The block in the drawing has dimensions L0×2L0×3L0,where L0 =0.5 m. The block has a thermal conductivity of 300 J/(s·m·C˚). In drawings A, B, and C, heat is conducted through the block in three different directions; in each case the temperature of the warmer surface is 37 ˚C and that of the cooler surface is 8 ˚C Determine the heat that flows in 3 s for each case.

Answers

Answer 1

The drawing showing the block is missing, so i have attached it.

Answer:

Q_p = 19575 J

Q_o = 8700 J

Q_g = 78300 J

Explanation:

We are given L0 = 0.5 m

From the image, we can see that;

Length; L = 3L0 = 3 × 0.5 = 1.5 m

Width; W = L0 = 0.5 m

Height; H = 2L0 = 2 × 0.5 = 1 m

Temperature of warmer surface; T_h = 37 ˚C

Temperature of cooler surface; T_l = 8 ˚C

thermal conductivity; k = 300 J/(s·m·C˚)

Time for which the heat flows; t = 3 s

Now, from Fourier's law of conduction, the rate of heat flow is given by;

Q/t = kA(dT/dx)

Where;

A is area

dt is change in temperature = 37 - 8 = 29°C

dx is perpendicular distance

Now, for the amount heat flow perpendicular to the pink surface, from the image dx will be the height 1 m.

Thus;

Q_p/3 = 300 × (1.5 × 0.5) × (29/1)

Q_p/3 = 6525

Q_p = 3 × 6525

Q_p = 19575 J

for the amount heat flow perpendicular to the orange surface, from the image dx will be the length 1.5 m.

Thus;

Q_o/3 = 300 × (1 × 0.5) × (29/1.5)

Q_o/3 = 2900

Q_o = 2900 × 3

Q_o = 8700 J

for the amount heat flow perpendicular to the green surface, from the image dx will be the width 0.5 m.

Thus;

Q_g/3 = 300 × (1 × 1.5) × (29/0.5)

Q_g/3 = 26100

Q_g = 26100 × 3

Q_g = 78300 J

The Block In The Drawing Has Dimensions L02L03L0,where L0 =0.5 M. The Block Has A Thermal Conductivity

Related Questions

Write a letter to a Friend congratulating her / him for her excellent result in annual examination. class 5 the​

Answers

Answer:

ok will do that

Explanation:

Define Continental Drift

Answers

Answer:

the gradual movement of the continents across the earth's surface through geological time.

Answer:

Continental drift is the hypothesis that the Earth's continents have moved over geologic time relatives to each other.

4. A car, initially traveling east with a speed of
5.0 m/s, is accelerated uniformly at 2.0 m/s2 east for
10 s along a straight line. During this 10 s
interval the car travels a total distance of
A. 50 m
B. 60 m
C. 100 m
✓ D. 150 m

Answers

Answer:

150 m

Explanation:

Given,

u=5m/s

a=2m/s2

t=10s

v=?

s=?

Now,

v=u+at

=5+2×10

=5+20

=25m/s

So,

s=u+v/2×t

=5+25/2×10

=30/2×10

=15×10

=150m

What does Newton's first law describe?
A. The tendency of moving objects to stay in motion
OB. The attractive force between two objects due to their masses
O C. How forces balance out to zero net force
D. The change in an object's position over time

Answers

Answer:

A. the tendency of moving objects to stay in motion

Explanation:

just did it on ap3x

Which of the following concerning thermal energy flow be correct?

Heat would flow from a hot cup of coffee to a room temperature table.
Heat would flow from a cold glass of lemonade to your hand.
Heat would flow from an ice cube to your hand.
Heat would flow from your hand to a hot cup of coffee.

Answers

Answer:

Heat would flow from a hot cup of coffee to a room temperature table.

Explanation:

Thermal energy will flow from a hot cup of coffee to a room temperature table.

Heat is a form of thermal energy which is the  average kinetic energy of the particles of system.

Typically heat flows from a place system at high temperature to one with a low temperature. Heat never flows from a cold to a hot bodyHeat moves from a hot to a cold body in a system.

a 110 volt wall outlet supplies power to a stereo with a resistance of 10 ohms. how much current is flowing through the stereo?​

Answers

Answer:

look in internet u can find online converter and there u will get a rel answer

Explanation:

A small first-aid kit is dropped by a rock climber who is descending steadily at -1.25 m/s. After 2.5 seconds, what is the velocity of the first aid kit and how far is the kit below the climber?

