The average speed of an oxygen molecule is 6.14 x 104 cm/sec at a certain temperature. What is the average speed of a CO2 molecule at the same temperature? (molar mass O2 = 31.9988; CO2 = 44.0098)

Answers

Answer 1

Answer:

the average speed of [tex]V_{av} CO_2[/tex] is 5.24 ×  104 cm/s

Explanation:

The computation of the average speed of a [tex]CO_2[/tex] is as follows:

[tex]\sqrt{average} = \sqrt{\frac{8 RT}{\pi M} }[/tex]

where,

M = Molar mass

[tex]V_{av} = \frac{\sqrt{1}}{M}[/tex]

Given that

[tex]V_{av} \ of\ oxygen= 6.14 \times 10^4 cm/s[/tex]

The molar mass of oxygen i.e. (MO_2) = 31.9988 g/mol

And, the molar mass of CO_2 is  44.0098 g/mol

Now

[tex]\frac{V_{av} CO_2}{V_{av} O_2} = \frac{\sqrt{M_{O2} }}{M_{CO2}}[/tex]

Now place these values to the above formula

[tex]\frac{V_{av}CO_2}{6.14\times 104 cm/s} = \frac{\sqrt{31.9988} }{44.0098}[/tex]

So,

V_av CO_2 is 5.24 ×  104 cm/s

hence, the average speed of [tex]V_{av} CO_2[/tex] is 5.24 ×  104 cm/s


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Answers

The question is incorrect, the correct question is;

Carbon-14, which is present in all living tissue, radioactively decays via a first-order process. A one-gram sample of wood taken from a living tree gives a rate for carbon-14 decay of 13.6 counts per minute. If the half-life for carbon-14 is 5720 years, how old is a wood sample that gives a rate for carbon-14 decay of 11.9 counts per minute?

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Answers

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