mass function of X is:

P(X=x | Y=1) = P(X=x, Y=1) / P(Y=1) for x = 0,1,2,3

From the joint probability mass function in part (a), we have:

P(X=0, Y=1) = 1/16, P(X=1, Y=1) = 1/16, P(X=2, Y=1) = 1/16, P(X=3, Y=1) = 2/16

P(Y=1) = 5/16

Using these values, we get:

P(X=0 | Y=1) = (1/16) / (5/16) = 0.2

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The interval the value of the function (f - g)(x) is negative is (-∞, 2]

A function is a rule or definition that maps an input variable unto an output such that each input has exactly one output.

The equations on the possible graphs in the question, obtained from a similar question posted online are;

f(x) = x - 3

g(x) = -0.5·x

(f - g)(x) = x - 3 - (-0.5·x) = 1.5·x - 3

(f - g)(x) = 1.5·x - 3

Therefore; The x-intercept of the function (f - g)(x) = 1.5·x - 3 is; (f - g)(x) = 0 1.5·x - 3

1.5·x - 3 = 0

1.5·x = 3

x = 3/1.5 = 2

x = 2

The y-intercept is the point where, x = 0, therefore;

(f - g)(0) = 1.5×0 - 3 = -3

The interval the function is negative is therefore;

The equations of the possible graphs of the function, obtained from a question posted online are;

f(x) = x - 3, g(x) = -0.5·x

The interval the function (f - g)(x) is negative is required

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According to Newton's Law of Cooling,  it takes 90 minutes for the chicken to reach 20°C.

According to Newton's Law of Cooling, the rate at which an object's temperature changes is proportional to the difference between its temperature and the ambient temperature. The formula for Newton's Law of Cooling is:

ΔT/Δt = k(T - Ta)

Where ΔT is the change in temperature, Δt is the change in time, k is a constant, T is the object's temperature, and Ta is the ambient temperature.

From the given information, we have:

ΔT1 = 10C - 0C = 10°C
Δt1 = 45 minutes
Ta = 23°C

Now, we want to find the time it takes for the chicken to reach 20°C:

ΔT2 = 20C - 0C = 20°C

Using the formula and the fact that k and Ta are constants, we can set up the following proportion:

(ΔT1/Δt1) / (ΔT2/Δt2) = 1

Solving for Δt2:

(10/45) / (20/Δt2) = 1

Cross-multiplying and solving for Δt2, we get:

Δt2 = 90 minutes

So, it takes 90 minutes for the chicken to reach 20°C.

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Answer:

-31 c + 13

Step-by-step explanation:

-13c+8-18c+5

combine like terms

-18c and -13c combined is -31c

8 + 5 = 13

-31 c + 13

Answer

-31c+13 is your answer (see explanation below!)

Step-by-step explanation:

1) Add the numbers:

[tex]-13c + 8 - 18c + 5\\-13c + 13 -18c\\[/tex]

2) Combine like terms:

[tex]-13c+13-18c\\-31c+13\\[/tex]

[tex]A: -31c+13[/tex]

Hope this helped you! Please mark me brainliest! Thanks! Have a great day! :)

Answer:

  see attached

Step-by-step explanation:

You want the empty cells of the given table filled in.

The differences between the first In values are ...

  15 -7 = 8

  21 -15 = 6

The corresponding differences between the Out values are ...

  32 -16 = 16

  44 -32 = 12

The ratios of Out differences to In differences are ...

  16/8 = 2

  12/6 = 2

These are constant, so we can conclude the relation is linear with a slope of m = 2.

We can find the y-intercept by ...

  b = y -mx

  b = 16 -2(7) = 2 . . . . . . using (x, y) = (7, 16) and m=2

Then the equation  of the output (y) in relation to the input (x) is ...

  y = mx +b

  y = 2x +2 . . . . . . . . . . . . . . table entry on 4th line from the bottom

Solving for x, we get ...

  y -2 = 2x

  (y -2)/2 = x

This tells us the input needed to give an output of y is (y -2)/2, the entry in the table on the 3rd line from the bottom.

We can use the equation for y when In is given:

And we can use the equation for x when Out is given:

The completed table is attached.

<95141404393>

The value returned by the call binary Search(values, target) is 5.