Answers

The genuine answer here

A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has a period of 0.5 seconds. Determine the length of the rope (the radius of the circle. ​

Answers

Answer:

r = 0.5 m

Explanation:

First we find the angular speed of the ball by using its period:

ω = θ/t

For the time period:

ω = angular speed = ?

θ = angular displacement = 2π rad

t = time period = 0.5 s

Therefore,

ω = 2π rad/0.5 s

ω = 12.56 rad/s

Now, for the radius:

v = rω

r = v/ω

where,

v = linear speed = 6.29 m/s

r = radius = ?

r = (6.29 m/s)/(12.56 rad/s)

r = 0.5 m

An object traveling at a constant velocity of 15 m/s is experiencing no net
force.
True or
False

Answers

False
It is experiencing net force

Equations of Motion 2D - Will mark the brainliest

A cannon on horizontal ground, at point C, is used to target a point T 25m behind a narrow wall. Unfortunately the cannon is damaged and can only fire at a 45 ∘ angle and at one speed.

a. If the cannonball leaves the cannon at u =35ms −1 at what distance d must the cannon be placed in front of the wall in order to hit the target, if the wall is ignored and the target is at the same height as the cannon


b. The wall is 15.0m high. Does the cannonball actually go over the wall and hit the target? If so, by how much?

Answers

Answer:

Using the range formula   S = V^2 * sin 2 theta / g

So the cannonball should travel

S = 35^2 * sin 90 / 9.8 = 125 m

Then the cannon should be placed 100 m from the wall

H = Vy t - 1/2 g t^2   height of cannonball after time t

Vy = 35 * sin 45 = 24.7 m/s     vertical speed of cannonball

Vx = 35 * cos 45 = 24.7 m/s

t = 100 m / 24,7 m/s = 4.04 sec    time for cannonball to reach wall

H = Vy t - 1/2 g t^2       height of cannonball after time t

H = 24.7 * 4.04 - 1/2 * 9.8 * 4.04^2 = 19.8 m

19.8 m - 15 m = 4.8 m     cannonball clears wall by 4.8 m

The projectile launch ratios allow to find the results on the cannonball launch questions are:

 a) The canyon is at x = 100 m from the wall.

 b) The bullet hits the wall at a height of 4.8 m above the height of the wall.

Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is gravity acceleration.

A) Indicate that the initial speed of the bullet is v = 35 m/s with an angle  θ=45º, which is the distance from the wall. The target is 25 m behind the wall, in the attachment we have a scheme of the system.

Let's find the range that is the horizontal distance for which the height is  zero.

       [tex]R = \frac{v_p^2 \ sin \ 2\theta}{g}[/tex]

Let's calculate.

       R = [tex]\frac{35^2 \ sin ( 2 45(}{9.8}[/tex]  

       R = 125 m

Therefore the canonl must be 100 m from the wall.

B) The height of the wall is y = 15m, the blah manages to pass it and by how much.

We use trigonometry to find the components of velocity.

         v₀ₓ = v₀ cos θ

         [tex]v_{oy}[/tex] = v₀ sin θ

          v₀ₓ = 34 cos 45 = 24.7 m / s

          [tex]v_{oy}[/tex] = vo sin 45 = 24.7 m / s

Let's find the time it takes for the cannonball to travel the x = 100 m

        [tex]v_x = \frac{x}{t} \\ t = \frac{x}{v_x}[/tex]

        t = [tex]\frac{100}{35 \ cos 45 }[/tex]  

        t = 4.04 s

Let's find the height for this time.

        y = [tex]v_[oy}[/tex] t - ½ g t²

         

Let's calculate

        y = 24.7 4.04 - ½ 9.8 4.04²

        y = 19.8 m

This height is greater than the height of the wall h = 15m, therefore the cannoball passes the wall, by a difference in height.

        Δy = y -h

        Δy = 19.8-15

        Δy = 4.8 m

In conclusion, using the projectile launch ratios we can find the results on the cannonball launch questions are:

 a) The canyon is at x = 100 m from the wall.

 b) The cannonball hits the wall at a height of 4.8m above the height of the wall.

