The polynomial p(x) = 5x^2 – 9x2 - 6x + 8 has a known factor of (x + 1).
Rewrite p(x) as a product of linear factors.

Answer:

[tex]y=-1[/tex]

Step-by-step explanation:

[tex]y-14=6(x-2.5)[/tex]

[tex]y-14=6(0-2.5)[/tex]

[tex]y-14=6(-2.5)[/tex]

[tex]y-14=-15[/tex]

[tex]y=-1[/tex]

Answer:

y = -6/5x+56/5

Step-by-step explanation:

Answer:

a + 12 = -6 , a = -18

Step-by-step explanation:

Hi there!

the first half of the statement says “the *sum* of a number a and 12, so we can write that as a+12. The second half of the statement says that the sum of both of those values is -6, meaning that a + 12 = -6. Knowing this, we can now solve. In order to isolate a, subtract 12 from both sides of the equation. You will be left with a = -18.

Hope this helps!

Answer:

[tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \frac{159}{10}[/tex]

General Formulas and Concepts:

Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                     [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                       [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Property [Splitting Integral]:                                                               [tex]\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle f(x) = \left \{ {{9x^9 ,\ 0 \leq x \leq 1} \atop {4x^3 ,\ 1 \leq x \leq 2}} \right.[/tex]

[tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \ ?[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Answer:

Step-by-step explanation:

[tex]\int\limits^1_0 {9x^9} \, dx +\int\limits^2_1 {4x^3} \, dx[/tex]

=[tex]\frac{9x^{10}}{10} |_0^1 + x^4|_1^2[/tex]

[tex]=\frac{9}{10}+2^4 -1 = 15\frac{9}{10}[/tex]

Answer:

Use a website called desmos and type in y=-3/4(x+4)-2

Step-by-step explanation:

1) isolate y by subtracting 2 on both sides

y=-3/4(x+4)-2

Answer:

Clue: two points : (0,-5)   ( 4 , -8)

Step-by-step explanation:

Look at the graph.

Answer:

1 is acute

2 is a right triangle

3 is obtuse

Step-by-step explanation:

A 90 degree angle will be written as a box in the corner. Any angle less than 90 is acute, and any angle more than 90 is obtuse.

Answer:

Correct answer: 2.25

Answer:

1) 4x^{5} y^{2} (5y+2xy-1)

2) Implied to have no solution based on given context.

Step-by-step explanation:

Problem 1:

1) Find the Greatest Common Factor (GCF).

[tex]GCF=4x^{5} y^{2}[/tex]

2) Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

[tex]4x^{5}y^{2} (\frac{20x^{5} y^{3} }{4x^{5}y^{2} } +\frac{8x^{6}y^{3} }{4x^{5} y^{2} } +\frac{-4x^{5} y^{2} }{4x^{5} y^{2} } )[/tex]

3) Simplify each term in parentheses.

[tex]4x^{5} y^{2} (5y+2xy-1)[/tex]

Problem 2:

From the way the problem is given, there is no solution.

Answer:

11, 12, 13

Step-by-step explanation:

let's put the first number of the three as a:

a; a+1; a+2

The sum of the first and the twice second is 35 means:

a + 2(a+1) = 35

a + 2a + 2 = 35

3a = 33

a=11

now that we know a, we just need to add 1 and 2 as they are consecutive:

11, 12, 13

Answer:

2,3,4,5,6 is the domain

4,6,8,10,12 is the range

Step-by-step explanation:

Answer:

The domain is {2,3,4,5,6} and the range is {4,6,8,10,12}.

Step-by-step explanation:

Answer:

x = Total meal cost

y = Total cost-plus tip

113% * x  =  y

The total cost curve shows the cost of total shipment from the different

cities.

Reasons:

The given parameters are;

The number of shipment per = From 550,000 to 600,000 per year

The given table is presented as follows;

[tex]\begin{tabular}{|l|c|c|c|}Location&Annual Fixed Costs&Variable Cost \\Denver&\$5,000,000&\$4.65 \\Santa Fe&\$4,200,000&\$6.25\\Salt Lake City&\$3,500,000&\$7.25\end{array}\right][/tex]

a. Required:

The plot total cost curve for the locations on a single graph.

Solution:

b. Required:

The city that provides the lowest overall cost.

Solution:

The two cities with the lowest overall costs are Denver and Salt Lake City.