Let's perform a binary search on the given array:

The code segment provided is: int[] values = {1, 2, 3, 4, 5, 8, 8, 8}; int target = 8;

1. Initialize variables: low = 0, high = 7 (length of array - 1)
2. Calculate mid: mid = (low + high) / 2 = (0 + 7) / 2 = 3
3. Check if the target is equal to the middle element: values[3] = 4, which is not equal to 8
4. Since the target (8) is greater than the middle element (4), update low: low = mid + 1 = 3 + 1 = 4
5. Calculate mid again: mid = (low + high) / 2 = (4 + 7) / 2 = 5
6. Check if the target is equal to the middle element: values[5] = 8, which is equal to the target

As a result, the binary search function returns the index of the target, which is 5.

Therefore, the value returned by the call binary Search(values, target) is 5.

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Answer: 2 red balloons and 4 white balloons in each bunch

Step-by-step explanation:

divide 16/8 = 2 balloons in each bunch

divide 32/8 = 4 balloons in each bunch

Answer:

4

Step-by-step explanation:

Answer:

3(x - 1)

Step-by-step explanation:

Let x be the number.

3(x - 1)

Answer:

y= what u get after calculation

x = number that u think

so

y=3(x-1)

Each subfield of Z, which is the set of integers, contains the field of rational numbers (Q).

To show that each subfield of Z contains Q, we can start by understanding what a subfield is. A subfield of a field is a subset that is also a field, meaning it must satisfy certain properties such as closure under addition, subtraction, multiplication, and division (except for division by zero), among others.

In this case, Z is the set of integers, which includes positive integers, negative integers, and zero. Q, on the other hand, is the set of rational numbers, which includes all numbers that can be expressed as the quotient of two integers, where the denominator is not zero.

Now, let's consider any subfield of Z. Since it is a field, it must contain the integers, including positive integers, negative integers, and zero. Since all integers are rational numbers (they can be expressed as the quotient of themselves divided by 1), any subfield of Z must contain all integers, and therefore it must also contain Q, which is the set of rational numbers.

Therefore, we can conclude that each subfield of Z contains Q, as Q is a subset of Z and is also a field, satisfying the properties of closure under addition, subtraction, multiplication, and division (except for division by zero).

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Answer:

8x^(3/2)

Step-by-step explanation:

We can simplify the expression first:

2sqrt(x)4x^(-5/2)=8x^(-3/2)

Now we can rewrite this in the form kx^2:

8x^(=3/2)=8(x^(-3/2))(x^(5/2))/x^2

=8(x^2/x^3)(x^(1/2))/x^2

=8x^(-1/2)

therefore, 2sqrt(x)4x^(-5/2) is equivalent to 8x^(-1/2), which can be written in the form kx^2 as 8x^(3/2)

I hope this helps!

The iterated integral evaluates to approximately 37.45.

To evaluate the iterated integral ∫(from 0 to 3) ∫(from 0 to 9) y*cos(x) dy dx:

1. Start with the inner integral, which is with respect to y: ∫(from 0 to 9) y*cos(x) dy. Integrate y, giving (1/2)y^2*cos(x). Evaluate this from y=0 to y=9, resulting in (1/2)*81*cos(x).

2. Now, move to the outer integral, which is with respect to x: ∫(from 0 to 3) (1/2)*81*cos(x) dx. Integrate cos(x), giving 40.5*sin(x). Evaluate this from x=0 to x=3, resulting in 40.5*(sin(3) - sin(0)).

3. Finally, calculate the value: 40.5*(sin(3) - 0) ≈ 37.45.

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The single summation expression in terms of k is:

\sum_[tex]{i=1}^{{m}}[/tex]i(i+1)(i+2) = 2k + 10

What is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

We can approach this problem by first expanding the summation expressions on both sides of the equation:

On the left-hand side:

m k Σ m + 1 Σ = ∑[tex]{i=1}^{{m}}[/tex]i{m} i ∑{j=1}^{i+1} j

On the right-hand side:

k + 5 k = 6k

Now, we can combine the two summations on the left-hand side by first fixing the value of i in the inner summation and then summing over all possible values of i:

m k Σ m + 1 Σ = ∑[tex]{i=1}^{{m}}[/tex]i i ∑{j=1}^{i+1} j = ∑_[tex]{i=1}^{{m}}[/tex]i i \left(\frac{(i+1)(i+2)}{2}\right)