Learn more here:  brainly.com/question/10903823

After 20 seconds, a 200-kg object increases its velocity from 15 m/s to 40 m/s. Determine the impulse applied to the object. (Also show your work so I can understand it better and ty)

Answers

Answer:

Imp_{1-2}=5000[kg*m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.

It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.

ΣPbefore = ΣPafter

P = momentum = m*v [kg*m/s]

In this way, we will construct the following equation.

[tex](m_{1}*v_{1})+ Imp_{1-2}=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the object = 200 [kg]

v₁ = velocity of the object before the impulse = 15 [m/s]

v₂ = velocity of the object after the impulse = 40 [m/s]

Now replacing:

[tex](200*15) + Imp_{1-2} = (200*40)\\Imp_{1-2}=5000[kg*m/s][/tex]

Which statement best describes scientific laws? (2 points)
O Scientific laws are scientists' opinions of why events occur.
Scientific laws are facts that describe observed reoccurring natural events.
Scientific laws explain why natural events occur.
Scientific laws were theories that have been proven to be true.

Answers

Answer:

Scientific laws are facts that describe observed reoccurring natural events.

Explanation:

Scientific laws are explanations for the behavior of the natural world. Scientific theories are explanations for scientific laws.

Andy took a bus and then walked from his home to downtown. For the
first 1.6 hour, the bus drove at an average speed of 15 km/h. For the
next 0.4 hours, he walked at an average speed of 4.5 km/h. What was
the average speed for the whole journey?

Answers

Answer:

Av = 12.9 [km/h]

Explanation:

We must remember that the average speed is defined as the relationship between the space traveled over a certain time.

[tex]Av = x/t[/tex]

where:

Av = average speed [km/h]

x = distance [km]

t = time [hr]

For when he was on the bus

The distance can be calculated by clearing the equation, for the term of the distance

[tex]x_{1}= A_{v}*t\\x_{1}= 15*1.6\\x_{1}=24[km][/tex]

For when Andy was walking

[tex]x_{2}=A_{v}*t\\x_{2}=4.5*0.4\\x_{2}=1.8 [km][/tex]

Now the total time is the sum of 1.6 + 0.4 = 2 [hr], and the total distance is the sum of the distances calculated above.

[tex]x = 24 + 1.8\\x = 25.8 [km][/tex]

The average speed is calculated using the ratio of space to time.

[tex]Av = 25.8/2\\Av = 12.9 [km/h][/tex]

what is the significance of second law of thermodynamics​

Answers

Answer: Second law of thermodynamics is very important because it talks about entropy and  'entropy dictates whether or not a process or a reaction is going to be spontaneous'.

Explanation:

What would take more work: a 10 kg bowling ball lifted 1 meter off the ground, or a 1 kg laptop lifted 10 meter off the ground? Explain how you arrived at your answer. PLEASE HELP!!!!!!!!!! 50 POINTSSSSS

Answers

Answer:

10kg ball

Explanation:

a laptop is a lot less in weight so you have to use less force to lift it

Answer:

10 kg bowling ball

Explanation:

A h e m.

It would be easy to lift 1kg laptop 20 meters without breaking a sweat and would be less than your body weight. But a 10kg bowling ball is that x10 so its  heavier

What is the gravitational force between two identical 50,000 kg asteroids whose centers of mass are separated by 1000 m?

Answers

Answer:

The gravitational force between the two masses is 1.668575 × 10⁻¹¹ N

Explanation:

The given parameters are;

The mass of the two asteroids having gravitational attraction, are m₁ = m₂ = m = 50,000 kg

The separation distance between their centers, r = 1,000 m

The gravitational attraction force, F, between the two masses is given as follows;

[tex]F =G\dfrac{m_{1}m_{2}}{r^{2}}[/tex]

Where;

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m₁ = m₂ = m

Substituting the values gives;

[tex]F =6.67430 \times 10^{-11} \times \dfrac{50,000 \times 50,000}{1000^{2}} = 1.668575 \times 10^{-7} \ N[/tex]

The gravitational force, F, between the two masses = 1.668575 × 10⁻¹¹ N.

The gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.