Area under the curve for Denver;

(7557500 + 7790000) ÷ 2 × 50,000 = 383687500000

Area under the curve for Salt Lake City

(7487500 + 7850000) ÷ 2 × 50,000 = 383437500000

Therefore;

Learn more about total cost curves here:

https://brainly.com/question/4888738

[tex]-3 (-3 - n) - 4 = 3n + 5\\\\\implies 9+3n -4 = 3n+5\\\\\implies 5 +3n = 3n+5\\\\\text{The equation is true for all values of n.}[/tex]

Answer:

There are 55 rooms

Step-by-step explanation:

There are 165 beds in the hospital. Each room contains 3 beds. In order to find the number of beds per room, take the total number of beds and divide it by the number of rooms in each bed. 165/3=55. There are 55 rooms in the hospital, all containing 3 beds.

Hope this helps!

Answer:

C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection

Step-by-step explanation:

A. isn't correct because all four sides aren't congruent, only the pair of opposite sides are congruent. Sense only opposite side are congruent you can only reflect the opposite sides onto each other and not diagonally meaning B. and D. are incorrect leaving C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection as the correct answer

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

[tex]\%Percentage = \frac{450}{500}[/tex]

Divide 450 by 500

[tex]\%Percentage = 0.9[/tex]

Express as percentage

[tex]\%Percentage = 90\%[/tex]

Hence, the percentage of commuters that travel more than 45 minutes is 90%

Read more about histograms at:

https://brainly.com/question/2776232

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    y-(x-4)=0  

STEP

1

:

Equation of a Straight Line

1.1     Solve   y-x+4  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line  y-x+4  = 0 and calculate its properties

Step-by-step explanation:

Using the t-distribution, it is found that since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.

At the null hypothesis, it is tested if the average box of cereal does not contain more than 368 grams, that is:

[tex]H_0: \mu \leq 368[/tex]

At the alternative hypothesis, it is tested if it contains, that is:

[tex]H_1: \mu > 368[/tex]

We have the standard deviation for the sample, hence, the t-distribution is used to solve this question.

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

In this problem, the values of the parameters are: [tex]\overline{x} = 372.5, \mu = 368, s = 15, n = 25[/tex].

Hence, the value of the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{372.5 - 368}{\frac{15}{\sqrt{25}}}[/tex]

[tex]t = 1.5[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, with 25 -1 = 24 df, is of [tex]t^{\ast} = 1.71[/tex].

Since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.

You can learn more about the use of the t-distribution to test an hypothesis at https://brainly.com/question/13873630

Answer:

216

Step-by-step explanation:

Cube A volume

3*3*3=27

Cube B volume

6*6*6=216

Edge length of cube B=2(3)=6in

Volume:-

[tex]\\ \sf\longmapsto V=(6)^3[/tex]

[tex]\\ \sf\longmapsto V=6(6)(6)[/tex]

[tex]\\ \sf\longmapsto V=216in^3[/tex]

Answer:

non of these because you are a good friend and look at the house to you nanu you nanu to get the house ☺️ to get well and

Step-by-step explanation:

solution

here,

1 dollar = rs 72.45

or, 1/72.45 dollars= rs 1

or, rs 1 = 1/72.45 dollars

now,

rs 1449= 1449/72.45 dollars

or,rs1449= 20 dollars

therefore, 20 dollars can be exchanged for rs 1449

Answer:

Oook, quick setup: pick a cartesian plane, be [tex](0;y(t))[/tex]the position of the helicopter as time passes, and [tex](x(t);0)[/tex] your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need,  in general what you want is to move one end of the segment up, the other right, and stretch it.

That distance is easily found with the formula for the distance between two points in the plane, or [tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)}[/tex] (playing a bit with the squares). At this point we need to write down expressions for both [tex]x(t), y(t)[/tex] and find at what value of t we need to evaluate our distance.

For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form [tex]s=vt+s_0[/tex]

The equation for the runner becomes simply [tex]x(t)=10t[/tex], since you haven't moved until the heli is high enough.

The equation of the helicopter is [tex]y=25t+30[/tex] since the heli is 30ft above ground when you start running.

Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when [tex]60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s[/tex]. in this time, you are at  [tex]x(1.2)=10(1.2)=12ft[/tex] from the origin.

Plugging it in the distance formula you get: [tex]\sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft[/tex]