The active ingredient in one does of antacid A is 0.50g Al(OH)3. the active ingredient in one does of antacid B is 0.50g CaCO3. Would one does of antacid A or B neutralize more stomach acid? Explain your choice, and show a calculation to support your answer.

Answer:

n = 0.0102 mol.

Explanation:

Hello there!

In this case, according to the ideal gas law, which allows us to set up a relationship among volume, pressure, temperature and moles, we can define it as:

[tex]PV=nRT[/tex]

Thus, given the volume in liters (0.1000 L), temperature in kelvins (298.15 K) and pressure in atmospheres (2.50 atm), we can solve for moles as shown below:

[tex]n=\frac{PV}{RT}[/tex]

Thereafter, we plug in the aforementioned values to obtain:

[tex]n=\frac{2.50atm*0.1000L}{0.08206\frac{atm*L}{mol*K}*298.15K}\\\\n=0.0102mol[/tex]

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Answer:

The number of protons in one atom of an element determines the atom's identity, and the number of electrons determines its electrical charge. The atomic number tells you the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element.

Explanation:

Answer:

Performance Tasks 188; Instructional Videos 75

Explanation:

Answer:

True

Explanation:

Answer:

Of course I breathe air.

Explanation:

I'm not a fish.

Answer:

[tex]ummmmmmm \: yes \: [/tex]

Answer:

not the right answer but I need this for the answer the question thing

Answer:

In summer, it typically rains less than 5 cm (<2 inches), while in winter it rains 25–44 cm (10–17 inches).

Explanation:

because tundra vegetation is mostly found in desert areas

Answer:

.0014 M/s ( (mol*L^-1 / s) )

Explanation:

Since the rate law of a zero order reaction is Rate = k[A]^0, the rate is .0014 * (1.65)^0 = .0014

Answer:

F

Explanation:

Answer:

PCl₃

Explanation:

To determine the empirical formula of a compound, we need to follow a series of steps.

Step 1: Divide each percent composition by the atomic mass of the element

P: 22.6/30.97 = 0.729

Cl: 77.4/35.45 = 2.18

Step 2: Divide all the numbers by the smallest one, i.e. 0.729

P: 0.729/0.729 = 1

Cl: 2.18/0.729 ≈ 3

The empirical formula of the compound is PCl₃.

Answer:

If you add bromine water, an aqueous solution of bromine, to the test tubes, you can tell which is propene, the alkene. The bromine reacts with and saturates the double bonds in alkenes, and so decolourises.

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Answer:

The explanation is given below:

Explanation:

As we know that the volume is inversely proportional to the volume. If the pressure is rising from 1 atm to 3 atm so the volume of the ballon would decrease

P_1V_1 = P_2V_2

1.0 × 2.5L = 3 × V_2

V_2 = 0.833L

Since the air is moving from high pressure to low pressure and the two ballons are interconnected via a long pipe so the movement of the air is from bottom to top

Answer:

pOH = 11.5

[H⁺] = 0.003 M

[OH⁻] = 3 × 10⁻¹² M

Explanation:

The computation is shown below:

Given that

pH = 2.5

Based on the above information

We know that

pH + pOH = 14  ⇒  pOH = 14 - pH

pOH = 14 - 2.5

pOH = 11.5

[H⁺] = 10^(-pH) = 10^(-2.5)

[H⁺] = 0.003 M

[OH⁻] = 10^(-pOH)

= 10^(-11.5)

= 3 × 10⁻¹² M

[OH⁻] = 3 × 10⁻¹² M

Hence, the above represents the answer

Explanation:

This would be similar to how the poles work in the North and South. Due to their placement, they recieve much more sun light than the rest of the Earth since we rotate horizontally. However, their placement also makes them farther from the sun than the rest of Earth, therefore not receiving as much heat.

Answer:

[tex]\Delta _{neutralization}H=-73\frac{J}{mmol}[/tex]

Explanation:

Hello there!

In this case, by considering this calorimetry problem, it is possible to realize that the heat released by the reaction between HCl and NaOH is absorbed by the reaction mixture, which can be assumed to have the same density and specific heat of pure water; thus, we calculate this heat as a function of the specified temperature change:

[tex]Q_{rxn}=-Q_{solution}\\\\Q_{rxn}=-m_{solution}C_{solution}(T_2-T_1)[/tex]

Thus, we plug in the data, by also considering that the total volume of solution is 19mL+19mL=38mL:

[tex]Q_{rxn}=-(38mL*\frac{1g}{1mL} )(4.184\frac{J}{g\°C}) (37.3\°C-28.6\°C)\\\\Q_{rxn}=-1383.2J[/tex]

Next, since the reaction between NaOH and HCl is:

[tex]NaOH+HCl\rightarrow NaCl+H_2O[/tex]

Whereas there is 1:1 mole ratio of NaOH to HCl, we infer they both react with the same moles, defined by the volume and molarity:

[tex]n_{rxn}=0.019L*1mol/L\\\\n_{rxn}=0.019mol[/tex]

Finally, to compute the enthalpy of neutralization we divide the total heat due to the reaction by the reaction moles to obtain:

[tex]\Delta _{neutralization}H=\frac{Q_{rxn}}{n_{rxn}=}\\\\ \Delta _{neutralization}H=\frac{-1383.23J}{0.019mol}\\\\\Delta _{neutralization}H=-72801.6\frac{J}{mol}*\frac{1mol}{1000mmol}\\\\\Delta _{neutralization}H=-73\frac{J}{mmol}[/tex]

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Answer:

4.5M

Explanation:

The solution was diluted from 2.0L to 3.0L, the dilution factor was:

3.0L / 2.0L = 1.5.