Given the data in the question

Since the asteroids are identical

Mass of the asteroids; [tex]m_1 = m_2 = 50000kg[/tex]Distance between the centers of the masses; [tex]r = 1000m[/tex]

Gravitational force; [tex]F =\ ?[/tex]

To determine the gravitational force between two identical asteroids, we use the Newton's law of universal gravitation:

[tex]F = G\frac{m_1m_2}{r^2}[/tex]

Where [tex]m_1[/tex] is mass of object 1, [tex]m_2[/tex] is mass of object 2, r is the distance between centers of the masses and G is the Gravitational constant ( [tex]6.67408 * 10^{-11} m^3/kgs^2[/tex] )

We substitute our values into the equation

[tex]F = (6.67408 * 10^{-11} m^3/kgs^2) \frac{50000kg*50000kg}{(1000m)^2} \\\\F = \frac{0.166852kgm^3/s^2}{1000000m^2}\\\\ F = 1.67 * 10^{-7}kg.m/s^2\\\\F = 1.67 * 10^{-7}N[/tex]

Therefore, the gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.

Learn more: https://brainly.com/question/19228907

Which type of heating system includes fans to circulate warm air?
(DIsclaimer: Unless you have an explanation on how you got your answer, don't bother awnesering.)

A. Radiant heating
B. Electric baseboard heating
C. Forced-air heating
D. Hot water heating

Answers

Answer:

C.Forced air

Explanation:

HVAC system

"By far the most common HVAC system in modern North American homes is the forced-air system that uses a furnace with a blower fan that delivers warmed air to the various rooms of the home through a network of ducts."

So can you please mark me brainliest?

Determine the momentum of a 25kg freshman football player moving southward at 2m/s.

Answers

Answer:

50 kg*m/s southward

Explanation:

p=mv

 =25kg(2m/s)

 =50 kg*m/s

If your problem 50 joules of work lifting a 10 - box from to a shelf how high is the segregation

Answers

Answer:

5m

Explanation:

Given parameters:

Work done in lifting the box  = 50J

Force applied  = 10N

Unknown:

Height of lifting the box  = ?

Solution:

Work done is the produce of force and distance;

      Work done  = Force x distance

Now to find the height;

  Work done  = Force  x height;

   50  = 10 x h

         h  = 5m

Pls help, I have a test on this, with explanation.

Answers

Answer:

the answer is B

Explanation:

we assume that all of these springs have tha same k , the spring constant

elastic energy for the initial system = Ep1=  [tex]\frac{kd^{2} }{2}[/tex]

for the new changed system , the spring constant = k1+k2 = k+k = 2k  , but the displacement is also reduced to 0.5 d

so Ep2 = [tex]\frac{2k(0.5d)^{2} }{2} = \frac{kd^2}{4}[/tex]

so the new total Ep stored in the new system is 1/2Ep

hope it helps

a flywheel turns at 600 rpm compute the angular speed at any point on the wheel and the tangential speed 0.5 m from the centre ​

Answers

Answer:

30m÷hour

Explanation:

600÷0.5=30m÷hour

What part of the plant takes in carbon dioxide?

1.Roots
2.Stomata
3.Minerals
4.Soil

Answers

The answer is number 2 stomata.

the answer is stomata 2

An 856 kg drag race car accelerates from rest to 105 km/h in .934s. What change in momentum does the force produce? Answer in units of kg • m/s

Part 2: what average force is exerted on the car? Answer in N

Answers

Hello!

Topic: Dinamic

Value to calculate: Force

First, we have to calculate the aceleration, for that, lets aplicate the formula:

[tex]\boxed{a=\frac{V-Vi}{t} }[/tex]

How the final velocity is in km/h, we have to convert it on m/s, so:

m/s = km/h / 3,6

m/s = 105 / 3,6

m/s = 29,16

Then, lets replace formula according problem information:

[tex]a = \dfrac{29,16m/s-0m/s}{0,934s}[/tex]

[tex]a =31,22\ m/s^{2}[/tex]

Now, how we have the aceleration, lets applicate second law of newton for calculate the force produced:

[tex]\boxed{F=ma}[/tex]

Replace and resolve it:

F = 856 kg * 31,22 m/s^2

F = 26724,32 kg * m/s^2

Then the force is of 26724,32 kg * m/s^2

But how we know an 1 kg * m/s^2 = 1 N

Then the average of the force is of 26724,32 N  

(1) The change in momentum of race car is 89880 kg-km/h.

