The graph represents data from an experiment.



Complete the sentence by selecting the correct distribution type from the drop-down menu.

The distribution of the experiment data is
Choose a: normal b: uniform c: skewed right d: skewed left
.

Answer:

B is the answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

5.

26 red cards in a 52-card deck so 3 red cards combo = 26*25*24 = 15600

6.

4 aces in a deck so 3 aces = 4*3*2 = 24

7.

12 face cards in a deck so 3 face cards = 12*11*10 = 1320

8.

13 hearts in a deck so 3 hearts = 13*12*11 = 1716

9.

4 kinds in a deck: spade, heart, diamond and club so 3 of one kind = 4*1716

= 6864

Answer:

Step-by-step explanation:

5. half deck are red; 2nd card is 1 less n 3rd card 2 less: 26x25x24 = 15600

6. 4 aces total: 4x3x2 = 24

7. 3 face cards per suit; 12 total: 12*11*10 = 1320

8. 13 heart cards: 13x12x11 = 1716

9. 4 suits: 1716x4 = 6864

Answer: feugfberuyvfeygcreuyug

Step-by-step hththrhfhr

Answer:

9/13 should be the answer

Explanation:

does not have a sister & has a brother / does not have a sister & has a brother + does not have a sister & does not have a brother =

9 / (9 + 4) = 9 / 13

Answer:

das

Step-by-step explanation:

adsasc

Answer:

perimeter = 25.62 units

Step-by-step explanation:

Let the quadrilateral be ABCD

A = (1, 5), B = (6, 5), C= (1, 11) , D = (6, 11)

To find the perimeter we need to add the lengths of sides AB , BC, CD, and AD.

Lets find the length of all sides using distance formula;

[tex]distance = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

[tex]AB = \sqrt{(1-6)^2+(5-5)^2} = \sqrt{25} = 5units\\\\BC= \sqrt{(6-1)^2+(5-11)^2} = \sqrt{25+36} =\sqrt{61} units\\\\CD=\sqrt{(1-6)^2 + (11-11)^2} = \sqrt{25} = 5units\\\\AD = \sqrt{(1-6)^2+(5-11)^2} = \sqrt{25+36} = \sqrt{61}units[/tex]

Perimeter = AB + BC + CD + AD

               [tex]=10 + 2\sqrt{61} units[/tex] = 25.62 units

Answer:

[tex]S_{15}= 50[/tex]

Step-by-step explanation:

Given

[tex]a_7 = \frac{14}{3}[/tex]

[tex]d = -\frac{4}{3}[/tex]

[tex]n = 15[/tex]

Required

The sum of n terms

First, we calculate the first term using:

[tex]a_n = a + (n - 1)d[/tex]

Let [tex]n = 7[/tex]

So, we have:

[tex]a_7 = a + (7 - 1)d[/tex]

[tex]a_7 = a + 6d[/tex]

Substitute [tex]a_7 = \frac{14}{3}[/tex] and [tex]d = -\frac{4}{3}[/tex]

[tex]\frac{14}{3} = a + 6*\frac{-4}{3}[/tex]

[tex]\frac{14}{3} = a -8[/tex]

Collect like terms

[tex]a =\frac{14}{3} +8[/tex]

Take LCM and solve

[tex]a =\frac{14+24}{3}[/tex]

[tex]a =\frac{38}{3}[/tex]

The sum of n terms is then calculated as:

[tex]S_n = \frac{n}{2}(2a + (n - 1)d)[/tex]

Where: [tex]n = 15[/tex]

So, we have:

[tex]S_n = \frac{15}{2}(2*\frac{38}{3} + (15 - 1)*\frac{-4}{3})[/tex]

[tex]S_n = \frac{15}{2}(2*\frac{38}{3} + 14 *\frac{-4}{3})[/tex]

[tex]S_n = \frac{15}{2}(2*\frac{38}{3} - 14 *\frac{4}{3})[/tex]

[tex]S_n = \frac{15}{2}(\frac{2*38}{3} - \frac{14 *4}{3})[/tex]

Take LCM

[tex]S_n = \frac{15}{2}(\frac{2*38-14 *4}{3})[/tex]

[tex]S_n = \frac{15}{2}(\frac{20}{3})[/tex]

Open bracket

[tex]S_n = \frac{15*20}{2*3}[/tex]

[tex]S_n = \frac{300}{6}[/tex]

[tex]S_n = 50[/tex]

Hence,

[tex]S_{15}= 50[/tex]

Answer:

L = 3 + x

W = x

A = L x W

130 = 3 +( x × x)

B. X2 + 3 = 130

The equation that can be used to solve for x is;

x(x + 3) = 130

We are told that area of a rectangle is;

A = 130 mm².

