Answer:
moon by earth is 1.62/s and squre in mathematical terms and earth by moon is the same answer
Compared to the earth, which has a mass of 5.97 into 10 to the power of 24 kilograms, the moon has a mass of 7.35 into 10 to the power of 22 kilograms. The moon is 3.84 into 10 to the power 8 meters away from the earth, but this is from the center, where the earth cannot see it. We have to judge by the moon.
What is the gravitational force on the moon by the earth?The moon's mass divided by its orbital distance will determine the magnitude of both forces, which will be equal in strength but acting in opposite directions. It is commonplace.
This can be solved within the square as a whole, giving us a result of 19.85 into 10 to the power of 19 newtons. This force will be roughly equivalent to 1.99 into 10 and will have a magnitude of 20 newtons. This will turn out to be the solution to the issue.
The earth will be the moon, and both forces will be moving in the same direction. The force on the moon and the force on earth are the same.
Therefore, The moon's mass is 7.35 into 10 to the power 22, the earth's g square mass is 5.97 into 10 to the power 24, and the r value is 3.84 into 10 to the power 8. Moon by earth is 1.62/s.
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Define Continental Drift
Answer:
the gradual movement of the continents across the earth's surface through geological time.
Answer:
Continental drift is the hypothesis that the Earth's continents have moved over geologic time relatives to each other.
which term describes energy stored inside the nucleus of an atom?
a. light energy
b. nuclear energy
c. chemical energy
d. thermal energy
Answer:
here ya go.
Explanation:
I'm not very good and science or math, but I try my best.
What is the gravitational force between two identical 50,000 kg asteroids whose centers of mass are separated by 1000 m?
Answer:
The gravitational force between the two masses is 1.668575 × 10⁻¹¹ N
Explanation:
The given parameters are;
The mass of the two asteroids having gravitational attraction, are m₁ = m₂ = m = 50,000 kg
The separation distance between their centers, r = 1,000 m
The gravitational attraction force, F, between the two masses is given as follows;
[tex]F =G\dfrac{m_{1}m_{2}}{r^{2}}[/tex]
Where;
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
m₁ = m₂ = m
Substituting the values gives;
[tex]F =6.67430 \times 10^{-11} \times \dfrac{50,000 \times 50,000}{1000^{2}} = 1.668575 \times 10^{-7} \ N[/tex]
The gravitational force, F, between the two masses = 1.668575 × 10⁻¹¹ N.
The gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.
Given the data in the question
Since the asteroids are identical
Mass of the asteroids; [tex]m_1 = m_2 = 50000kg[/tex]Distance between the centers of the masses; [tex]r = 1000m[/tex]Gravitational force; [tex]F =\ ?[/tex]
To determine the gravitational force between two identical asteroids, we use the Newton's law of universal gravitation:
[tex]F = G\frac{m_1m_2}{r^2}[/tex]
Where [tex]m_1[/tex] is mass of object 1, [tex]m_2[/tex] is mass of object 2, r is the distance between centers of the masses and G is the Gravitational constant ( [tex]6.67408 * 10^{-11} m^3/kgs^2[/tex] )
We substitute our values into the equation
[tex]F = (6.67408 * 10^{-11} m^3/kgs^2) \frac{50000kg*50000kg}{(1000m)^2} \\\\F = \frac{0.166852kgm^3/s^2}{1000000m^2}\\\\ F = 1.67 * 10^{-7}kg.m/s^2\\\\F = 1.67 * 10^{-7}N[/tex]
Therefore, the gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.
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After 20 seconds, a 200-kg object increases its velocity from 15 m/s to 40 m/s. Determine the impulse applied to the object. (Also show your work so I can understand it better and ty)
Answer:
Imp_{1-2}=5000[kg*m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.
It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.
ΣPbefore = ΣPafter
P = momentum = m*v [kg*m/s]
In this way, we will construct the following equation.
[tex](m_{1}*v_{1})+ Imp_{1-2}=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 200 [kg]
v₁ = velocity of the object before the impulse = 15 [m/s]
v₂ = velocity of the object after the impulse = 40 [m/s]
Now replacing:
[tex](200*15) + Imp_{1-2} = (200*40)\\Imp_{1-2}=5000[kg*m/s][/tex]
How much net force is required to accelerate a 6 kg toy car initially at rest to a velocity of 2m/s in 4s?
Answer:
3N
Explanation:
Given parameters:
Mass of toy car = 6kg
Initial velocity = 0m/s
Final velocity = 2m/s
Time = 4s
Unknown:
Net force = ?