(2) The average force exerted on the car is of 96231.26 N.

Given data:

The mass of race car is, m = 856 kg.

The initial speed of car is, u = 0 km/h.

The final speed of car is, v = 105 km/h.

The time interval is, t = 0.934 s.

1)

The change in the impact due to average force is known as momentum change. The expression for the change in momentum is given as follows,

[tex]\Delta P = m(v-u)[/tex]

Solving as,

[tex]\Delta P = 856 \times (105-0)\\\\\Delta P = 89880 \;\rm kg.km/h[/tex]

Thus, we can conclude that the change in momentum of race car is 89880 kg-km/h.

2)

Now, use the concept of impulse-momentum which says that the impulse is equal to change in momentum. Which means,

[tex]I = \Delta P[/tex]

And impulse is,

[tex]F \times t = \Delta P\\\\F = \dfrac{\Delta P}{t}[/tex]

Solving as,

[tex]F = \dfrac{89880}{0.934}\\\\F = 96231.26 \;\rm N[/tex]

Thus, we can conclude that the average force exerted on the car is of 96231.26 N.

Learn more about the impulse-momentum theorem here:

https://brainly.com/question/14121529

Who is son of nation ​

Answers

Explanation:

well the father of nation is Mahtma Gandhi.

How much net force is required to accelerate a 6 kg toy car initially at rest to a velocity of 2m/s in 4s?

Answers

Answer:

3N

Explanation:

Given parameters:

Mass of toy car  = 6kg

Initial velocity = 0m/s

Final velocity  = 2m/s

Time  = 4s

Unknown:

Net force  = ?

Solution:

The net force is given by;

      Force  = mass x acceleration;

     Force  = mass  x [tex]\frac{v - u}{t}[/tex]  

 v is the final velocity

 u is the initial velocity

 t is the time taken

Now insert the parameters and solve;

  Force  = 6 x [tex]\frac{2 - 0}{4}[/tex]   = 3N

what is the process of subduction

Answers

Answer:

Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.

What is the best way to dress for an outdoor trip in cold weather?

A. Wear several thin layers and a waterproof top layer.

B. Wear two layers of heavy clothing and a waterproof jacket.

C. Wear dark colors for insulation.

D. Wear only cotton clothing.

Answers

Answer:

A: wear several thin layers and a waterproof top layer

Explanation:

The most common cause of hypothermia is getting wet. Wet clothes combined with wind can pull heat away from the body very quickly. Wool is a good insulator even when it is wet, but wet cotton will bolster heat loss. When dressing for cold weather, put on several thin layers, rather than one or two heavy ones, and top with windproof and waterproof outer layers.

The best way to dress for an outdoor trip in cold weather is to wear several thin layers and a waterproof top layer, the correct option is A.

What is insulation?

Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.

For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.

Learn more about insulation

https://brainly.com/question/14363642

#SPJ2

A shopper walks westward 2.8 meters in the first 5 minutes and then eastward 9.2 meters in the next 10 minutes. What is the shopper's total travel distance? ​

Answers

Answer:

12m

Explanation:

Given parameters:

Distance walked westward  = 2.8m

Time of travel  = 5min

Distance walked eastward = 9.2m

Time of travel  = 10min

Unknown:

The total shopper's travel distance  = ?

Solution:

Total distance traveled is the sum of the length of path covered by a body. It is a scalar quantity.

 Total distance = distance walked westward + distance walked eastward

  Total distance  = 2.8m + 9.2m  = 12m

A map of earthquakes and volcanoes on Earth shows that they do not occur in evenly distributed areas, but they also do not occur randomly over Earth's surface. Describe what GPS measurements show about the distribution of locations where earthquakes and volcanoes occur.

Answers

Volcanoes occur at any location where the Earth's crust is broken allowing the magma within the Earth to escape. Volcanoes are commonly found at edges of tectonic plates. ... Near tectonic plate boundaries. The world's tectonic plates is where you find the distribution of major earthquakes and volcanoes.

Having good etiquette and sports ethics will make you a more respected player.

Answers

Answer:

this is true

Explanation:

just did the it on edg 2020

Answer:

True

Explanation:

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