We are told that length is 3 mm greater than its width.

Now, if the width is x, then

Length = x + 3

Formula for area of a rectangle is;

A = length * width

Thus;

(x + 3)x = 130

x² + 3x = 130

Read more about area of a rectangle at;https://brainly.com/question/13048427

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of  lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

[tex]z_1 = \dfrac{X-\mu}{\sigma}[/tex]

[tex]-1.88 = \dfrac{X-3570}{500}[/tex]

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth   that differentiates the babies that needed special treatment from those that do not

Answer:

I believe the answer is D

Step-by-step explanation:

Mars is approximately 940 times farther away from Earth than the Moon.

In mathematics, divides left-hand operands into right-hand operands in the division operation.

Mars is on average 2.25 x 10⁸ miles away from Earth.

The moon is on average 2.388 x 10⁵ miles away from Earth.

To calculate the answer, we need to divide the distance from Mars to Earth by the distance from the Moon to Earth. This gives us:

2.25 x 10⁸ miles / 2.388 x 10⁵ miles = 942.42

Rounded to the nearest whole number, this means that Mars is approximately 940 times farther away from Earth than the Moon is.

Therefore, the answer is D) 940 times.

To learn more about the division operation click here :

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Answer:

"Variable cost" is the appropriate answer.

Step by-step explanation:

Let an equation,

⇒ [tex]y=a+bx[/tex]

here,

or,

We can say that, "y" is a dependent variable as well as "x" is an independent variable.

Thus the independent variable is Variable cost.

Answer: 80%

Step-by-step explanation:

Hence, if the numerator is decreased by 40% and the denominator is decreased by 25%, the original fraction is decreased by 80 percent.

Answer:

the common difference is 10

Answer:

D 5pi/2

Step-by-step explanation:

Found the circumference then quartered. Can I have brainiest I need one more to upgrade.

Answer:

Step-by-step explanation:

13 - 6 = 6 - 1

7 = 5  (FALSE)

-----------------------------

6 - 5 = 7 - 6

1 = 1   (TRUE)

------------------------------

8 - 4 = 11 - 8

4 = 3  (FALSE)

Answer:

42.39 ft²

Step-by-step explanation:

area of sector= 3/8 × 3.14 × 6²

= 42.39 ft²

The area of the sector is 42.39 ft²

Given that, a sector of a circle has a diameter of 12 feet and an angle of 3pi/4 radians, we need to find the area of the sector,

Area of the sector = θ/360° / π·radius²

area of sector= 3/8 × 3.14 × 6²

= 42.39 ft²

Hence, the  area of the sector is 42.39 ft²

Learn more about the sector of the circle, click;

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Answer:

r = 1,248 in

Step-by-step explanation:

v(c) = 12 in³

The surface area of a right cylinder is:

Area of the base and top  + lateral area

S(a)  =  2*π*r²  + 2*π*r*h   (1)

v(c) = 12 in³  =  π*r²*h        h is the height of the cylinder, then

h  =  12 / π*r²

By substitution,  in equation (1) we get  the  Surface area as a function of r

S(r)  =  2*π*r² +   2*π*r*  ( 12 / π*r²)

S(r)  =  2*π*r² + 24 /r

Tacking derivatives on both sides of the equation we get:

S´(r)  =  4*π*r -  24 /r²

S´(r)  = 0            4*π*r -  24 /r²  =  0       π*r - 6/r² = 0

 π*r³ - 6  = 0

r³   =  1,91    

r = 1,248 in    

How do we know that the value  r  =  1,248 makes  Surface area minimum??

We get the second derivative

S´´(r)  =  4*π  +  48/r³    S´´(r)  will be always positive therefore we have a minumum of S   at the value of   r = 1,248 in

Answer:

6. 8 in.²

7. 47.6 m²

9. 20 cm²

Step-by-step explanation:

6. Area of triangle = ½*base*height

base = 4 in.

height = 4 in.