Solution:
The net force is given by;
Force = mass x acceleration;
Force = mass x [tex]\frac{v - u}{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
Now insert the parameters and solve;
Force = 6 x [tex]\frac{2 - 0}{4}[/tex] = 3N
Pls help, I have a test on this, with explanation.
Answer:
the answer is B
Explanation:
we assume that all of these springs have tha same k , the spring constant
elastic energy for the initial system = Ep1= [tex]\frac{kd^{2} }{2}[/tex]
for the new changed system , the spring constant = k1+k2 = k+k = 2k , but the displacement is also reduced to 0.5 d
so Ep2 = [tex]\frac{2k(0.5d)^{2} }{2} = \frac{kd^2}{4}[/tex]
so the new total Ep stored in the new system is 1/2Ep
hope it helps
An 856 kg drag race car accelerates from rest to 105 km/h in .934s. What change in momentum does the force produce? Answer in units of kg • m/s
Part 2: what average force is exerted on the car? Answer in N
Hello!
Topic: Dinamic
Value to calculate: Force
First, we have to calculate the aceleration, for that, lets aplicate the formula:
[tex]\boxed{a=\frac{V-Vi}{t} }[/tex]
How the final velocity is in km/h, we have to convert it on m/s, so:
m/s = km/h / 3,6
m/s = 105 / 3,6
m/s = 29,16
Then, lets replace formula according problem information:
[tex]a = \dfrac{29,16m/s-0m/s}{0,934s}[/tex]
[tex]a =31,22\ m/s^{2}[/tex]
Now, how we have the aceleration, lets applicate second law of newton for calculate the force produced:
[tex]\boxed{F=ma}[/tex]
Replace and resolve it:
F = 856 kg * 31,22 m/s^2
F = 26724,32 kg * m/s^2
Then the force is of 26724,32 kg * m/s^2
But how we know an 1 kg * m/s^2 = 1 N
Then the average of the force is of 26724,32 N
(1) The change in momentum of race car is 89880 kg-km/h.
(2) The average force exerted on the car is of 96231.26 N.
Given data:
The mass of race car is, m = 856 kg.
The initial speed of car is, u = 0 km/h.
The final speed of car is, v = 105 km/h.
The time interval is, t = 0.934 s.
1)
The change in the impact due to average force is known as momentum change. The expression for the change in momentum is given as follows,
[tex]\Delta P = m(v-u)[/tex]
Solving as,
[tex]\Delta P = 856 \times (105-0)\\\\\Delta P = 89880 \;\rm kg.km/h[/tex]
Thus, we can conclude that the change in momentum of race car is 89880 kg-km/h.
2)
Now, use the concept of impulse-momentum which says that the impulse is equal to change in momentum. Which means,
[tex]I = \Delta P[/tex]
And impulse is,
[tex]F \times t = \Delta P\\\\F = \dfrac{\Delta P}{t}[/tex]
Solving as,
[tex]F = \dfrac{89880}{0.934}\\\\F = 96231.26 \;\rm N[/tex]
Thus, we can conclude that the average force exerted on the car is of 96231.26 N.
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A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has a period of 0.5 seconds. Determine the length of the rope (the radius of the circle.
Answer:
r = 0.5 m
Explanation:
First we find the angular speed of the ball by using its period:
ω = θ/t
For the time period:
ω = angular speed = ?
θ = angular displacement = 2π rad
t = time period = 0.5 s
Therefore,
ω = 2π rad/0.5 s
ω = 12.56 rad/s
Now, for the radius:
v = rω
r = v/ω
where,
v = linear speed = 6.29 m/s
r = radius = ?
r = (6.29 m/s)/(12.56 rad/s)
r = 0.5 m
A balloon-powered car rolls across the floor at a speed of 0.711 m/s. How long does it take to cover 8.25 m?
Answer:
11.6 seconds
Explanation:
8.25/0.711=11.6
Equations of Motion 2D - Will mark the brainliest
A cannon on horizontal ground, at point C, is used to target a point T 25m behind a narrow wall. Unfortunately the cannon is damaged and can only fire at a 45 ∘ angle and at one speed.
a. If the cannonball leaves the cannon at u =35ms −1 at what distance d must the cannon be placed in front of the wall in order to hit the target, if the wall is ignored and the target is at the same height as the cannon
b. The wall is 15.0m high. Does the cannonball actually go over the wall and hit the target? If so, by how much?