Simplifying this expression, we get:

m k Σ m + 1 Σ = \frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex]ii(i+1)(i+2)

Now, we can express the right-hand side of the equation as a summation in terms of k:

k + 5 k = 6k = \sum_{i=1}^{k+5} 1

Therefore, the original equation can be written as:

\frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex] i(i+1)(i+2) = \sum_{i=1}^{k+5} 1

Simplifying further, we get:

\frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex] i(i+1)(i+2) = k + 5

Therefore, the single summation expression in terms of k is:

\sum_[tex]{i=1}^{{m}}[/tex]i(i+1)(i+2) = 2k + 10.

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If your opponent goes first, you are guaranteed to win with 8 gems if

your opponent takes 1, 2, or 3 gems on their first turn.

In general, if there are n gems, you can guarantee a win if your opponent

takes n/2 or fewer gems on their first turn when you go second.

Let's consider the starting configuration of gems with 8 gems total.

If you go first, the maximum number of gems you can take on your first

turn is 4 (either 4 diamonds or 4 rubies or 2 of each).

If you take 4 diamonds, your opponent can take all 4 rubies, leaving you

with no choice but to take the remaining 4 diamonds on your next turn,

which means your opponent will take the last 4 rubies and win. Similarly,

if you take 4 rubies on your first turn, your opponent can take all 4

diamonds and win.

If you take 2 diamonds and 2 rubies on your first turn, your opponent can

mirror your move and take 2 diamonds and 2 rubies, leaving you with 2

diamonds and 2 rubies left. At this point, no matter what you do, your

opponent can take the remaining gems and win.

So, if you go first, there is no way to guarantee a win with 8 gems.

Now let's consider the case where your opponent goes first. If your

opponent takes 1, 2, or 3 gems on their first turn, you can mirror their

move and take the same number of gems, leaving 4, 5, or 6 gems left

respectively.

At this point, no matter what your opponent does, you can take enough

gems to ensure that you take the last gem and win. For example, if there

are 4 gems left, you can take 2 diamonds (or 2 rubies) to leave 2 gems,

and then take the remaining 2 gems on your next turn. Similarly, if there

are 5 gems left, you can take 1 diamond and 1 ruby to leave 3 gems, and

then take the remaining 3 gems on your next turn. And if there are 6

gems left, you can take 2 diamonds and 2 rubies to leave 2 gems, and

then take the remaining 2 gems on your next turn.

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Therefore, the area of the region inside the circle and outside the cardioid is. [tex]2\sqrt(3)[/tex].

To find the area of the region inside the circle and outside the cardioid, we need to integrate the difference between the areas of the circle and the cardioid over the interval where they intersect. The points of intersection are at theta = pi/6 and theta = 5pi/6, as given in the problem.

First, let's find the equation of the cardioid in Cartesian coordinates. We have r = 3 + 3sin(θ), so in Cartesian coordinates, this is:

[tex]x^2 + y^2[/tex]= [tex](3 + 3sin(θ)) ^2[/tex]

[tex]x^2 + y^2[/tex]= [tex]9 + 18sin(θ) + 9sin^2(θ)[/tex]

[tex](x^2 + y^2 - 9)[/tex] = [tex]18sin(θ) + 9sin^2(θ)[/tex]

Using the equation of the circle, r = 9sin(theta), we can rewrite sin(theta) as r/9:

([tex]x^2 + y^2 - 9) = 18(r/9) + 9(r/9)^2[/tex]

[tex]x^2 + y^2 = 3r + r^2/3[/tex]

Now we can set up the integral to find the area:

A = 1/2 ∫[tex](pi/6) ^{(5\pi/6)} [81sin^2(θ) - 9 - 18sin(θ) - 9sin^2(θ)] dθ[/tex]

[tex]A = 1/2 ∫(pi/6)^(5pi/6) [72sin^2(θ) - 9 - 18sin(θ)] dθ[/tex]

Since the region is symmetric about the vertical axis theta = pi/2, we can double this integral:

A = ∫[tex](pi/6)^(pi/2) [72sin^2(θ) - 9 - 18sin(θ)] dθ[/tex]

Now we can use the identity sin^2(θ) = 1/2(1 - cos(2θ)) to simplify the integral:

A = ∫[tex](\pi/6) ^(pi/2) [36(1-cos(2θ)) - 9 - 18sin(θ)] dθ[/tex]

A = ∫[tex](pi/6) ^(\pi/2) [-36cos(2θ) - sin(θ)] dθ[/tex]

Integrating, we get:

A = [-[tex]18sin(2θ) - cos(θ)] |_\pi/6^\pi/2[/tex]

[tex]A = [-18sin(2(\pi/2) - 2(\pi/6)) - cos(\pi/2) + cos(\pi/6)] - [-18sin(2(\pi/6)) - cos(\pi/6)][/tex]

[tex]A = [-18sin(\pi /3) - 0.5] - [-9\sqrt(3)/2 - sqrt(3)/2][/tex]

[tex]A = -18\sqrt(3)/2 + 4.5 + 9\sqrt(3)/2 - \sqrt(3)/2[/tex]

[tex]A = 4\sqrt(3)/2[/tex]

[tex]A = 2\sqrt(3)[/tex]

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Every minute, the number of bacteria decays by a factor of 16^(-60).

An exponential function has the definition presented as follows:

y = ab^x.

In which the parameters are given as follows:

The decay factor k of the exponential function is obtained as follows:

b = 1 - k

k = 1 - b.

The parameter b for the function in this problem is given as follows:

b = 15/16.

Hence the decay factor each second is obtained as follows:

k = 1 - 15/16

k = 16/16 - 15/16

k = 1/16.

Then the decay factor each minute is given as follows:

k = (1/16)^60

k = 16^(-60).

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Answer:

The equation of a circle with center (a,b) and radius r is given by:

(x - a)² + (y - b)² = r²

Comparing this with the given equation x² + y² = 196, we can see that a = 0, b = 0, and r² = 196. Therefore, the radius of the circle is:

r = sqrt(196) = 14

Hence, the radius of the circle is 14 units.

Answer:

B

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The general solution for the Cauchy-Euler equation is a linear combination of the two solutions:

[tex]y(t) = C_1 * t^{-9} + C_2 * t^2[/tex]

To find the general solution to the given Cauchy-Euler equation for t > 0, first, we'll rewrite the equation using the given terms:

[tex]t^2 \frac{d^2y}{dt^2}+ 8t(dy/dt) - 18y = 0[/tex]

Now, we'll use the substitution y(t) = t^m, where m is a constant, to transform the equation into a simpler form:

By using this substitution, we get:

[tex]dy/dt = m * t^{m-1}\\d^{2}y/dt^2= m * (m-1) * t^{m-2}[/tex]

Substitute these expressions back into the original Cauchy-Euler equation:

[tex]t^2 * m * {m-1} * t^{m-2}+ 8t * m * t^{m-1} - 18 * t^m = 0[/tex]

Simplify by dividing both sides by t^(m-2):

[tex]m * (m-1) + 8m - 18t^2 = 0[/tex]

Now, we have a characteristic equation in terms of m:

[tex]m^2 + 7m - 18 = 0[/tex]

Factoring this equation gives:

(m+9)(m-2) = 0

This yields two possible values for m: m1 = -9, m2 = 2

Therefore, the general solution for the Cauchy-Euler equation is a linear combination of the two solutions:

[tex]y(t) = C_1 * t^{-9} + C_2 * t^2[/tex]

Where C1 and C2 are constants determined by any initial conditions.

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The correct answer is (b) Analysis of variance.

The most appropriate test to determine if there is a difference in fatigue between three groups of subjects is the analysis of variance (ANOVA) test. ANOVA is a statistical method used to compare the means of three or more groups to determine if there are significant differences between them.

In this case, the three groups of subjects represent different levels of the independent variable (such as different treatments or conditions), and the dependent variable is fatigue. By performing an ANOVA test, we can determine if there is a significant difference in the mean fatigue scores between the three groups. If the ANOVA test shows that there is a significant difference, further post-hoc tests can be performed to determine which groups differ significantly from each other.

Therefore, the correct answer is (b) Analysis of variance.

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Answer:

14.1mm² (to 1 d.p)

Step-by-step explanation:

area of a circle = πr²

so therefore the area of a semicircle is πr²/2 (because a semicircle is half of a circle)

radius = 3mm

area = π×3²/2

=9/2π

=14.13716....