That means the solution was diluted 1.5 times.

As the final molarity of the diluted solution is 3.0M, the initial molarity of the solution was:

3.0M * 1.5 =

Answer:

decomposers

Explanation:

Answer:

[tex]T_1=-91.18\°C[/tex]

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

[tex]\frac{T_1}{V_1}= \frac{T_2}{V_2}[/tex]

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

[tex]T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C[/tex]

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Answer:

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

Explanation:

The question is missing but I think it must be about writing and balancing the equation.

Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce  a precipitate of copper (II) fluoride (I fixed a mistake here) and aqueous potassium sulfate. This is a double displacement reaction.

CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄

Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

Answer:

A) 1.72 atm

Explanation:

Dalton's Law of Partial Pressures

[tex]P_{t} = P_{1} + P_{2} + P_{3} ....[/tex]

4.43 atm = 1.23 atm + 1.48 atm + x

x = 4.43 atm - (1.23 atm + 1.48 atm)

x = 1.72 atm

Answer:

The correct answer is C, tertiary.

The following alcohol is a tertiary alcohol. Hence, option C is correct.

A primary alcohol is a compound in which a hydroxy group, ‒OH, is attached to a saturated carbon atom which has either three hydrogen atoms attached to it or only one other carbon atom and two hydrogen atoms attached to it.

Here, the carbon atom holding the OH group is attached directly to three alkyl groups.

Hence, the following alcohol is a tertiary alcohol.

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Answer:

there are N_A, "Avogadro's number" of copper atoms in a 63.55*g mass of copper wire. And N_A, "Avogadro's number" = 6.022xx10^23 individual copper atoms. I look on the Periodic Table, and at Z=29, i.e. copper, the quoted atomic mass is 63.55*g.

Explanation:

One mole of every substance contains 6.022×10²³ atoms. The atomic mass of copper is 63.55 g. Thus it is one mole of copper which contains copper 6.022×10²³ atoms.

Copper is 29th element in periodic table. It is a transition metal classified into d-block. Transition metals are named so because they in between the metals and non-metals in periodic table.

Transition metals have varying oxidation state. Copper exists in +1, +2 and +3 oxidation states.

Any substance containing 6.022×10²³ atoms is called one mole of that substance. This number is called Avogadro number. Hence one mole of each element contains avogadro number of its atoms.

Similarly one mole of each compound contains 6.022×10²³ number of molecules. Here, the atomic mass of copper is 63.55 g. That is one mole of copper weighs 63.55 g. Hence, number of atoms in 63.55 g of copper is 6.022×10²³ atoms.

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Answer:

There are 2.85 x 10^22 atoms of carbon in a diamond with a mass of 0.568 g.

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Answer:

Unbalanced forces are not equal, and they always cause the motion of an object to change the speed and/or direction that it is moving.

Explanation:

When two unbalanced forces are exerted in opposite directions, their combined force is equal to the difference between the two forces.

The magnitude and direction of the net force affects the resulting motion

This combined force is exerted in the direction of the larger force

For example, if two students push on opposite sides of a box sitting on the floor, the student on the left pushes with less force (small arrow) on the box than the student on the right side of the box (long arrow).

The resulting action (net force: smaller arrow to the right of the = shows that the box will change its motion in the direction of the greater force

If unbalanced forces are exerted in the same direction, the resulting force (net force) will be the sum of the forces in the direction the forces are applied.

When forces act in the same direction, their forces are added. When forces act in opposite directions, their forces are subtracted from each other.

Unbalanced forces also cause a nonmoving object to change its motion

If there is no net force acting on the object, the motion does not change. If there is a net force acting on an object, the speed of the object will change in the direction of the net force.

Answer: I dont know

Explanation: figure it out

Answer:

Sally's average speed is 0.5 km/min

Explanation:

speed=distance/time

so, 5km/10min=0.5 km/min

Answer:

NH3 ------dipole - dipole forces

CH3OH ------ dipole - dipole forces

AlBr3 ------- ion - dipole forces

AlCl3 ------- ion - dipole forces

Explanation:

Let us recall that water is a polar molecule. This means that water has a positive as well as a negative end. NH3 also has a dipole. The interaction between solute and solvent dipoles leads to the dissolution of NH3 in water. Hence the strongest intermolecular force here is dipole - dipole forces.

Similarly, CH3OH  possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.

As for AlBr3 and AlCl3, the two substances dissociate into ions in solution and these ions interact with the dipole in water via ion - dipole interaction as its strongest intermolecular interaction.

Answer:

Ammonia [tex]NH_3[/tex]

Aluminium Chloride [tex]AlCl[/tex]

Methanol [tex]CH_3OH[/tex]

Aluminium bromide [tex]AlBr_3[/tex]

Explanation:

Because water is not in ionic form it can only forms dipole forces which are strongest. Methanol, Ammonia and AlCl are also dipoles not ions . Thus dipole dipole forces exist.

On the other hand, aluminium bromide are ionic and it can forms ion dipole bonds with water.

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Answer:

it is soluble in water

Explanation:

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