Answer:
Using the range formula S = V^2 * sin 2 theta / g
So the cannonball should travel
S = 35^2 * sin 90 / 9.8 = 125 m
Then the cannon should be placed 100 m from the wall
H = Vy t - 1/2 g t^2 height of cannonball after time t
Vy = 35 * sin 45 = 24.7 m/s vertical speed of cannonball
Vx = 35 * cos 45 = 24.7 m/s
t = 100 m / 24,7 m/s = 4.04 sec time for cannonball to reach wall
H = Vy t - 1/2 g t^2 height of cannonball after time t
H = 24.7 * 4.04 - 1/2 * 9.8 * 4.04^2 = 19.8 m
19.8 m - 15 m = 4.8 m cannonball clears wall by 4.8 m
The projectile launch ratios allow to find the results on the cannonball launch questions are:
a) The canyon is at x = 100 m from the wall.
b) The bullet hits the wall at a height of 4.8 m above the height of the wall.
Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is gravity acceleration.
A) Indicate that the initial speed of the bullet is v = 35 m/s with an angle θ=45º, which is the distance from the wall. The target is 25 m behind the wall, in the attachment we have a scheme of the system.
Let's find the range that is the horizontal distance for which the height is zero.
[tex]R = \frac{v_p^2 \ sin \ 2\theta}{g}[/tex]
Let's calculate.
R = [tex]\frac{35^2 \ sin ( 2 45(}{9.8}[/tex]
R = 125 m
Therefore the canonl must be 100 m from the wall.
B) The height of the wall is y = 15m, the blah manages to pass it and by how much.
We use trigonometry to find the components of velocity.
v₀ₓ = v₀ cos θ
[tex]v_{oy}[/tex] = v₀ sin θ
v₀ₓ = 34 cos 45 = 24.7 m / s
[tex]v_{oy}[/tex] = vo sin 45 = 24.7 m / s
Let's find the time it takes for the cannonball to travel the x = 100 m
[tex]v_x = \frac{x}{t} \\ t = \frac{x}{v_x}[/tex]
t = [tex]\frac{100}{35 \ cos 45 }[/tex]
t = 4.04 s
Let's find the height for this time.
y = [tex]v_[oy}[/tex] t - ½ g t²
Let's calculate
y = 24.7 4.04 - ½ 9.8 4.04²
y = 19.8 m
This height is greater than the height of the wall h = 15m, therefore the cannoball passes the wall, by a difference in height.
Δy = y -h
Δy = 19.8-15
Δy = 4.8 m
In conclusion, using the projectile launch ratios we can find the results on the cannonball launch questions are:
a) The canyon is at x = 100 m from the wall.
b) The cannonball hits the wall at a height of 4.8m above the height of the wall.
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what causes the air to move?
Answer:
Movement of air caused by temperature or pressure differences is wind.
Explanation:
This is due to the rotation of the Earth beneath the moving air, which causes an apparent deflection of the wind to the right in the northern hemisphere, and left in the southern hemisphere.
Answer:
Air moves because of wind
Explanation:
Air moves due to a difference of air pressure which can be caused by different temperatures. Air pressure is the push caused by the particles in the air. Hope this helps
Katie claims that steel is a homogeneous mixture, even though it looks like a
pure substance. Which statement, if true, would support her claim?
A. Steel contains only iron atoms.
B. Steel is made from iron atoms with clumps of carbon atoms
mixed in.
C. Steel contains carbon and iron atoms, evenly mixed.
D. Steel is made of different compounds distributed unevenly.
Answer:
D. Steel is made of different compounds distributed unevenly.
Explanation:
The statement that will support her claim that steel is a homogenous mixture is that steel is made up of different compounds distributed unevenly.
Steel is an alloy of carbon and iron in its composition. Alloys are classified as mixtures. Their constituent reacts differently to changed medium. The iron in steel does not chemically bond with the carbon.The true statement according to Katie's claim is Steel is made from iron atoms with clumps of carbon atoms mixed in. (option b)
Steel is an alloy composed mainly of iron and carbon, along with other elements in smaller quantities. An alloy is a type of homogeneous mixture where two or more substances are combined at the atomic or molecular level. In the case of steel, it is made by mixing iron atoms with clumps of carbon atoms, and possibly other elements, throughout the material. This means that the carbon and iron atoms are evenly distributed and thoroughly mixed, creating a uniform composition throughout the steel.
Option B is the statement that would support Katie's claim. It correctly describes that steel is made from iron atoms with clumps of carbon atoms mixed in, forming a homogeneous mixture despite its pure-looking appearance.