=14.1mm² (to 1 d.p)

The value of the definite integral ∫(4 - 4√(16 - x^2)) dx, as determined by the area under the graph of the integral from x = -4 to x = 4, is 8π.

To evaluate the definite integral ∫(4 - 4√(16 - x^2)) dx:

We will first graph the integrand and then find the area under the curve.

Step 1: Graph the integrand
The integrand function is f(x) = 4 - 4√(16 - x^2).

This represents a semicircle with a radius of 4 and centered at the origin (0, 4).

The function is transformed from the standard semicircle equation by subtracting 4 from the square root term.

Step 2: Determine the limits of integration
The given integral is a definite integral with limits -4 to 4.

This means that we will find the area under the curve of the function f(x) from x = -4 to x = 4.

Step 3: Calculate the area under the curve
Since the function represents a semicircle, we can find the area of the whole circle and then divide by 2.

The area of a circle is given by A = πr^2, where r is the radius. In our case, r = 4.

A = π(4^2) = 16π

Now, we'll divide the area by 2 to get the area of the semicircle.

Area of semicircle = (1/2) * 16π = 8π

Step 4: Determine the value of the definite integral
The value of the definite integral ∫(4 - 4√(16 - x^2)) dx, as determined by the area under the graph of the integral from x = -4 to x = 4, is 8π.

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Values the constant c are;

a) c = 2.16.

b) c = 0.57.

c) c = -1.17.

a) We need to find the value of c such that Φ(c) = 0.9838. Using a standard normal table or a calculator, we find that the z-score corresponding to a cumulative probability of 0.9838 is approximately 2.16. Therefore, c = 2.16.

b) We need to find the value of c such that P(0 ≤ Z ≤ c) = 0.291. Using a standard normal table or a calculator, we find that the z-score corresponding to a cumulative probability of 0.291 is approximately 0.57. Therefore, c = 0.57.

c) We need to find the value of c such that P(c ≤ Z) = 0.121. Using a standard normal table or a calculator, we find that the z-score corresponding to a cumulative probability of 0.121 is approximately -1.17. Therefore, c = -1.17.

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30 students needs to be added for the food to be enough for 75 days

A hostel contains 150 students

They have food that will last them for 90 days

If the food is supposed to last for 75 days, the number of students that will be added can be calculated as follows

150= 90

1= x

cross multiply

x= 150×90

x= 13,500

= 13500/75

= 180

180 students will be fed for 75 days

We initially had 150 students, subtract 150 from 180

180-150

= 30

Hence 30 students needs to be added so the food lasts for 75 days

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c1 and c2 are arbitrary constants, and x is the independent variable.

We first need to find the characteristic equation:

r² + 10r + 41 = 0

Now, we need to find the roots of this quadratic equation. Using the quadratic formula:

r = (-b ± √(b² - 4ac)) / 2a

Here, a = 1, b = 10, and c = 41. Plugging in these values:

r = (-10 ± √(10² - 4(1)(41))) / 2(1)

r = (-10 ± √(100 - 164)) / 2

Since the discriminant (b² - 4ac) is negative, the roots will be complex:

r = (-10 ± √(-64)) / 2

r = -5 ± 4i

Now that we have the complex roots, we can write the general solution as:

y(x) = c1 * e^(-5x) * cos(4x) + c2 * e^(-5x) * sin(4x)

Here, c1 and c2 are arbitrary constants, and x is the independent variable.

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In a circle with center O, chord KL is perpendicular to diameter GH. If KP=PL=18 and GH=36, what is the measure of arc GM?

Based on the mentioned informations and provided valus, the measure of arc of the circle GM is calculated out to be 18π.

Since KL is perpendicular to GH and GH is a diameter, KL is a chord that bisects the circle into two equal halves. Therefore, the arc GM is half the measure of the circle.

The measure of the circle can be found using the diameter GH, which is equal to 36. The formula for the circumference of a circle is C = πd, where d is the diameter. Therefore, the circumference of this circle is C = π(36) = 36π.

Since arc GM is half the measure of the circle, its measure can be found by dividing the circumference by 2.

arc GM = (1/2)C = (1/2)(36π) = 18π

Therefore, the measure of arc GM is 18π.

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