Area = ½*4*4

Area = 2*4

Area = 8 in.²

7. Area of triangle = ½*base*height

base = 13.6 m

height = 7 m

Area = ½*13.6*7

Area = 47.6 m²

9. Area of the shaded figure = area of triangle + area of rectangle

= ½*b*h + L*W

b = 2 cm

h = 4 cm

L = 8 cm

W = 2 cm

Area of the shaded figure = ½*2*4 + 8*2

= 4 + 16

= 20 cm²

Answer:

d 14

Step-by-step explanation:

Answer:

[tex]Mean = 4[/tex]

Step-by-step explanation:

Given

[tex]f(x) =\left \{ {{\frac{c}{x^3} \ x\ge 2} \atop {0\ x<2}} \right.[/tex]

Required

The mean of x

Given that:

[tex]f(x) = \frac{c}{x^3}[/tex]     [tex]x \ge 2[/tex]

First, solve for c using;

[tex]\int\limits^a_b {f(x)} \, dx = 1[/tex]

Substitute [tex]f(x) = \frac{c}{x^3}[/tex] and [tex]x \ge 2[/tex]

[tex]\int\limits^{\infty}_2 {\frac{c}{x^3}} \, dx = 1[/tex]

Isolate c

[tex]c\int\limits^{\infty}_2 {\frac{1}{x^3}} \, dx = 1[/tex]

Rewrite as:

[tex]c\int\limits^{\infty}_2 {x^{-3}} \, dx = 1[/tex]

[tex]c[\frac{x^{-3+1}}{-3 +1}]|\limits^{\infty}_2 = 1[/tex]

[tex]c[\frac{x^{-2}}{-2}]|\limits^{\infty}_2 = 1[/tex]

[tex]-\frac{c}{2} [x^{-2}]|\limits^{\infty}_2 = 1[/tex]

Expand

[tex]-\frac{c}{2} [{\infty}^{-2} - {2}^{-2}]= 1[/tex]

[tex]-\frac{c}{2} [0 - \frac{1}{4}]= 1[/tex]

[tex]-\frac{c}{2} *- \frac{1}{4}= 1[/tex]

[tex]\frac{c}{8}= 1[/tex]

Solve for c

[tex]x = 8 * 1[/tex]

[tex]x = 8[/tex]

So, we have:

[tex]f(x) = \frac{c}{x^3}[/tex]     [tex]x \ge 2[/tex]

[tex]f(x) = \frac{8}{x^3}[/tex]     [tex]x \ge 2[/tex]

So, the mean is calculated as:

[tex]Mean = \int\limits^a_b {x * f(x)} \, dx[/tex]

This gives;

[tex]Mean = \int\limits^{\infty}_2 {x * \frac{8}{x^3}} \, dx[/tex]

[tex]Mean = \int\limits^{\infty}_2 {\frac{8}{x^2}} \, dx[/tex]

[tex]Mean = 8\int\limits^{\infty}_2 {\frac{1}{x^2}} \, dx[/tex]

Rewrite as:

[tex]Mean = 8\int\limits^{\infty}_2 {x^{-2} \, dx[/tex]

Integrate

[tex]Mean = 8 {\frac{x^{-2+1}}{-2+1}|\limits^{\infty}_2[/tex]

[tex]Mean = 8 {\frac{x^{-1}}{-1}}|\limits^{\infty}_2[/tex]

[tex]Mean = -8x^{-1}|\limits^{\infty}_2[/tex]

Expand

[tex]Mean = -8[(\infty)^{-1} - 2^{-1}][/tex]

[tex]Mean = -8[0 - \frac{1}{2}][/tex]

[tex]Mean = -8* - \frac{1}{2}[/tex]

[tex]Mean = 8* \frac{1}{2}[/tex]

[tex]Mean = 4[/tex]

Answer:

I don't understand any thing can you read the question

Answer:

I believe it's 17 :)

Step-by-step explanation:

5×3= 15 +2 = 17

I think the answer should be 12

this is because CH length is 6 x 5 is 30 so 60/5 is 12 for BH.

Answer:

a. y=x-2     b. -2

Step-by-step explanation:

a.) if the slope is 1, the x-int is always the negative of the y-int so y=x-2

b.) in y=mb+b (slope intercept form) b is the y-int so -2

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