So, the correct option is (b).
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plz. help ) An auto accelerates forward from 7.0 m/s at a uniform
0.71 m/s?. It travels a distance of 1033 m while
accelerating
(a) How fast is the auto moving just as it is traveled
the 1033 m?
(b) How many seconds did it take to travel the 1033 m?
Answer:
The auto is moving at 38.9 m/s
The auto took 45 seconds to travel the 1033 m
Explanation:
Constant Accelerated Motion
it's a type of motion in which the velocity of an object changes uniformly in time.
The relationship between initial and final speeds is calculated by the equation:
[tex]v_f=v_o+at\qquad\qquad [1][/tex]
Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.
Another useful equation allows us to calculate the distance x traveled by the object:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2][/tex]
(a)
Solving [1] for t and substituting into [2] we find the equation:
[tex]v_f^2=v_o^2+2ax[/tex]
This last equation will be used to solve the first part of the problem which gives the initial speed of vo=7 m/s, the uniform acceleration as a=0.71 m/s^2 and the distance traveled as x=1033 m, thus substituting:
[tex]v_f^2=7^2+2(0.71)(1033)[/tex]
[tex]v_f^2=49+1466.86=1515.86[/tex]
Thus:
[tex]v_f=\sqrt{1515.86}=38.9[/tex]
[tex]v_f=38.9 m/s[/tex]
The auto is moving at 38.9 m/s
(b)
To calculate the time, we solve [1] for t:
[tex]\displaystyle t=\frac{v_f-v_o}{a}[/tex]
[tex]\displaystyle t=\frac{38.9-7}{0.71}=45[/tex]
The auto took 45 seconds to travel the 1033 m
What is usually true about the relationship between the speed mechanical waves travel and the temperature of the medium?
Write a letter to a Friend congratulating her / him for her excellent result in annual examination. class 5 the
Answer:
ok will do that
Explanation:
A 30kg dog runs at a speed of 15 m/s. What is the dog's Kinetic energy?
What do car manufacturers do to reduce the fluid friction acting on a car
Answer:
The fluid friction or drag can be reduced are minimised by giving special shape called streamlined shape to the objects which Move through fluids like air or water
Answer:
ggggggggggggggggggggggggg
what is the significance of second law of thermodynamics
Answer: Second law of thermodynamics is very important because it talks about entropy and 'entropy dictates whether or not a process or a reaction is going to be spontaneous'.
Explanation:
Which type of heating system includes fans to circulate warm air?
(DIsclaimer: Unless you have an explanation on how you got your answer, don't bother awnesering.)
A. Radiant heating
B. Electric baseboard heating
C. Forced-air heating
D. Hot water heating
Answer:
C.Forced air
Explanation:
HVAC system
"By far the most common HVAC system in modern North American homes is the forced-air system that uses a furnace with a blower fan that delivers warmed air to the various rooms of the home through a network of ducts."
So can you please mark me brainliest?
What is the best way to dress for an outdoor trip in cold weather?
A. Wear several thin layers and a waterproof top layer.
B. Wear two layers of heavy clothing and a waterproof jacket.
C. Wear dark colors for insulation.
D. Wear only cotton clothing.
Answer:
A: wear several thin layers and a waterproof top layer
Explanation:
The most common cause of hypothermia is getting wet. Wet clothes combined with wind can pull heat away from the body very quickly. Wool is a good insulator even when it is wet, but wet cotton will bolster heat loss. When dressing for cold weather, put on several thin layers, rather than one or two heavy ones, and top with windproof and waterproof outer layers.
The best way to dress for an outdoor trip in cold weather is to wear several thin layers and a waterproof top layer, the correct option is A.
What is insulation?Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.
For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.
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The table shows the diameters of four different types of electrical wire. If the
resistance of the four wires is ranked from highest to lowest, how does the
resistance of a wire used to power clothes dryers rank?
Resistance of a wire used to power clothes dryers rank comes out to be Third. Therefore the correct answer is D.
What is resistance?
Resistance is the obstruction of electrons in an electrically conducting material.
The mathematical relation for variation in resistance with length is given by
R = ρ*L/A
where r is resistance
ρ is the resistivity constant for
L is the length of the wire
A is an area of the cross-section for the wire
From the above relation that resistance is inversely proportional to the area of the wire keeping other parameters constant.
Resistance of a wire used to power clothes dryers rank comes out to be Third. Therefore the correct answer is D.
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Determine the momentum of a 25kg freshman football player moving southward at 2m/s.
Answer:
50 kg*m/s southward
Explanation:
p=mv
=25kg(2m/s)
=50 kg*m/s
If your problem 50 joules of work lifting a 10 - box from to a shelf how high is the segregation
Answer:
5m
Explanation:
Given parameters:
Work done in lifting the box = 50J
Force applied = 10N
Unknown:
Height of lifting the box = ?
Solution:
Work done is the produce of force and distance;
Work done = Force x distance
Now to find the height;
Work done = Force x height;
50 = 10 x h
h = 5m
An underwater mountain system formed by diverging oceanic plates is______
Mid-Ocean Ridges
Mountain Formation
Boundary Type That Create Mountain
Divergent Boundary
Answer:
Mid-Ocean Ridges
Explanation:
The mid-ocean ridges is an underwater mountain system formed by diverging oceanic plates.
This mid - ocean ridge is one of the prominent land mass on the earth surface. At a diverging center, two tectonic plates are pulling apart from one another. This creates a space which allows for magma to rise up. The magma then crystallize to form an extensive ridge network known as the mid - oceanic ridge. The continental expression of the ridge can only be found in IcelandAndy took a bus and then walked from his home to downtown. For the
first 1.6 hour, the bus drove at an average speed of 15 km/h. For the
next 0.4 hours, he walked at an average speed of 4.5 km/h. What was
the average speed for the whole journey?
Answer:
Av = 12.9 [km/h]
Explanation:
We must remember that the average speed is defined as the relationship between the space traveled over a certain time.
[tex]Av = x/t[/tex]
where:
Av = average speed [km/h]
x = distance [km]
t = time [hr]
For when he was on the bus
The distance can be calculated by clearing the equation, for the term of the distance
[tex]x_{1}= A_{v}*t\\x_{1}= 15*1.6\\x_{1}=24[km][/tex]
For when Andy was walking
[tex]x_{2}=A_{v}*t\\x_{2}=4.5*0.4\\x_{2}=1.8 [km][/tex]
Now the total time is the sum of 1.6 + 0.4 = 2 [hr], and the total distance is the sum of the distances calculated above.
[tex]x = 24 + 1.8\\x = 25.8 [km][/tex]
The average speed is calculated using the ratio of space to time.
[tex]Av = 25.8/2\\Av = 12.9 [km/h][/tex]
Which of the following concerning thermal energy flow be correct?
Heat would flow from a hot cup of coffee to a room temperature table.
Heat would flow from a cold glass of lemonade to your hand.
Heat would flow from an ice cube to your hand.
Heat would flow from your hand to a hot cup of coffee.
Answer:
Heat would flow from a hot cup of coffee to a room temperature table.
Explanation:
Thermal energy will flow from a hot cup of coffee to a room temperature table.
Heat is a form of thermal energy which is the average kinetic energy of the particles of system.
Typically heat flows from a place system at high temperature to one with a low temperature. Heat never flows from a cold to a hot bodyHeat moves from a hot to a cold body in a system.A small first-aid kit is dropped by a rock climber who is descending steadily at -1.25 m/s. After 2.5 seconds, what is the velocity of the first aid kit and how far is the kit below the climber?
A shopper walks westward 2.8 meters in the first 5 minutes and then eastward 9.2 meters in the next 10 minutes. What is the shopper's total travel distance?
Answer:
12m
Explanation:
Given parameters:
Distance walked westward = 2.8m
Time of travel = 5min
Distance walked eastward = 9.2m
Time of travel = 10min
Unknown:
The total shopper's travel distance = ?
Solution:
Total distance traveled is the sum of the length of path covered by a body. It is a scalar quantity.
Total distance = distance walked westward + distance walked eastward
Total distance = 2.8m + 9.2m = 12m
4. A car, initially traveling east with a speed of
5.0 m/s, is accelerated uniformly at 2.0 m/s2 east for
10 s along a straight line. During this 10 s
interval the car travels a total distance of
A. 50 m
B. 60 m
C. 100 m
✓ D. 150 m
Answer:
150 m
Explanation:
Given,
u=5m/s
a=2m/s2
t=10s
v=?
s=?
Now,
v=u+at
=5+2×10
=5+20
=25m/s
So,
s=u+v/2×t
=5+25/2×10
=30/2×10
=15×10
=150m
An owl has a mass of 4.00 kg. It dives to catch a mouse, losing 800.00 J of its GPE. What was the starting height of the owl, in meters?
Answer:
height =20m
Explanation:
gpe=mgh
800=4×10×x
40x=800
x=20